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How to randomly split data into three equal sizes?


Randomly take equal number of elements from two groups — create two sub-dataframes from one dataframe with equal number of elementsHow to randomly select an item from a list?How to join (merge) data frames (inner, outer, left, right)How do I pick randomly from an array?Split Data into groups of equal meansdata.table vs dplyr: can one do something well the other can't or does poorly?Selecting random row from a data.frame and assigning it to one of the two other data.frames based on three conditions in RRandomly assign people into different size groups and categoryR: Splitting data frame into equal size groupsHow to Split a df into unique groups?How to Randomly Assign to Groups of Different Sizes






.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;








2















I have a dataset with 9558 rows from three different projects. I want to randomly split this dataset in three equal groups and assign a unique ID for each group, so that Project1_Project_2_Project3 becomes Project1, Project2 and Project3.



I have tried many things, and googled codes from people with similar problem as I have. I have used sample_n() and sample_frac(), but unfortunately I can't solve this issue myself :/



I have made an example of my dataset looking like this:



ProjectName <- c("Project1_Project2_Project3")
data <- data.frame(replicate(10,sample(0:1,9558,rep=TRUE)))
data <- data.frame(ProjectName, data)


And the output should be randomly split in three equal group of nrow=3186 and then assigned to the values



ProjectName Count of rows
Project1 3186
Project2 3186
Project3 3186









share|improve this question


























  • when you say split this means that you do not want repeats in the groups right? as in data in 15 is only in 1 set

    – Hojo.Timberwolf
    Mar 27 at 11:15











  • Does c("Project1", "Project2", "Project3") instead of c("Project1_Project2_Project3") give you what you want?

    – jay.sf
    Mar 27 at 11:18











  • @Hojo.Timberwolf Yes, i dont want repeats in the groups. What do you mean in 15 is only 1 set?

    – Rose Nonglak Seesan Jensen
    Mar 27 at 11:23











  • @jay.sf The real dataset that I have contains data from three different projects and there is only one unique ID for this and it is structured the same way as the one I made. But I would like to split it randomly into three equal groups and each group should have their own name: Project1, Project2 and Project3 :)

    – Rose Nonglak Seesan Jensen
    Mar 27 at 11:23











  • This question needs to be simply modified and asked in a better way to be useful for others too!

    – Majid
    Mar 27 at 11:31

















2















I have a dataset with 9558 rows from three different projects. I want to randomly split this dataset in three equal groups and assign a unique ID for each group, so that Project1_Project_2_Project3 becomes Project1, Project2 and Project3.



I have tried many things, and googled codes from people with similar problem as I have. I have used sample_n() and sample_frac(), but unfortunately I can't solve this issue myself :/



I have made an example of my dataset looking like this:



ProjectName <- c("Project1_Project2_Project3")
data <- data.frame(replicate(10,sample(0:1,9558,rep=TRUE)))
data <- data.frame(ProjectName, data)


And the output should be randomly split in three equal group of nrow=3186 and then assigned to the values



ProjectName Count of rows
Project1 3186
Project2 3186
Project3 3186









share|improve this question


























  • when you say split this means that you do not want repeats in the groups right? as in data in 15 is only in 1 set

    – Hojo.Timberwolf
    Mar 27 at 11:15











  • Does c("Project1", "Project2", "Project3") instead of c("Project1_Project2_Project3") give you what you want?

    – jay.sf
    Mar 27 at 11:18











  • @Hojo.Timberwolf Yes, i dont want repeats in the groups. What do you mean in 15 is only 1 set?

    – Rose Nonglak Seesan Jensen
    Mar 27 at 11:23











  • @jay.sf The real dataset that I have contains data from three different projects and there is only one unique ID for this and it is structured the same way as the one I made. But I would like to split it randomly into three equal groups and each group should have their own name: Project1, Project2 and Project3 :)

    – Rose Nonglak Seesan Jensen
    Mar 27 at 11:23











  • This question needs to be simply modified and asked in a better way to be useful for others too!

    – Majid
    Mar 27 at 11:31













2












2








2


1






I have a dataset with 9558 rows from three different projects. I want to randomly split this dataset in three equal groups and assign a unique ID for each group, so that Project1_Project_2_Project3 becomes Project1, Project2 and Project3.



I have tried many things, and googled codes from people with similar problem as I have. I have used sample_n() and sample_frac(), but unfortunately I can't solve this issue myself :/



I have made an example of my dataset looking like this:



ProjectName <- c("Project1_Project2_Project3")
data <- data.frame(replicate(10,sample(0:1,9558,rep=TRUE)))
data <- data.frame(ProjectName, data)


And the output should be randomly split in three equal group of nrow=3186 and then assigned to the values



ProjectName Count of rows
Project1 3186
Project2 3186
Project3 3186









share|improve this question
















I have a dataset with 9558 rows from three different projects. I want to randomly split this dataset in three equal groups and assign a unique ID for each group, so that Project1_Project_2_Project3 becomes Project1, Project2 and Project3.



I have tried many things, and googled codes from people with similar problem as I have. I have used sample_n() and sample_frac(), but unfortunately I can't solve this issue myself :/



I have made an example of my dataset looking like this:



ProjectName <- c("Project1_Project2_Project3")
data <- data.frame(replicate(10,sample(0:1,9558,rep=TRUE)))
data <- data.frame(ProjectName, data)


And the output should be randomly split in three equal group of nrow=3186 and then assigned to the values



ProjectName Count of rows
Project1 3186
Project2 3186
Project3 3186






r random group-by dplyr divide






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Mar 27 at 11:43









kath

5,71411 silver badges27 bronze badges




5,71411 silver badges27 bronze badges










asked Mar 27 at 11:11









Rose Nonglak Seesan JensenRose Nonglak Seesan Jensen

256 bronze badges




256 bronze badges















  • when you say split this means that you do not want repeats in the groups right? as in data in 15 is only in 1 set

    – Hojo.Timberwolf
    Mar 27 at 11:15











  • Does c("Project1", "Project2", "Project3") instead of c("Project1_Project2_Project3") give you what you want?

    – jay.sf
    Mar 27 at 11:18











  • @Hojo.Timberwolf Yes, i dont want repeats in the groups. What do you mean in 15 is only 1 set?

    – Rose Nonglak Seesan Jensen
    Mar 27 at 11:23











  • @jay.sf The real dataset that I have contains data from three different projects and there is only one unique ID for this and it is structured the same way as the one I made. But I would like to split it randomly into three equal groups and each group should have their own name: Project1, Project2 and Project3 :)

    – Rose Nonglak Seesan Jensen
    Mar 27 at 11:23











  • This question needs to be simply modified and asked in a better way to be useful for others too!

    – Majid
    Mar 27 at 11:31

















  • when you say split this means that you do not want repeats in the groups right? as in data in 15 is only in 1 set

    – Hojo.Timberwolf
    Mar 27 at 11:15











  • Does c("Project1", "Project2", "Project3") instead of c("Project1_Project2_Project3") give you what you want?

    – jay.sf
    Mar 27 at 11:18











  • @Hojo.Timberwolf Yes, i dont want repeats in the groups. What do you mean in 15 is only 1 set?

    – Rose Nonglak Seesan Jensen
    Mar 27 at 11:23











  • @jay.sf The real dataset that I have contains data from three different projects and there is only one unique ID for this and it is structured the same way as the one I made. But I would like to split it randomly into three equal groups and each group should have their own name: Project1, Project2 and Project3 :)

    – Rose Nonglak Seesan Jensen
    Mar 27 at 11:23











  • This question needs to be simply modified and asked in a better way to be useful for others too!

    – Majid
    Mar 27 at 11:31
















when you say split this means that you do not want repeats in the groups right? as in data in 15 is only in 1 set

– Hojo.Timberwolf
Mar 27 at 11:15





when you say split this means that you do not want repeats in the groups right? as in data in 15 is only in 1 set

– Hojo.Timberwolf
Mar 27 at 11:15













Does c("Project1", "Project2", "Project3") instead of c("Project1_Project2_Project3") give you what you want?

– jay.sf
Mar 27 at 11:18





Does c("Project1", "Project2", "Project3") instead of c("Project1_Project2_Project3") give you what you want?

– jay.sf
Mar 27 at 11:18













@Hojo.Timberwolf Yes, i dont want repeats in the groups. What do you mean in 15 is only 1 set?

– Rose Nonglak Seesan Jensen
Mar 27 at 11:23





@Hojo.Timberwolf Yes, i dont want repeats in the groups. What do you mean in 15 is only 1 set?

– Rose Nonglak Seesan Jensen
Mar 27 at 11:23













@jay.sf The real dataset that I have contains data from three different projects and there is only one unique ID for this and it is structured the same way as the one I made. But I would like to split it randomly into three equal groups and each group should have their own name: Project1, Project2 and Project3 :)

– Rose Nonglak Seesan Jensen
Mar 27 at 11:23





@jay.sf The real dataset that I have contains data from three different projects and there is only one unique ID for this and it is structured the same way as the one I made. But I would like to split it randomly into three equal groups and each group should have their own name: Project1, Project2 and Project3 :)

– Rose Nonglak Seesan Jensen
Mar 27 at 11:23













This question needs to be simply modified and asked in a better way to be useful for others too!

– Majid
Mar 27 at 11:31





This question needs to be simply modified and asked in a better way to be useful for others too!

– Majid
Mar 27 at 11:31












4 Answers
4






active

oldest

votes


















2














IMO it should be sufficient to assign just random project names.



dat$ProjectName <- sample(factor(rep(1:3, length.out=nrow(dat)), 
labels=paste0("Project", 1:3)))


Result



head(dat)
# X1 X2 X3 X4 X5 X6 X7 X8 X9 X10 ProjectName
# 1 1 1 0 1 1 1 1 0 1 0 Project1
# 2 1 1 1 1 1 1 0 0 1 0 Project1
# 3 0 0 1 1 0 0 0 1 1 1 Project1
# 4 1 1 1 0 1 0 1 1 0 1 Project3
# 5 1 0 0 1 1 1 1 0 0 1 Project1
# 6 1 0 0 0 0 1 0 1 1 1 Project3

table(dat$ProjectName)
# Project1 Project2 Project3
# 3186 3186 3186


Data



set.seed(42)
dat <- data.frame(replicate(10, sample(0:1, 9558, rep=TRUE)))





share|improve this answer






















  • 1





    Thank you Jay :)

    – Rose Nonglak Seesan Jensen
    Mar 27 at 12:26











  • You're very welcome @RoseNonglakSeesanJensen.

    – jay.sf
    Mar 27 at 12:30


















2














Add an id to data:



data$id <- 1:nrow(data)


Take the first sample:



project1 <- dplyr::sample_frac(data, 0.33333)


Remove the used rows from data and save into project2:



project2 <- data[!(data$id %in% project1$id), ]


Sample half of the remainder:



project3 <- dplyr::sample_frac(project2, 0.5)


Finally remove those in the project3 sample from project2:



project2 <- project2[!(project2$id %in% project3$id), ]


Check all ids are unique:



# should all be FALSE
any(project1$id %in% project2$id)
any(project1$id %in% project3$id)
any(project2$id %in% project3$id)


And double-check the data frames have the right number of cases:



nrow(project1)
nrow(project2)
nrow(project3)





share|improve this answer

























  • Thank you so much Phil :)

    – Rose Nonglak Seesan Jensen
    Mar 27 at 12:26


















2














I had this same problem once. This is how I did it. If you just use sample, the groups are uneven, by sampling off a vector where the groups are even worked for me.



sampleframe <- rep(1:3, ceiling( nrow( data)/3 ) ) 

data$grp <- 0
data[ , "grp" ] <- sample( sampleframe , size=nrow( data) , replace=FALSE )

project1 <- data[data$grp %in% 1 ,]
project2 <- data[data$grp %in% 2 ,]
project3 <- data[data$grp %in% 3 ,]





share|improve this answer

























  • Thank you so much for this! It works :D

    – Rose Nonglak Seesan Jensen
    Mar 27 at 12:26


















1














I like the solution in this comment to a Github gist.



You could generate the indices as suggested:



folds <- split(sample(nrow(data), nrow(data), replace = FALSE), as.factor(1:3))


Then get a list of 3 equal size data frames using:



datalist <- lapply(folds, function(x) data[x, ])





share|improve this answer



























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    4 Answers
    4






    active

    oldest

    votes








    4 Answers
    4






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    2














    IMO it should be sufficient to assign just random project names.



    dat$ProjectName <- sample(factor(rep(1:3, length.out=nrow(dat)), 
    labels=paste0("Project", 1:3)))


    Result



    head(dat)
    # X1 X2 X3 X4 X5 X6 X7 X8 X9 X10 ProjectName
    # 1 1 1 0 1 1 1 1 0 1 0 Project1
    # 2 1 1 1 1 1 1 0 0 1 0 Project1
    # 3 0 0 1 1 0 0 0 1 1 1 Project1
    # 4 1 1 1 0 1 0 1 1 0 1 Project3
    # 5 1 0 0 1 1 1 1 0 0 1 Project1
    # 6 1 0 0 0 0 1 0 1 1 1 Project3

    table(dat$ProjectName)
    # Project1 Project2 Project3
    # 3186 3186 3186


    Data



    set.seed(42)
    dat <- data.frame(replicate(10, sample(0:1, 9558, rep=TRUE)))





    share|improve this answer






















    • 1





      Thank you Jay :)

      – Rose Nonglak Seesan Jensen
      Mar 27 at 12:26











    • You're very welcome @RoseNonglakSeesanJensen.

      – jay.sf
      Mar 27 at 12:30















    2














    IMO it should be sufficient to assign just random project names.



    dat$ProjectName <- sample(factor(rep(1:3, length.out=nrow(dat)), 
    labels=paste0("Project", 1:3)))


    Result



    head(dat)
    # X1 X2 X3 X4 X5 X6 X7 X8 X9 X10 ProjectName
    # 1 1 1 0 1 1 1 1 0 1 0 Project1
    # 2 1 1 1 1 1 1 0 0 1 0 Project1
    # 3 0 0 1 1 0 0 0 1 1 1 Project1
    # 4 1 1 1 0 1 0 1 1 0 1 Project3
    # 5 1 0 0 1 1 1 1 0 0 1 Project1
    # 6 1 0 0 0 0 1 0 1 1 1 Project3

    table(dat$ProjectName)
    # Project1 Project2 Project3
    # 3186 3186 3186


    Data



    set.seed(42)
    dat <- data.frame(replicate(10, sample(0:1, 9558, rep=TRUE)))





    share|improve this answer






















    • 1





      Thank you Jay :)

      – Rose Nonglak Seesan Jensen
      Mar 27 at 12:26











    • You're very welcome @RoseNonglakSeesanJensen.

      – jay.sf
      Mar 27 at 12:30













    2












    2








    2







    IMO it should be sufficient to assign just random project names.



    dat$ProjectName <- sample(factor(rep(1:3, length.out=nrow(dat)), 
    labels=paste0("Project", 1:3)))


    Result



    head(dat)
    # X1 X2 X3 X4 X5 X6 X7 X8 X9 X10 ProjectName
    # 1 1 1 0 1 1 1 1 0 1 0 Project1
    # 2 1 1 1 1 1 1 0 0 1 0 Project1
    # 3 0 0 1 1 0 0 0 1 1 1 Project1
    # 4 1 1 1 0 1 0 1 1 0 1 Project3
    # 5 1 0 0 1 1 1 1 0 0 1 Project1
    # 6 1 0 0 0 0 1 0 1 1 1 Project3

    table(dat$ProjectName)
    # Project1 Project2 Project3
    # 3186 3186 3186


    Data



    set.seed(42)
    dat <- data.frame(replicate(10, sample(0:1, 9558, rep=TRUE)))





    share|improve this answer















    IMO it should be sufficient to assign just random project names.



    dat$ProjectName <- sample(factor(rep(1:3, length.out=nrow(dat)), 
    labels=paste0("Project", 1:3)))


    Result



    head(dat)
    # X1 X2 X3 X4 X5 X6 X7 X8 X9 X10 ProjectName
    # 1 1 1 0 1 1 1 1 0 1 0 Project1
    # 2 1 1 1 1 1 1 0 0 1 0 Project1
    # 3 0 0 1 1 0 0 0 1 1 1 Project1
    # 4 1 1 1 0 1 0 1 1 0 1 Project3
    # 5 1 0 0 1 1 1 1 0 0 1 Project1
    # 6 1 0 0 0 0 1 0 1 1 1 Project3

    table(dat$ProjectName)
    # Project1 Project2 Project3
    # 3186 3186 3186


    Data



    set.seed(42)
    dat <- data.frame(replicate(10, sample(0:1, 9558, rep=TRUE)))






    share|improve this answer














    share|improve this answer



    share|improve this answer








    edited Mar 29 at 5:45

























    answered Mar 27 at 11:50









    jay.sfjay.sf

    10.6k3 gold badges21 silver badges45 bronze badges




    10.6k3 gold badges21 silver badges45 bronze badges










    • 1





      Thank you Jay :)

      – Rose Nonglak Seesan Jensen
      Mar 27 at 12:26











    • You're very welcome @RoseNonglakSeesanJensen.

      – jay.sf
      Mar 27 at 12:30












    • 1





      Thank you Jay :)

      – Rose Nonglak Seesan Jensen
      Mar 27 at 12:26











    • You're very welcome @RoseNonglakSeesanJensen.

      – jay.sf
      Mar 27 at 12:30







    1




    1





    Thank you Jay :)

    – Rose Nonglak Seesan Jensen
    Mar 27 at 12:26





    Thank you Jay :)

    – Rose Nonglak Seesan Jensen
    Mar 27 at 12:26













    You're very welcome @RoseNonglakSeesanJensen.

    – jay.sf
    Mar 27 at 12:30





    You're very welcome @RoseNonglakSeesanJensen.

    – jay.sf
    Mar 27 at 12:30













    2














    Add an id to data:



    data$id <- 1:nrow(data)


    Take the first sample:



    project1 <- dplyr::sample_frac(data, 0.33333)


    Remove the used rows from data and save into project2:



    project2 <- data[!(data$id %in% project1$id), ]


    Sample half of the remainder:



    project3 <- dplyr::sample_frac(project2, 0.5)


    Finally remove those in the project3 sample from project2:



    project2 <- project2[!(project2$id %in% project3$id), ]


    Check all ids are unique:



    # should all be FALSE
    any(project1$id %in% project2$id)
    any(project1$id %in% project3$id)
    any(project2$id %in% project3$id)


    And double-check the data frames have the right number of cases:



    nrow(project1)
    nrow(project2)
    nrow(project3)





    share|improve this answer

























    • Thank you so much Phil :)

      – Rose Nonglak Seesan Jensen
      Mar 27 at 12:26















    2














    Add an id to data:



    data$id <- 1:nrow(data)


    Take the first sample:



    project1 <- dplyr::sample_frac(data, 0.33333)


    Remove the used rows from data and save into project2:



    project2 <- data[!(data$id %in% project1$id), ]


    Sample half of the remainder:



    project3 <- dplyr::sample_frac(project2, 0.5)


    Finally remove those in the project3 sample from project2:



    project2 <- project2[!(project2$id %in% project3$id), ]


    Check all ids are unique:



    # should all be FALSE
    any(project1$id %in% project2$id)
    any(project1$id %in% project3$id)
    any(project2$id %in% project3$id)


    And double-check the data frames have the right number of cases:



    nrow(project1)
    nrow(project2)
    nrow(project3)





    share|improve this answer

























    • Thank you so much Phil :)

      – Rose Nonglak Seesan Jensen
      Mar 27 at 12:26













    2












    2








    2







    Add an id to data:



    data$id <- 1:nrow(data)


    Take the first sample:



    project1 <- dplyr::sample_frac(data, 0.33333)


    Remove the used rows from data and save into project2:



    project2 <- data[!(data$id %in% project1$id), ]


    Sample half of the remainder:



    project3 <- dplyr::sample_frac(project2, 0.5)


    Finally remove those in the project3 sample from project2:



    project2 <- project2[!(project2$id %in% project3$id), ]


    Check all ids are unique:



    # should all be FALSE
    any(project1$id %in% project2$id)
    any(project1$id %in% project3$id)
    any(project2$id %in% project3$id)


    And double-check the data frames have the right number of cases:



    nrow(project1)
    nrow(project2)
    nrow(project3)





    share|improve this answer













    Add an id to data:



    data$id <- 1:nrow(data)


    Take the first sample:



    project1 <- dplyr::sample_frac(data, 0.33333)


    Remove the used rows from data and save into project2:



    project2 <- data[!(data$id %in% project1$id), ]


    Sample half of the remainder:



    project3 <- dplyr::sample_frac(project2, 0.5)


    Finally remove those in the project3 sample from project2:



    project2 <- project2[!(project2$id %in% project3$id), ]


    Check all ids are unique:



    # should all be FALSE
    any(project1$id %in% project2$id)
    any(project1$id %in% project3$id)
    any(project2$id %in% project3$id)


    And double-check the data frames have the right number of cases:



    nrow(project1)
    nrow(project2)
    nrow(project3)






    share|improve this answer












    share|improve this answer



    share|improve this answer










    answered Mar 27 at 11:21









    PhilPhil

    3,1981 gold badge15 silver badges29 bronze badges




    3,1981 gold badge15 silver badges29 bronze badges















    • Thank you so much Phil :)

      – Rose Nonglak Seesan Jensen
      Mar 27 at 12:26

















    • Thank you so much Phil :)

      – Rose Nonglak Seesan Jensen
      Mar 27 at 12:26
















    Thank you so much Phil :)

    – Rose Nonglak Seesan Jensen
    Mar 27 at 12:26





    Thank you so much Phil :)

    – Rose Nonglak Seesan Jensen
    Mar 27 at 12:26











    2














    I had this same problem once. This is how I did it. If you just use sample, the groups are uneven, by sampling off a vector where the groups are even worked for me.



    sampleframe <- rep(1:3, ceiling( nrow( data)/3 ) ) 

    data$grp <- 0
    data[ , "grp" ] <- sample( sampleframe , size=nrow( data) , replace=FALSE )

    project1 <- data[data$grp %in% 1 ,]
    project2 <- data[data$grp %in% 2 ,]
    project3 <- data[data$grp %in% 3 ,]





    share|improve this answer

























    • Thank you so much for this! It works :D

      – Rose Nonglak Seesan Jensen
      Mar 27 at 12:26















    2














    I had this same problem once. This is how I did it. If you just use sample, the groups are uneven, by sampling off a vector where the groups are even worked for me.



    sampleframe <- rep(1:3, ceiling( nrow( data)/3 ) ) 

    data$grp <- 0
    data[ , "grp" ] <- sample( sampleframe , size=nrow( data) , replace=FALSE )

    project1 <- data[data$grp %in% 1 ,]
    project2 <- data[data$grp %in% 2 ,]
    project3 <- data[data$grp %in% 3 ,]





    share|improve this answer

























    • Thank you so much for this! It works :D

      – Rose Nonglak Seesan Jensen
      Mar 27 at 12:26













    2












    2








    2







    I had this same problem once. This is how I did it. If you just use sample, the groups are uneven, by sampling off a vector where the groups are even worked for me.



    sampleframe <- rep(1:3, ceiling( nrow( data)/3 ) ) 

    data$grp <- 0
    data[ , "grp" ] <- sample( sampleframe , size=nrow( data) , replace=FALSE )

    project1 <- data[data$grp %in% 1 ,]
    project2 <- data[data$grp %in% 2 ,]
    project3 <- data[data$grp %in% 3 ,]





    share|improve this answer













    I had this same problem once. This is how I did it. If you just use sample, the groups are uneven, by sampling off a vector where the groups are even worked for me.



    sampleframe <- rep(1:3, ceiling( nrow( data)/3 ) ) 

    data$grp <- 0
    data[ , "grp" ] <- sample( sampleframe , size=nrow( data) , replace=FALSE )

    project1 <- data[data$grp %in% 1 ,]
    project2 <- data[data$grp %in% 2 ,]
    project3 <- data[data$grp %in% 3 ,]






    share|improve this answer












    share|improve this answer



    share|improve this answer










    answered Mar 27 at 11:26









    MatthewRMatthewR

    1,1611 gold badge13 silver badges22 bronze badges




    1,1611 gold badge13 silver badges22 bronze badges















    • Thank you so much for this! It works :D

      – Rose Nonglak Seesan Jensen
      Mar 27 at 12:26

















    • Thank you so much for this! It works :D

      – Rose Nonglak Seesan Jensen
      Mar 27 at 12:26
















    Thank you so much for this! It works :D

    – Rose Nonglak Seesan Jensen
    Mar 27 at 12:26





    Thank you so much for this! It works :D

    – Rose Nonglak Seesan Jensen
    Mar 27 at 12:26











    1














    I like the solution in this comment to a Github gist.



    You could generate the indices as suggested:



    folds <- split(sample(nrow(data), nrow(data), replace = FALSE), as.factor(1:3))


    Then get a list of 3 equal size data frames using:



    datalist <- lapply(folds, function(x) data[x, ])





    share|improve this answer





























      1














      I like the solution in this comment to a Github gist.



      You could generate the indices as suggested:



      folds <- split(sample(nrow(data), nrow(data), replace = FALSE), as.factor(1:3))


      Then get a list of 3 equal size data frames using:



      datalist <- lapply(folds, function(x) data[x, ])





      share|improve this answer



























        1












        1








        1







        I like the solution in this comment to a Github gist.



        You could generate the indices as suggested:



        folds <- split(sample(nrow(data), nrow(data), replace = FALSE), as.factor(1:3))


        Then get a list of 3 equal size data frames using:



        datalist <- lapply(folds, function(x) data[x, ])





        share|improve this answer













        I like the solution in this comment to a Github gist.



        You could generate the indices as suggested:



        folds <- split(sample(nrow(data), nrow(data), replace = FALSE), as.factor(1:3))


        Then get a list of 3 equal size data frames using:



        datalist <- lapply(folds, function(x) data[x, ])






        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Mar 27 at 11:41









        neilfwsneilfws

        20.6k5 gold badges38 silver badges49 bronze badges




        20.6k5 gold badges38 silver badges49 bronze badges






























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