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AJAX live search does not always contain the full value in the search box


Comparison of full text search engine - Lucene, Sphinx, Postgresql, MySQL?Eliminating white space in ajax searchI need Ajax to be able to change a dropdown box selection based on a value from PHP received from SQLmysqli search with while loop output only returns one recordMySQL search in multiple columns using PHP and Ajaxsearch one value in two columns in MySQLPHP AJAX Live SearchSearch a MySQL database for superscript valueDisplay “No matches found” or hide DIV results (AJAX & MySQL)






.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty
margin-bottom:0;









0















I'm setting up a basic AJAX live search for my website but I am encountering an issue where sometimes the whole value of my search box is not being captured properly.



For instance, if I type 'roll' into the search box, sometimes it will return the values for 'ro' instead. This is the most common occurrence as seen here: https://imgur.com/a/u1vLhuz



I say most common occurrence because in the link above, you will see different values captured even though 'roll' is the value of search box for each result. The last image being the desired result. It's as if I type the value in too fast, because I can not reproduce the issue when slowly typing each character.



In desperation I have tried different events, such as keyup, keydown, changed, keypress .on('Keyup') etc. Logging the javascript variable to the console shows the incorrect value, so the sql statement is obviously returning the wrong results (as seen in the album above).



My index.php basically consists of every result before anything is searched:



<ul id="search-results" class="grid cs-style-2 justify-content-center">
$cosmetic->getCard($result);
</ul>


Here is the gist of my ajax.php file:



if (isset($_POST['search'])) 
$search = $_POST['search'];
$sql = "SELECT * FROM Cosmetics WHERE Name LIKE '%$search%' OR Type LIKE '%$search%' OR Rarity LIKE '%$search%' OR CostOrigin LIKE '%$search%' OR ImageName LIKE '%$search%' ORDER BY FIELD(Rarity,'legendary','epic','rare','uncommon','common'), Name";
echo($sql);
$result = $connection->query($sql);
$cosmetic->getCard($result);



and here is the script.js file that is included in the index.php:



$(document).ready(function() 
$("#search").on("keyup", function()
var name = document.getElementById("search").value;
console.log(name);
if (name !== " ")
$.post('/test/ajax.php',search:name, function(data)
$("#search-results").html(data);
);

);
);


In this album: https://imgur.com/a/u1vLhuz I expect the results to be the last image where it actually queries the correct word, instead of capturing other or no values from the search box.










share|improve this question
























  • As you aren't waiting for the whole string to be typed before you start processing it, I think you are having timing problems. I'm wondering what would happen if you simply ran the getElementById and ajax call twice in your function, so that the second call processed the search string as it stood when the first call had finished? Worth a try I think.

    – MandyShaw
    Mar 28 at 23:06











  • Unfortunately seems to still be an issue. I definitely agree though, it does seem to be a timing issue and I tried testing that too, but I don't think it's working. I had var name = $(this).delay(300).val();

    – Fraze
    Mar 29 at 12:48











  • A delay in the script isn't going to help because control is still with the script. You need the script to be releasing control. Have you got the ajax running asynchronously?

    – MandyShaw
    Mar 29 at 13:51











  • Sorry for my ignorance, but isn't it asynchronous by default?

    – Fraze
    Mar 29 at 13:53











  • I don't know, because I don't use JQuery, sorry.

    – MandyShaw
    Mar 29 at 13:55

















0















I'm setting up a basic AJAX live search for my website but I am encountering an issue where sometimes the whole value of my search box is not being captured properly.



For instance, if I type 'roll' into the search box, sometimes it will return the values for 'ro' instead. This is the most common occurrence as seen here: https://imgur.com/a/u1vLhuz



I say most common occurrence because in the link above, you will see different values captured even though 'roll' is the value of search box for each result. The last image being the desired result. It's as if I type the value in too fast, because I can not reproduce the issue when slowly typing each character.



In desperation I have tried different events, such as keyup, keydown, changed, keypress .on('Keyup') etc. Logging the javascript variable to the console shows the incorrect value, so the sql statement is obviously returning the wrong results (as seen in the album above).



My index.php basically consists of every result before anything is searched:



<ul id="search-results" class="grid cs-style-2 justify-content-center">
$cosmetic->getCard($result);
</ul>


Here is the gist of my ajax.php file:



if (isset($_POST['search'])) 
$search = $_POST['search'];
$sql = "SELECT * FROM Cosmetics WHERE Name LIKE '%$search%' OR Type LIKE '%$search%' OR Rarity LIKE '%$search%' OR CostOrigin LIKE '%$search%' OR ImageName LIKE '%$search%' ORDER BY FIELD(Rarity,'legendary','epic','rare','uncommon','common'), Name";
echo($sql);
$result = $connection->query($sql);
$cosmetic->getCard($result);



and here is the script.js file that is included in the index.php:



$(document).ready(function() 
$("#search").on("keyup", function()
var name = document.getElementById("search").value;
console.log(name);
if (name !== " ")
$.post('/test/ajax.php',search:name, function(data)
$("#search-results").html(data);
);

);
);


In this album: https://imgur.com/a/u1vLhuz I expect the results to be the last image where it actually queries the correct word, instead of capturing other or no values from the search box.










share|improve this question
























  • As you aren't waiting for the whole string to be typed before you start processing it, I think you are having timing problems. I'm wondering what would happen if you simply ran the getElementById and ajax call twice in your function, so that the second call processed the search string as it stood when the first call had finished? Worth a try I think.

    – MandyShaw
    Mar 28 at 23:06











  • Unfortunately seems to still be an issue. I definitely agree though, it does seem to be a timing issue and I tried testing that too, but I don't think it's working. I had var name = $(this).delay(300).val();

    – Fraze
    Mar 29 at 12:48











  • A delay in the script isn't going to help because control is still with the script. You need the script to be releasing control. Have you got the ajax running asynchronously?

    – MandyShaw
    Mar 29 at 13:51











  • Sorry for my ignorance, but isn't it asynchronous by default?

    – Fraze
    Mar 29 at 13:53











  • I don't know, because I don't use JQuery, sorry.

    – MandyShaw
    Mar 29 at 13:55













0












0








0








I'm setting up a basic AJAX live search for my website but I am encountering an issue where sometimes the whole value of my search box is not being captured properly.



For instance, if I type 'roll' into the search box, sometimes it will return the values for 'ro' instead. This is the most common occurrence as seen here: https://imgur.com/a/u1vLhuz



I say most common occurrence because in the link above, you will see different values captured even though 'roll' is the value of search box for each result. The last image being the desired result. It's as if I type the value in too fast, because I can not reproduce the issue when slowly typing each character.



In desperation I have tried different events, such as keyup, keydown, changed, keypress .on('Keyup') etc. Logging the javascript variable to the console shows the incorrect value, so the sql statement is obviously returning the wrong results (as seen in the album above).



My index.php basically consists of every result before anything is searched:



<ul id="search-results" class="grid cs-style-2 justify-content-center">
$cosmetic->getCard($result);
</ul>


Here is the gist of my ajax.php file:



if (isset($_POST['search'])) 
$search = $_POST['search'];
$sql = "SELECT * FROM Cosmetics WHERE Name LIKE '%$search%' OR Type LIKE '%$search%' OR Rarity LIKE '%$search%' OR CostOrigin LIKE '%$search%' OR ImageName LIKE '%$search%' ORDER BY FIELD(Rarity,'legendary','epic','rare','uncommon','common'), Name";
echo($sql);
$result = $connection->query($sql);
$cosmetic->getCard($result);



and here is the script.js file that is included in the index.php:



$(document).ready(function() 
$("#search").on("keyup", function()
var name = document.getElementById("search").value;
console.log(name);
if (name !== " ")
$.post('/test/ajax.php',search:name, function(data)
$("#search-results").html(data);
);

);
);


In this album: https://imgur.com/a/u1vLhuz I expect the results to be the last image where it actually queries the correct word, instead of capturing other or no values from the search box.










share|improve this question














I'm setting up a basic AJAX live search for my website but I am encountering an issue where sometimes the whole value of my search box is not being captured properly.



For instance, if I type 'roll' into the search box, sometimes it will return the values for 'ro' instead. This is the most common occurrence as seen here: https://imgur.com/a/u1vLhuz



I say most common occurrence because in the link above, you will see different values captured even though 'roll' is the value of search box for each result. The last image being the desired result. It's as if I type the value in too fast, because I can not reproduce the issue when slowly typing each character.



In desperation I have tried different events, such as keyup, keydown, changed, keypress .on('Keyup') etc. Logging the javascript variable to the console shows the incorrect value, so the sql statement is obviously returning the wrong results (as seen in the album above).



My index.php basically consists of every result before anything is searched:



<ul id="search-results" class="grid cs-style-2 justify-content-center">
$cosmetic->getCard($result);
</ul>


Here is the gist of my ajax.php file:



if (isset($_POST['search'])) 
$search = $_POST['search'];
$sql = "SELECT * FROM Cosmetics WHERE Name LIKE '%$search%' OR Type LIKE '%$search%' OR Rarity LIKE '%$search%' OR CostOrigin LIKE '%$search%' OR ImageName LIKE '%$search%' ORDER BY FIELD(Rarity,'legendary','epic','rare','uncommon','common'), Name";
echo($sql);
$result = $connection->query($sql);
$cosmetic->getCard($result);



and here is the script.js file that is included in the index.php:



$(document).ready(function() 
$("#search").on("keyup", function()
var name = document.getElementById("search").value;
console.log(name);
if (name !== " ")
$.post('/test/ajax.php',search:name, function(data)
$("#search-results").html(data);
);

);
);


In this album: https://imgur.com/a/u1vLhuz I expect the results to be the last image where it actually queries the correct word, instead of capturing other or no values from the search box.







php mysql ajax






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Mar 28 at 21:02









FrazeFraze

1




1















  • As you aren't waiting for the whole string to be typed before you start processing it, I think you are having timing problems. I'm wondering what would happen if you simply ran the getElementById and ajax call twice in your function, so that the second call processed the search string as it stood when the first call had finished? Worth a try I think.

    – MandyShaw
    Mar 28 at 23:06











  • Unfortunately seems to still be an issue. I definitely agree though, it does seem to be a timing issue and I tried testing that too, but I don't think it's working. I had var name = $(this).delay(300).val();

    – Fraze
    Mar 29 at 12:48











  • A delay in the script isn't going to help because control is still with the script. You need the script to be releasing control. Have you got the ajax running asynchronously?

    – MandyShaw
    Mar 29 at 13:51











  • Sorry for my ignorance, but isn't it asynchronous by default?

    – Fraze
    Mar 29 at 13:53











  • I don't know, because I don't use JQuery, sorry.

    – MandyShaw
    Mar 29 at 13:55

















  • As you aren't waiting for the whole string to be typed before you start processing it, I think you are having timing problems. I'm wondering what would happen if you simply ran the getElementById and ajax call twice in your function, so that the second call processed the search string as it stood when the first call had finished? Worth a try I think.

    – MandyShaw
    Mar 28 at 23:06











  • Unfortunately seems to still be an issue. I definitely agree though, it does seem to be a timing issue and I tried testing that too, but I don't think it's working. I had var name = $(this).delay(300).val();

    – Fraze
    Mar 29 at 12:48











  • A delay in the script isn't going to help because control is still with the script. You need the script to be releasing control. Have you got the ajax running asynchronously?

    – MandyShaw
    Mar 29 at 13:51











  • Sorry for my ignorance, but isn't it asynchronous by default?

    – Fraze
    Mar 29 at 13:53











  • I don't know, because I don't use JQuery, sorry.

    – MandyShaw
    Mar 29 at 13:55
















As you aren't waiting for the whole string to be typed before you start processing it, I think you are having timing problems. I'm wondering what would happen if you simply ran the getElementById and ajax call twice in your function, so that the second call processed the search string as it stood when the first call had finished? Worth a try I think.

– MandyShaw
Mar 28 at 23:06





As you aren't waiting for the whole string to be typed before you start processing it, I think you are having timing problems. I'm wondering what would happen if you simply ran the getElementById and ajax call twice in your function, so that the second call processed the search string as it stood when the first call had finished? Worth a try I think.

– MandyShaw
Mar 28 at 23:06













Unfortunately seems to still be an issue. I definitely agree though, it does seem to be a timing issue and I tried testing that too, but I don't think it's working. I had var name = $(this).delay(300).val();

– Fraze
Mar 29 at 12:48





Unfortunately seems to still be an issue. I definitely agree though, it does seem to be a timing issue and I tried testing that too, but I don't think it's working. I had var name = $(this).delay(300).val();

– Fraze
Mar 29 at 12:48













A delay in the script isn't going to help because control is still with the script. You need the script to be releasing control. Have you got the ajax running asynchronously?

– MandyShaw
Mar 29 at 13:51





A delay in the script isn't going to help because control is still with the script. You need the script to be releasing control. Have you got the ajax running asynchronously?

– MandyShaw
Mar 29 at 13:51













Sorry for my ignorance, but isn't it asynchronous by default?

– Fraze
Mar 29 at 13:53





Sorry for my ignorance, but isn't it asynchronous by default?

– Fraze
Mar 29 at 13:53













I don't know, because I don't use JQuery, sorry.

– MandyShaw
Mar 29 at 13:55





I don't know, because I don't use JQuery, sorry.

– MandyShaw
Mar 29 at 13:55












1 Answer
1






active

oldest

votes


















0
















This query should output them in the correct order.
First items: Exact match to search term
Next items: Items that start with search term
Third items: All items that include search term



SELECT * 
FROM Cosmetics
WHERE Name LIKE '%$search%'
ORDER BY (CASE WHEN name = '$search' THEN 1 WHEN name LIKE '$search%' THEN 2 ELSE 3 END);





share|improve this answer



























  • Hi Ralph. Thank you, but the issue isn't the order they're in. It's the value being captured from the search box isn't always the whole value.

    – Fraze
    Mar 29 at 12:51












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1 Answer
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0
















This query should output them in the correct order.
First items: Exact match to search term
Next items: Items that start with search term
Third items: All items that include search term



SELECT * 
FROM Cosmetics
WHERE Name LIKE '%$search%'
ORDER BY (CASE WHEN name = '$search' THEN 1 WHEN name LIKE '$search%' THEN 2 ELSE 3 END);





share|improve this answer



























  • Hi Ralph. Thank you, but the issue isn't the order they're in. It's the value being captured from the search box isn't always the whole value.

    – Fraze
    Mar 29 at 12:51















0
















This query should output them in the correct order.
First items: Exact match to search term
Next items: Items that start with search term
Third items: All items that include search term



SELECT * 
FROM Cosmetics
WHERE Name LIKE '%$search%'
ORDER BY (CASE WHEN name = '$search' THEN 1 WHEN name LIKE '$search%' THEN 2 ELSE 3 END);





share|improve this answer



























  • Hi Ralph. Thank you, but the issue isn't the order they're in. It's the value being captured from the search box isn't always the whole value.

    – Fraze
    Mar 29 at 12:51













0














0










0









This query should output them in the correct order.
First items: Exact match to search term
Next items: Items that start with search term
Third items: All items that include search term



SELECT * 
FROM Cosmetics
WHERE Name LIKE '%$search%'
ORDER BY (CASE WHEN name = '$search' THEN 1 WHEN name LIKE '$search%' THEN 2 ELSE 3 END);





share|improve this answer















This query should output them in the correct order.
First items: Exact match to search term
Next items: Items that start with search term
Third items: All items that include search term



SELECT * 
FROM Cosmetics
WHERE Name LIKE '%$search%'
ORDER BY (CASE WHEN name = '$search' THEN 1 WHEN name LIKE '$search%' THEN 2 ELSE 3 END);






share|improve this answer














share|improve this answer



share|improve this answer








edited Mar 28 at 21:29

























answered Mar 28 at 21:23









RalphRalph

2272 silver badges10 bronze badges




2272 silver badges10 bronze badges















  • Hi Ralph. Thank you, but the issue isn't the order they're in. It's the value being captured from the search box isn't always the whole value.

    – Fraze
    Mar 29 at 12:51

















  • Hi Ralph. Thank you, but the issue isn't the order they're in. It's the value being captured from the search box isn't always the whole value.

    – Fraze
    Mar 29 at 12:51
















Hi Ralph. Thank you, but the issue isn't the order they're in. It's the value being captured from the search box isn't always the whole value.

– Fraze
Mar 29 at 12:51





Hi Ralph. Thank you, but the issue isn't the order they're in. It's the value being captured from the search box isn't always the whole value.

– Fraze
Mar 29 at 12:51




















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