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Sort dictionary after class attributes and today's date


How do I sort a list of dictionaries by a value of the dictionary?How to sort a list of objects based on an attribute of the objects?How do I sort a dictionary by value?Sort a list by multiple attributes?In python. How do I have a user change a dictionary value, when that dictionary is in a class?How can I sort a dictionary by key?Getting today's date in YYYY-MM-DD in Python?Python trainticket machineHow to detect EOF when input is not from a file?Adding multiple events to a PDF report






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margin-bottom:0;









0















I have a class, Reminder, and dictionary, Events, and would like to sort the dictionary based on today's date.



The program should ask the user for an int input of today's date, and then print all keys in the dictionary that are relevant for this day and further.



Eg. it should not print events that have already passed.



 class Reminder:
self.name = name
self.date = date
self.reminder = reminder


 event1 = Reminder('trip to vegas', 20130312, 'buy a suitcase')
event2 = Reminder('to do next month', 20190401, 'get a job')
event3 = Reminder('apply for college', 20190603, 'send in application'

event_dict =
event_dict[event1.name] = event1
event_dict[event2.name] = event2
event_dict[event3.name] = event3

todays date = int(input("Input today's date!"))


So now when the user puts in for example the date 20190328, the program should not print event1 since it has already passed.



And as said I want event 2 and 3 to be sorted before printed, so that the next upcoming date is printed first.



It might seem unnecessary to sort 2 events but in the whole code it will be more events.










share|improve this question
































    0















    I have a class, Reminder, and dictionary, Events, and would like to sort the dictionary based on today's date.



    The program should ask the user for an int input of today's date, and then print all keys in the dictionary that are relevant for this day and further.



    Eg. it should not print events that have already passed.



     class Reminder:
    self.name = name
    self.date = date
    self.reminder = reminder


     event1 = Reminder('trip to vegas', 20130312, 'buy a suitcase')
    event2 = Reminder('to do next month', 20190401, 'get a job')
    event3 = Reminder('apply for college', 20190603, 'send in application'

    event_dict =
    event_dict[event1.name] = event1
    event_dict[event2.name] = event2
    event_dict[event3.name] = event3

    todays date = int(input("Input today's date!"))


    So now when the user puts in for example the date 20190328, the program should not print event1 since it has already passed.



    And as said I want event 2 and 3 to be sorted before printed, so that the next upcoming date is printed first.



    It might seem unnecessary to sort 2 events but in the whole code it will be more events.










    share|improve this question




























      0












      0








      0








      I have a class, Reminder, and dictionary, Events, and would like to sort the dictionary based on today's date.



      The program should ask the user for an int input of today's date, and then print all keys in the dictionary that are relevant for this day and further.



      Eg. it should not print events that have already passed.



       class Reminder:
      self.name = name
      self.date = date
      self.reminder = reminder


       event1 = Reminder('trip to vegas', 20130312, 'buy a suitcase')
      event2 = Reminder('to do next month', 20190401, 'get a job')
      event3 = Reminder('apply for college', 20190603, 'send in application'

      event_dict =
      event_dict[event1.name] = event1
      event_dict[event2.name] = event2
      event_dict[event3.name] = event3

      todays date = int(input("Input today's date!"))


      So now when the user puts in for example the date 20190328, the program should not print event1 since it has already passed.



      And as said I want event 2 and 3 to be sorted before printed, so that the next upcoming date is printed first.



      It might seem unnecessary to sort 2 events but in the whole code it will be more events.










      share|improve this question
















      I have a class, Reminder, and dictionary, Events, and would like to sort the dictionary based on today's date.



      The program should ask the user for an int input of today's date, and then print all keys in the dictionary that are relevant for this day and further.



      Eg. it should not print events that have already passed.



       class Reminder:
      self.name = name
      self.date = date
      self.reminder = reminder


       event1 = Reminder('trip to vegas', 20130312, 'buy a suitcase')
      event2 = Reminder('to do next month', 20190401, 'get a job')
      event3 = Reminder('apply for college', 20190603, 'send in application'

      event_dict =
      event_dict[event1.name] = event1
      event_dict[event2.name] = event2
      event_dict[event3.name] = event3

      todays date = int(input("Input today's date!"))


      So now when the user puts in for example the date 20190328, the program should not print event1 since it has already passed.



      And as said I want event 2 and 3 to be sorted before printed, so that the next upcoming date is printed first.



      It might seem unnecessary to sort 2 events but in the whole code it will be more events.







      python python-3.x






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited Mar 28 at 20:50







      Jonas Graffman

















      asked Mar 28 at 20:44









      Jonas GraffmanJonas Graffman

      525 bronze badges




      525 bronze badges

























          2 Answers
          2






          active

          oldest

          votes


















          1
















          Simple implementation:



          class Reminder:

          def __init__(self, name, date, reminder):
          self.name = name
          self.date = date
          self.reminder = reminder

          def __str__(self):
          return "Name: '' - Date: '' - Reminder: ''".format(self.name,
          self.date,
          self.reminder)

          event1 = Reminder('trip to vegas', 20130312, 'buy a suitcase')
          event2 = Reminder('to do next month', 20190401, 'get a job')
          event3 = Reminder('apply for college', 20190603, 'send in application')

          event_dict =
          event_dict[event1.name] = event1
          event_dict[event2.name] = event2
          event_dict[event3.name] = event3

          todays_date = 20180101

          # implementation
          events_sorted = sorted(event_dict.items(), key=lambda t: t[1].date)
          events = [e[1] for e in events_sorted if e[1].date >= todays_date]

          for e in events:
          print(e)


          Output:



          Name: 'to do next month' - Date: '20190401' - Reminder: 'get a job'
          Name: 'apply for college' - Date: '20190603' - Reminder: 'send in application'





          share|improve this answer



























          • You are amazing!! Thank you so much

            – Jonas Graffman
            Mar 28 at 21:50


















          1
















          class Reminder(object):
          def __init__(self, name, date, reminder):
          self.name = name
          self.date = date
          self.reminder = reminder

          event1 = Reminder('trip to vegas', 20130312, 'buy a suitcase')
          event2 = Reminder('to do next month', 20190401, 'get a job')
          event3 = Reminder('apply for college', 20190603, 'send in application')


          event_dict =
          event_dict[event1.date] = event1
          event_dict[event2.date] = event2
          event_dict[event3.date] = event3

          todays_date = int(input("Input today's date!"))

          import operator
          #filter passed dates
          event_dict = k: v for k, v in event_dict.items() if k > todays_date

          #sort dictionary
          sorted_events = sorted(event_dict.items(), key=operator.itemgetter(0))

          #print results
          for item in sorted_events:
          print("trip name: " , item[1].name, "| trip date: ", item[1].date, "| trip reminder: ", item[1].reminder,' n')


          Output:



          trip name: to do next month | trip date: 20190401 | trip reminder: get a job 
          trip name: apply for college | trip date: 20190603 | trip reminder: send in application





          share|improve this answer


























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            2 Answers
            2






            active

            oldest

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            2 Answers
            2






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes









            1
















            Simple implementation:



            class Reminder:

            def __init__(self, name, date, reminder):
            self.name = name
            self.date = date
            self.reminder = reminder

            def __str__(self):
            return "Name: '' - Date: '' - Reminder: ''".format(self.name,
            self.date,
            self.reminder)

            event1 = Reminder('trip to vegas', 20130312, 'buy a suitcase')
            event2 = Reminder('to do next month', 20190401, 'get a job')
            event3 = Reminder('apply for college', 20190603, 'send in application')

            event_dict =
            event_dict[event1.name] = event1
            event_dict[event2.name] = event2
            event_dict[event3.name] = event3

            todays_date = 20180101

            # implementation
            events_sorted = sorted(event_dict.items(), key=lambda t: t[1].date)
            events = [e[1] for e in events_sorted if e[1].date >= todays_date]

            for e in events:
            print(e)


            Output:



            Name: 'to do next month' - Date: '20190401' - Reminder: 'get a job'
            Name: 'apply for college' - Date: '20190603' - Reminder: 'send in application'





            share|improve this answer



























            • You are amazing!! Thank you so much

              – Jonas Graffman
              Mar 28 at 21:50















            1
















            Simple implementation:



            class Reminder:

            def __init__(self, name, date, reminder):
            self.name = name
            self.date = date
            self.reminder = reminder

            def __str__(self):
            return "Name: '' - Date: '' - Reminder: ''".format(self.name,
            self.date,
            self.reminder)

            event1 = Reminder('trip to vegas', 20130312, 'buy a suitcase')
            event2 = Reminder('to do next month', 20190401, 'get a job')
            event3 = Reminder('apply for college', 20190603, 'send in application')

            event_dict =
            event_dict[event1.name] = event1
            event_dict[event2.name] = event2
            event_dict[event3.name] = event3

            todays_date = 20180101

            # implementation
            events_sorted = sorted(event_dict.items(), key=lambda t: t[1].date)
            events = [e[1] for e in events_sorted if e[1].date >= todays_date]

            for e in events:
            print(e)


            Output:



            Name: 'to do next month' - Date: '20190401' - Reminder: 'get a job'
            Name: 'apply for college' - Date: '20190603' - Reminder: 'send in application'





            share|improve this answer



























            • You are amazing!! Thank you so much

              – Jonas Graffman
              Mar 28 at 21:50













            1














            1










            1









            Simple implementation:



            class Reminder:

            def __init__(self, name, date, reminder):
            self.name = name
            self.date = date
            self.reminder = reminder

            def __str__(self):
            return "Name: '' - Date: '' - Reminder: ''".format(self.name,
            self.date,
            self.reminder)

            event1 = Reminder('trip to vegas', 20130312, 'buy a suitcase')
            event2 = Reminder('to do next month', 20190401, 'get a job')
            event3 = Reminder('apply for college', 20190603, 'send in application')

            event_dict =
            event_dict[event1.name] = event1
            event_dict[event2.name] = event2
            event_dict[event3.name] = event3

            todays_date = 20180101

            # implementation
            events_sorted = sorted(event_dict.items(), key=lambda t: t[1].date)
            events = [e[1] for e in events_sorted if e[1].date >= todays_date]

            for e in events:
            print(e)


            Output:



            Name: 'to do next month' - Date: '20190401' - Reminder: 'get a job'
            Name: 'apply for college' - Date: '20190603' - Reminder: 'send in application'





            share|improve this answer















            Simple implementation:



            class Reminder:

            def __init__(self, name, date, reminder):
            self.name = name
            self.date = date
            self.reminder = reminder

            def __str__(self):
            return "Name: '' - Date: '' - Reminder: ''".format(self.name,
            self.date,
            self.reminder)

            event1 = Reminder('trip to vegas', 20130312, 'buy a suitcase')
            event2 = Reminder('to do next month', 20190401, 'get a job')
            event3 = Reminder('apply for college', 20190603, 'send in application')

            event_dict =
            event_dict[event1.name] = event1
            event_dict[event2.name] = event2
            event_dict[event3.name] = event3

            todays_date = 20180101

            # implementation
            events_sorted = sorted(event_dict.items(), key=lambda t: t[1].date)
            events = [e[1] for e in events_sorted if e[1].date >= todays_date]

            for e in events:
            print(e)


            Output:



            Name: 'to do next month' - Date: '20190401' - Reminder: 'get a job'
            Name: 'apply for college' - Date: '20190603' - Reminder: 'send in application'






            share|improve this answer














            share|improve this answer



            share|improve this answer








            edited Mar 28 at 21:15

























            answered Mar 28 at 21:08









            dzangdzang

            6093 silver badges10 bronze badges




            6093 silver badges10 bronze badges















            • You are amazing!! Thank you so much

              – Jonas Graffman
              Mar 28 at 21:50

















            • You are amazing!! Thank you so much

              – Jonas Graffman
              Mar 28 at 21:50
















            You are amazing!! Thank you so much

            – Jonas Graffman
            Mar 28 at 21:50





            You are amazing!! Thank you so much

            – Jonas Graffman
            Mar 28 at 21:50













            1
















            class Reminder(object):
            def __init__(self, name, date, reminder):
            self.name = name
            self.date = date
            self.reminder = reminder

            event1 = Reminder('trip to vegas', 20130312, 'buy a suitcase')
            event2 = Reminder('to do next month', 20190401, 'get a job')
            event3 = Reminder('apply for college', 20190603, 'send in application')


            event_dict =
            event_dict[event1.date] = event1
            event_dict[event2.date] = event2
            event_dict[event3.date] = event3

            todays_date = int(input("Input today's date!"))

            import operator
            #filter passed dates
            event_dict = k: v for k, v in event_dict.items() if k > todays_date

            #sort dictionary
            sorted_events = sorted(event_dict.items(), key=operator.itemgetter(0))

            #print results
            for item in sorted_events:
            print("trip name: " , item[1].name, "| trip date: ", item[1].date, "| trip reminder: ", item[1].reminder,' n')


            Output:



            trip name: to do next month | trip date: 20190401 | trip reminder: get a job 
            trip name: apply for college | trip date: 20190603 | trip reminder: send in application





            share|improve this answer





























              1
















              class Reminder(object):
              def __init__(self, name, date, reminder):
              self.name = name
              self.date = date
              self.reminder = reminder

              event1 = Reminder('trip to vegas', 20130312, 'buy a suitcase')
              event2 = Reminder('to do next month', 20190401, 'get a job')
              event3 = Reminder('apply for college', 20190603, 'send in application')


              event_dict =
              event_dict[event1.date] = event1
              event_dict[event2.date] = event2
              event_dict[event3.date] = event3

              todays_date = int(input("Input today's date!"))

              import operator
              #filter passed dates
              event_dict = k: v for k, v in event_dict.items() if k > todays_date

              #sort dictionary
              sorted_events = sorted(event_dict.items(), key=operator.itemgetter(0))

              #print results
              for item in sorted_events:
              print("trip name: " , item[1].name, "| trip date: ", item[1].date, "| trip reminder: ", item[1].reminder,' n')


              Output:



              trip name: to do next month | trip date: 20190401 | trip reminder: get a job 
              trip name: apply for college | trip date: 20190603 | trip reminder: send in application





              share|improve this answer



























                1














                1










                1









                class Reminder(object):
                def __init__(self, name, date, reminder):
                self.name = name
                self.date = date
                self.reminder = reminder

                event1 = Reminder('trip to vegas', 20130312, 'buy a suitcase')
                event2 = Reminder('to do next month', 20190401, 'get a job')
                event3 = Reminder('apply for college', 20190603, 'send in application')


                event_dict =
                event_dict[event1.date] = event1
                event_dict[event2.date] = event2
                event_dict[event3.date] = event3

                todays_date = int(input("Input today's date!"))

                import operator
                #filter passed dates
                event_dict = k: v for k, v in event_dict.items() if k > todays_date

                #sort dictionary
                sorted_events = sorted(event_dict.items(), key=operator.itemgetter(0))

                #print results
                for item in sorted_events:
                print("trip name: " , item[1].name, "| trip date: ", item[1].date, "| trip reminder: ", item[1].reminder,' n')


                Output:



                trip name: to do next month | trip date: 20190401 | trip reminder: get a job 
                trip name: apply for college | trip date: 20190603 | trip reminder: send in application





                share|improve this answer













                class Reminder(object):
                def __init__(self, name, date, reminder):
                self.name = name
                self.date = date
                self.reminder = reminder

                event1 = Reminder('trip to vegas', 20130312, 'buy a suitcase')
                event2 = Reminder('to do next month', 20190401, 'get a job')
                event3 = Reminder('apply for college', 20190603, 'send in application')


                event_dict =
                event_dict[event1.date] = event1
                event_dict[event2.date] = event2
                event_dict[event3.date] = event3

                todays_date = int(input("Input today's date!"))

                import operator
                #filter passed dates
                event_dict = k: v for k, v in event_dict.items() if k > todays_date

                #sort dictionary
                sorted_events = sorted(event_dict.items(), key=operator.itemgetter(0))

                #print results
                for item in sorted_events:
                print("trip name: " , item[1].name, "| trip date: ", item[1].date, "| trip reminder: ", item[1].reminder,' n')


                Output:



                trip name: to do next month | trip date: 20190401 | trip reminder: get a job 
                trip name: apply for college | trip date: 20190603 | trip reminder: send in application






                share|improve this answer












                share|improve this answer



                share|improve this answer










                answered Mar 28 at 21:13









                Maria NazariMaria Nazari

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                3301 silver badge14 bronze badges































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