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Can't iterate over field of a struct matlab
Apply a function to all fields of an array of structs in MatlabAccess complex matlab struct with function/stringHow can I create a Matlab struct array from scipy.io?Matlab loop to assign rows to cell arrayIterating through Struct MATLABReshaping nested struct array to cell array having elements with different sizesCombining Matlab files using structsPlotting structure array in MatlabMATLAB: How to use cellfun with a struct?Matlab: calculating the mean of an array nested in a struct
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I am working currently with matlab and I try to extract some data from a struct that I have, but it seems it is not as easy I thought it would be.
structExample = 1x100000
fieldnames(structExample)
ans =
6×1 cell array
'a'
'b'
'c'
'd'
'e'
'f'
I am interested in the values saved in field 'b'.
When I type structExample.b it prints out all the values, but when I do
values = structExample.b
It only saves the first values ([1.2,5.33]) . 'b' has double values for example
[1.2,5.33], 1x86double, 1x120double ...
My aim is to be able to plot them with cdfplot()
So I thought maybe iterate over all values in the field and save them in a separate array. But I don't know how to iterate through it, since structExample.b only takes the first values. Any ideas?
Edit:
structExample.b(3) returns
Expected one output from a curly brace or dot indexing expression, but
there were 41817 results.
matlab
add a comment
|
I am working currently with matlab and I try to extract some data from a struct that I have, but it seems it is not as easy I thought it would be.
structExample = 1x100000
fieldnames(structExample)
ans =
6×1 cell array
'a'
'b'
'c'
'd'
'e'
'f'
I am interested in the values saved in field 'b'.
When I type structExample.b it prints out all the values, but when I do
values = structExample.b
It only saves the first values ([1.2,5.33]) . 'b' has double values for example
[1.2,5.33], 1x86double, 1x120double ...
My aim is to be able to plot them with cdfplot()
So I thought maybe iterate over all values in the field and save them in a separate array. But I don't know how to iterate through it, since structExample.b only takes the first values. Any ideas?
Edit:
structExample.b(3) returns
Expected one output from a curly brace or dot indexing expression, but
there were 41817 results.
matlab
add a comment
|
I am working currently with matlab and I try to extract some data from a struct that I have, but it seems it is not as easy I thought it would be.
structExample = 1x100000
fieldnames(structExample)
ans =
6×1 cell array
'a'
'b'
'c'
'd'
'e'
'f'
I am interested in the values saved in field 'b'.
When I type structExample.b it prints out all the values, but when I do
values = structExample.b
It only saves the first values ([1.2,5.33]) . 'b' has double values for example
[1.2,5.33], 1x86double, 1x120double ...
My aim is to be able to plot them with cdfplot()
So I thought maybe iterate over all values in the field and save them in a separate array. But I don't know how to iterate through it, since structExample.b only takes the first values. Any ideas?
Edit:
structExample.b(3) returns
Expected one output from a curly brace or dot indexing expression, but
there were 41817 results.
matlab
I am working currently with matlab and I try to extract some data from a struct that I have, but it seems it is not as easy I thought it would be.
structExample = 1x100000
fieldnames(structExample)
ans =
6×1 cell array
'a'
'b'
'c'
'd'
'e'
'f'
I am interested in the values saved in field 'b'.
When I type structExample.b it prints out all the values, but when I do
values = structExample.b
It only saves the first values ([1.2,5.33]) . 'b' has double values for example
[1.2,5.33], 1x86double, 1x120double ...
My aim is to be able to plot them with cdfplot()
So I thought maybe iterate over all values in the field and save them in a separate array. But I don't know how to iterate through it, since structExample.b only takes the first values. Any ideas?
Edit:
structExample.b(3) returns
Expected one output from a curly brace or dot indexing expression, but
there were 41817 results.
matlab
matlab
asked Mar 28 at 14:32
CroatiaHRCroatiaHR
929 bronze badges
929 bronze badges
add a comment
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add a comment
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1 Answer
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When you access a field of a structure array, it returns a comma-separated list of values. By default, only the first value in a list will be assigned to a single variable. If you want to capture all of these values, you have to collect them using []
(for a normal array) or (for a cell array). Since you are dealing with different-sized sets of data in each structure, you will need to use a cell array:
values = structExample.b;
So, values1
will contain [1.2,5.33]
, values2
will contain 1x86 double
, etc..
For the case where you want to iterate over the structure array, you have to index array elements and fields in the correct order. You should index the element first (which gives you a single structure element from the array), then index the field you want:
value = structExample(3).b; % Field b of the third array element
For the additional case where you want to collect a field from an indexed subset of elements in your structure array, you have to combine the indexing and collection schemes from above. For example:
values = structExample([structExample.a] == 1).b;
This will collect all a
field values from structExample
into an array, find a logical index for where they equal 1
, index the structExample
array with that logical array, then collect the values of field b
from that subarray and place them in a cell array.
If I may add a further question, is there a neat way to save data based on a value from 'a'. Example: values1 = [structExample.b] if 'a' == 1
– CroatiaHR
Mar 28 at 14:52
the problem from iterating is that when I call length(structExample.b) it says that it has too many values
– CroatiaHR
Mar 28 at 14:55
1
As explained by gnovice you need to encapsulate the data in an array. Solength([structExample.b])
should work
– obchardon
Mar 28 at 15:01
add a comment
|
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votes
When you access a field of a structure array, it returns a comma-separated list of values. By default, only the first value in a list will be assigned to a single variable. If you want to capture all of these values, you have to collect them using []
(for a normal array) or (for a cell array). Since you are dealing with different-sized sets of data in each structure, you will need to use a cell array:
values = structExample.b;
So, values1
will contain [1.2,5.33]
, values2
will contain 1x86 double
, etc..
For the case where you want to iterate over the structure array, you have to index array elements and fields in the correct order. You should index the element first (which gives you a single structure element from the array), then index the field you want:
value = structExample(3).b; % Field b of the third array element
For the additional case where you want to collect a field from an indexed subset of elements in your structure array, you have to combine the indexing and collection schemes from above. For example:
values = structExample([structExample.a] == 1).b;
This will collect all a
field values from structExample
into an array, find a logical index for where they equal 1
, index the structExample
array with that logical array, then collect the values of field b
from that subarray and place them in a cell array.
If I may add a further question, is there a neat way to save data based on a value from 'a'. Example: values1 = [structExample.b] if 'a' == 1
– CroatiaHR
Mar 28 at 14:52
the problem from iterating is that when I call length(structExample.b) it says that it has too many values
– CroatiaHR
Mar 28 at 14:55
1
As explained by gnovice you need to encapsulate the data in an array. Solength([structExample.b])
should work
– obchardon
Mar 28 at 15:01
add a comment
|
When you access a field of a structure array, it returns a comma-separated list of values. By default, only the first value in a list will be assigned to a single variable. If you want to capture all of these values, you have to collect them using []
(for a normal array) or (for a cell array). Since you are dealing with different-sized sets of data in each structure, you will need to use a cell array:
values = structExample.b;
So, values1
will contain [1.2,5.33]
, values2
will contain 1x86 double
, etc..
For the case where you want to iterate over the structure array, you have to index array elements and fields in the correct order. You should index the element first (which gives you a single structure element from the array), then index the field you want:
value = structExample(3).b; % Field b of the third array element
For the additional case where you want to collect a field from an indexed subset of elements in your structure array, you have to combine the indexing and collection schemes from above. For example:
values = structExample([structExample.a] == 1).b;
This will collect all a
field values from structExample
into an array, find a logical index for where they equal 1
, index the structExample
array with that logical array, then collect the values of field b
from that subarray and place them in a cell array.
If I may add a further question, is there a neat way to save data based on a value from 'a'. Example: values1 = [structExample.b] if 'a' == 1
– CroatiaHR
Mar 28 at 14:52
the problem from iterating is that when I call length(structExample.b) it says that it has too many values
– CroatiaHR
Mar 28 at 14:55
1
As explained by gnovice you need to encapsulate the data in an array. Solength([structExample.b])
should work
– obchardon
Mar 28 at 15:01
add a comment
|
When you access a field of a structure array, it returns a comma-separated list of values. By default, only the first value in a list will be assigned to a single variable. If you want to capture all of these values, you have to collect them using []
(for a normal array) or (for a cell array). Since you are dealing with different-sized sets of data in each structure, you will need to use a cell array:
values = structExample.b;
So, values1
will contain [1.2,5.33]
, values2
will contain 1x86 double
, etc..
For the case where you want to iterate over the structure array, you have to index array elements and fields in the correct order. You should index the element first (which gives you a single structure element from the array), then index the field you want:
value = structExample(3).b; % Field b of the third array element
For the additional case where you want to collect a field from an indexed subset of elements in your structure array, you have to combine the indexing and collection schemes from above. For example:
values = structExample([structExample.a] == 1).b;
This will collect all a
field values from structExample
into an array, find a logical index for where they equal 1
, index the structExample
array with that logical array, then collect the values of field b
from that subarray and place them in a cell array.
When you access a field of a structure array, it returns a comma-separated list of values. By default, only the first value in a list will be assigned to a single variable. If you want to capture all of these values, you have to collect them using []
(for a normal array) or (for a cell array). Since you are dealing with different-sized sets of data in each structure, you will need to use a cell array:
values = structExample.b;
So, values1
will contain [1.2,5.33]
, values2
will contain 1x86 double
, etc..
For the case where you want to iterate over the structure array, you have to index array elements and fields in the correct order. You should index the element first (which gives you a single structure element from the array), then index the field you want:
value = structExample(3).b; % Field b of the third array element
For the additional case where you want to collect a field from an indexed subset of elements in your structure array, you have to combine the indexing and collection schemes from above. For example:
values = structExample([structExample.a] == 1).b;
This will collect all a
field values from structExample
into an array, find a logical index for where they equal 1
, index the structExample
array with that logical array, then collect the values of field b
from that subarray and place them in a cell array.
edited Mar 28 at 15:01
answered Mar 28 at 14:38
gnovicegnovice
120k13 gold badges238 silver badges342 bronze badges
120k13 gold badges238 silver badges342 bronze badges
If I may add a further question, is there a neat way to save data based on a value from 'a'. Example: values1 = [structExample.b] if 'a' == 1
– CroatiaHR
Mar 28 at 14:52
the problem from iterating is that when I call length(structExample.b) it says that it has too many values
– CroatiaHR
Mar 28 at 14:55
1
As explained by gnovice you need to encapsulate the data in an array. Solength([structExample.b])
should work
– obchardon
Mar 28 at 15:01
add a comment
|
If I may add a further question, is there a neat way to save data based on a value from 'a'. Example: values1 = [structExample.b] if 'a' == 1
– CroatiaHR
Mar 28 at 14:52
the problem from iterating is that when I call length(structExample.b) it says that it has too many values
– CroatiaHR
Mar 28 at 14:55
1
As explained by gnovice you need to encapsulate the data in an array. Solength([structExample.b])
should work
– obchardon
Mar 28 at 15:01
If I may add a further question, is there a neat way to save data based on a value from 'a'. Example: values1 = [structExample.b] if 'a' == 1
– CroatiaHR
Mar 28 at 14:52
If I may add a further question, is there a neat way to save data based on a value from 'a'. Example: values1 = [structExample.b] if 'a' == 1
– CroatiaHR
Mar 28 at 14:52
the problem from iterating is that when I call length(structExample.b) it says that it has too many values
– CroatiaHR
Mar 28 at 14:55
the problem from iterating is that when I call length(structExample.b) it says that it has too many values
– CroatiaHR
Mar 28 at 14:55
1
1
As explained by gnovice you need to encapsulate the data in an array. So
length([structExample.b])
should work– obchardon
Mar 28 at 15:01
As explained by gnovice you need to encapsulate the data in an array. So
length([structExample.b])
should work– obchardon
Mar 28 at 15:01
add a comment
|
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