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Initializers in array, but I wanna control each object in array with variable

How do I check if an array includes an object in JavaScript?How do you check if a variable is an array in JavaScript?Sorting an array of JavaScript objects by propertySort array of objects by string property valueHow do I declare and initialize an array in Java?How to check if an object is an array?JavaScript check if variable exists (is defined/initialized)Find object by id in an array of JavaScript objectsindexOf method in an object array?For-each over an array in JavaScript?

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-1

I have an array with objects, like this:

var animals = [new Animal("dog", "Max"), new Animal("dog", "Ben"), new Animal("cat", "Ella"), new Animal("cat", "Sophia")];

And now I need to control each object as variable, like this:

console.log(dog_max.sound());
console.log(cat_sophia.eat());

How should I do it?

Theoretically, I don't know which object is what index,

I'll use random mix function for array.

javascript arrays class

share|improve this question

asked Mar 28 at 5:57

John DoeJohn Doe

1411 bronze badge

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  In simple words you are asking for dynamic variable names.
  
  – Maheer Ali
  Mar 28 at 5:58
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  describe Animal (class)
  
  – Mister Jojo
  Mar 28 at 6:01
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  make a resolve method / class. E.g. AnimalFinder.GetDogMax(Animal[])
  
  – LuckyLikey
  Mar 28 at 6:01
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  why do you need this anyway?
  
  – LuckyLikey
  Mar 28 at 6:03
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  You must have some input parameter. Like "In this array, find a dog which is named Max". This is an XY problem Please post your inputs and the expected output and a clear problem statement.
  
  – adiga
  Mar 28 at 6:07
  
  

  
  
  
  

 | 
show 1 more comment

-1

I have an array with objects, like this:

var animals = [new Animal("dog", "Max"), new Animal("dog", "Ben"), new Animal("cat", "Ella"), new Animal("cat", "Sophia")];

And now I need to control each object as variable, like this:

console.log(dog_max.sound());
console.log(cat_sophia.eat());

How should I do it?

Theoretically, I don't know which object is what index,

I'll use random mix function for array.

javascript arrays class

share|improve this question

asked Mar 28 at 5:57

John DoeJohn Doe

1411 bronze badge

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  In simple words you are asking for dynamic variable names.
  
  – Maheer Ali
  Mar 28 at 5:58
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  describe Animal (class)
  
  – Mister Jojo
  Mar 28 at 6:01
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  make a resolve method / class. E.g. AnimalFinder.GetDogMax(Animal[])
  
  – LuckyLikey
  Mar 28 at 6:01
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  why do you need this anyway?
  
  – LuckyLikey
  Mar 28 at 6:03
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  You must have some input parameter. Like "In this array, find a dog which is named Max". This is an XY problem Please post your inputs and the expected output and a clear problem statement.
  
  – adiga
  Mar 28 at 6:07
  
  

  
  
  
  

 | 
show 1 more comment

I have an array with objects, like this:

var animals = [new Animal("dog", "Max"), new Animal("dog", "Ben"), new Animal("cat", "Ella"), new Animal("cat", "Sophia")];

And now I need to control each object as variable, like this:

console.log(dog_max.sound());
console.log(cat_sophia.eat());

How should I do it?

Theoretically, I don't know which object is what index,

I'll use random mix function for array.

javascript arrays class

share|improve this question

asked Mar 28 at 5:57

John DoeJohn Doe

1411 bronze badge

var animals = [new Animal("dog", "Max"), new Animal("dog", "Ben"), new Animal("cat", "Ella"), new Animal("cat", "Sophia")];

console.log(dog_max.sound());
console.log(cat_sophia.eat());

share|improve this question

asked Mar 28 at 5:57

John DoeJohn Doe

1411 bronze badge

share|improve this question

asked Mar 28 at 5:57

John DoeJohn Doe

1411 bronze badge

asked Mar 28 at 5:57

John DoeJohn Doe

1411 bronze badge

asked Mar 28 at 5:57

John DoeJohn Doe

1411 bronze badge

1 Answer
1

active

oldest

votes

0

You want to create dynamic variable names which is not possible with eval()

Using eval()

class Animal
 constructor(name1,name2)
 this.name1 = name1
 this.name2 = name2
 
 sound()
 return `$this.name1 makes sound`;
 

var animals = [new Animal("dog", "Max"), new Animal("dog", "Ben"), new Animal("cat", "Ella"), new Animal("cat", "Sophia")];


for(let i = 0;i<animals.length;i++)
 eval(`var $animals[i].name1_$animals[i].name2.toLowerCase() = animals[i]`);


console.log(dog_max.sound())
console.log(cat_ella.sound())

Using Object

But using eval() is not recommended. You can can create a object to store these

class Animal
 constructor(name1,name2)
 this.name1 = name1
 this.name2 = name2
 
 sound()
 return `$this.name1 makes sound`;
 

var animals = [new Animal("dog", "Max"), new Animal("dog", "Ben"), new Animal("cat", "Ella"), new Animal("cat", "Sophia")];

let a = ;
for(let i = 0;i<animals.length;i++)
 a[`$animals[i].name1_$animals[i].name2.toLowerCase()`] = animals[i]


console.log(a.dog_max.sound())
console.log(a.cat_ella.sound())

share|improve this answer

answered Mar 28 at 6:09

Maheer AliMaheer Ali

23.7k44 gold badges2121 silver badges3838 bronze badges

add a comment | 

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0

You want to create dynamic variable names which is not possible with eval()

Using eval()

class Animal
 constructor(name1,name2)
 this.name1 = name1
 this.name2 = name2
 
 sound()
 return `$this.name1 makes sound`;
 

var animals = [new Animal("dog", "Max"), new Animal("dog", "Ben"), new Animal("cat", "Ella"), new Animal("cat", "Sophia")];


for(let i = 0;i<animals.length;i++)
 eval(`var $animals[i].name1_$animals[i].name2.toLowerCase() = animals[i]`);


console.log(dog_max.sound())
console.log(cat_ella.sound())

Using Object

But using eval() is not recommended. You can can create a object to store these

class Animal
 constructor(name1,name2)
 this.name1 = name1
 this.name2 = name2
 
 sound()
 return `$this.name1 makes sound`;
 

var animals = [new Animal("dog", "Max"), new Animal("dog", "Ben"), new Animal("cat", "Ella"), new Animal("cat", "Sophia")];

let a = ;
for(let i = 0;i<animals.length;i++)
 a[`$animals[i].name1_$animals[i].name2.toLowerCase()`] = animals[i]


console.log(a.dog_max.sound())
console.log(a.cat_ella.sound())

share|improve this answer

answered Mar 28 at 6:09

Maheer AliMaheer Ali

23.7k44 gold badges2121 silver badges3838 bronze badges

add a comment | 

0

You want to create dynamic variable names which is not possible with eval()

Using eval()

class Animal
 constructor(name1,name2)
 this.name1 = name1
 this.name2 = name2
 
 sound()
 return `$this.name1 makes sound`;
 

var animals = [new Animal("dog", "Max"), new Animal("dog", "Ben"), new Animal("cat", "Ella"), new Animal("cat", "Sophia")];


for(let i = 0;i<animals.length;i++)
 eval(`var $animals[i].name1_$animals[i].name2.toLowerCase() = animals[i]`);


console.log(dog_max.sound())
console.log(cat_ella.sound())

Using Object

But using eval() is not recommended. You can can create a object to store these

class Animal
 constructor(name1,name2)
 this.name1 = name1
 this.name2 = name2
 
 sound()
 return `$this.name1 makes sound`;
 

var animals = [new Animal("dog", "Max"), new Animal("dog", "Ben"), new Animal("cat", "Ella"), new Animal("cat", "Sophia")];

let a = ;
for(let i = 0;i<animals.length;i++)
 a[`$animals[i].name1_$animals[i].name2.toLowerCase()`] = animals[i]


console.log(a.dog_max.sound())
console.log(a.cat_ella.sound())

share|improve this answer

answered Mar 28 at 6:09

Maheer AliMaheer Ali

23.7k44 gold badges2121 silver badges3838 bronze badges

add a comment | 

You want to create dynamic variable names which is not possible with eval()

Using eval()

class Animal
 constructor(name1,name2)
 this.name1 = name1
 this.name2 = name2
 
 sound()
 return `$this.name1 makes sound`;
 

var animals = [new Animal("dog", "Max"), new Animal("dog", "Ben"), new Animal("cat", "Ella"), new Animal("cat", "Sophia")];


for(let i = 0;i<animals.length;i++)
 eval(`var $animals[i].name1_$animals[i].name2.toLowerCase() = animals[i]`);


console.log(dog_max.sound())
console.log(cat_ella.sound())

Using Object

But using eval() is not recommended. You can can create a object to store these

class Animal
 constructor(name1,name2)
 this.name1 = name1
 this.name2 = name2
 
 sound()
 return `$this.name1 makes sound`;
 

var animals = [new Animal("dog", "Max"), new Animal("dog", "Ben"), new Animal("cat", "Ella"), new Animal("cat", "Sophia")];

let a = ;
for(let i = 0;i<animals.length;i++)
 a[`$animals[i].name1_$animals[i].name2.toLowerCase()`] = animals[i]


console.log(a.dog_max.sound())
console.log(a.cat_ella.sound())

share|improve this answer

answered Mar 28 at 6:09

Maheer AliMaheer Ali

23.7k44 gold badges2121 silver badges3838 bronze badges

class Animal
 constructor(name1,name2)
 this.name1 = name1
 this.name2 = name2
 
 sound()
 return `$this.name1 makes sound`;
 

var animals = [new Animal("dog", "Max"), new Animal("dog", "Ben"), new Animal("cat", "Ella"), new Animal("cat", "Sophia")];


for(let i = 0;i<animals.length;i++)
 eval(`var $animals[i].name1_$animals[i].name2.toLowerCase() = animals[i]`);


console.log(dog_max.sound())
console.log(cat_ella.sound())

class Animal
 constructor(name1,name2)
 this.name1 = name1
 this.name2 = name2
 
 sound()
 return `$this.name1 makes sound`;
 

var animals = [new Animal("dog", "Max"), new Animal("dog", "Ben"), new Animal("cat", "Ella"), new Animal("cat", "Sophia")];

let a = ;
for(let i = 0;i<animals.length;i++)
 a[`$animals[i].name1_$animals[i].name2.toLowerCase()`] = animals[i]


console.log(a.dog_max.sound())
console.log(a.cat_ella.sound())

class Animal
 constructor(name1,name2)
 this.name1 = name1
 this.name2 = name2
 
 sound()
 return `$this.name1 makes sound`;
 

var animals = [new Animal("dog", "Max"), new Animal("dog", "Ben"), new Animal("cat", "Ella"), new Animal("cat", "Sophia")];


for(let i = 0;i<animals.length;i++)
 eval(`var $animals[i].name1_$animals[i].name2.toLowerCase() = animals[i]`);


console.log(dog_max.sound())
console.log(cat_ella.sound())

class Animal
 constructor(name1,name2)
 this.name1 = name1
 this.name2 = name2
 
 sound()
 return `$this.name1 makes sound`;
 

var animals = [new Animal("dog", "Max"), new Animal("dog", "Ben"), new Animal("cat", "Ella"), new Animal("cat", "Sophia")];


for(let i = 0;i<animals.length;i++)
 eval(`var $animals[i].name1_$animals[i].name2.toLowerCase() = animals[i]`);


console.log(dog_max.sound())
console.log(cat_ella.sound())

class Animal
 constructor(name1,name2)
 this.name1 = name1
 this.name2 = name2
 
 sound()
 return `$this.name1 makes sound`;
 

var animals = [new Animal("dog", "Max"), new Animal("dog", "Ben"), new Animal("cat", "Ella"), new Animal("cat", "Sophia")];

let a = ;
for(let i = 0;i<animals.length;i++)
 a[`$animals[i].name1_$animals[i].name2.toLowerCase()`] = animals[i]


console.log(a.dog_max.sound())
console.log(a.cat_ella.sound())

class Animal
 constructor(name1,name2)
 this.name1 = name1
 this.name2 = name2
 
 sound()
 return `$this.name1 makes sound`;
 

var animals = [new Animal("dog", "Max"), new Animal("dog", "Ben"), new Animal("cat", "Ella"), new Animal("cat", "Sophia")];

let a = ;
for(let i = 0;i<animals.length;i++)
 a[`$animals[i].name1_$animals[i].name2.toLowerCase()`] = animals[i]


console.log(a.dog_max.sound())
console.log(a.cat_ella.sound())

share|improve this answer

answered Mar 28 at 6:09

Maheer AliMaheer Ali

23.7k44 gold badges2121 silver badges3838 bronze badges

answered Mar 28 at 6:09

Maheer AliMaheer Ali

23.7k44 gold badges2121 silver badges3838 bronze badges

answered Mar 28 at 6:09

Maheer AliMaheer Ali

23.7k44 gold badges2121 silver badges3838 bronze badges