Find descriptions that have 'taxes' as 2nd word The Next CEO of Stack OverflowSQL question: How can I extract this information from these tables?Finding duplicate values in a SQL tableFind all tables containing column with specified name - MS SQL Serveroracle 10g get all selected columns and datatype from a single select statementSQL Joins using ParentType and Parent Tablesstore separate select statements as tables before doing EXCEPT/ JOIN (t-sql)MYSQL query help- Substring and InstringSQL Join Query in MS AccessPostgreSQL joining multiple tablesSQL join statement between table and selection in Knex
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Find descriptions that have 'taxes' as 2nd word
The Next CEO of Stack OverflowSQL question: How can I extract this information from these tables?Finding duplicate values in a SQL tableFind all tables containing column with specified name - MS SQL Serveroracle 10g get all selected columns and datatype from a single select statementSQL Joins using ParentType and Parent Tablesstore separate select statements as tables before doing EXCEPT/ JOIN (t-sql)MYSQL query help- Substring and InstringSQL Join Query in MS AccessPostgreSQL joining multiple tablesSQL join statement between table and selection in Knex
I am trying to write a statement that will output all of the descriptions that have taxes as the 2nd word. I am fairly confident with the first 4 lines but after that I am confused on how to do this. What I am will execute without error but it displays no information. Based on the information in my tables, there should be 7 things being displayed
SELECT vendor_name, account_description
FROM ap_vendors v
JOIN ap_general_ledger_accounts la
ON v.default_account_number = la.account_number
WHERE SUBSTR(LOWER(account_description),INSTR(account_description, ' ')) = 'taxes';
sql
add a comment |
I am trying to write a statement that will output all of the descriptions that have taxes as the 2nd word. I am fairly confident with the first 4 lines but after that I am confused on how to do this. What I am will execute without error but it displays no information. Based on the information in my tables, there should be 7 things being displayed
SELECT vendor_name, account_description
FROM ap_vendors v
JOIN ap_general_ledger_accounts la
ON v.default_account_number = la.account_number
WHERE SUBSTR(LOWER(account_description),INSTR(account_description, ' ')) = 'taxes';
sql
2
When you say second word, do you need to account for punctuation, spaces, etc? If the second "word" istaxeseseses
then is that a match or not? How robust do you need this to be? Do you have examples of the cases you need to cater for?
– MatBailie
Mar 21 at 16:24
2
Which DBMS product are you using? "SQL" is just a query language, not the name of a specific database product. Please add a tag for the database product you are usingpostgresql
,oracle
,sql-server
,db2
, ...
– a_horse_with_no_name
Mar 21 at 16:24
add a comment |
I am trying to write a statement that will output all of the descriptions that have taxes as the 2nd word. I am fairly confident with the first 4 lines but after that I am confused on how to do this. What I am will execute without error but it displays no information. Based on the information in my tables, there should be 7 things being displayed
SELECT vendor_name, account_description
FROM ap_vendors v
JOIN ap_general_ledger_accounts la
ON v.default_account_number = la.account_number
WHERE SUBSTR(LOWER(account_description),INSTR(account_description, ' ')) = 'taxes';
sql
I am trying to write a statement that will output all of the descriptions that have taxes as the 2nd word. I am fairly confident with the first 4 lines but after that I am confused on how to do this. What I am will execute without error but it displays no information. Based on the information in my tables, there should be 7 things being displayed
SELECT vendor_name, account_description
FROM ap_vendors v
JOIN ap_general_ledger_accounts la
ON v.default_account_number = la.account_number
WHERE SUBSTR(LOWER(account_description),INSTR(account_description, ' ')) = 'taxes';
sql
sql
asked Mar 21 at 16:19
user11119624user11119624
12
12
2
When you say second word, do you need to account for punctuation, spaces, etc? If the second "word" istaxeseseses
then is that a match or not? How robust do you need this to be? Do you have examples of the cases you need to cater for?
– MatBailie
Mar 21 at 16:24
2
Which DBMS product are you using? "SQL" is just a query language, not the name of a specific database product. Please add a tag for the database product you are usingpostgresql
,oracle
,sql-server
,db2
, ...
– a_horse_with_no_name
Mar 21 at 16:24
add a comment |
2
When you say second word, do you need to account for punctuation, spaces, etc? If the second "word" istaxeseseses
then is that a match or not? How robust do you need this to be? Do you have examples of the cases you need to cater for?
– MatBailie
Mar 21 at 16:24
2
Which DBMS product are you using? "SQL" is just a query language, not the name of a specific database product. Please add a tag for the database product you are usingpostgresql
,oracle
,sql-server
,db2
, ...
– a_horse_with_no_name
Mar 21 at 16:24
2
2
When you say second word, do you need to account for punctuation, spaces, etc? If the second "word" is
taxeseseses
then is that a match or not? How robust do you need this to be? Do you have examples of the cases you need to cater for?– MatBailie
Mar 21 at 16:24
When you say second word, do you need to account for punctuation, spaces, etc? If the second "word" is
taxeseseses
then is that a match or not? How robust do you need this to be? Do you have examples of the cases you need to cater for?– MatBailie
Mar 21 at 16:24
2
2
Which DBMS product are you using? "SQL" is just a query language, not the name of a specific database product. Please add a tag for the database product you are using
postgresql
, oracle
, sql-server
, db2
, ...– a_horse_with_no_name
Mar 21 at 16:24
Which DBMS product are you using? "SQL" is just a query language, not the name of a specific database product. Please add a tag for the database product you are using
postgresql
, oracle
, sql-server
, db2
, ...– a_horse_with_no_name
Mar 21 at 16:24
add a comment |
2 Answers
2
active
oldest
votes
This can only work if 'taxes' is always the second and the last word.
If there are more words after taxes, it will not work.
Try Adding +1 to the 4th line.
WHERE SUBSTR(LOWER(account_description),INSTR(account_description, ' ')+1) = 'taxes';
add a comment |
How about using LIKE
:
WHERE account_description LIKE '% taxes%' AND
account_description NOT LIKE '% % taxes'
If your database supports regular expressions, you can use those as well.
add a comment |
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2 Answers
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2 Answers
2
active
oldest
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active
oldest
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active
oldest
votes
This can only work if 'taxes' is always the second and the last word.
If there are more words after taxes, it will not work.
Try Adding +1 to the 4th line.
WHERE SUBSTR(LOWER(account_description),INSTR(account_description, ' ')+1) = 'taxes';
add a comment |
This can only work if 'taxes' is always the second and the last word.
If there are more words after taxes, it will not work.
Try Adding +1 to the 4th line.
WHERE SUBSTR(LOWER(account_description),INSTR(account_description, ' ')+1) = 'taxes';
add a comment |
This can only work if 'taxes' is always the second and the last word.
If there are more words after taxes, it will not work.
Try Adding +1 to the 4th line.
WHERE SUBSTR(LOWER(account_description),INSTR(account_description, ' ')+1) = 'taxes';
This can only work if 'taxes' is always the second and the last word.
If there are more words after taxes, it will not work.
Try Adding +1 to the 4th line.
WHERE SUBSTR(LOWER(account_description),INSTR(account_description, ' ')+1) = 'taxes';
answered Mar 21 at 16:27
Maris MolsMaris Mols
174
174
add a comment |
add a comment |
How about using LIKE
:
WHERE account_description LIKE '% taxes%' AND
account_description NOT LIKE '% % taxes'
If your database supports regular expressions, you can use those as well.
add a comment |
How about using LIKE
:
WHERE account_description LIKE '% taxes%' AND
account_description NOT LIKE '% % taxes'
If your database supports regular expressions, you can use those as well.
add a comment |
How about using LIKE
:
WHERE account_description LIKE '% taxes%' AND
account_description NOT LIKE '% % taxes'
If your database supports regular expressions, you can use those as well.
How about using LIKE
:
WHERE account_description LIKE '% taxes%' AND
account_description NOT LIKE '% % taxes'
If your database supports regular expressions, you can use those as well.
answered Mar 21 at 17:33
Gordon LinoffGordon Linoff
791k35316419
791k35316419
add a comment |
add a comment |
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2
When you say second word, do you need to account for punctuation, spaces, etc? If the second "word" is
taxeseseses
then is that a match or not? How robust do you need this to be? Do you have examples of the cases you need to cater for?– MatBailie
Mar 21 at 16:24
2
Which DBMS product are you using? "SQL" is just a query language, not the name of a specific database product. Please add a tag for the database product you are using
postgresql
,oracle
,sql-server
,db2
, ...– a_horse_with_no_name
Mar 21 at 16:24