Find descriptions that have 'taxes' as 2nd word The Next CEO of Stack OverflowSQL question: How can I extract this information from these tables?Finding duplicate values in a SQL tableFind all tables containing column with specified name - MS SQL Serveroracle 10g get all selected columns and datatype from a single select statementSQL Joins using ParentType and Parent Tablesstore separate select statements as tables before doing EXCEPT/ JOIN (t-sql)MYSQL query help- Substring and InstringSQL Join Query in MS AccessPostgreSQL joining multiple tablesSQL join statement between table and selection in Knex

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Find descriptions that have 'taxes' as 2nd word



The Next CEO of Stack OverflowSQL question: How can I extract this information from these tables?Finding duplicate values in a SQL tableFind all tables containing column with specified name - MS SQL Serveroracle 10g get all selected columns and datatype from a single select statementSQL Joins using ParentType and Parent Tablesstore separate select statements as tables before doing EXCEPT/ JOIN (t-sql)MYSQL query help- Substring and InstringSQL Join Query in MS AccessPostgreSQL joining multiple tablesSQL join statement between table and selection in Knex










0















I am trying to write a statement that will output all of the descriptions that have taxes as the 2nd word. I am fairly confident with the first 4 lines but after that I am confused on how to do this. What I am will execute without error but it displays no information. Based on the information in my tables, there should be 7 things being displayed



SELECT vendor_name, account_description
FROM ap_vendors v
JOIN ap_general_ledger_accounts la
ON v.default_account_number = la.account_number
WHERE SUBSTR(LOWER(account_description),INSTR(account_description, ' ')) = 'taxes';









share|improve this question

















  • 2





    When you say second word, do you need to account for punctuation, spaces, etc? If the second "word" is taxeseseses then is that a match or not? How robust do you need this to be? Do you have examples of the cases you need to cater for?

    – MatBailie
    Mar 21 at 16:24






  • 2





    Which DBMS product are you using? "SQL" is just a query language, not the name of a specific database product. Please add a tag for the database product you are using postgresql, oracle, sql-server, db2, ...

    – a_horse_with_no_name
    Mar 21 at 16:24















0















I am trying to write a statement that will output all of the descriptions that have taxes as the 2nd word. I am fairly confident with the first 4 lines but after that I am confused on how to do this. What I am will execute without error but it displays no information. Based on the information in my tables, there should be 7 things being displayed



SELECT vendor_name, account_description
FROM ap_vendors v
JOIN ap_general_ledger_accounts la
ON v.default_account_number = la.account_number
WHERE SUBSTR(LOWER(account_description),INSTR(account_description, ' ')) = 'taxes';









share|improve this question

















  • 2





    When you say second word, do you need to account for punctuation, spaces, etc? If the second "word" is taxeseseses then is that a match or not? How robust do you need this to be? Do you have examples of the cases you need to cater for?

    – MatBailie
    Mar 21 at 16:24






  • 2





    Which DBMS product are you using? "SQL" is just a query language, not the name of a specific database product. Please add a tag for the database product you are using postgresql, oracle, sql-server, db2, ...

    – a_horse_with_no_name
    Mar 21 at 16:24













0












0








0








I am trying to write a statement that will output all of the descriptions that have taxes as the 2nd word. I am fairly confident with the first 4 lines but after that I am confused on how to do this. What I am will execute without error but it displays no information. Based on the information in my tables, there should be 7 things being displayed



SELECT vendor_name, account_description
FROM ap_vendors v
JOIN ap_general_ledger_accounts la
ON v.default_account_number = la.account_number
WHERE SUBSTR(LOWER(account_description),INSTR(account_description, ' ')) = 'taxes';









share|improve this question














I am trying to write a statement that will output all of the descriptions that have taxes as the 2nd word. I am fairly confident with the first 4 lines but after that I am confused on how to do this. What I am will execute without error but it displays no information. Based on the information in my tables, there should be 7 things being displayed



SELECT vendor_name, account_description
FROM ap_vendors v
JOIN ap_general_ledger_accounts la
ON v.default_account_number = la.account_number
WHERE SUBSTR(LOWER(account_description),INSTR(account_description, ' ')) = 'taxes';






sql






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Mar 21 at 16:19









user11119624user11119624

12




12







  • 2





    When you say second word, do you need to account for punctuation, spaces, etc? If the second "word" is taxeseseses then is that a match or not? How robust do you need this to be? Do you have examples of the cases you need to cater for?

    – MatBailie
    Mar 21 at 16:24






  • 2





    Which DBMS product are you using? "SQL" is just a query language, not the name of a specific database product. Please add a tag for the database product you are using postgresql, oracle, sql-server, db2, ...

    – a_horse_with_no_name
    Mar 21 at 16:24












  • 2





    When you say second word, do you need to account for punctuation, spaces, etc? If the second "word" is taxeseseses then is that a match or not? How robust do you need this to be? Do you have examples of the cases you need to cater for?

    – MatBailie
    Mar 21 at 16:24






  • 2





    Which DBMS product are you using? "SQL" is just a query language, not the name of a specific database product. Please add a tag for the database product you are using postgresql, oracle, sql-server, db2, ...

    – a_horse_with_no_name
    Mar 21 at 16:24







2




2





When you say second word, do you need to account for punctuation, spaces, etc? If the second "word" is taxeseseses then is that a match or not? How robust do you need this to be? Do you have examples of the cases you need to cater for?

– MatBailie
Mar 21 at 16:24





When you say second word, do you need to account for punctuation, spaces, etc? If the second "word" is taxeseseses then is that a match or not? How robust do you need this to be? Do you have examples of the cases you need to cater for?

– MatBailie
Mar 21 at 16:24




2




2





Which DBMS product are you using? "SQL" is just a query language, not the name of a specific database product. Please add a tag for the database product you are using postgresql, oracle, sql-server, db2, ...

– a_horse_with_no_name
Mar 21 at 16:24





Which DBMS product are you using? "SQL" is just a query language, not the name of a specific database product. Please add a tag for the database product you are using postgresql, oracle, sql-server, db2, ...

– a_horse_with_no_name
Mar 21 at 16:24












2 Answers
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0














This can only work if 'taxes' is always the second and the last word.
If there are more words after taxes, it will not work.



Try Adding +1 to the 4th line.



WHERE SUBSTR(LOWER(account_description),INSTR(account_description, ' ')+1) = 'taxes';






share|improve this answer






























    0














    How about using LIKE:



    WHERE account_description LIKE '% taxes%' AND
    account_description NOT LIKE '% % taxes'


    If your database supports regular expressions, you can use those as well.






    share|improve this answer























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      2 Answers
      2






      active

      oldest

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      2 Answers
      2






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes









      0














      This can only work if 'taxes' is always the second and the last word.
      If there are more words after taxes, it will not work.



      Try Adding +1 to the 4th line.



      WHERE SUBSTR(LOWER(account_description),INSTR(account_description, ' ')+1) = 'taxes';






      share|improve this answer



























        0














        This can only work if 'taxes' is always the second and the last word.
        If there are more words after taxes, it will not work.



        Try Adding +1 to the 4th line.



        WHERE SUBSTR(LOWER(account_description),INSTR(account_description, ' ')+1) = 'taxes';






        share|improve this answer

























          0












          0








          0







          This can only work if 'taxes' is always the second and the last word.
          If there are more words after taxes, it will not work.



          Try Adding +1 to the 4th line.



          WHERE SUBSTR(LOWER(account_description),INSTR(account_description, ' ')+1) = 'taxes';






          share|improve this answer













          This can only work if 'taxes' is always the second and the last word.
          If there are more words after taxes, it will not work.



          Try Adding +1 to the 4th line.



          WHERE SUBSTR(LOWER(account_description),INSTR(account_description, ' ')+1) = 'taxes';







          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Mar 21 at 16:27









          Maris MolsMaris Mols

          174




          174























              0














              How about using LIKE:



              WHERE account_description LIKE '% taxes%' AND
              account_description NOT LIKE '% % taxes'


              If your database supports regular expressions, you can use those as well.






              share|improve this answer



























                0














                How about using LIKE:



                WHERE account_description LIKE '% taxes%' AND
                account_description NOT LIKE '% % taxes'


                If your database supports regular expressions, you can use those as well.






                share|improve this answer

























                  0












                  0








                  0







                  How about using LIKE:



                  WHERE account_description LIKE '% taxes%' AND
                  account_description NOT LIKE '% % taxes'


                  If your database supports regular expressions, you can use those as well.






                  share|improve this answer













                  How about using LIKE:



                  WHERE account_description LIKE '% taxes%' AND
                  account_description NOT LIKE '% % taxes'


                  If your database supports regular expressions, you can use those as well.







                  share|improve this answer












                  share|improve this answer



                  share|improve this answer










                  answered Mar 21 at 17:33









                  Gordon LinoffGordon Linoff

                  791k35316419




                  791k35316419



























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