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Having a List as an element in the list Prolog
How do I check if a list is empty?Finding the index of an item given a list containing it in PythonDifference between append vs. extend list methods in PythonHow do you split a list into evenly sized chunks?How do I remove an element from a list by index in Python?Getting the last element of a list in PythonHow to make a flat list out of list of lists?How do I get the number of elements in a list in Python?How do I concatenate two lists in Python?How to clone or copy a list?
Given a list (List1), I am trying to square each number in the list and return the answers in a new list (List2), where each element in List2 is in the form (Xi, Ji).
?- square([1,2,3,], L).
L = [[1,1],[2,4],[3,9]].
This is my code:
square([], []).
square([N|Tail], [SqrdN|SqrdTail]) :-
SqrdN is [N|N*N],
square(Tail, SqrdTail).
This is giving me a type error: '[]' expected, found `[1|1*1]' (a compound) ("x" must hold one character).
How can I achieve this?
list recursion prolog
edited Mar 21 at 16:47
false
10.3k773151
asked Mar 21 at 13:42
ps1234ps1234
105
add a comment |
Given a list (List1), I am trying to square each number in the list and return the answers in a new list (List2), where each element in List2 is in the form (Xi, Ji).
?- square([1,2,3,], L).
L = [[1,1],[2,4],[3,9]].
This is my code:
square([], []).
square([N|Tail], [SqrdN|SqrdTail]) :-
SqrdN is [N|N*N],
square(Tail, SqrdTail).
This is giving me a type error: '[]' expected, found `[1|1*1]' (a compound) ("x" must hold one character).
How can I achieve this?
list recursion prolog
edited Mar 21 at 16:47
false
10.3k773151
asked Mar 21 at 13:42
ps1234ps1234
105
add a comment |
Given a list (List1), I am trying to square each number in the list and return the answers in a new list (List2), where each element in List2 is in the form (Xi, Ji).
?- square([1,2,3,], L).
L = [[1,1],[2,4],[3,9]].
This is my code:
square([], []).
square([N|Tail], [SqrdN|SqrdTail]) :-
SqrdN is [N|N*N],
square(Tail, SqrdTail).
This is giving me a type error: '[]' expected, found `[1|1*1]' (a compound) ("x" must hold one character).
How can I achieve this?
list recursion prolog
edited Mar 21 at 16:47
false
10.3k773151
asked Mar 21 at 13:42
ps1234ps1234
105
Given a list (List1), I am trying to square each number in the list and return the answers in a new list (List2), where each element in List2 is in the form (Xi, Ji).
?- square([1,2,3,], L).
L = [[1,1],[2,4],[3,9]].
This is my code:
square([], []).
square([N|Tail], [SqrdN|SqrdTail]) :-
SqrdN is [N|N*N],
square(Tail, SqrdTail).
This is giving me a type error: '[]' expected, found `[1|1*1]' (a compound) ("x" must hold one character).
How can I achieve this?
list recursion prolog
list recursion prolog
edited Mar 21 at 16:47
false
10.3k773151
asked Mar 21 at 13:42
ps1234ps1234
105
edited Mar 21 at 16:47
false
10.3k773151
asked Mar 21 at 13:42
ps1234ps1234
105
edited Mar 21 at 16:47
false
10.3k773151
edited Mar 21 at 16:47
false
10.3k773151
edited Mar 21 at 16:47
false
10.3k773151
10.3k773151
asked Mar 21 at 13:42
ps1234ps1234
105
asked Mar 21 at 13:42
ps1234ps1234
105
asked Mar 21 at 13:42
ps1234ps1234
105
105
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
You are mixing your output representation (lists of [Item, SquaredItem]) with the computation of the squares, and your output term is also not a proper list of two items.
Using library clpfd:
:- use_module(library(clpfd)).
square([], []).
square([N|Tail], [[N, SqrdN]|SqrdTail]) :-
SqrdN #= N*N,
square(Tail, SqrdTail).
or without clpfd:
square([], []).
square([N|Tail], [[N, SqrdN]|SqrdTail]) :-
SqrdN is N*N,
square(Tail, SqrdTail).
answered Mar 21 at 14:01
gusbrogusbro
15.3k2134
add a comment |
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1 Answer
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active
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oldest
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oldest
votes
You are mixing your output representation (lists of [Item, SquaredItem]) with the computation of the squares, and your output term is also not a proper list of two items.
Using library clpfd:
:- use_module(library(clpfd)).
square([], []).
square([N|Tail], [[N, SqrdN]|SqrdTail]) :-
SqrdN #= N*N,
square(Tail, SqrdTail).
or without clpfd:
square([], []).
square([N|Tail], [[N, SqrdN]|SqrdTail]) :-
SqrdN is N*N,
square(Tail, SqrdTail).
answered Mar 21 at 14:01
gusbrogusbro
15.3k2134
add a comment |
You are mixing your output representation (lists of [Item, SquaredItem]) with the computation of the squares, and your output term is also not a proper list of two items.
Using library clpfd:
:- use_module(library(clpfd)).
square([], []).
square([N|Tail], [[N, SqrdN]|SqrdTail]) :-
SqrdN #= N*N,
square(Tail, SqrdTail).
or without clpfd:
square([], []).
square([N|Tail], [[N, SqrdN]|SqrdTail]) :-
SqrdN is N*N,
square(Tail, SqrdTail).
answered Mar 21 at 14:01
gusbrogusbro
15.3k2134
add a comment |
You are mixing your output representation (lists of [Item, SquaredItem]) with the computation of the squares, and your output term is also not a proper list of two items.
Using library clpfd:
:- use_module(library(clpfd)).
square([], []).
square([N|Tail], [[N, SqrdN]|SqrdTail]) :-
SqrdN #= N*N,
square(Tail, SqrdTail).
or without clpfd:
square([], []).
square([N|Tail], [[N, SqrdN]|SqrdTail]) :-
SqrdN is N*N,
square(Tail, SqrdTail).
answered Mar 21 at 14:01
gusbrogusbro
15.3k2134
You are mixing your output representation (lists of [Item, SquaredItem]) with the computation of the squares, and your output term is also not a proper list of two items.
Using library clpfd:
:- use_module(library(clpfd)).
square([], []).
square([N|Tail], [[N, SqrdN]|SqrdTail]) :-
SqrdN #= N*N,
square(Tail, SqrdTail).
or without clpfd:
square([], []).
square([N|Tail], [[N, SqrdN]|SqrdTail]) :-
SqrdN is N*N,
square(Tail, SqrdTail).
answered Mar 21 at 14:01
gusbrogusbro
15.3k2134
answered Mar 21 at 14:01
gusbrogusbro
15.3k2134
answered Mar 21 at 14:01
gusbrogusbro
15.3k2134
answered Mar 21 at 14:01
gusbrogusbro
15.3k2134
15.3k2134
add a comment |
add a comment |
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