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1

I'm using the library gremlin-scala to interact with Janusgraph.

Using the DSL, a way to insert a new vertex is by doing the following:

val Id = Key[Long]("id")
val Name = Key[String]("name")
graph + ("label", Id -> 42, Name -> "Mike")

I want to make this part into a a function ("label", Id -> 42, Name -> "Mike")

case class VertexModel(id: Long, name: String) 
 def toVertex: (Label, KeyValue[Long], KeyValue[String]) = 
 val Id = Key[Long]("id")
 val Name = Key[String]("name")
 ("item", Id -> id, Name -> name)
 


val model = VertexModel(1, "Bill")
graph + model.toVertex

This fails with the following error:

Error:(26, 11) type mismatch;
 found : T1
 required: gremlin.scala.Label
 (which expands to) String
 graph + vertex
Error:(26, 11) type mismatch;
 found : T2
 required: gremlin.scala.KeyValue[Long]
 graph + vertex
Error:(26, 11) type mismatch;
 found : T3
 required: gremlin.scala.KeyValue[String]
 graph + vertex

Not sure how to fix this.

scala gremlin-scala

share|improve this question

edited Mar 21 at 13:57

drum

asked Mar 21 at 13:49

drumdrum

1,78943654

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  From gremlin-scala's source code it looks like the argument to + on a graph isn't a tuple but just a regular argument list.
  
  – Levi Ramsey
  Mar 21 at 14:34
  
  

  
  
  
  

add a comment | 

1

I'm using the library gremlin-scala to interact with Janusgraph.

Using the DSL, a way to insert a new vertex is by doing the following:

val Id = Key[Long]("id")
val Name = Key[String]("name")
graph + ("label", Id -> 42, Name -> "Mike")

I want to make this part into a a function ("label", Id -> 42, Name -> "Mike")

case class VertexModel(id: Long, name: String) 
 def toVertex: (Label, KeyValue[Long], KeyValue[String]) = 
 val Id = Key[Long]("id")
 val Name = Key[String]("name")
 ("item", Id -> id, Name -> name)
 


val model = VertexModel(1, "Bill")
graph + model.toVertex

This fails with the following error:

Error:(26, 11) type mismatch;
 found : T1
 required: gremlin.scala.Label
 (which expands to) String
 graph + vertex
Error:(26, 11) type mismatch;
 found : T2
 required: gremlin.scala.KeyValue[Long]
 graph + vertex
Error:(26, 11) type mismatch;
 found : T3
 required: gremlin.scala.KeyValue[String]
 graph + vertex

Not sure how to fix this.

scala gremlin-scala

share|improve this question

edited Mar 21 at 13:57

drum

asked Mar 21 at 13:49

drumdrum

1,78943654

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  From gremlin-scala's source code it looks like the argument to + on a graph isn't a tuple but just a regular argument list.
  
  – Levi Ramsey
  Mar 21 at 14:34
  
  

  
  
  
  

add a comment | 

I'm using the library gremlin-scala to interact with Janusgraph.

Using the DSL, a way to insert a new vertex is by doing the following:

val Id = Key[Long]("id")
val Name = Key[String]("name")
graph + ("label", Id -> 42, Name -> "Mike")

I want to make this part into a a function ("label", Id -> 42, Name -> "Mike")

case class VertexModel(id: Long, name: String) 
 def toVertex: (Label, KeyValue[Long], KeyValue[String]) = 
 val Id = Key[Long]("id")
 val Name = Key[String]("name")
 ("item", Id -> id, Name -> name)
 


val model = VertexModel(1, "Bill")
graph + model.toVertex

This fails with the following error:

Error:(26, 11) type mismatch;
 found : T1
 required: gremlin.scala.Label
 (which expands to) String
 graph + vertex
Error:(26, 11) type mismatch;
 found : T2
 required: gremlin.scala.KeyValue[Long]
 graph + vertex
Error:(26, 11) type mismatch;
 found : T3
 required: gremlin.scala.KeyValue[String]
 graph + vertex

Not sure how to fix this.

scala gremlin-scala

share|improve this question

edited Mar 21 at 13:57

drum

asked Mar 21 at 13:49

drumdrum

1,78943654

val Id = Key[Long]("id")
val Name = Key[String]("name")
graph + ("label", Id -> 42, Name -> "Mike")

case class VertexModel(id: Long, name: String) 
 def toVertex: (Label, KeyValue[Long], KeyValue[String]) = 
 val Id = Key[Long]("id")
 val Name = Key[String]("name")
 ("item", Id -> id, Name -> name)
 


val model = VertexModel(1, "Bill")
graph + model.toVertex

Error:(26, 11) type mismatch;
 found : T1
 required: gremlin.scala.Label
 (which expands to) String
 graph + vertex
Error:(26, 11) type mismatch;
 found : T2
 required: gremlin.scala.KeyValue[Long]
 graph + vertex
Error:(26, 11) type mismatch;
 found : T3
 required: gremlin.scala.KeyValue[String]
 graph + vertex

share|improve this question

edited Mar 21 at 13:57

drum

asked Mar 21 at 13:49

drumdrum

1,78943654

share|improve this question

edited Mar 21 at 13:57

drum

asked Mar 21 at 13:49

drumdrum

1,78943654

asked Mar 21 at 13:49

drumdrum

1,78943654

asked Mar 21 at 13:49

drumdrum

1,78943654

1 Answer
1

active

oldest

votes

2

Why do you need extension method toVertex?

Doesn't this work just like

import gremlin.scala._
import org.apache.tinkerpop.gremlin.tinkergraph.structure.TinkerGraph

object App 

 implicit val graph: ScalaGraph = TinkerGraph.open.asScala

 case class VertexModel(id: Long, name: String) 

 val model = VertexModel(1, "Bill")
 graph + model

?

build.sbt

scalaVersion := "2.12.8"
libraryDependencies += "com.michaelpollmeier" %% "gremlin-scala" % "3.4.0.4"
libraryDependencies += "org.apache.tinkerpop" % "tinkergraph-gremlin" % "3.4.0"

share|improve this answer

edited 2 days ago

answered Mar 21 at 14:39

Dmytro MitinDmytro Mitin

7,947619

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  That's cool! Didn't know that was possible. 1 more question: How can I add the label to the class? Expanding on your solution: case class VertexModel(label: Label, id: Long, name: String), I get Name cannot be in protected namespace: label
  
  – drum
  Mar 21 at 14:49
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Sorry, can't reproduce. case class VertexModel(label: Label, id: Long, name: String) val model = VertexModel("item", 1, "Bill") graph + model compiles for me.
  
  – Dmytro Mitin
  Mar 21 at 14:56
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  That's during runtime by the gremlin server
  
  – drum
  Mar 21 at 15:12
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Another issue is that I cannot use different Key names. For example I want a key type but I can't do case class VertexModel(type: String, id: Long, name: String) because type is a keyword.
  
  – drum
  Mar 21 at 15:20
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  What if you try label, type in backticks?
  
  – Dmytro Mitin
  Mar 21 at 15:35
  

  
  
  
  

add a comment | 

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2

Why do you need extension method toVertex?

Doesn't this work just like

import gremlin.scala._
import org.apache.tinkerpop.gremlin.tinkergraph.structure.TinkerGraph

object App 

 implicit val graph: ScalaGraph = TinkerGraph.open.asScala

 case class VertexModel(id: Long, name: String) 

 val model = VertexModel(1, "Bill")
 graph + model

?

build.sbt

scalaVersion := "2.12.8"
libraryDependencies += "com.michaelpollmeier" %% "gremlin-scala" % "3.4.0.4"
libraryDependencies += "org.apache.tinkerpop" % "tinkergraph-gremlin" % "3.4.0"

share|improve this answer

edited 2 days ago

answered Mar 21 at 14:39

Dmytro MitinDmytro Mitin

7,947619

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  That's cool! Didn't know that was possible. 1 more question: How can I add the label to the class? Expanding on your solution: case class VertexModel(label: Label, id: Long, name: String), I get Name cannot be in protected namespace: label
  
  – drum
  Mar 21 at 14:49
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Sorry, can't reproduce. case class VertexModel(label: Label, id: Long, name: String) val model = VertexModel("item", 1, "Bill") graph + model compiles for me.
  
  – Dmytro Mitin
  Mar 21 at 14:56
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  That's during runtime by the gremlin server
  
  – drum
  Mar 21 at 15:12
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Another issue is that I cannot use different Key names. For example I want a key type but I can't do case class VertexModel(type: String, id: Long, name: String) because type is a keyword.
  
  – drum
  Mar 21 at 15:20
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  What if you try label, type in backticks?
  
  – Dmytro Mitin
  Mar 21 at 15:35
  

  
  
  
  

add a comment | 

2

Why do you need extension method toVertex?

Doesn't this work just like

import gremlin.scala._
import org.apache.tinkerpop.gremlin.tinkergraph.structure.TinkerGraph

object App 

 implicit val graph: ScalaGraph = TinkerGraph.open.asScala

 case class VertexModel(id: Long, name: String) 

 val model = VertexModel(1, "Bill")
 graph + model

?

build.sbt

scalaVersion := "2.12.8"
libraryDependencies += "com.michaelpollmeier" %% "gremlin-scala" % "3.4.0.4"
libraryDependencies += "org.apache.tinkerpop" % "tinkergraph-gremlin" % "3.4.0"

share|improve this answer

edited 2 days ago

answered Mar 21 at 14:39

Dmytro MitinDmytro Mitin

7,947619

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  That's cool! Didn't know that was possible. 1 more question: How can I add the label to the class? Expanding on your solution: case class VertexModel(label: Label, id: Long, name: String), I get Name cannot be in protected namespace: label
  
  – drum
  Mar 21 at 14:49
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Sorry, can't reproduce. case class VertexModel(label: Label, id: Long, name: String) val model = VertexModel("item", 1, "Bill") graph + model compiles for me.
  
  – Dmytro Mitin
  Mar 21 at 14:56
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  That's during runtime by the gremlin server
  
  – drum
  Mar 21 at 15:12
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Another issue is that I cannot use different Key names. For example I want a key type but I can't do case class VertexModel(type: String, id: Long, name: String) because type is a keyword.
  
  – drum
  Mar 21 at 15:20
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  What if you try label, type in backticks?
  
  – Dmytro Mitin
  Mar 21 at 15:35
  

  
  
  
  

add a comment | 

Why do you need extension method toVertex?

Doesn't this work just like

import gremlin.scala._
import org.apache.tinkerpop.gremlin.tinkergraph.structure.TinkerGraph

object App 

 implicit val graph: ScalaGraph = TinkerGraph.open.asScala

 case class VertexModel(id: Long, name: String) 

 val model = VertexModel(1, "Bill")
 graph + model

?

build.sbt

scalaVersion := "2.12.8"
libraryDependencies += "com.michaelpollmeier" %% "gremlin-scala" % "3.4.0.4"
libraryDependencies += "org.apache.tinkerpop" % "tinkergraph-gremlin" % "3.4.0"

share|improve this answer

edited 2 days ago

answered Mar 21 at 14:39

Dmytro MitinDmytro Mitin

7,947619

import gremlin.scala._
import org.apache.tinkerpop.gremlin.tinkergraph.structure.TinkerGraph

object App 

 implicit val graph: ScalaGraph = TinkerGraph.open.asScala

 case class VertexModel(id: Long, name: String) 

 val model = VertexModel(1, "Bill")
 graph + model

scalaVersion := "2.12.8"
libraryDependencies += "com.michaelpollmeier" %% "gremlin-scala" % "3.4.0.4"
libraryDependencies += "org.apache.tinkerpop" % "tinkergraph-gremlin" % "3.4.0"

share|improve this answer

edited 2 days ago

answered Mar 21 at 14:39

Dmytro MitinDmytro Mitin

7,947619

answered Mar 21 at 14:39

Dmytro MitinDmytro Mitin

7,947619

answered Mar 21 at 14:39

Dmytro MitinDmytro Mitin

7,947619