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dynamic keyword affects return type

What is the yield keyword used for in C#?What's the difference between the 'ref' and 'out' keywords?Func delegate with no return typeType Checking: typeof, GetType, or is?Deserialize JSON into C# dynamic object?Dynamic + linq compilation errorDifferent return type for same method of a base classdynamic keyword with ExpandoObject to attach and remove propertiesWhy won't the DLR (dynamic) bind to a private type?What is the difference between .NET Core and .NET Standard Class Library project types?

1

I'm not entirley sure why the following code compiles

namespace ConsoleApp13

 public class Person
 

 
 class Program
 
 static void Main(string[] args)
 
 dynamic expand = new ExpandoObject();
 List<Person> people = GetPerson(expand);

 

 public static Person GetPerson(int item)
 
 return new Person();
 

 

Why does the dynamic keyword impact the return type. It's like the compiler give's up on type checking as soon as dynamic is introduced. Is this expected behavior?

c# .net dynamic .net-core

share|improve this question

edited Mar 21 at 23:43

ArunPratap

2,20621028

asked Mar 21 at 13:45

Steven YatesSteven Yates

1,2081943

add a comment | 

1

I'm not entirley sure why the following code compiles

namespace ConsoleApp13

 public class Person
 

 
 class Program
 
 static void Main(string[] args)
 
 dynamic expand = new ExpandoObject();
 List<Person> people = GetPerson(expand);

 

 public static Person GetPerson(int item)
 
 return new Person();
 

 

Why does the dynamic keyword impact the return type. It's like the compiler give's up on type checking as soon as dynamic is introduced. Is this expected behavior?

c# .net dynamic .net-core

share|improve this question

edited Mar 21 at 23:43

ArunPratap

2,20621028

asked Mar 21 at 13:45

Steven YatesSteven Yates

1,2081943

add a comment | 

I'm not entirley sure why the following code compiles

namespace ConsoleApp13

 public class Person
 

 
 class Program
 
 static void Main(string[] args)
 
 dynamic expand = new ExpandoObject();
 List<Person> people = GetPerson(expand);

 

 public static Person GetPerson(int item)
 
 return new Person();
 

 

Why does the dynamic keyword impact the return type. It's like the compiler give's up on type checking as soon as dynamic is introduced. Is this expected behavior?

c# .net dynamic .net-core

share|improve this question

edited Mar 21 at 23:43

ArunPratap

2,20621028

asked Mar 21 at 13:45

Steven YatesSteven Yates

1,2081943

namespace ConsoleApp13

 public class Person
 

 
 class Program
 
 static void Main(string[] args)
 
 dynamic expand = new ExpandoObject();
 List<Person> people = GetPerson(expand);

 

 public static Person GetPerson(int item)
 
 return new Person();
 

 

share|improve this question

edited Mar 21 at 23:43

ArunPratap

2,20621028

asked Mar 21 at 13:45

Steven YatesSteven Yates

1,2081943

share|improve this question

edited Mar 21 at 23:43

ArunPratap

2,20621028

asked Mar 21 at 13:45

Steven YatesSteven Yates

1,2081943

edited Mar 21 at 23:43

ArunPratap

2,20621028

edited Mar 21 at 23:43

ArunPratap

2,20621028

asked Mar 21 at 13:45

Steven YatesSteven Yates

1,2081943

asked Mar 21 at 13:45

Steven YatesSteven Yates

1,2081943

1 Answer
1

active

oldest

votes

3

Is this expected behavior?

Yes. Almost anything you do that involves a dynamic value ends up with a compile-time type of dynamic. Note that binding is performed dynamically, so even though in this specific case you've only got one GetPerson method, in the more general case of method invocation, overloads could be present at execution time that aren't present at compile-time, with different return types.

There are a few operations which don't end up with a dynamic type:

• Casting (e.g. (string) dynamicValue)


• The is operator (e.g. dynamicValue is string)


• The as operator (e.g. dynamicValue as string
  


• Constructor calls (e.g. new Foo(dynamicValue))

share|improve this answer

answered Mar 21 at 13:49

Jon SkeetJon Skeet

1094k69579788464

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Thanks! I ended up looking deeper at the IL and then understood what was going on but thank you got the explanation, much appreciated
  
  – Steven Yates
  Mar 21 at 16:29
  

  
  
  
  

add a comment | 

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3

Is this expected behavior?

Yes. Almost anything you do that involves a dynamic value ends up with a compile-time type of dynamic. Note that binding is performed dynamically, so even though in this specific case you've only got one GetPerson method, in the more general case of method invocation, overloads could be present at execution time that aren't present at compile-time, with different return types.

There are a few operations which don't end up with a dynamic type:

• Casting (e.g. (string) dynamicValue)


• The is operator (e.g. dynamicValue is string)


• The as operator (e.g. dynamicValue as string
  


• Constructor calls (e.g. new Foo(dynamicValue))

share|improve this answer

answered Mar 21 at 13:49

Jon SkeetJon Skeet

1094k69579788464

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Thanks! I ended up looking deeper at the IL and then understood what was going on but thank you got the explanation, much appreciated
  
  – Steven Yates
  Mar 21 at 16:29
  

  
  
  
  

add a comment | 

3

Is this expected behavior?

Yes. Almost anything you do that involves a dynamic value ends up with a compile-time type of dynamic. Note that binding is performed dynamically, so even though in this specific case you've only got one GetPerson method, in the more general case of method invocation, overloads could be present at execution time that aren't present at compile-time, with different return types.

There are a few operations which don't end up with a dynamic type:

• Casting (e.g. (string) dynamicValue)


• The is operator (e.g. dynamicValue is string)


• The as operator (e.g. dynamicValue as string
  


• Constructor calls (e.g. new Foo(dynamicValue))

share|improve this answer

answered Mar 21 at 13:49

Jon SkeetJon Skeet

1094k69579788464

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Thanks! I ended up looking deeper at the IL and then understood what was going on but thank you got the explanation, much appreciated
  
  – Steven Yates
  Mar 21 at 16:29
  

  
  
  
  

add a comment | 

Is this expected behavior?

Yes. Almost anything you do that involves a dynamic value ends up with a compile-time type of dynamic. Note that binding is performed dynamically, so even though in this specific case you've only got one GetPerson method, in the more general case of method invocation, overloads could be present at execution time that aren't present at compile-time, with different return types.

There are a few operations which don't end up with a dynamic type:

• Casting (e.g. (string) dynamicValue)


• The is operator (e.g. dynamicValue is string)


• The as operator (e.g. dynamicValue as string
  


• Constructor calls (e.g. new Foo(dynamicValue))

share|improve this answer

answered Mar 21 at 13:49

Jon SkeetJon Skeet

1094k69579788464

share|improve this answer

answered Mar 21 at 13:49

Jon SkeetJon Skeet

1094k69579788464

answered Mar 21 at 13:49

Jon SkeetJon Skeet

1094k69579788464

answered Mar 21 at 13:49

Jon SkeetJon Skeet

1094k69579788464