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Python traceback for coroutine

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1

Let's say I have the following code:

from types import coroutine

@coroutine
def stop():
 yield 1

async def test2():
 await stop()

async def test1():
 await test2()
 await test2() # Here
 await test2()

coro = test1()
coro.send(None)
coro.send(None)

How can I get traceback (traceback object) for current coroutine state, i.e. line marked with comment, without artificially throwing unneeded exception?

python-3.x python-asyncio coroutine

share|improve this question

asked yesterday

adontzadontz

8681029

add a comment | 

1

Let's say I have the following code:

from types import coroutine

@coroutine
def stop():
 yield 1

async def test2():
 await stop()

async def test1():
 await test2()
 await test2() # Here
 await test2()

coro = test1()
coro.send(None)
coro.send(None)

How can I get traceback (traceback object) for current coroutine state, i.e. line marked with comment, without artificially throwing unneeded exception?

python-3.x python-asyncio coroutine

share|improve this question

asked yesterday

adontzadontz

8681029

add a comment | 

Let's say I have the following code:

from types import coroutine

@coroutine
def stop():
 yield 1

async def test2():
 await stop()

async def test1():
 await test2()
 await test2() # Here
 await test2()

coro = test1()
coro.send(None)
coro.send(None)

How can I get traceback (traceback object) for current coroutine state, i.e. line marked with comment, without artificially throwing unneeded exception?

python-3.x python-asyncio coroutine

share|improve this question

asked yesterday

adontzadontz

8681029

from types import coroutine

@coroutine
def stop():
 yield 1

async def test2():
 await stop()

async def test1():
 await test2()
 await test2() # Here
 await test2()

coro = test1()
coro.send(None)
coro.send(None)

share|improve this question

asked yesterday

adontzadontz

8681029

share|improve this question

asked yesterday

adontzadontz

8681029

asked yesterday

adontzadontz

8681029

asked yesterday

adontzadontz

8681029

1 Answer
1

active

oldest

votes

0

Use of traceback.print_stack() will give you the exact same traceback as thrown exception:

async def test1():
 await test2()

 traceback.print_stack()
 # raise Exception()

 await test2() # Here
 await test2()

You can use traceback.extract_stack() if you want to recieve object instead of printing.

---

Note however that you're doing something strange. asyncio coroutines is not supposed to be run use it's generator's nature functions like .send().

In asyncio you await for coroutines and run top level coroutine using event loop. Please see how it's done in documentation.

I write another small example that shows how to print start inside inner coroutine when you use asyncio regular way:

import asyncio
import traceback


async def test3():
 traceback.print_stack()


async def test2():
 await test3()


async def test1():
 await test2()


asyncio.run(test1())

You'll see:

 File "C:main.py", line 24, in <module>
 asyncio.run(test1())

 # inner event loop stack here

 File "C:main.py", line 21, in test1
 await test2()
 File "C:main.py", line 17, in test2
 await test3()
 File "C:main.py", line 13, in test3
 traceback.print_stack()

share|improve this answer

answered 16 hours ago

Mikhail GerasimovMikhail Gerasimov

14.6k44071

add a comment | 

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0

Use of traceback.print_stack() will give you the exact same traceback as thrown exception:

async def test1():
 await test2()

 traceback.print_stack()
 # raise Exception()

 await test2() # Here
 await test2()

You can use traceback.extract_stack() if you want to recieve object instead of printing.

---

Note however that you're doing something strange. asyncio coroutines is not supposed to be run use it's generator's nature functions like .send().

In asyncio you await for coroutines and run top level coroutine using event loop. Please see how it's done in documentation.

I write another small example that shows how to print start inside inner coroutine when you use asyncio regular way:

import asyncio
import traceback


async def test3():
 traceback.print_stack()


async def test2():
 await test3()


async def test1():
 await test2()


asyncio.run(test1())

You'll see:

 File "C:main.py", line 24, in <module>
 asyncio.run(test1())

 # inner event loop stack here

 File "C:main.py", line 21, in test1
 await test2()
 File "C:main.py", line 17, in test2
 await test3()
 File "C:main.py", line 13, in test3
 traceback.print_stack()

share|improve this answer

answered 16 hours ago

Mikhail GerasimovMikhail Gerasimov

14.6k44071

add a comment | 

0

Use of traceback.print_stack() will give you the exact same traceback as thrown exception:

async def test1():
 await test2()

 traceback.print_stack()
 # raise Exception()

 await test2() # Here
 await test2()

You can use traceback.extract_stack() if you want to recieve object instead of printing.

---

Note however that you're doing something strange. asyncio coroutines is not supposed to be run use it's generator's nature functions like .send().

In asyncio you await for coroutines and run top level coroutine using event loop. Please see how it's done in documentation.

I write another small example that shows how to print start inside inner coroutine when you use asyncio regular way:

import asyncio
import traceback


async def test3():
 traceback.print_stack()


async def test2():
 await test3()


async def test1():
 await test2()


asyncio.run(test1())

You'll see:

 File "C:main.py", line 24, in <module>
 asyncio.run(test1())

 # inner event loop stack here

 File "C:main.py", line 21, in test1
 await test2()
 File "C:main.py", line 17, in test2
 await test3()
 File "C:main.py", line 13, in test3
 traceback.print_stack()

share|improve this answer

answered 16 hours ago

Mikhail GerasimovMikhail Gerasimov

14.6k44071

add a comment | 

Use of traceback.print_stack() will give you the exact same traceback as thrown exception:

async def test1():
 await test2()

 traceback.print_stack()
 # raise Exception()

 await test2() # Here
 await test2()

You can use traceback.extract_stack() if you want to recieve object instead of printing.

---

Note however that you're doing something strange. asyncio coroutines is not supposed to be run use it's generator's nature functions like .send().

In asyncio you await for coroutines and run top level coroutine using event loop. Please see how it's done in documentation.

I write another small example that shows how to print start inside inner coroutine when you use asyncio regular way:

import asyncio
import traceback


async def test3():
 traceback.print_stack()


async def test2():
 await test3()


async def test1():
 await test2()


asyncio.run(test1())

You'll see:

 File "C:main.py", line 24, in <module>
 asyncio.run(test1())

 # inner event loop stack here

 File "C:main.py", line 21, in test1
 await test2()
 File "C:main.py", line 17, in test2
 await test3()
 File "C:main.py", line 13, in test3
 traceback.print_stack()

share|improve this answer

answered 16 hours ago

Mikhail GerasimovMikhail Gerasimov

14.6k44071

async def test1():
 await test2()

 traceback.print_stack()
 # raise Exception()

 await test2() # Here
 await test2()

import asyncio
import traceback


async def test3():
 traceback.print_stack()


async def test2():
 await test3()


async def test1():
 await test2()


asyncio.run(test1())

 File "C:main.py", line 24, in <module>
 asyncio.run(test1())

 # inner event loop stack here

 File "C:main.py", line 21, in test1
 await test2()
 File "C:main.py", line 17, in test2
 await test3()
 File "C:main.py", line 13, in test3
 traceback.print_stack()

share|improve this answer

answered 16 hours ago

Mikhail GerasimovMikhail Gerasimov

14.6k44071

answered 16 hours ago

Mikhail GerasimovMikhail Gerasimov

14.6k44071

answered 16 hours ago

Mikhail GerasimovMikhail Gerasimov

14.6k44071