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C#: Min to max number of digits after a decimal
How to validate decimal number input to restrict them to only two decimal places?Validate decimal numbers in JavaScript - IsNumeric()What are the correct version numbers for C#?How do I generate a random int number?Regex to validate a number with only one digit following a decimalhow to limit only two digits after decimal point using Regex ValidatorRegular expression for a decimal with a max of 2 digits before decimal pointRegex on JavaScript to accept only numbers with 2 decimalsregex for decimal value restrict 16 digitHow to limit total number of digits in a decimal numberregular expression for number and decimal points in javascript
I'm trying to do a check for a user input for the rate entered, I want to accept the value entered if it has min 2 digits to a max of 5 digits after the decimal.
Valid Example:
*1.12
*1.123
*1.1234
*1.12345
Not Valid:
1
1.1
1.123456
etc.
I've been trying to get it with Regex but right now it only allows only 5 digits after the decimal nothing less nothing more. Here's the code:
//Check if the string is a double
bool IsDouble(string s)
var regex = new Regex(@"^d+.d5?$");
var check = regex.IsMatch(s);
return check;
A little help would be greatly appreciated.
c# regex validation
edited Jan 30 '14 at 14:54
crush
12.6k74590
asked Jan 30 '14 at 14:25
kknaguibkknaguib
4061927
add a comment |
I'm trying to do a check for a user input for the rate entered, I want to accept the value entered if it has min 2 digits to a max of 5 digits after the decimal.
Valid Example:
*1.12
*1.123
*1.1234
*1.12345
Not Valid:
1
1.1
1.123456
etc.
I've been trying to get it with Regex but right now it only allows only 5 digits after the decimal nothing less nothing more. Here's the code:
//Check if the string is a double
bool IsDouble(string s)
var regex = new Regex(@"^d+.d5?$");
var check = regex.IsMatch(s);
return check;
A little help would be greatly appreciated.
c# regex validation
edited Jan 30 '14 at 14:54
crush
12.6k74590
asked Jan 30 '14 at 14:25
kknaguibkknaguib
4061927
add a comment |
I'm trying to do a check for a user input for the rate entered, I want to accept the value entered if it has min 2 digits to a max of 5 digits after the decimal.
Valid Example:
*1.12
*1.123
*1.1234
*1.12345
Not Valid:
1
1.1
1.123456
etc.
I've been trying to get it with Regex but right now it only allows only 5 digits after the decimal nothing less nothing more. Here's the code:
//Check if the string is a double
bool IsDouble(string s)
var regex = new Regex(@"^d+.d5?$");
var check = regex.IsMatch(s);
return check;
A little help would be greatly appreciated.
c# regex validation
edited Jan 30 '14 at 14:54
crush
12.6k74590
asked Jan 30 '14 at 14:25
kknaguibkknaguib
4061927
I'm trying to do a check for a user input for the rate entered, I want to accept the value entered if it has min 2 digits to a max of 5 digits after the decimal.
Valid Example:
*1.12
*1.123
*1.1234
*1.12345
Not Valid:
1
1.1
1.123456
etc.
I've been trying to get it with Regex but right now it only allows only 5 digits after the decimal nothing less nothing more. Here's the code:
//Check if the string is a double
bool IsDouble(string s)
var regex = new Regex(@"^d+.d5?$");
var check = regex.IsMatch(s);
return check;
A little help would be greatly appreciated.
c# regex validation
c# regex validation
edited Jan 30 '14 at 14:54
crush
12.6k74590
asked Jan 30 '14 at 14:25
kknaguibkknaguib
4061927
edited Jan 30 '14 at 14:54
crush
12.6k74590
asked Jan 30 '14 at 14:25
kknaguibkknaguib
4061927
edited Jan 30 '14 at 14:54
crush
12.6k74590
edited Jan 30 '14 at 14:54
crush
12.6k74590
edited Jan 30 '14 at 14:54
crush
12.6k74590
12.6k74590
asked Jan 30 '14 at 14:25
kknaguibkknaguib
4061927
asked Jan 30 '14 at 14:25
kknaguibkknaguib
4061927
asked Jan 30 '14 at 14:25
kknaguibkknaguib
4061927
4061927
add a comment |
add a comment |
4 Answers
4
active
oldest
votes
This should do it:
^d+.d2,5$
answered Jan 30 '14 at 14:29
Patrick QuirkPatrick Quirk
18k14373
Great thanks man!
– kknaguib
Jan 30 '14 at 14:32
add a comment |
Use the pattern
"^d+.d2,5?$"
to match between 2 and 5 characters
answered Jan 30 '14 at 14:29
D StanleyD Stanley
124k9116180
Thanks! Works like a charm
– kknaguib
Jan 30 '14 at 14:36
add a comment |
Try this Regex
you can specify your own range here d2,5
^s*-?[1-9]d*(.d2,5)?s*$
(Or)
^(d1,5|d0,5.d2,5)$
REGEX DEMO
answered Jan 30 '14 at 14:31
Vignesh Kumar AVignesh Kumar A
18.7k104187
This will accept integers that are not allowed.
– Toto
Jan 30 '14 at 14:41
add a comment |
A non-regex solution
It also returns the decimal
public int? DecimalAfter (string strDec, out decimal? decNull)
int? decAfter = null;
strDec = strDec.Trim();
decimal dec;
if (decimal.TryParse(strDec, out dec))
decNull = dec;
int decPos = strDec.IndexOf('.');
if (decPos == -1)
decAfter = 0;
else
decAfter = strDec.Length - decPos - 1;
else decNull = null;
return decAfter;
answered Jan 30 '14 at 14:59
paparazzopaparazzo
37.7k1775140
add a comment |
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4 Answers
4
active
oldest
votes
4 Answers
4
active
oldest
votes
active
oldest
votes
active
oldest
votes
This should do it:
^d+.d2,5$
answered Jan 30 '14 at 14:29
Patrick QuirkPatrick Quirk
18k14373
Great thanks man!
– kknaguib
Jan 30 '14 at 14:32
add a comment |
This should do it:
^d+.d2,5$
answered Jan 30 '14 at 14:29
Patrick QuirkPatrick Quirk
18k14373
Great thanks man!
– kknaguib
Jan 30 '14 at 14:32
add a comment |
This should do it:
^d+.d2,5$
answered Jan 30 '14 at 14:29
Patrick QuirkPatrick Quirk
18k14373
This should do it:
^d+.d2,5$
answered Jan 30 '14 at 14:29
Patrick QuirkPatrick Quirk
18k14373
answered Jan 30 '14 at 14:29
Patrick QuirkPatrick Quirk
18k14373
answered Jan 30 '14 at 14:29
Patrick QuirkPatrick Quirk
18k14373
answered Jan 30 '14 at 14:29
Patrick QuirkPatrick Quirk
18k14373
18k14373
Great thanks man!
– kknaguib
Jan 30 '14 at 14:32
add a comment |
Great thanks man!
– kknaguib
Jan 30 '14 at 14:32
Great thanks man!
– kknaguib
Jan 30 '14 at 14:32
Great thanks man!
– kknaguib
Jan 30 '14 at 14:32
add a comment |
Use the pattern
"^d+.d2,5?$"
to match between 2 and 5 characters
answered Jan 30 '14 at 14:29
D StanleyD Stanley
124k9116180
Thanks! Works like a charm
– kknaguib
Jan 30 '14 at 14:36
add a comment |
Use the pattern
"^d+.d2,5?$"
to match between 2 and 5 characters
answered Jan 30 '14 at 14:29
D StanleyD Stanley
124k9116180
Thanks! Works like a charm
– kknaguib
Jan 30 '14 at 14:36
add a comment |
Use the pattern
"^d+.d2,5?$"
to match between 2 and 5 characters
answered Jan 30 '14 at 14:29
D StanleyD Stanley
124k9116180
Use the pattern
"^d+.d2,5?$"
to match between 2 and 5 characters
answered Jan 30 '14 at 14:29
D StanleyD Stanley
124k9116180
answered Jan 30 '14 at 14:29
D StanleyD Stanley
124k9116180
answered Jan 30 '14 at 14:29
D StanleyD Stanley
124k9116180
answered Jan 30 '14 at 14:29
D StanleyD Stanley
124k9116180
124k9116180
Thanks! Works like a charm
– kknaguib
Jan 30 '14 at 14:36
add a comment |
Thanks! Works like a charm
– kknaguib
Jan 30 '14 at 14:36
Thanks! Works like a charm
– kknaguib
Jan 30 '14 at 14:36
Thanks! Works like a charm
– kknaguib
Jan 30 '14 at 14:36
add a comment |
Try this Regex
you can specify your own range here d2,5
^s*-?[1-9]d*(.d2,5)?s*$
(Or)
^(d1,5|d0,5.d2,5)$
REGEX DEMO
answered Jan 30 '14 at 14:31
Vignesh Kumar AVignesh Kumar A
18.7k104187
This will accept integers that are not allowed.
– Toto
Jan 30 '14 at 14:41
add a comment |
Try this Regex
you can specify your own range here d2,5
^s*-?[1-9]d*(.d2,5)?s*$
(Or)
^(d1,5|d0,5.d2,5)$
REGEX DEMO
answered Jan 30 '14 at 14:31
Vignesh Kumar AVignesh Kumar A
18.7k104187
This will accept integers that are not allowed.
– Toto
Jan 30 '14 at 14:41
add a comment |
Try this Regex
you can specify your own range here d2,5
^s*-?[1-9]d*(.d2,5)?s*$
(Or)
^(d1,5|d0,5.d2,5)$
REGEX DEMO
answered Jan 30 '14 at 14:31
Vignesh Kumar AVignesh Kumar A
18.7k104187
Try this Regex
you can specify your own range here d2,5
^s*-?[1-9]d*(.d2,5)?s*$
(Or)
^(d1,5|d0,5.d2,5)$
REGEX DEMO
answered Jan 30 '14 at 14:31
Vignesh Kumar AVignesh Kumar A
18.7k104187
answered Jan 30 '14 at 14:31
Vignesh Kumar AVignesh Kumar A
18.7k104187
answered Jan 30 '14 at 14:31
Vignesh Kumar AVignesh Kumar A
18.7k104187
answered Jan 30 '14 at 14:31
Vignesh Kumar AVignesh Kumar A
18.7k104187
18.7k104187
This will accept integers that are not allowed.
– Toto
Jan 30 '14 at 14:41
add a comment |
This will accept integers that are not allowed.
– Toto
Jan 30 '14 at 14:41
This will accept integers that are not allowed.
– Toto
Jan 30 '14 at 14:41
This will accept integers that are not allowed.
– Toto
Jan 30 '14 at 14:41
add a comment |
A non-regex solution
It also returns the decimal
public int? DecimalAfter (string strDec, out decimal? decNull)
int? decAfter = null;
strDec = strDec.Trim();
decimal dec;
if (decimal.TryParse(strDec, out dec))
decNull = dec;
int decPos = strDec.IndexOf('.');
if (decPos == -1)
decAfter = 0;
else
decAfter = strDec.Length - decPos - 1;
else decNull = null;
return decAfter;
answered Jan 30 '14 at 14:59
paparazzopaparazzo
37.7k1775140
add a comment |
A non-regex solution
It also returns the decimal
public int? DecimalAfter (string strDec, out decimal? decNull)
int? decAfter = null;
strDec = strDec.Trim();
decimal dec;
if (decimal.TryParse(strDec, out dec))
decNull = dec;
int decPos = strDec.IndexOf('.');
if (decPos == -1)
decAfter = 0;
else
decAfter = strDec.Length - decPos - 1;
else decNull = null;
return decAfter;
answered Jan 30 '14 at 14:59
paparazzopaparazzo
37.7k1775140
add a comment |
A non-regex solution
It also returns the decimal
public int? DecimalAfter (string strDec, out decimal? decNull)
int? decAfter = null;
strDec = strDec.Trim();
decimal dec;
if (decimal.TryParse(strDec, out dec))
decNull = dec;
int decPos = strDec.IndexOf('.');
if (decPos == -1)
decAfter = 0;
else
decAfter = strDec.Length - decPos - 1;
else decNull = null;
return decAfter;
answered Jan 30 '14 at 14:59
paparazzopaparazzo
37.7k1775140
A non-regex solution
It also returns the decimal
public int? DecimalAfter (string strDec, out decimal? decNull)
int? decAfter = null;
strDec = strDec.Trim();
decimal dec;
if (decimal.TryParse(strDec, out dec))
decNull = dec;
int decPos = strDec.IndexOf('.');
if (decPos == -1)
decAfter = 0;
else
decAfter = strDec.Length - decPos - 1;
else decNull = null;
return decAfter;
answered Jan 30 '14 at 14:59
paparazzopaparazzo
37.7k1775140
answered Jan 30 '14 at 14:59
paparazzopaparazzo
37.7k1775140
answered Jan 30 '14 at 14:59
paparazzopaparazzo
37.7k1775140
answered Jan 30 '14 at 14:59
paparazzopaparazzo
37.7k1775140
37.7k1775140
add a comment |
add a comment |
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