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JavaScript needed in determining seconds elapsed in current year starting Jan 01 at 00:00 [on hold]

How to determine equality for two JavaScript objects?Why would a JavaScript variable start with a dollar sign?Get the current URL with JavaScript?How do I get the current date in JavaScript?Why does the JavaScript need to start with “;”?Get current date/time in secondsGet the current year in JavaScriptGetting current date and time in JavaScriptGetting a MySQL DateTime in PHP to seconds in javascriptJavascript, counting years and days since 1970-01-01 until today

-1

I am newbee in JavaScript and i am having toughtime calculating seconds elapsed in current year not from 1970 as JavaScript default method calculates.
Basically i need to develop script which will show countup timer of products produced in current year. Question is a company produces 4 million product in a year and i need to show Counter which will show current number of items produced and keep on counting up as long as i am on this counter page. So i need number of items produced till time i have opened page and numer of milliseconds remaining in current year till 31st dec at 24:00

javascript gettime

share|improve this question

asked yesterday

Jagdish PrabhuJagdish Prabhu

1

put on hold as off-topic by Idan, Billal Begueradj, Matt Raines, Matteo Baldi, David Makogon yesterday

This question appears to be off-topic. The users who voted to close gave this specific reason:

• "Questions seeking debugging help ("why isn't this code working?") must include the desired behavior, a specific problem or error and the shortest code necessary to reproduce it in the question itself. Questions without a clear problem statement are not useful to other readers. See: How to create a Minimal, Complete, and Verifiable example." – Idan, Billal Begueradj, Matt Raines, Matteo Baldi

If this question can be reworded to fit the rules in the help center, please edit the question.

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  What have you tried? How was it deficient?
  
  – Scott Hunter
  yesterday
  

  
  
  
  

add a comment | 

-1

I am newbee in JavaScript and i am having toughtime calculating seconds elapsed in current year not from 1970 as JavaScript default method calculates.
Basically i need to develop script which will show countup timer of products produced in current year. Question is a company produces 4 million product in a year and i need to show Counter which will show current number of items produced and keep on counting up as long as i am on this counter page. So i need number of items produced till time i have opened page and numer of milliseconds remaining in current year till 31st dec at 24:00

javascript gettime

share|improve this question

asked yesterday

Jagdish PrabhuJagdish Prabhu

1

put on hold as off-topic by Idan, Billal Begueradj, Matt Raines, Matteo Baldi, David Makogon yesterday

This question appears to be off-topic. The users who voted to close gave this specific reason:

• "Questions seeking debugging help ("why isn't this code working?") must include the desired behavior, a specific problem or error and the shortest code necessary to reproduce it in the question itself. Questions without a clear problem statement are not useful to other readers. See: How to create a Minimal, Complete, and Verifiable example." – Idan, Billal Begueradj, Matt Raines, Matteo Baldi

If this question can be reworded to fit the rules in the help center, please edit the question.

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  What have you tried? How was it deficient?
  
  – Scott Hunter
  yesterday
  

  
  
  
  

add a comment | 

I am newbee in JavaScript and i am having toughtime calculating seconds elapsed in current year not from 1970 as JavaScript default method calculates.
Basically i need to develop script which will show countup timer of products produced in current year. Question is a company produces 4 million product in a year and i need to show Counter which will show current number of items produced and keep on counting up as long as i am on this counter page. So i need number of items produced till time i have opened page and numer of milliseconds remaining in current year till 31st dec at 24:00

javascript gettime

share|improve this question

asked yesterday

Jagdish PrabhuJagdish Prabhu

1

share|improve this question

asked yesterday

Jagdish PrabhuJagdish Prabhu

1

share|improve this question

asked yesterday

Jagdish PrabhuJagdish Prabhu

1

asked yesterday

Jagdish PrabhuJagdish Prabhu

1

asked yesterday

Jagdish PrabhuJagdish Prabhu

1

4 Answers
4

active

oldest

votes

1

 const first = new Date();
 first.setDate(1);
 first setMonth(0);
 first.setHours(0);
 first.setMinutes(0);

 const delta = Date.now() - first;

 const perMS = 4 * 10 ** 6 / (1000 * 60 * 60 * 24 * 365);

 console.log(delta * perMS);

share|improve this answer

answered yesterday

Jonas WilmsJonas Wilms

62.7k53456

add a comment | 

0

This will give you the total number of milliseconds passed in the current year, you can then subtract it from total milliseconds in a year

var diff = new Date(Math.abs(new Date() - new Date(new Date().getFullYear(), 0, 1))).getTime();
console.log(diff);

share|improve this answer

answered yesterday

Chaitanya BankanhalChaitanya Bankanhal

6815

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Thanks, i used this script and got desired result. Thanks all who replied to my question.
  
  – Jagdish Prabhu
  yesterday
  
  

  
  
  
  

add a comment | 

0

I have used below script, countup script is working fine, I need 'from' and 'speed' variable.

$.fn.countTo = function(options) ;

$.fn.countTo.defaults = 
 from: 0, // the number the element should start at
 to: 100, // the number the element should end at
 speed: 1000, // how long it should take to count between the target numbers
 refreshInterval: 100, // how often the element should be updated
 decimals: 0, // the number of decimal places to show
 onUpdate: null, // callback method for every time the element is updated,
 onComplete: null, // callback method for when the element finishes updating
;

var date = new Date("2019, 1, 1");
var seconds = date.getTime() / 1000; 

var prRatePerSec = 0.12;
var prPerYear = 4000000;
var prProducedTill = Math.round(seconds * prRatePerSec);

$('.timer').countTo(
 from: 0,
 to: prPerYear,
 speed: 31540000000,
 refreshInterval: 50,
 onComplete: function (value) 
 console.debug(this);
 
);

share|improve this answer

answered yesterday

Jagdish PrabhuJagdish Prabhu

1

add a comment | 

0

You can substract two date object with javascript.

So substract the current date with the start year date

Like

var second = diffCurrentYear() / 1000;
var day = second / 60 / 60 / 24;

console.log(day)

function diffCurrentYear() 
 var currentYear = new Date().getFullYear(),
 diff = (new Date()).getTime() - (new Date(currentYear + '-01-01')).getTime()
 return diff;

share|improve this answer

answered yesterday

R3tepR3tep

7,97682962

add a comment | 

1

 const first = new Date();
 first.setDate(1);
 first setMonth(0);
 first.setHours(0);
 first.setMinutes(0);

 const delta = Date.now() - first;

 const perMS = 4 * 10 ** 6 / (1000 * 60 * 60 * 24 * 365);

 console.log(delta * perMS);

share|improve this answer

answered yesterday

Jonas WilmsJonas Wilms

62.7k53456

add a comment | 

1

 const first = new Date();
 first.setDate(1);
 first setMonth(0);
 first.setHours(0);
 first.setMinutes(0);

 const delta = Date.now() - first;

 const perMS = 4 * 10 ** 6 / (1000 * 60 * 60 * 24 * 365);

 console.log(delta * perMS);

share|improve this answer

answered yesterday

Jonas WilmsJonas Wilms

62.7k53456

add a comment | 

 const first = new Date();
 first.setDate(1);
 first setMonth(0);
 first.setHours(0);
 first.setMinutes(0);

 const delta = Date.now() - first;

 const perMS = 4 * 10 ** 6 / (1000 * 60 * 60 * 24 * 365);

 console.log(delta * perMS);

share|improve this answer

answered yesterday

Jonas WilmsJonas Wilms

62.7k53456

 const first = new Date();
 first.setDate(1);
 first setMonth(0);
 first.setHours(0);
 first.setMinutes(0);

 const delta = Date.now() - first;

 const perMS = 4 * 10 ** 6 / (1000 * 60 * 60 * 24 * 365);

 console.log(delta * perMS);

share|improve this answer

answered yesterday

Jonas WilmsJonas Wilms

62.7k53456

answered yesterday

Jonas WilmsJonas Wilms

62.7k53456

answered yesterday

Jonas WilmsJonas Wilms

62.7k53456

0

This will give you the total number of milliseconds passed in the current year, you can then subtract it from total milliseconds in a year

var diff = new Date(Math.abs(new Date() - new Date(new Date().getFullYear(), 0, 1))).getTime();
console.log(diff);

share|improve this answer

answered yesterday

Chaitanya BankanhalChaitanya Bankanhal

6815

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Thanks, i used this script and got desired result. Thanks all who replied to my question.
  
  – Jagdish Prabhu
  yesterday
  
  

  
  
  
  

add a comment | 

0

This will give you the total number of milliseconds passed in the current year, you can then subtract it from total milliseconds in a year

var diff = new Date(Math.abs(new Date() - new Date(new Date().getFullYear(), 0, 1))).getTime();
console.log(diff);

share|improve this answer

answered yesterday

Chaitanya BankanhalChaitanya Bankanhal

6815

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Thanks, i used this script and got desired result. Thanks all who replied to my question.
  
  – Jagdish Prabhu
  yesterday
  
  

  
  
  
  

add a comment | 

This will give you the total number of milliseconds passed in the current year, you can then subtract it from total milliseconds in a year

var diff = new Date(Math.abs(new Date() - new Date(new Date().getFullYear(), 0, 1))).getTime();
console.log(diff);

share|improve this answer

answered yesterday

Chaitanya BankanhalChaitanya Bankanhal

6815

var diff = new Date(Math.abs(new Date() - new Date(new Date().getFullYear(), 0, 1))).getTime();
console.log(diff);

share|improve this answer

answered yesterday

Chaitanya BankanhalChaitanya Bankanhal

6815

answered yesterday

Chaitanya BankanhalChaitanya Bankanhal

6815

answered yesterday

Chaitanya BankanhalChaitanya Bankanhal

6815

0

I have used below script, countup script is working fine, I need 'from' and 'speed' variable.

$.fn.countTo = function(options) ;

$.fn.countTo.defaults = 
 from: 0, // the number the element should start at
 to: 100, // the number the element should end at
 speed: 1000, // how long it should take to count between the target numbers
 refreshInterval: 100, // how often the element should be updated
 decimals: 0, // the number of decimal places to show
 onUpdate: null, // callback method for every time the element is updated,
 onComplete: null, // callback method for when the element finishes updating
;

var date = new Date("2019, 1, 1");
var seconds = date.getTime() / 1000; 

var prRatePerSec = 0.12;
var prPerYear = 4000000;
var prProducedTill = Math.round(seconds * prRatePerSec);

$('.timer').countTo(
 from: 0,
 to: prPerYear,
 speed: 31540000000,
 refreshInterval: 50,
 onComplete: function (value) 
 console.debug(this);
 
);

share|improve this answer

answered yesterday

Jagdish PrabhuJagdish Prabhu

1

add a comment | 

0

I have used below script, countup script is working fine, I need 'from' and 'speed' variable.

$.fn.countTo = function(options) ;

$.fn.countTo.defaults = 
 from: 0, // the number the element should start at
 to: 100, // the number the element should end at
 speed: 1000, // how long it should take to count between the target numbers
 refreshInterval: 100, // how often the element should be updated
 decimals: 0, // the number of decimal places to show
 onUpdate: null, // callback method for every time the element is updated,
 onComplete: null, // callback method for when the element finishes updating
;

var date = new Date("2019, 1, 1");
var seconds = date.getTime() / 1000; 

var prRatePerSec = 0.12;
var prPerYear = 4000000;
var prProducedTill = Math.round(seconds * prRatePerSec);

$('.timer').countTo(
 from: 0,
 to: prPerYear,
 speed: 31540000000,
 refreshInterval: 50,
 onComplete: function (value) 
 console.debug(this);
 
);

share|improve this answer

answered yesterday

Jagdish PrabhuJagdish Prabhu

1

add a comment | 

I have used below script, countup script is working fine, I need 'from' and 'speed' variable.

$.fn.countTo = function(options) ;

$.fn.countTo.defaults = 
 from: 0, // the number the element should start at
 to: 100, // the number the element should end at
 speed: 1000, // how long it should take to count between the target numbers
 refreshInterval: 100, // how often the element should be updated
 decimals: 0, // the number of decimal places to show
 onUpdate: null, // callback method for every time the element is updated,
 onComplete: null, // callback method for when the element finishes updating
;

var date = new Date("2019, 1, 1");
var seconds = date.getTime() / 1000; 

var prRatePerSec = 0.12;
var prPerYear = 4000000;
var prProducedTill = Math.round(seconds * prRatePerSec);

$('.timer').countTo(
 from: 0,
 to: prPerYear,
 speed: 31540000000,
 refreshInterval: 50,
 onComplete: function (value) 
 console.debug(this);
 
);

share|improve this answer

answered yesterday

Jagdish PrabhuJagdish Prabhu

1

$.fn.countTo = function(options) ;

$.fn.countTo.defaults = 
 from: 0, // the number the element should start at
 to: 100, // the number the element should end at
 speed: 1000, // how long it should take to count between the target numbers
 refreshInterval: 100, // how often the element should be updated
 decimals: 0, // the number of decimal places to show
 onUpdate: null, // callback method for every time the element is updated,
 onComplete: null, // callback method for when the element finishes updating
;

var date = new Date("2019, 1, 1");
var seconds = date.getTime() / 1000; 

var prRatePerSec = 0.12;
var prPerYear = 4000000;
var prProducedTill = Math.round(seconds * prRatePerSec);

$('.timer').countTo(
 from: 0,
 to: prPerYear,
 speed: 31540000000,
 refreshInterval: 50,
 onComplete: function (value) 
 console.debug(this);
 
);

share|improve this answer

answered yesterday

Jagdish PrabhuJagdish Prabhu

1

answered yesterday

Jagdish PrabhuJagdish Prabhu

1

answered yesterday

Jagdish PrabhuJagdish Prabhu

1

0

You can substract two date object with javascript.

So substract the current date with the start year date

Like

var second = diffCurrentYear() / 1000;
var day = second / 60 / 60 / 24;

console.log(day)

function diffCurrentYear() 
 var currentYear = new Date().getFullYear(),
 diff = (new Date()).getTime() - (new Date(currentYear + '-01-01')).getTime()
 return diff;

share|improve this answer

answered yesterday

R3tepR3tep

7,97682962

add a comment | 

0

You can substract two date object with javascript.

So substract the current date with the start year date

Like

var second = diffCurrentYear() / 1000;
var day = second / 60 / 60 / 24;

console.log(day)

function diffCurrentYear() 
 var currentYear = new Date().getFullYear(),
 diff = (new Date()).getTime() - (new Date(currentYear + '-01-01')).getTime()
 return diff;

share|improve this answer

answered yesterday

R3tepR3tep

7,97682962

add a comment | 

You can substract two date object with javascript.

So substract the current date with the start year date

Like

var second = diffCurrentYear() / 1000;
var day = second / 60 / 60 / 24;

console.log(day)

function diffCurrentYear() 
 var currentYear = new Date().getFullYear(),
 diff = (new Date()).getTime() - (new Date(currentYear + '-01-01')).getTime()
 return diff;

share|improve this answer

answered yesterday

R3tepR3tep

7,97682962

var second = diffCurrentYear() / 1000;
var day = second / 60 / 60 / 24;

console.log(day)

function diffCurrentYear() 
 var currentYear = new Date().getFullYear(),
 diff = (new Date()).getTime() - (new Date(currentYear + '-01-01')).getTime()
 return diff;

var second = diffCurrentYear() / 1000;
var day = second / 60 / 60 / 24;

console.log(day)

function diffCurrentYear() 
 var currentYear = new Date().getFullYear(),
 diff = (new Date()).getTime() - (new Date(currentYear + '-01-01')).getTime()
 return diff;

var second = diffCurrentYear() / 1000;
var day = second / 60 / 60 / 24;

console.log(day)

function diffCurrentYear() 
 var currentYear = new Date().getFullYear(),
 diff = (new Date()).getTime() - (new Date(currentYear + '-01-01')).getTime()
 return diff;

share|improve this answer

answered yesterday

R3tepR3tep

7,97682962

answered yesterday

R3tepR3tep

7,97682962

answered yesterday

R3tepR3tep

7,97682962