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Finding the pair number of a sum in java


Is Java “pass-by-reference” or “pass-by-value”?How do I efficiently iterate over each entry in a Java Map?Does a finally block always get executed in Java?What is the difference between public, protected, package-private and private in Java?How do I read / convert an InputStream into a String in Java?When to use LinkedList over ArrayList in Java?How do I generate random integers within a specific range in Java?How do I determine whether an array contains a particular value in Java?How do I convert a String to an int in Java?Creating a memory leak with Java






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0















public class Test 
public static void pair(int array[], int data)
for (int i = 0; i < array.length - 1; i++)
for (int j = i + 1; j < array.length; j++)
if (array[i] + array[j] == data)
System.out.println("Pair: " + i + " and " + j);
return;



System.out.println("Pair not found");



public class Main

public static void main(String[] args)

int[] num = 1,6,8,12,19;
Test.pair(num,20);




I am trying to create a pair of given sum for example, it would output from the middle numbers to outer numbers e.g. 8,12 and 1,19. But my current output is just 0 and 4










share|improve this question




























    0















    public class Test 
    public static void pair(int array[], int data)
    for (int i = 0; i < array.length - 1; i++)
    for (int j = i + 1; j < array.length; j++)
    if (array[i] + array[j] == data)
    System.out.println("Pair: " + i + " and " + j);
    return;



    System.out.println("Pair not found");



    public class Main

    public static void main(String[] args)

    int[] num = 1,6,8,12,19;
    Test.pair(num,20);




    I am trying to create a pair of given sum for example, it would output from the middle numbers to outer numbers e.g. 8,12 and 1,19. But my current output is just 0 and 4










    share|improve this question
























      0












      0








      0








      public class Test 
      public static void pair(int array[], int data)
      for (int i = 0; i < array.length - 1; i++)
      for (int j = i + 1; j < array.length; j++)
      if (array[i] + array[j] == data)
      System.out.println("Pair: " + i + " and " + j);
      return;



      System.out.println("Pair not found");



      public class Main

      public static void main(String[] args)

      int[] num = 1,6,8,12,19;
      Test.pair(num,20);




      I am trying to create a pair of given sum for example, it would output from the middle numbers to outer numbers e.g. 8,12 and 1,19. But my current output is just 0 and 4










      share|improve this question














      public class Test 
      public static void pair(int array[], int data)
      for (int i = 0; i < array.length - 1; i++)
      for (int j = i + 1; j < array.length; j++)
      if (array[i] + array[j] == data)
      System.out.println("Pair: " + i + " and " + j);
      return;



      System.out.println("Pair not found");



      public class Main

      public static void main(String[] args)

      int[] num = 1,6,8,12,19;
      Test.pair(num,20);




      I am trying to create a pair of given sum for example, it would output from the middle numbers to outer numbers e.g. 8,12 and 1,19. But my current output is just 0 and 4







      java sum






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked Mar 22 at 1:54









      davyJdavyJ

      102




      102






















          1 Answer
          1






          active

          oldest

          votes


















          0














          You are only outputting your loop variables i & j. You need to access the array at those positions:



          System.out.println("Pair: " + array[i] + " and " + array[j]);


          This will only print out 1 matching pair because of the return. If you need more, you'll need to remove that & use a variable to control whether or not the message gets printed.






          share|improve this answer

























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            1 Answer
            1






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes









            0














            You are only outputting your loop variables i & j. You need to access the array at those positions:



            System.out.println("Pair: " + array[i] + " and " + array[j]);


            This will only print out 1 matching pair because of the return. If you need more, you'll need to remove that & use a variable to control whether or not the message gets printed.






            share|improve this answer





























              0














              You are only outputting your loop variables i & j. You need to access the array at those positions:



              System.out.println("Pair: " + array[i] + " and " + array[j]);


              This will only print out 1 matching pair because of the return. If you need more, you'll need to remove that & use a variable to control whether or not the message gets printed.






              share|improve this answer



























                0












                0








                0







                You are only outputting your loop variables i & j. You need to access the array at those positions:



                System.out.println("Pair: " + array[i] + " and " + array[j]);


                This will only print out 1 matching pair because of the return. If you need more, you'll need to remove that & use a variable to control whether or not the message gets printed.






                share|improve this answer















                You are only outputting your loop variables i & j. You need to access the array at those positions:



                System.out.println("Pair: " + array[i] + " and " + array[j]);


                This will only print out 1 matching pair because of the return. If you need more, you'll need to remove that & use a variable to control whether or not the message gets printed.







                share|improve this answer














                share|improve this answer



                share|improve this answer








                edited Mar 22 at 2:00

























                answered Mar 22 at 1:57









                ItsPeteItsPete

                1,0301328




                1,0301328





























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