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Property '0' is missing in type


Compiler error in Typescript version 3 but not in version 2How to assign any[][] to typescript interfaceDetecting an undefined object propertyHow do I check if an object has a property in JavaScript?How can I merge properties of two JavaScript objects dynamically?How do I remove a property from a JavaScript object?Get the name of an object's typeSorting an array of JavaScript objects by propertySort array of objects by string property valueIterate through object propertiesCan't bind to 'ngModel' since it isn't a known property of 'input'Types of property X are incompatible






.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty height:90px;width:728px;box-sizing:border-box;








17















I have my interface like this



export interface Details 
Name: [
First: string;
Last: string;
];



I have a observable config variable



Configuration: KnockoutObservable<Details> = ko.observable<Details>();


and I would like to assign it a value in the constructor as follows -



config = 
Name: [
First: "ABC",
Last: "DEF"
,

First: "LMN",
Last: "XYZ"
]
;

this.Configuration(config);


and I am getting an error:




Types of property 'Name' is incompatible and property '0' is missing
in type.



Type ' First:string; Last:string; []' is not assignable to type '[
First: string; Last:string; ]'




I don't have control on changing the interface as it is being used elsewhere. What is the correct way to initialize this config variable ?



Thanks in advance.










share|improve this question






























    17















    I have my interface like this



    export interface Details 
    Name: [
    First: string;
    Last: string;
    ];



    I have a observable config variable



    Configuration: KnockoutObservable<Details> = ko.observable<Details>();


    and I would like to assign it a value in the constructor as follows -



    config = 
    Name: [
    First: "ABC",
    Last: "DEF"
    ,

    First: "LMN",
    Last: "XYZ"
    ]
    ;

    this.Configuration(config);


    and I am getting an error:




    Types of property 'Name' is incompatible and property '0' is missing
    in type.



    Type ' First:string; Last:string; []' is not assignable to type '[
    First: string; Last:string; ]'




    I don't have control on changing the interface as it is being used elsewhere. What is the correct way to initialize this config variable ?



    Thanks in advance.










    share|improve this question


























      17












      17








      17








      I have my interface like this



      export interface Details 
      Name: [
      First: string;
      Last: string;
      ];



      I have a observable config variable



      Configuration: KnockoutObservable<Details> = ko.observable<Details>();


      and I would like to assign it a value in the constructor as follows -



      config = 
      Name: [
      First: "ABC",
      Last: "DEF"
      ,

      First: "LMN",
      Last: "XYZ"
      ]
      ;

      this.Configuration(config);


      and I am getting an error:




      Types of property 'Name' is incompatible and property '0' is missing
      in type.



      Type ' First:string; Last:string; []' is not assignable to type '[
      First: string; Last:string; ]'




      I don't have control on changing the interface as it is being used elsewhere. What is the correct way to initialize this config variable ?



      Thanks in advance.










      share|improve this question
















      I have my interface like this



      export interface Details 
      Name: [
      First: string;
      Last: string;
      ];



      I have a observable config variable



      Configuration: KnockoutObservable<Details> = ko.observable<Details>();


      and I would like to assign it a value in the constructor as follows -



      config = 
      Name: [
      First: "ABC",
      Last: "DEF"
      ,

      First: "LMN",
      Last: "XYZ"
      ]
      ;

      this.Configuration(config);


      and I am getting an error:




      Types of property 'Name' is incompatible and property '0' is missing
      in type.



      Type ' First:string; Last:string; []' is not assignable to type '[
      First: string; Last:string; ]'




      I don't have control on changing the interface as it is being used elsewhere. What is the correct way to initialize this config variable ?



      Thanks in advance.







      javascript typescript knockout.js observable






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited Jun 9 '17 at 2:48









      Pablo Cesar Cordova Morales

      87031225




      87031225










      asked Jun 9 '17 at 1:00









      rktrkt

      3761318




      3761318






















          4 Answers
          4






          active

          oldest

          votes


















          16














          I came across the same issue and got around it by changing the interface to:



           interface Details 
          Name:
          First: string;
          Last: string;
          [];



          I know you may not want the interface changed but hope this helps for anyone that is in this situation.






          share|improve this answer























          • I want to kiss you! I fought this for so long without any answers. Thanks you so much!

            – Joseph Hamilton
            Mar 29 '18 at 1:39











          • Ha! I am glad this helped because I definitely found myself in the same boat some time ago.

            – RyanA91
            Mar 29 '18 at 14:43











          • Just in case it isn't obvious the solution here is to move the [] to immediately follow instead of being [ ]. This is a change in syntax with recent typescript version.

            – Simon_Weaver
            May 8 '18 at 18:39



















          8














          In this type definition:



          interface Details 
          Name: [
          First: string;
          Last: string;
          ];



          Name is not an array at compile-time. It's a tuple with one element. Tuples in Typescript are allowed to have extra elements, but they can't have missing elements. As a 1-tuple, Name is essentially an array which must have at least one element.



          However, in this value:



          const config = 
          Name: [
          First: "ABC",
          Last: "DEF"
          ,

          First: "LMN",
          Last: "XYZ"
          ]
          ;


          Since there is no explicit typing, the Name property here defaults to array type. Arrays can have any number of elements, including zero - which doesn't fit in a 1-tuple. Hence your error.



          Your error can be fixed by giving the compiler a hint that your literal is actually a tuple:



          const config: Details = Name: [..., ...] ;


          If you do need to be able to take in an array of names, you'll have to do some casting, maybe something like this:



          if (names.length > 0) 
          const config =
          Name: names as Details['Name']
          ;
          Configuration(config);



          (You could remove the if check if you can determine that the tuple was simply a mistake by whoever wrote the typings.)



          Tuples reference:
          https://www.typescriptlang.org/docs/handbook/basic-types.html






          share|improve this answer























          • great answer! just helped me out.

            – royse41
            Aug 11 '17 at 7:23


















          6














          Updating the interface to following should fix the issue :



           interface Details 
          Name: Array<
          First: string;
          Last: string;
          >;






          share|improve this answer


















          • 2





            Can you explain why this fixes the issue please?

            – CharliePrynn
            Apr 4 '18 at 14:03











          • I believe, [] in typescript refers to tuple type , Array<> is a closer representation of javascript arrays. That's my understanding .

            – Rajaram Nayak
            Apr 5 '18 at 13:51


















          1














          This error can come from incorrectly typing an array (like I just did):



          myArray:[]; //Incorrect, results in error message of `Property '0' is missing in type`

          myArray: Array<string>; //Correct

          myArray: string[]; //Also correct


          The reason is that braces denote a tuple in Typescript, not an array.



          The Docs






          share|improve this answer























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            4 Answers
            4






            active

            oldest

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            4 Answers
            4






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes









            16














            I came across the same issue and got around it by changing the interface to:



             interface Details 
            Name:
            First: string;
            Last: string;
            [];



            I know you may not want the interface changed but hope this helps for anyone that is in this situation.






            share|improve this answer























            • I want to kiss you! I fought this for so long without any answers. Thanks you so much!

              – Joseph Hamilton
              Mar 29 '18 at 1:39











            • Ha! I am glad this helped because I definitely found myself in the same boat some time ago.

              – RyanA91
              Mar 29 '18 at 14:43











            • Just in case it isn't obvious the solution here is to move the [] to immediately follow instead of being [ ]. This is a change in syntax with recent typescript version.

              – Simon_Weaver
              May 8 '18 at 18:39
















            16














            I came across the same issue and got around it by changing the interface to:



             interface Details 
            Name:
            First: string;
            Last: string;
            [];



            I know you may not want the interface changed but hope this helps for anyone that is in this situation.






            share|improve this answer























            • I want to kiss you! I fought this for so long without any answers. Thanks you so much!

              – Joseph Hamilton
              Mar 29 '18 at 1:39











            • Ha! I am glad this helped because I definitely found myself in the same boat some time ago.

              – RyanA91
              Mar 29 '18 at 14:43











            • Just in case it isn't obvious the solution here is to move the [] to immediately follow instead of being [ ]. This is a change in syntax with recent typescript version.

              – Simon_Weaver
              May 8 '18 at 18:39














            16












            16








            16







            I came across the same issue and got around it by changing the interface to:



             interface Details 
            Name:
            First: string;
            Last: string;
            [];



            I know you may not want the interface changed but hope this helps for anyone that is in this situation.






            share|improve this answer













            I came across the same issue and got around it by changing the interface to:



             interface Details 
            Name:
            First: string;
            Last: string;
            [];



            I know you may not want the interface changed but hope this helps for anyone that is in this situation.







            share|improve this answer












            share|improve this answer



            share|improve this answer










            answered Sep 26 '17 at 7:51









            RyanA91RyanA91

            22127




            22127












            • I want to kiss you! I fought this for so long without any answers. Thanks you so much!

              – Joseph Hamilton
              Mar 29 '18 at 1:39











            • Ha! I am glad this helped because I definitely found myself in the same boat some time ago.

              – RyanA91
              Mar 29 '18 at 14:43











            • Just in case it isn't obvious the solution here is to move the [] to immediately follow instead of being [ ]. This is a change in syntax with recent typescript version.

              – Simon_Weaver
              May 8 '18 at 18:39


















            • I want to kiss you! I fought this for so long without any answers. Thanks you so much!

              – Joseph Hamilton
              Mar 29 '18 at 1:39











            • Ha! I am glad this helped because I definitely found myself in the same boat some time ago.

              – RyanA91
              Mar 29 '18 at 14:43











            • Just in case it isn't obvious the solution here is to move the [] to immediately follow instead of being [ ]. This is a change in syntax with recent typescript version.

              – Simon_Weaver
              May 8 '18 at 18:39

















            I want to kiss you! I fought this for so long without any answers. Thanks you so much!

            – Joseph Hamilton
            Mar 29 '18 at 1:39





            I want to kiss you! I fought this for so long without any answers. Thanks you so much!

            – Joseph Hamilton
            Mar 29 '18 at 1:39













            Ha! I am glad this helped because I definitely found myself in the same boat some time ago.

            – RyanA91
            Mar 29 '18 at 14:43





            Ha! I am glad this helped because I definitely found myself in the same boat some time ago.

            – RyanA91
            Mar 29 '18 at 14:43













            Just in case it isn't obvious the solution here is to move the [] to immediately follow instead of being [ ]. This is a change in syntax with recent typescript version.

            – Simon_Weaver
            May 8 '18 at 18:39






            Just in case it isn't obvious the solution here is to move the [] to immediately follow instead of being [ ]. This is a change in syntax with recent typescript version.

            – Simon_Weaver
            May 8 '18 at 18:39














            8














            In this type definition:



            interface Details 
            Name: [
            First: string;
            Last: string;
            ];



            Name is not an array at compile-time. It's a tuple with one element. Tuples in Typescript are allowed to have extra elements, but they can't have missing elements. As a 1-tuple, Name is essentially an array which must have at least one element.



            However, in this value:



            const config = 
            Name: [
            First: "ABC",
            Last: "DEF"
            ,

            First: "LMN",
            Last: "XYZ"
            ]
            ;


            Since there is no explicit typing, the Name property here defaults to array type. Arrays can have any number of elements, including zero - which doesn't fit in a 1-tuple. Hence your error.



            Your error can be fixed by giving the compiler a hint that your literal is actually a tuple:



            const config: Details = Name: [..., ...] ;


            If you do need to be able to take in an array of names, you'll have to do some casting, maybe something like this:



            if (names.length > 0) 
            const config =
            Name: names as Details['Name']
            ;
            Configuration(config);



            (You could remove the if check if you can determine that the tuple was simply a mistake by whoever wrote the typings.)



            Tuples reference:
            https://www.typescriptlang.org/docs/handbook/basic-types.html






            share|improve this answer























            • great answer! just helped me out.

              – royse41
              Aug 11 '17 at 7:23















            8














            In this type definition:



            interface Details 
            Name: [
            First: string;
            Last: string;
            ];



            Name is not an array at compile-time. It's a tuple with one element. Tuples in Typescript are allowed to have extra elements, but they can't have missing elements. As a 1-tuple, Name is essentially an array which must have at least one element.



            However, in this value:



            const config = 
            Name: [
            First: "ABC",
            Last: "DEF"
            ,

            First: "LMN",
            Last: "XYZ"
            ]
            ;


            Since there is no explicit typing, the Name property here defaults to array type. Arrays can have any number of elements, including zero - which doesn't fit in a 1-tuple. Hence your error.



            Your error can be fixed by giving the compiler a hint that your literal is actually a tuple:



            const config: Details = Name: [..., ...] ;


            If you do need to be able to take in an array of names, you'll have to do some casting, maybe something like this:



            if (names.length > 0) 
            const config =
            Name: names as Details['Name']
            ;
            Configuration(config);



            (You could remove the if check if you can determine that the tuple was simply a mistake by whoever wrote the typings.)



            Tuples reference:
            https://www.typescriptlang.org/docs/handbook/basic-types.html






            share|improve this answer























            • great answer! just helped me out.

              – royse41
              Aug 11 '17 at 7:23













            8












            8








            8







            In this type definition:



            interface Details 
            Name: [
            First: string;
            Last: string;
            ];



            Name is not an array at compile-time. It's a tuple with one element. Tuples in Typescript are allowed to have extra elements, but they can't have missing elements. As a 1-tuple, Name is essentially an array which must have at least one element.



            However, in this value:



            const config = 
            Name: [
            First: "ABC",
            Last: "DEF"
            ,

            First: "LMN",
            Last: "XYZ"
            ]
            ;


            Since there is no explicit typing, the Name property here defaults to array type. Arrays can have any number of elements, including zero - which doesn't fit in a 1-tuple. Hence your error.



            Your error can be fixed by giving the compiler a hint that your literal is actually a tuple:



            const config: Details = Name: [..., ...] ;


            If you do need to be able to take in an array of names, you'll have to do some casting, maybe something like this:



            if (names.length > 0) 
            const config =
            Name: names as Details['Name']
            ;
            Configuration(config);



            (You could remove the if check if you can determine that the tuple was simply a mistake by whoever wrote the typings.)



            Tuples reference:
            https://www.typescriptlang.org/docs/handbook/basic-types.html






            share|improve this answer













            In this type definition:



            interface Details 
            Name: [
            First: string;
            Last: string;
            ];



            Name is not an array at compile-time. It's a tuple with one element. Tuples in Typescript are allowed to have extra elements, but they can't have missing elements. As a 1-tuple, Name is essentially an array which must have at least one element.



            However, in this value:



            const config = 
            Name: [
            First: "ABC",
            Last: "DEF"
            ,

            First: "LMN",
            Last: "XYZ"
            ]
            ;


            Since there is no explicit typing, the Name property here defaults to array type. Arrays can have any number of elements, including zero - which doesn't fit in a 1-tuple. Hence your error.



            Your error can be fixed by giving the compiler a hint that your literal is actually a tuple:



            const config: Details = Name: [..., ...] ;


            If you do need to be able to take in an array of names, you'll have to do some casting, maybe something like this:



            if (names.length > 0) 
            const config =
            Name: names as Details['Name']
            ;
            Configuration(config);



            (You could remove the if check if you can determine that the tuple was simply a mistake by whoever wrote the typings.)



            Tuples reference:
            https://www.typescriptlang.org/docs/handbook/basic-types.html







            share|improve this answer












            share|improve this answer



            share|improve this answer










            answered Jun 9 '17 at 5:29









            dbandstradbandstra

            1,05259




            1,05259












            • great answer! just helped me out.

              – royse41
              Aug 11 '17 at 7:23

















            • great answer! just helped me out.

              – royse41
              Aug 11 '17 at 7:23
















            great answer! just helped me out.

            – royse41
            Aug 11 '17 at 7:23





            great answer! just helped me out.

            – royse41
            Aug 11 '17 at 7:23











            6














            Updating the interface to following should fix the issue :



             interface Details 
            Name: Array<
            First: string;
            Last: string;
            >;






            share|improve this answer


















            • 2





              Can you explain why this fixes the issue please?

              – CharliePrynn
              Apr 4 '18 at 14:03











            • I believe, [] in typescript refers to tuple type , Array<> is a closer representation of javascript arrays. That's my understanding .

              – Rajaram Nayak
              Apr 5 '18 at 13:51















            6














            Updating the interface to following should fix the issue :



             interface Details 
            Name: Array<
            First: string;
            Last: string;
            >;






            share|improve this answer


















            • 2





              Can you explain why this fixes the issue please?

              – CharliePrynn
              Apr 4 '18 at 14:03











            • I believe, [] in typescript refers to tuple type , Array<> is a closer representation of javascript arrays. That's my understanding .

              – Rajaram Nayak
              Apr 5 '18 at 13:51













            6












            6








            6







            Updating the interface to following should fix the issue :



             interface Details 
            Name: Array<
            First: string;
            Last: string;
            >;






            share|improve this answer













            Updating the interface to following should fix the issue :



             interface Details 
            Name: Array<
            First: string;
            Last: string;
            >;







            share|improve this answer












            share|improve this answer



            share|improve this answer










            answered Apr 4 '18 at 14:00









            Rajaram NayakRajaram Nayak

            7413




            7413







            • 2





              Can you explain why this fixes the issue please?

              – CharliePrynn
              Apr 4 '18 at 14:03











            • I believe, [] in typescript refers to tuple type , Array<> is a closer representation of javascript arrays. That's my understanding .

              – Rajaram Nayak
              Apr 5 '18 at 13:51












            • 2





              Can you explain why this fixes the issue please?

              – CharliePrynn
              Apr 4 '18 at 14:03











            • I believe, [] in typescript refers to tuple type , Array<> is a closer representation of javascript arrays. That's my understanding .

              – Rajaram Nayak
              Apr 5 '18 at 13:51







            2




            2





            Can you explain why this fixes the issue please?

            – CharliePrynn
            Apr 4 '18 at 14:03





            Can you explain why this fixes the issue please?

            – CharliePrynn
            Apr 4 '18 at 14:03













            I believe, [] in typescript refers to tuple type , Array<> is a closer representation of javascript arrays. That's my understanding .

            – Rajaram Nayak
            Apr 5 '18 at 13:51





            I believe, [] in typescript refers to tuple type , Array<> is a closer representation of javascript arrays. That's my understanding .

            – Rajaram Nayak
            Apr 5 '18 at 13:51











            1














            This error can come from incorrectly typing an array (like I just did):



            myArray:[]; //Incorrect, results in error message of `Property '0' is missing in type`

            myArray: Array<string>; //Correct

            myArray: string[]; //Also correct


            The reason is that braces denote a tuple in Typescript, not an array.



            The Docs






            share|improve this answer



























              1














              This error can come from incorrectly typing an array (like I just did):



              myArray:[]; //Incorrect, results in error message of `Property '0' is missing in type`

              myArray: Array<string>; //Correct

              myArray: string[]; //Also correct


              The reason is that braces denote a tuple in Typescript, not an array.



              The Docs






              share|improve this answer

























                1












                1








                1







                This error can come from incorrectly typing an array (like I just did):



                myArray:[]; //Incorrect, results in error message of `Property '0' is missing in type`

                myArray: Array<string>; //Correct

                myArray: string[]; //Also correct


                The reason is that braces denote a tuple in Typescript, not an array.



                The Docs






                share|improve this answer













                This error can come from incorrectly typing an array (like I just did):



                myArray:[]; //Incorrect, results in error message of `Property '0' is missing in type`

                myArray: Array<string>; //Correct

                myArray: string[]; //Also correct


                The reason is that braces denote a tuple in Typescript, not an array.



                The Docs







                share|improve this answer












                share|improve this answer



                share|improve this answer










                answered Mar 22 at 1:44









                Greg GumGreg Gum

                11.7k1985136




                11.7k1985136



























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