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How to get the number of reservations for each customer for the below table
MySQL Error 1093 - Can't specify target table for update in FROM clauseCan I concatenate multiple MySQL rows into one field?How do I specify unique constraint for multiple columns in MySQL?How to get a list of MySQL user accountsHost 'xxx.xx.xxx.xxx' is not allowed to connect to this MySQL serverMySQL - Get row number on selectHow do I escape reserved words used as column names? MySQL/Create TableCreate a temporary table in a SELECT statement without a separate CREATE TABLEHow to get the sizes of the tables of a MySQL database?Reference - What does this error mean in PHP?
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty height:90px;width:728px;box-sizing:border-box;
I have two tables and i just want to know how to get the number of reservations for each customer for the below table.
Thank you for your support.
mysql
asked Mar 22 at 1:02
rook12320rook12320
85
add a comment |
I have two tables and i just want to know how to get the number of reservations for each customer for the below table.
Thank you for your support.
mysql
asked Mar 22 at 1:02
rook12320rook12320
85
2
What code have you tried? We are happy to help you troubleshoot, but we aren't a code writing service. We expect that you at least make an effort to answer the question yourself.
– Jane
Mar 22 at 1:03
add a comment |
I have two tables and i just want to know how to get the number of reservations for each customer for the below table.
Thank you for your support.
mysql
asked Mar 22 at 1:02
rook12320rook12320
85
I have two tables and i just want to know how to get the number of reservations for each customer for the below table.
Thank you for your support.
mysql
mysql
asked Mar 22 at 1:02
rook12320rook12320
85
asked Mar 22 at 1:02
rook12320rook12320
85
asked Mar 22 at 1:02
rook12320rook12320
85
asked Mar 22 at 1:02
rook12320rook12320
85
asked Mar 22 at 1:02
rook12320rook12320
85
85
2
What code have you tried? We are happy to help you troubleshoot, but we aren't a code writing service. We expect that you at least make an effort to answer the question yourself.
– Jane
Mar 22 at 1:03
add a comment |
2
What code have you tried? We are happy to help you troubleshoot, but we aren't a code writing service. We expect that you at least make an effort to answer the question yourself.
– Jane
Mar 22 at 1:03
2
2
What code have you tried? We are happy to help you troubleshoot, but we aren't a code writing service. We expect that you at least make an effort to answer the question yourself.
– Jane
Mar 22 at 1:03
What code have you tried? We are happy to help you troubleshoot, but we aren't a code writing service. We expect that you at least make an effort to answer the question yourself.
– Jane
Mar 22 at 1:03
add a comment |
1 Answer
1
active
oldest
votes
You could use a group by query:
select customer.customer_id from customer, count(customer.customer_id) as reservation_count
from customer
left join reservation on reservation.customer_customer_id = customer.customer_id
group by customer.customer_id
In this case a left join is used to include customers that don't have any reservations and should have a reservation_count of 0. Customers with reservations will have a reservation_count greater than 0.
answered Mar 22 at 1:07
jspcaljspcal
40.2k45264
Thank you for your collaboration I tried to use this but there is an error after as SELECT customer.customer_id FROM customer, COUNT * AS reservation_count LEFT JOIN reservation ON reservation.customer_customer_id = customer.customer_id GROUP BY customer.customer_id
– rook12320
Mar 22 at 1:16
I also tryed to remove the * after COUNT but doesn't work
– rook12320
Mar 22 at 1:19
Interesting, can you post the full error?
– jspcal
Mar 22 at 1:22
I tryed this code also BUT still also SELECT customer.customer_id FROM customer JOIN reservation, COUNT AS reservation_count LEFT JOIN reservation ON reservation.customer_customer_id = customer.customer_id WHERE reservation.customer_customer_id = customer.customer_id GROUP BY customer.customer_id here is the error #1066 - Not unique table/alias: 'reservation'
– rook12320
Mar 22 at 1:27
I think it should be reservation table because we need the total number of reservation for each customer. what is your advise
– rook12320
Mar 22 at 1:30
|
show 4 more comments
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1 Answer
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oldest
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1 Answer
1
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oldest
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oldest
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active
oldest
votes
You could use a group by query:
select customer.customer_id from customer, count(customer.customer_id) as reservation_count
from customer
left join reservation on reservation.customer_customer_id = customer.customer_id
group by customer.customer_id
In this case a left join is used to include customers that don't have any reservations and should have a reservation_count of 0. Customers with reservations will have a reservation_count greater than 0.
answered Mar 22 at 1:07
jspcaljspcal
40.2k45264
Thank you for your collaboration I tried to use this but there is an error after as SELECT customer.customer_id FROM customer, COUNT * AS reservation_count LEFT JOIN reservation ON reservation.customer_customer_id = customer.customer_id GROUP BY customer.customer_id
– rook12320
Mar 22 at 1:16
I also tryed to remove the * after COUNT but doesn't work
– rook12320
Mar 22 at 1:19
Interesting, can you post the full error?
– jspcal
Mar 22 at 1:22
I tryed this code also BUT still also SELECT customer.customer_id FROM customer JOIN reservation, COUNT AS reservation_count LEFT JOIN reservation ON reservation.customer_customer_id = customer.customer_id WHERE reservation.customer_customer_id = customer.customer_id GROUP BY customer.customer_id here is the error #1066 - Not unique table/alias: 'reservation'
– rook12320
Mar 22 at 1:27
I think it should be reservation table because we need the total number of reservation for each customer. what is your advise
– rook12320
Mar 22 at 1:30
|
show 4 more comments
You could use a group by query:
select customer.customer_id from customer, count(customer.customer_id) as reservation_count
from customer
left join reservation on reservation.customer_customer_id = customer.customer_id
group by customer.customer_id
In this case a left join is used to include customers that don't have any reservations and should have a reservation_count of 0. Customers with reservations will have a reservation_count greater than 0.
answered Mar 22 at 1:07
jspcaljspcal
40.2k45264
Thank you for your collaboration I tried to use this but there is an error after as SELECT customer.customer_id FROM customer, COUNT * AS reservation_count LEFT JOIN reservation ON reservation.customer_customer_id = customer.customer_id GROUP BY customer.customer_id
– rook12320
Mar 22 at 1:16
I also tryed to remove the * after COUNT but doesn't work
– rook12320
Mar 22 at 1:19
Interesting, can you post the full error?
– jspcal
Mar 22 at 1:22
I tryed this code also BUT still also SELECT customer.customer_id FROM customer JOIN reservation, COUNT AS reservation_count LEFT JOIN reservation ON reservation.customer_customer_id = customer.customer_id WHERE reservation.customer_customer_id = customer.customer_id GROUP BY customer.customer_id here is the error #1066 - Not unique table/alias: 'reservation'
– rook12320
Mar 22 at 1:27
I think it should be reservation table because we need the total number of reservation for each customer. what is your advise
– rook12320
Mar 22 at 1:30
|
show 4 more comments
You could use a group by query:
select customer.customer_id from customer, count(customer.customer_id) as reservation_count
from customer
left join reservation on reservation.customer_customer_id = customer.customer_id
group by customer.customer_id
In this case a left join is used to include customers that don't have any reservations and should have a reservation_count of 0. Customers with reservations will have a reservation_count greater than 0.
answered Mar 22 at 1:07
jspcaljspcal
40.2k45264
You could use a group by query:
select customer.customer_id from customer, count(customer.customer_id) as reservation_count
from customer
left join reservation on reservation.customer_customer_id = customer.customer_id
group by customer.customer_id
In this case a left join is used to include customers that don't have any reservations and should have a reservation_count of 0. Customers with reservations will have a reservation_count greater than 0.
answered Mar 22 at 1:07
jspcaljspcal
40.2k45264
edited Mar 22 at 1:22
answered Mar 22 at 1:07
jspcaljspcal
40.2k45264
answered Mar 22 at 1:07
jspcaljspcal
40.2k45264
answered Mar 22 at 1:07
jspcaljspcal
40.2k45264
40.2k45264
Thank you for your collaboration I tried to use this but there is an error after as SELECT customer.customer_id FROM customer, COUNT * AS reservation_count LEFT JOIN reservation ON reservation.customer_customer_id = customer.customer_id GROUP BY customer.customer_id
– rook12320
Mar 22 at 1:16
I also tryed to remove the * after COUNT but doesn't work
– rook12320
Mar 22 at 1:19
Interesting, can you post the full error?
– jspcal
Mar 22 at 1:22
I tryed this code also BUT still also SELECT customer.customer_id FROM customer JOIN reservation, COUNT AS reservation_count LEFT JOIN reservation ON reservation.customer_customer_id = customer.customer_id WHERE reservation.customer_customer_id = customer.customer_id GROUP BY customer.customer_id here is the error #1066 - Not unique table/alias: 'reservation'
– rook12320
Mar 22 at 1:27
I think it should be reservation table because we need the total number of reservation for each customer. what is your advise
– rook12320
Mar 22 at 1:30
|
show 4 more comments
Thank you for your collaboration I tried to use this but there is an error after as SELECT customer.customer_id FROM customer, COUNT * AS reservation_count LEFT JOIN reservation ON reservation.customer_customer_id = customer.customer_id GROUP BY customer.customer_id
– rook12320
Mar 22 at 1:16
I also tryed to remove the * after COUNT but doesn't work
– rook12320
Mar 22 at 1:19
Interesting, can you post the full error?
– jspcal
Mar 22 at 1:22
I tryed this code also BUT still also SELECT customer.customer_id FROM customer JOIN reservation, COUNT AS reservation_count LEFT JOIN reservation ON reservation.customer_customer_id = customer.customer_id WHERE reservation.customer_customer_id = customer.customer_id GROUP BY customer.customer_id here is the error #1066 - Not unique table/alias: 'reservation'
– rook12320
Mar 22 at 1:27
I think it should be reservation table because we need the total number of reservation for each customer. what is your advise
– rook12320
Mar 22 at 1:30
Thank you for your collaboration I tried to use this but there is an error after as SELECT customer.customer_id FROM customer, COUNT * AS reservation_count LEFT JOIN reservation ON reservation.customer_customer_id = customer.customer_id GROUP BY customer.customer_id
– rook12320
Mar 22 at 1:16
Thank you for your collaboration I tried to use this but there is an error after as SELECT customer.customer_id FROM customer, COUNT * AS reservation_count LEFT JOIN reservation ON reservation.customer_customer_id = customer.customer_id GROUP BY customer.customer_id
– rook12320
Mar 22 at 1:16
I also tryed to remove the * after COUNT but doesn't work
– rook12320
Mar 22 at 1:19
I also tryed to remove the * after COUNT but doesn't work
– rook12320
Mar 22 at 1:19
Interesting, can you post the full error?
– jspcal
Mar 22 at 1:22
Interesting, can you post the full error?
– jspcal
Mar 22 at 1:22
I tryed this code also BUT still also SELECT customer.customer_id FROM customer JOIN reservation, COUNT AS reservation_count LEFT JOIN reservation ON reservation.customer_customer_id = customer.customer_id WHERE reservation.customer_customer_id = customer.customer_id GROUP BY customer.customer_id here is the error #1066 - Not unique table/alias: 'reservation'
– rook12320
Mar 22 at 1:27
I tryed this code also BUT still also SELECT customer.customer_id FROM customer JOIN reservation, COUNT AS reservation_count LEFT JOIN reservation ON reservation.customer_customer_id = customer.customer_id WHERE reservation.customer_customer_id = customer.customer_id GROUP BY customer.customer_id here is the error #1066 - Not unique table/alias: 'reservation'
– rook12320
Mar 22 at 1:27
I think it should be reservation table because we need the total number of reservation for each customer. what is your advise
– rook12320
Mar 22 at 1:30
I think it should be reservation table because we need the total number of reservation for each customer. what is your advise
– rook12320
Mar 22 at 1:30
|
show 4 more comments
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What code have you tried? We are happy to help you troubleshoot, but we aren't a code writing service. We expect that you at least make an effort to answer the question yourself.
– Jane
Mar 22 at 1:03