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Javascript return array from array of objects where property value matches

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0

Is there a built in Javascript function or library to do the following:

const data = [
 name: 'name1', type: 'type1' ,
 name: 'name2', type: 'type2' ,
 name: 'name3', type: 'type3' ,
 name: 'name4', type: 'type2' ,
];

To search the following and return all objects where type = 'type2'

Something similar to data.findIndex((i) => i.type === 'type2') but returns all matches rather than first index?

Thanks

javascript arrays

share|improve this question

asked Mar 22 at 16:49

ArthurArthur

64721026

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Possible duplicate of Javascript: How to filter object array based on attributes?
  
  – Jibin Joseph
  Mar 22 at 16:53
  

  
  
  
  

add a comment | 

0

Is there a built in Javascript function or library to do the following:

const data = [
 name: 'name1', type: 'type1' ,
 name: 'name2', type: 'type2' ,
 name: 'name3', type: 'type3' ,
 name: 'name4', type: 'type2' ,
];

To search the following and return all objects where type = 'type2'

Something similar to data.findIndex((i) => i.type === 'type2') but returns all matches rather than first index?

Thanks

javascript arrays

share|improve this question

asked Mar 22 at 16:49

ArthurArthur

64721026

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Possible duplicate of Javascript: How to filter object array based on attributes?
  
  – Jibin Joseph
  Mar 22 at 16:53
  

  
  
  
  

add a comment | 

Is there a built in Javascript function or library to do the following:

const data = [
 name: 'name1', type: 'type1' ,
 name: 'name2', type: 'type2' ,
 name: 'name3', type: 'type3' ,
 name: 'name4', type: 'type2' ,
];

To search the following and return all objects where type = 'type2'

Something similar to data.findIndex((i) => i.type === 'type2') but returns all matches rather than first index?

Thanks

javascript arrays

share|improve this question

asked Mar 22 at 16:49

ArthurArthur

64721026

const data = [
 name: 'name1', type: 'type1' ,
 name: 'name2', type: 'type2' ,
 name: 'name3', type: 'type3' ,
 name: 'name4', type: 'type2' ,
];

share|improve this question

asked Mar 22 at 16:49

ArthurArthur

64721026

share|improve this question

asked Mar 22 at 16:49

ArthurArthur

64721026

asked Mar 22 at 16:49

ArthurArthur

64721026

asked Mar 22 at 16:49

ArthurArthur

64721026

2 Answers
2

active

oldest

votes

9

You are looking for Array.filter():

The filter() method creates a new array with all elements that pass
the test implemented by the provided function.

Example:

const data = [
 name: 'name1', type: 'type1' ,
 name: 'name2', type: 'type2' ,
 name: 'name3', type: 'type3' ,
 name: 'name4', type: 'type2' ,
]

const result = data.filter(o => o.type === 'type2')

console.log(result)

share|improve this answer

answered Mar 22 at 16:50

Ori DroriOri Drori

83.4k159099

add a comment | 

1

You can use filter()

const data = [
 name: 'name1', type: 'type1' ,
 name: 'name2', type: 'type2' ,
 name: 'name3', type: 'type3' ,
 name: 'name4', type: 'type2' ,
];
let res = data.filter((type) => type === "type2");
console.log(res)

share|improve this answer

answered Mar 22 at 16:50

Maheer AliMaheer Ali

12.9k1330

add a comment | 

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9

You are looking for Array.filter():

The filter() method creates a new array with all elements that pass
the test implemented by the provided function.

Example:

const data = [
 name: 'name1', type: 'type1' ,
 name: 'name2', type: 'type2' ,
 name: 'name3', type: 'type3' ,
 name: 'name4', type: 'type2' ,
]

const result = data.filter(o => o.type === 'type2')

console.log(result)

share|improve this answer

answered Mar 22 at 16:50

Ori DroriOri Drori

83.4k159099

add a comment | 

9

You are looking for Array.filter():

The filter() method creates a new array with all elements that pass
the test implemented by the provided function.

Example:

const data = [
 name: 'name1', type: 'type1' ,
 name: 'name2', type: 'type2' ,
 name: 'name3', type: 'type3' ,
 name: 'name4', type: 'type2' ,
]

const result = data.filter(o => o.type === 'type2')

console.log(result)

share|improve this answer

answered Mar 22 at 16:50

Ori DroriOri Drori

83.4k159099

add a comment | 

You are looking for Array.filter():

The filter() method creates a new array with all elements that pass
the test implemented by the provided function.

Example:

const data = [
 name: 'name1', type: 'type1' ,
 name: 'name2', type: 'type2' ,
 name: 'name3', type: 'type3' ,
 name: 'name4', type: 'type2' ,
]

const result = data.filter(o => o.type === 'type2')

console.log(result)

share|improve this answer

answered Mar 22 at 16:50

Ori DroriOri Drori

83.4k159099

const data = [
 name: 'name1', type: 'type1' ,
 name: 'name2', type: 'type2' ,
 name: 'name3', type: 'type3' ,
 name: 'name4', type: 'type2' ,
]

const result = data.filter(o => o.type === 'type2')

console.log(result)

const data = [
 name: 'name1', type: 'type1' ,
 name: 'name2', type: 'type2' ,
 name: 'name3', type: 'type3' ,
 name: 'name4', type: 'type2' ,
]

const result = data.filter(o => o.type === 'type2')

console.log(result)

const data = [
 name: 'name1', type: 'type1' ,
 name: 'name2', type: 'type2' ,
 name: 'name3', type: 'type3' ,
 name: 'name4', type: 'type2' ,
]

const result = data.filter(o => o.type === 'type2')

console.log(result)

share|improve this answer

answered Mar 22 at 16:50

Ori DroriOri Drori

83.4k159099

answered Mar 22 at 16:50

Ori DroriOri Drori

83.4k159099

answered Mar 22 at 16:50

Ori DroriOri Drori

83.4k159099

1

You can use filter()

const data = [
 name: 'name1', type: 'type1' ,
 name: 'name2', type: 'type2' ,
 name: 'name3', type: 'type3' ,
 name: 'name4', type: 'type2' ,
];
let res = data.filter((type) => type === "type2");
console.log(res)

share|improve this answer

answered Mar 22 at 16:50

Maheer AliMaheer Ali

12.9k1330

add a comment | 

1

You can use filter()

const data = [
 name: 'name1', type: 'type1' ,
 name: 'name2', type: 'type2' ,
 name: 'name3', type: 'type3' ,
 name: 'name4', type: 'type2' ,
];
let res = data.filter((type) => type === "type2");
console.log(res)

share|improve this answer

answered Mar 22 at 16:50

Maheer AliMaheer Ali

12.9k1330

add a comment | 

You can use filter()

const data = [
 name: 'name1', type: 'type1' ,
 name: 'name2', type: 'type2' ,
 name: 'name3', type: 'type3' ,
 name: 'name4', type: 'type2' ,
];
let res = data.filter((type) => type === "type2");
console.log(res)

share|improve this answer

answered Mar 22 at 16:50

Maheer AliMaheer Ali

12.9k1330

const data = [
 name: 'name1', type: 'type1' ,
 name: 'name2', type: 'type2' ,
 name: 'name3', type: 'type3' ,
 name: 'name4', type: 'type2' ,
];
let res = data.filter((type) => type === "type2");
console.log(res)

const data = [
 name: 'name1', type: 'type1' ,
 name: 'name2', type: 'type2' ,
 name: 'name3', type: 'type3' ,
 name: 'name4', type: 'type2' ,
];
let res = data.filter((type) => type === "type2");
console.log(res)

const data = [
 name: 'name1', type: 'type1' ,
 name: 'name2', type: 'type2' ,
 name: 'name3', type: 'type3' ,
 name: 'name4', type: 'type2' ,
];
let res = data.filter((type) => type === "type2");
console.log(res)

share|improve this answer

answered Mar 22 at 16:50

Maheer AliMaheer Ali

12.9k1330

answered Mar 22 at 16:50

Maheer AliMaheer Ali

12.9k1330

answered Mar 22 at 16:50

Maheer AliMaheer Ali

12.9k1330