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How can I get the points between two points on a line?


Collision detection with complex shapesPrecise subpixel line drawing algorithm (rasterization algorithm)How to deal with “java.lang.OutOfMemoryError: Java heap space” error?How can I concatenate two arrays in Java?How can I determine whether a 2D Point is within a Polygon?Fastest way to determine if an integer's square root is an integerHow can I create an executable JAR with dependencies using Maven?How to get an enum value from a string value in Java?How can I convert a stack trace to a string?Can't start Eclipse - Java was started but returned exit code=13how to bypass calling of parent class paint methodExtending Graphics class with drawLine(double, double, double, double)






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-1















How can I get the points between a start point (x1, y1) and end point (x2, y2) on a line. I need these points to check if it's located in free space or on an obstacle. How can I do this in Java?



 public void paint(Graphics g) 
super.paint(g);
g.drawLine(50, 50, 400, 400);




Is there an existing function that can help me get these points?










share|improve this question



















  • 4





    That's not how you detect collision(there are theoretically infinitely many points). You should use some analytical function to compare the line with obstacle. You should probably add more context.

    – NeplatnyUdaj
    Mar 22 at 16:51












  • Regardless of collision i need to get points of the line

    – zoya
    Mar 22 at 16:55







  • 1





    It is better to use geometry to find out the intersection of your line with various obstacles. If you must get points, you can get points on the line with the formula t*(end - start) + start where t is a number between 0 and 1 representing how far along the line the point is. For half way down your line: x = 0.5 * (400 - 50) + 50 and y = 0.5 * (400 - 50) + 50

    – aptriangle
    Mar 22 at 16:58











  • Well, the API won't give them but you can calculate those pixels with Bresenham algorithm.

    – Arnaud Denoyelle
    Mar 22 at 16:58












  • In short, calculate the slope : if the line is "more horizontal", iterate on x values and find the corresponding y values. If the line is "more vertical", iterate on y values and find the corresponding x values.

    – Arnaud Denoyelle
    Mar 22 at 17:03

















-1















How can I get the points between a start point (x1, y1) and end point (x2, y2) on a line. I need these points to check if it's located in free space or on an obstacle. How can I do this in Java?



 public void paint(Graphics g) 
super.paint(g);
g.drawLine(50, 50, 400, 400);




Is there an existing function that can help me get these points?










share|improve this question



















  • 4





    That's not how you detect collision(there are theoretically infinitely many points). You should use some analytical function to compare the line with obstacle. You should probably add more context.

    – NeplatnyUdaj
    Mar 22 at 16:51












  • Regardless of collision i need to get points of the line

    – zoya
    Mar 22 at 16:55







  • 1





    It is better to use geometry to find out the intersection of your line with various obstacles. If you must get points, you can get points on the line with the formula t*(end - start) + start where t is a number between 0 and 1 representing how far along the line the point is. For half way down your line: x = 0.5 * (400 - 50) + 50 and y = 0.5 * (400 - 50) + 50

    – aptriangle
    Mar 22 at 16:58











  • Well, the API won't give them but you can calculate those pixels with Bresenham algorithm.

    – Arnaud Denoyelle
    Mar 22 at 16:58












  • In short, calculate the slope : if the line is "more horizontal", iterate on x values and find the corresponding y values. If the line is "more vertical", iterate on y values and find the corresponding x values.

    – Arnaud Denoyelle
    Mar 22 at 17:03













-1












-1








-1








How can I get the points between a start point (x1, y1) and end point (x2, y2) on a line. I need these points to check if it's located in free space or on an obstacle. How can I do this in Java?



 public void paint(Graphics g) 
super.paint(g);
g.drawLine(50, 50, 400, 400);




Is there an existing function that can help me get these points?










share|improve this question
















How can I get the points between a start point (x1, y1) and end point (x2, y2) on a line. I need these points to check if it's located in free space or on an obstacle. How can I do this in Java?



 public void paint(Graphics g) 
super.paint(g);
g.drawLine(50, 50, 400, 400);




Is there an existing function that can help me get these points?







java graphics awt drawing java-2d






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Mar 23 at 2:25









Andrew Thompson

154k29166352




154k29166352










asked Mar 22 at 16:44









zoyazoya

11




11







  • 4





    That's not how you detect collision(there are theoretically infinitely many points). You should use some analytical function to compare the line with obstacle. You should probably add more context.

    – NeplatnyUdaj
    Mar 22 at 16:51












  • Regardless of collision i need to get points of the line

    – zoya
    Mar 22 at 16:55







  • 1





    It is better to use geometry to find out the intersection of your line with various obstacles. If you must get points, you can get points on the line with the formula t*(end - start) + start where t is a number between 0 and 1 representing how far along the line the point is. For half way down your line: x = 0.5 * (400 - 50) + 50 and y = 0.5 * (400 - 50) + 50

    – aptriangle
    Mar 22 at 16:58











  • Well, the API won't give them but you can calculate those pixels with Bresenham algorithm.

    – Arnaud Denoyelle
    Mar 22 at 16:58












  • In short, calculate the slope : if the line is "more horizontal", iterate on x values and find the corresponding y values. If the line is "more vertical", iterate on y values and find the corresponding x values.

    – Arnaud Denoyelle
    Mar 22 at 17:03












  • 4





    That's not how you detect collision(there are theoretically infinitely many points). You should use some analytical function to compare the line with obstacle. You should probably add more context.

    – NeplatnyUdaj
    Mar 22 at 16:51












  • Regardless of collision i need to get points of the line

    – zoya
    Mar 22 at 16:55







  • 1





    It is better to use geometry to find out the intersection of your line with various obstacles. If you must get points, you can get points on the line with the formula t*(end - start) + start where t is a number between 0 and 1 representing how far along the line the point is. For half way down your line: x = 0.5 * (400 - 50) + 50 and y = 0.5 * (400 - 50) + 50

    – aptriangle
    Mar 22 at 16:58











  • Well, the API won't give them but you can calculate those pixels with Bresenham algorithm.

    – Arnaud Denoyelle
    Mar 22 at 16:58












  • In short, calculate the slope : if the line is "more horizontal", iterate on x values and find the corresponding y values. If the line is "more vertical", iterate on y values and find the corresponding x values.

    – Arnaud Denoyelle
    Mar 22 at 17:03







4




4





That's not how you detect collision(there are theoretically infinitely many points). You should use some analytical function to compare the line with obstacle. You should probably add more context.

– NeplatnyUdaj
Mar 22 at 16:51






That's not how you detect collision(there are theoretically infinitely many points). You should use some analytical function to compare the line with obstacle. You should probably add more context.

– NeplatnyUdaj
Mar 22 at 16:51














Regardless of collision i need to get points of the line

– zoya
Mar 22 at 16:55






Regardless of collision i need to get points of the line

– zoya
Mar 22 at 16:55





1




1





It is better to use geometry to find out the intersection of your line with various obstacles. If you must get points, you can get points on the line with the formula t*(end - start) + start where t is a number between 0 and 1 representing how far along the line the point is. For half way down your line: x = 0.5 * (400 - 50) + 50 and y = 0.5 * (400 - 50) + 50

– aptriangle
Mar 22 at 16:58





It is better to use geometry to find out the intersection of your line with various obstacles. If you must get points, you can get points on the line with the formula t*(end - start) + start where t is a number between 0 and 1 representing how far along the line the point is. For half way down your line: x = 0.5 * (400 - 50) + 50 and y = 0.5 * (400 - 50) + 50

– aptriangle
Mar 22 at 16:58













Well, the API won't give them but you can calculate those pixels with Bresenham algorithm.

– Arnaud Denoyelle
Mar 22 at 16:58






Well, the API won't give them but you can calculate those pixels with Bresenham algorithm.

– Arnaud Denoyelle
Mar 22 at 16:58














In short, calculate the slope : if the line is "more horizontal", iterate on x values and find the corresponding y values. If the line is "more vertical", iterate on y values and find the corresponding x values.

– Arnaud Denoyelle
Mar 22 at 17:03





In short, calculate the slope : if the line is "more horizontal", iterate on x values and find the corresponding y values. If the line is "more vertical", iterate on y values and find the corresponding x values.

– Arnaud Denoyelle
Mar 22 at 17:03












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