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Receiving updated value from recursive call



Announcing the arrival of Valued Associate #679: Cesar Manara
Planned maintenance scheduled April 23, 2019 at 23:30 UTC (7:30pm US/Eastern)
Data science time! April 2019 and salary with experience
The Ask Question Wizard is Live!What is tail recursion?Recursion or Iteration?Way to go from recursion to iterationCan I call a constructor from another constructor (do constructor chaining) in C++?What Is Tail Call Optimization?Understanding recursionWhy is reading lines from stdin much slower in C++ than Python?How to pair socks from a pile efficiently?A more haskellian way to write this recursion?How to properly use a function that is recursive and receives a single argument?



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0















I have a DFS function which collects entry and leave times of vertices. Unfortunately, I am unable to receive a proper value for leave time, because it is not connected with the value from recursive call.



void DFS_visit(int i, vector<int> Adj[], int visited[], int p[], int entry[], int leave[], int t)

visited[i] = 1;
entry[i] = t;
cout << i << " ";
for (auto u : Adj[i])

if (!visited[u])

p[u] = i;
DFS_visit(u, Adj, visited, p, entry, leave, t++);


leave[i] = t++;



It is obviously an auxiliary function, I also have a "main" DFS function:



void DFS(vector<int> Adj[], int n)
{
int visited[n], p[n], entry[n], leave[n];
int t = 0;

for (int i = 0; i < n; i++)

visited[i] = 0;
p[i] = -1;


for (int i = 0; i < n; i++)

if (!visited[i])

DFS_visit(i, Adj, visited, p, entry, leave, t);




Could you please tell me how I am supposed to pass the updated value of leave time to leave[i]? Thanks in advance!










share|improve this question

















  • 4





    pass t by reference

    – yassin
    Mar 22 at 15:04







  • 1





    or make it a return value (t = DFS_visit(u, Adj, visited, p, entry, leave, t + 1);).

    – Dan M.
    Mar 22 at 15:05


















0















I have a DFS function which collects entry and leave times of vertices. Unfortunately, I am unable to receive a proper value for leave time, because it is not connected with the value from recursive call.



void DFS_visit(int i, vector<int> Adj[], int visited[], int p[], int entry[], int leave[], int t)

visited[i] = 1;
entry[i] = t;
cout << i << " ";
for (auto u : Adj[i])

if (!visited[u])

p[u] = i;
DFS_visit(u, Adj, visited, p, entry, leave, t++);


leave[i] = t++;



It is obviously an auxiliary function, I also have a "main" DFS function:



void DFS(vector<int> Adj[], int n)
{
int visited[n], p[n], entry[n], leave[n];
int t = 0;

for (int i = 0; i < n; i++)

visited[i] = 0;
p[i] = -1;


for (int i = 0; i < n; i++)

if (!visited[i])

DFS_visit(i, Adj, visited, p, entry, leave, t);




Could you please tell me how I am supposed to pass the updated value of leave time to leave[i]? Thanks in advance!










share|improve this question

















  • 4





    pass t by reference

    – yassin
    Mar 22 at 15:04







  • 1





    or make it a return value (t = DFS_visit(u, Adj, visited, p, entry, leave, t + 1);).

    – Dan M.
    Mar 22 at 15:05














0












0








0








I have a DFS function which collects entry and leave times of vertices. Unfortunately, I am unable to receive a proper value for leave time, because it is not connected with the value from recursive call.



void DFS_visit(int i, vector<int> Adj[], int visited[], int p[], int entry[], int leave[], int t)

visited[i] = 1;
entry[i] = t;
cout << i << " ";
for (auto u : Adj[i])

if (!visited[u])

p[u] = i;
DFS_visit(u, Adj, visited, p, entry, leave, t++);


leave[i] = t++;



It is obviously an auxiliary function, I also have a "main" DFS function:



void DFS(vector<int> Adj[], int n)
{
int visited[n], p[n], entry[n], leave[n];
int t = 0;

for (int i = 0; i < n; i++)

visited[i] = 0;
p[i] = -1;


for (int i = 0; i < n; i++)

if (!visited[i])

DFS_visit(i, Adj, visited, p, entry, leave, t);




Could you please tell me how I am supposed to pass the updated value of leave time to leave[i]? Thanks in advance!










share|improve this question














I have a DFS function which collects entry and leave times of vertices. Unfortunately, I am unable to receive a proper value for leave time, because it is not connected with the value from recursive call.



void DFS_visit(int i, vector<int> Adj[], int visited[], int p[], int entry[], int leave[], int t)

visited[i] = 1;
entry[i] = t;
cout << i << " ";
for (auto u : Adj[i])

if (!visited[u])

p[u] = i;
DFS_visit(u, Adj, visited, p, entry, leave, t++);


leave[i] = t++;



It is obviously an auxiliary function, I also have a "main" DFS function:



void DFS(vector<int> Adj[], int n)
{
int visited[n], p[n], entry[n], leave[n];
int t = 0;

for (int i = 0; i < n; i++)

visited[i] = 0;
p[i] = -1;


for (int i = 0; i < n; i++)

if (!visited[i])

DFS_visit(i, Adj, visited, p, entry, leave, t);




Could you please tell me how I am supposed to pass the updated value of leave time to leave[i]? Thanks in advance!







c++ algorithm recursion






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Mar 22 at 14:59









imalgrabimalgrab

33




33







  • 4





    pass t by reference

    – yassin
    Mar 22 at 15:04







  • 1





    or make it a return value (t = DFS_visit(u, Adj, visited, p, entry, leave, t + 1);).

    – Dan M.
    Mar 22 at 15:05













  • 4





    pass t by reference

    – yassin
    Mar 22 at 15:04







  • 1





    or make it a return value (t = DFS_visit(u, Adj, visited, p, entry, leave, t + 1);).

    – Dan M.
    Mar 22 at 15:05








4




4





pass t by reference

– yassin
Mar 22 at 15:04






pass t by reference

– yassin
Mar 22 at 15:04





1




1





or make it a return value (t = DFS_visit(u, Adj, visited, p, entry, leave, t + 1);).

– Dan M.
Mar 22 at 15:05






or make it a return value (t = DFS_visit(u, Adj, visited, p, entry, leave, t + 1);).

– Dan M.
Mar 22 at 15:05













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