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Unparseable Date in android, pattern character 'T'

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0

Is there any way I can remove characters from an EditText brought from a JSONObject response? Example: 2019-03-06T00:00:00 and only present the chain in this way: 2019-02-10, when making the conversion I throw an exception which is:

 java.lang.IllegalArgumentException: Illegal pattern character 'T'

Code:

 String yourJsonDateString = jsonResponse.getString(DataManager.Birthdate);
 try 
 Date yourJsonDate = new SimpleDateFormat("yyyy-MM-dd'T'hh:mm:ss.SSS").parse(yourJsonDateString);
 String newDateString = new SimpleDateFormat("yyyy-MM-dd").format(yourJsonDate);
 System.out.println(newDateString);
 catch (ParseException e) 
 e.printStackTrace();
 

java android simpledateformat date-parsing datetime-parsing

share|improve this question

edited Mar 23 at 9:49

Ole V.V.

32.5k74258

asked Mar 22 at 1:41

Gregorio TancitaroGregorio Tancitaro

254

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  What are you using to parse the Json string? What you are receiving is a Date from the Json perspective not a String.
  
  – Juan
  Mar 22 at 1:52
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  Check this answer out
  
  – StaticBeagle
  Mar 22 at 1:53
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  From the json get this string. "2019-03-06T00:00:00"
  
  – Gregorio Tancitaro
  Mar 22 at 14:44
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  As an aside consider throwing away the long outmoded and notoriously troublesome SimpleDateFormat and friends, and adding ThreeTenABP to your Android project in order to use java.time, the modern Java date and time API. It is so much nicer to work with.
  
  – Ole V.V.
  Mar 23 at 9:48
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  Nice link, @StaticBeagle, thanks. This one may match even a bit better.
  
  – Ole V.V.
  Mar 23 at 9:52
  

  
  
  
  

 | 
show 1 more comment

0

Is there any way I can remove characters from an EditText brought from a JSONObject response? Example: 2019-03-06T00:00:00 and only present the chain in this way: 2019-02-10, when making the conversion I throw an exception which is:

 java.lang.IllegalArgumentException: Illegal pattern character 'T'

Code:

 String yourJsonDateString = jsonResponse.getString(DataManager.Birthdate);
 try 
 Date yourJsonDate = new SimpleDateFormat("yyyy-MM-dd'T'hh:mm:ss.SSS").parse(yourJsonDateString);
 String newDateString = new SimpleDateFormat("yyyy-MM-dd").format(yourJsonDate);
 System.out.println(newDateString);
 catch (ParseException e) 
 e.printStackTrace();
 

java android simpledateformat date-parsing datetime-parsing

share|improve this question

edited Mar 23 at 9:49

Ole V.V.

32.5k74258

asked Mar 22 at 1:41

Gregorio TancitaroGregorio Tancitaro

254

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  What are you using to parse the Json string? What you are receiving is a Date from the Json perspective not a String.
  
  – Juan
  Mar 22 at 1:52
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  Check this answer out
  
  – StaticBeagle
  Mar 22 at 1:53
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  From the json get this string. "2019-03-06T00:00:00"
  
  – Gregorio Tancitaro
  Mar 22 at 14:44
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  As an aside consider throwing away the long outmoded and notoriously troublesome SimpleDateFormat and friends, and adding ThreeTenABP to your Android project in order to use java.time, the modern Java date and time API. It is so much nicer to work with.
  
  – Ole V.V.
  Mar 23 at 9:48
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  Nice link, @StaticBeagle, thanks. This one may match even a bit better.
  
  – Ole V.V.
  Mar 23 at 9:52
  

  
  
  
  

 | 
show 1 more comment

Is there any way I can remove characters from an EditText brought from a JSONObject response? Example: 2019-03-06T00:00:00 and only present the chain in this way: 2019-02-10, when making the conversion I throw an exception which is:

 java.lang.IllegalArgumentException: Illegal pattern character 'T'

Code:

 String yourJsonDateString = jsonResponse.getString(DataManager.Birthdate);
 try 
 Date yourJsonDate = new SimpleDateFormat("yyyy-MM-dd'T'hh:mm:ss.SSS").parse(yourJsonDateString);
 String newDateString = new SimpleDateFormat("yyyy-MM-dd").format(yourJsonDate);
 System.out.println(newDateString);
 catch (ParseException e) 
 e.printStackTrace();
 

java android simpledateformat date-parsing datetime-parsing

share|improve this question

edited Mar 23 at 9:49

Ole V.V.

32.5k74258

asked Mar 22 at 1:41

Gregorio TancitaroGregorio Tancitaro

254

 java.lang.IllegalArgumentException: Illegal pattern character 'T'

 String yourJsonDateString = jsonResponse.getString(DataManager.Birthdate);
 try 
 Date yourJsonDate = new SimpleDateFormat("yyyy-MM-dd'T'hh:mm:ss.SSS").parse(yourJsonDateString);
 String newDateString = new SimpleDateFormat("yyyy-MM-dd").format(yourJsonDate);
 System.out.println(newDateString);
 catch (ParseException e) 
 e.printStackTrace();
 

java android simpledateformat date-parsing datetime-parsing

java android simpledateformat date-parsing datetime-parsing

share|improve this question

edited Mar 23 at 9:49

Ole V.V.

32.5k74258

asked Mar 22 at 1:41

Gregorio TancitaroGregorio Tancitaro

254

share|improve this question

edited Mar 23 at 9:49

Ole V.V.

32.5k74258

asked Mar 22 at 1:41

Gregorio TancitaroGregorio Tancitaro

254

edited Mar 23 at 9:49

Ole V.V.

32.5k74258

edited Mar 23 at 9:49

Ole V.V.

32.5k74258

asked Mar 22 at 1:41

Gregorio TancitaroGregorio Tancitaro

254

asked Mar 22 at 1:41

Gregorio TancitaroGregorio Tancitaro

254

1 Answer
1

active

oldest

votes

0

To simply 2019-03-06T00:00:00 into 2019-03-06 you can try this.

String dt = dateString.substring(0, 10)

if you use <1000 year dates, or even BCE format. you can use this

String dt = dateString.substring(0, dateString.indexOf("T"))

share|improve this answer

edited Mar 22 at 2:46

answered Mar 22 at 2:28

Andre Bahtiar FauziAndre Bahtiar Fauzi

545

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  Careful, this will fail for <1000 year dates. Should do something like dateString.substring(0, dateString.indexOf("T"))
  
  – Morgan
  Mar 22 at 2:34
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  thank you for the correction
  
  – Andre Bahtiar Fauzi
  Mar 22 at 2:46
  

  
  
  
  

add a comment | 

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0

To simply 2019-03-06T00:00:00 into 2019-03-06 you can try this.

String dt = dateString.substring(0, 10)

if you use <1000 year dates, or even BCE format. you can use this

String dt = dateString.substring(0, dateString.indexOf("T"))

share|improve this answer

edited Mar 22 at 2:46

answered Mar 22 at 2:28

Andre Bahtiar FauziAndre Bahtiar Fauzi

545

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  Careful, this will fail for <1000 year dates. Should do something like dateString.substring(0, dateString.indexOf("T"))
  
  – Morgan
  Mar 22 at 2:34
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  thank you for the correction
  
  – Andre Bahtiar Fauzi
  Mar 22 at 2:46
  

  
  
  
  

add a comment | 

0

To simply 2019-03-06T00:00:00 into 2019-03-06 you can try this.

String dt = dateString.substring(0, 10)

if you use <1000 year dates, or even BCE format. you can use this

String dt = dateString.substring(0, dateString.indexOf("T"))

share|improve this answer

edited Mar 22 at 2:46

answered Mar 22 at 2:28

Andre Bahtiar FauziAndre Bahtiar Fauzi

545

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  Careful, this will fail for <1000 year dates. Should do something like dateString.substring(0, dateString.indexOf("T"))
  
  – Morgan
  Mar 22 at 2:34
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  thank you for the correction
  
  – Andre Bahtiar Fauzi
  Mar 22 at 2:46
  

  
  
  
  

add a comment | 

To simply 2019-03-06T00:00:00 into 2019-03-06 you can try this.

String dt = dateString.substring(0, 10)

if you use <1000 year dates, or even BCE format. you can use this

String dt = dateString.substring(0, dateString.indexOf("T"))

share|improve this answer

edited Mar 22 at 2:46

answered Mar 22 at 2:28

Andre Bahtiar FauziAndre Bahtiar Fauzi

545

String dt = dateString.substring(0, 10)

String dt = dateString.substring(0, dateString.indexOf("T"))

share|improve this answer

edited Mar 22 at 2:46

answered Mar 22 at 2:28

Andre Bahtiar FauziAndre Bahtiar Fauzi

545

answered Mar 22 at 2:28

Andre Bahtiar FauziAndre Bahtiar Fauzi

545

answered Mar 22 at 2:28

Andre Bahtiar FauziAndre Bahtiar Fauzi

545