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URL.openstream() method can't read from link with &
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I have a link to a .csv which looks like this:
http://website.com/data.csv?since=2019-03-21T00:00Z&sensor=xxx
My method get this link as URL
BufferedReader in = new BufferedReader(new InputStreamReader(URL.openStream()));
The problem is that it is not properly downloading .csv. I have realized that if I add 'amp;' after & it works properly. Is there any easy way to work this out?
java html spring-boot url
asked Mar 21 at 23:03
sebaokasebaoka
478
add a comment |
I have a link to a .csv which looks like this:
http://website.com/data.csv?since=2019-03-21T00:00Z&sensor=xxx
My method get this link as URL
BufferedReader in = new BufferedReader(new InputStreamReader(URL.openStream()));
The problem is that it is not properly downloading .csv. I have realized that if I add 'amp;' after & it works properly. Is there any easy way to work this out?
java html spring-boot url
asked Mar 21 at 23:03
sebaokasebaoka
478
add a comment |
I have a link to a .csv which looks like this:
http://website.com/data.csv?since=2019-03-21T00:00Z&sensor=xxx
My method get this link as URL
BufferedReader in = new BufferedReader(new InputStreamReader(URL.openStream()));
The problem is that it is not properly downloading .csv. I have realized that if I add 'amp;' after & it works properly. Is there any easy way to work this out?
java html spring-boot url
asked Mar 21 at 23:03
sebaokasebaoka
478
I have a link to a .csv which looks like this:
http://website.com/data.csv?since=2019-03-21T00:00Z&sensor=xxx
My method get this link as URL
BufferedReader in = new BufferedReader(new InputStreamReader(URL.openStream()));
The problem is that it is not properly downloading .csv. I have realized that if I add 'amp;' after & it works properly. Is there any easy way to work this out?
java html spring-boot url
java html spring-boot url
asked Mar 21 at 23:03
sebaokasebaoka
478
asked Mar 21 at 23:03
sebaokasebaoka
478
asked Mar 21 at 23:03
sebaokasebaoka
478
asked Mar 21 at 23:03
sebaokasebaoka
478
asked Mar 21 at 23:03
sebaokasebaoka
478
478
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
I have found the solution: https://www.mkyong.com/java/java-httpurlconnection-follow-redirect-example/
public URL getFinalUrl(URL url)
try
HttpURLConnection conn = (HttpURLConnection) url.openConnection();
conn.setReadTimeout(5000);
conn.addRequestProperty("Accept-Language", "en-US,en;q=0.8");
conn.addRequestProperty("User-Agent", "Mozilla");
conn.addRequestProperty("Referer", "google.com");
boolean redirect = false;
int status = conn.getResponseCode();
if (status != HttpURLConnection.HTTP_OK)
if (status == HttpURLConnection.HTTP_MOVED_TEMP
String newUrl = null;
if (redirect)
// get redirect url from "location" header field
newUrl = conn.getHeaderField("Location");
// get the cookie if need, for login
String cookies = conn.getHeaderField("Set-Cookie");
// open the new connnection again
conn = (HttpURLConnection) new URL(newUrl).openConnection();
conn.setRequestProperty("Cookie", cookies);
conn.addRequestProperty("Accept-Language", "en-US,en;q=0.8");
conn.addRequestProperty("User-Agent", "Mozilla");
conn.addRequestProperty("Referer", "google.com");
System.out.println(newUrl);
return new URL(newUrl);
catch (IOException ioe)
System.out.println("Wrong sensor URL");
return null;
answered Mar 21 at 23:54
sebaokasebaoka
478
add a comment |
Your Answer
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
I have found the solution: https://www.mkyong.com/java/java-httpurlconnection-follow-redirect-example/
public URL getFinalUrl(URL url)
try
HttpURLConnection conn = (HttpURLConnection) url.openConnection();
conn.setReadTimeout(5000);
conn.addRequestProperty("Accept-Language", "en-US,en;q=0.8");
conn.addRequestProperty("User-Agent", "Mozilla");
conn.addRequestProperty("Referer", "google.com");
boolean redirect = false;
int status = conn.getResponseCode();
if (status != HttpURLConnection.HTTP_OK)
if (status == HttpURLConnection.HTTP_MOVED_TEMP
String newUrl = null;
if (redirect)
// get redirect url from "location" header field
newUrl = conn.getHeaderField("Location");
// get the cookie if need, for login
String cookies = conn.getHeaderField("Set-Cookie");
// open the new connnection again
conn = (HttpURLConnection) new URL(newUrl).openConnection();
conn.setRequestProperty("Cookie", cookies);
conn.addRequestProperty("Accept-Language", "en-US,en;q=0.8");
conn.addRequestProperty("User-Agent", "Mozilla");
conn.addRequestProperty("Referer", "google.com");
System.out.println(newUrl);
return new URL(newUrl);
catch (IOException ioe)
System.out.println("Wrong sensor URL");
return null;
answered Mar 21 at 23:54
sebaokasebaoka
478
add a comment |
I have found the solution: https://www.mkyong.com/java/java-httpurlconnection-follow-redirect-example/
public URL getFinalUrl(URL url)
try
HttpURLConnection conn = (HttpURLConnection) url.openConnection();
conn.setReadTimeout(5000);
conn.addRequestProperty("Accept-Language", "en-US,en;q=0.8");
conn.addRequestProperty("User-Agent", "Mozilla");
conn.addRequestProperty("Referer", "google.com");
boolean redirect = false;
int status = conn.getResponseCode();
if (status != HttpURLConnection.HTTP_OK)
if (status == HttpURLConnection.HTTP_MOVED_TEMP
String newUrl = null;
if (redirect)
// get redirect url from "location" header field
newUrl = conn.getHeaderField("Location");
// get the cookie if need, for login
String cookies = conn.getHeaderField("Set-Cookie");
// open the new connnection again
conn = (HttpURLConnection) new URL(newUrl).openConnection();
conn.setRequestProperty("Cookie", cookies);
conn.addRequestProperty("Accept-Language", "en-US,en;q=0.8");
conn.addRequestProperty("User-Agent", "Mozilla");
conn.addRequestProperty("Referer", "google.com");
System.out.println(newUrl);
return new URL(newUrl);
catch (IOException ioe)
System.out.println("Wrong sensor URL");
return null;
answered Mar 21 at 23:54
sebaokasebaoka
478
add a comment |
I have found the solution: https://www.mkyong.com/java/java-httpurlconnection-follow-redirect-example/
public URL getFinalUrl(URL url)
try
HttpURLConnection conn = (HttpURLConnection) url.openConnection();
conn.setReadTimeout(5000);
conn.addRequestProperty("Accept-Language", "en-US,en;q=0.8");
conn.addRequestProperty("User-Agent", "Mozilla");
conn.addRequestProperty("Referer", "google.com");
boolean redirect = false;
int status = conn.getResponseCode();
if (status != HttpURLConnection.HTTP_OK)
if (status == HttpURLConnection.HTTP_MOVED_TEMP
String newUrl = null;
if (redirect)
// get redirect url from "location" header field
newUrl = conn.getHeaderField("Location");
// get the cookie if need, for login
String cookies = conn.getHeaderField("Set-Cookie");
// open the new connnection again
conn = (HttpURLConnection) new URL(newUrl).openConnection();
conn.setRequestProperty("Cookie", cookies);
conn.addRequestProperty("Accept-Language", "en-US,en;q=0.8");
conn.addRequestProperty("User-Agent", "Mozilla");
conn.addRequestProperty("Referer", "google.com");
System.out.println(newUrl);
return new URL(newUrl);
catch (IOException ioe)
System.out.println("Wrong sensor URL");
return null;
answered Mar 21 at 23:54
sebaokasebaoka
478
I have found the solution: https://www.mkyong.com/java/java-httpurlconnection-follow-redirect-example/
public URL getFinalUrl(URL url)
try
HttpURLConnection conn = (HttpURLConnection) url.openConnection();
conn.setReadTimeout(5000);
conn.addRequestProperty("Accept-Language", "en-US,en;q=0.8");
conn.addRequestProperty("User-Agent", "Mozilla");
conn.addRequestProperty("Referer", "google.com");
boolean redirect = false;
int status = conn.getResponseCode();
if (status != HttpURLConnection.HTTP_OK)
if (status == HttpURLConnection.HTTP_MOVED_TEMP
String newUrl = null;
if (redirect)
// get redirect url from "location" header field
newUrl = conn.getHeaderField("Location");
// get the cookie if need, for login
String cookies = conn.getHeaderField("Set-Cookie");
// open the new connnection again
conn = (HttpURLConnection) new URL(newUrl).openConnection();
conn.setRequestProperty("Cookie", cookies);
conn.addRequestProperty("Accept-Language", "en-US,en;q=0.8");
conn.addRequestProperty("User-Agent", "Mozilla");
conn.addRequestProperty("Referer", "google.com");
System.out.println(newUrl);
return new URL(newUrl);
catch (IOException ioe)
System.out.println("Wrong sensor URL");
return null;
answered Mar 21 at 23:54
sebaokasebaoka
478
answered Mar 21 at 23:54
sebaokasebaoka
478
answered Mar 21 at 23:54
sebaokasebaoka
478
answered Mar 21 at 23:54
sebaokasebaoka
478
478
add a comment |
add a comment |
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