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Extract more than nine arguments that occur periodically in a sentence to use in macros in order to typset
How much negative space needed? To recognizably remove a space by letting something be added? For macros whose argument is another macro?How to define a command that takes more than 9 argumentsmacros that won't accept other macros as argumentsusing more than 2 arguments in a pgfplots styleUsing mathpalette with macros that take more argumentsUsing forcsvlist with macros that take more than one argumentHow to define a command that takes more than 18 argumentsHow to create a macro that creates other macros (that takes arguments)?How to create a table macro that takes more than 10 argumentsMacro with more than 9 argumentsDifferent command definitions with more than one optional arguments arguments
What is a good way to write a definition of the type fun below
funabc1 EDF1 xyz1 efg jkl abc2 EDF2 xyz2 efg jkl abc3 EDF3 xyz3 efg jkl abc4 EDF2 xyz4 ...
where the number of arguments is not known in advance, may be 1, or may be more than 9, like 12, and the result is as below
abc1 EDF1 formxyz1 efg jkl abc2 EDF2 formxyz2 efg jkl abc3 EDF3 formxyz3 efg jkl abc4 EDF2 formxyz4 ...
Assume for answers
formis same type asnewcommandform[1]emph#1. But delay expansion until the end. Just in case.
Probably requires several nested def cases taking two variables each and a if to decide when to halt the loop ... like when allowing more than 9 arguments to a macro? Or use etoolbox for something better?
If separator words efg jkl are not the same from one place to the next, certain they they are of some specific length, assume efg jkl <=> always 9 characters separating one input from the next. While abc EDF xyz are of different lengths possibly, but always three separate words.
CLARIFICATION: The
xyzcan be arbitrary. But the sentence is periodic in that the 3rd, 8th, 13th, 18th word isformwrapped. If it exists. At least 3 words exists. But can be 3, and if not 3 then 8, and if not 8 then 13, as long as needed, ends when no separator behind three words which can all differ ... The separator " efg jkl " does repeat with certainty however and can be caught to parse.
macros tex-core parsing
asked Mar 22 at 22:12
Guido JorgGuido Jorg
1,15631345
add a comment |
What is a good way to write a definition of the type fun below
funabc1 EDF1 xyz1 efg jkl abc2 EDF2 xyz2 efg jkl abc3 EDF3 xyz3 efg jkl abc4 EDF2 xyz4 ...
where the number of arguments is not known in advance, may be 1, or may be more than 9, like 12, and the result is as below
abc1 EDF1 formxyz1 efg jkl abc2 EDF2 formxyz2 efg jkl abc3 EDF3 formxyz3 efg jkl abc4 EDF2 formxyz4 ...
Assume for answers
formis same type asnewcommandform[1]emph#1. But delay expansion until the end. Just in case.
Probably requires several nested def cases taking two variables each and a if to decide when to halt the loop ... like when allowing more than 9 arguments to a macro? Or use etoolbox for something better?
If separator words efg jkl are not the same from one place to the next, certain they they are of some specific length, assume efg jkl <=> always 9 characters separating one input from the next. While abc EDF xyz are of different lengths possibly, but always three separate words.
CLARIFICATION: The
xyzcan be arbitrary. But the sentence is periodic in that the 3rd, 8th, 13th, 18th word isformwrapped. If it exists. At least 3 words exists. But can be 3, and if not 3 then 8, and if not 8 then 13, as long as needed, ends when no separator behind three words which can all differ ... The separator " efg jkl " does repeat with certainty however and can be caught to parse.
macros tex-core parsing
asked Mar 22 at 22:12
Guido JorgGuido Jorg
1,15631345
funabc1 EDF1 xyz1 efg jkl abc2 EDF2 xyz2 efg jkl abc3 EDF3 xyz3 efg jkl abc4 EDF2 xyz4andfunabc1 EDF1 xyz1andfunabc1 EDF1 xyz1 efg jkl abc2 EDF2 xyz2 efg jkl abc3 EDF3 xyz3 efg jkl abc4 EDF2 xyz4 ... efg jkl abc12 EDF12 xyz12, etc, equally possible. Some kind of loop required. But note that there would not appear any numbers in the input phrase; the numbers are here to illustrate how long happens to be the list. Just the list is always entered as a specific kind of sentence.
– Guido Jorg
Mar 22 at 22:13
Splitting such an input at spaces is easy, and testing for some regular expression too (with expl3) but your description is a bit confusing.
– Ulrike Fischer
Mar 22 at 22:19
Without knowing the rules for applyingformit's really difficult to answer.
– egreg
Mar 22 at 22:22
@GuidoJorg I'm not asking whatformshould do, but to which parts it should be applied. Some real world examples might help to understand. As the question stands, it's impossible to guess.
– egreg
Mar 22 at 22:41
@egreg to the 3rd, 8th, 13th, 18th ... word in the sentence. Separator can be assumed to repeat. form affects only these parts. And sentence can be arbitrarily long and will end without the separator.
– Guido Jorg
Mar 22 at 22:46
add a comment |
What is a good way to write a definition of the type fun below
funabc1 EDF1 xyz1 efg jkl abc2 EDF2 xyz2 efg jkl abc3 EDF3 xyz3 efg jkl abc4 EDF2 xyz4 ...
where the number of arguments is not known in advance, may be 1, or may be more than 9, like 12, and the result is as below
abc1 EDF1 formxyz1 efg jkl abc2 EDF2 formxyz2 efg jkl abc3 EDF3 formxyz3 efg jkl abc4 EDF2 formxyz4 ...
Assume for answers
formis same type asnewcommandform[1]emph#1. But delay expansion until the end. Just in case.
Probably requires several nested def cases taking two variables each and a if to decide when to halt the loop ... like when allowing more than 9 arguments to a macro? Or use etoolbox for something better?
If separator words efg jkl are not the same from one place to the next, certain they they are of some specific length, assume efg jkl <=> always 9 characters separating one input from the next. While abc EDF xyz are of different lengths possibly, but always three separate words.
CLARIFICATION: The
xyzcan be arbitrary. But the sentence is periodic in that the 3rd, 8th, 13th, 18th word isformwrapped. If it exists. At least 3 words exists. But can be 3, and if not 3 then 8, and if not 8 then 13, as long as needed, ends when no separator behind three words which can all differ ... The separator " efg jkl " does repeat with certainty however and can be caught to parse.
macros tex-core parsing
asked Mar 22 at 22:12
Guido JorgGuido Jorg
1,15631345
What is a good way to write a definition of the type fun below
funabc1 EDF1 xyz1 efg jkl abc2 EDF2 xyz2 efg jkl abc3 EDF3 xyz3 efg jkl abc4 EDF2 xyz4 ...
where the number of arguments is not known in advance, may be 1, or may be more than 9, like 12, and the result is as below
abc1 EDF1 formxyz1 efg jkl abc2 EDF2 formxyz2 efg jkl abc3 EDF3 formxyz3 efg jkl abc4 EDF2 formxyz4 ...
Assume for answers
formis same type asnewcommandform[1]emph#1. But delay expansion until the end. Just in case.
Probably requires several nested def cases taking two variables each and a if to decide when to halt the loop ... like when allowing more than 9 arguments to a macro? Or use etoolbox for something better?
If separator words efg jkl are not the same from one place to the next, certain they they are of some specific length, assume efg jkl <=> always 9 characters separating one input from the next. While abc EDF xyz are of different lengths possibly, but always three separate words.
CLARIFICATION: The
xyzcan be arbitrary. But the sentence is periodic in that the 3rd, 8th, 13th, 18th word isformwrapped. If it exists. At least 3 words exists. But can be 3, and if not 3 then 8, and if not 8 then 13, as long as needed, ends when no separator behind three words which can all differ ... The separator " efg jkl " does repeat with certainty however and can be caught to parse.
macros tex-core parsing
macros tex-core parsing
asked Mar 22 at 22:12
Guido JorgGuido Jorg
1,15631345
asked Mar 22 at 22:12
Guido JorgGuido Jorg
1,15631345
edited Mar 22 at 22:59
Guido Jorg
asked Mar 22 at 22:12
Guido JorgGuido Jorg
1,15631345
asked Mar 22 at 22:12
Guido JorgGuido Jorg
1,15631345
asked Mar 22 at 22:12
Guido JorgGuido Jorg
1,15631345
1,15631345
funabc1 EDF1 xyz1 efg jkl abc2 EDF2 xyz2 efg jkl abc3 EDF3 xyz3 efg jkl abc4 EDF2 xyz4andfunabc1 EDF1 xyz1andfunabc1 EDF1 xyz1 efg jkl abc2 EDF2 xyz2 efg jkl abc3 EDF3 xyz3 efg jkl abc4 EDF2 xyz4 ... efg jkl abc12 EDF12 xyz12, etc, equally possible. Some kind of loop required. But note that there would not appear any numbers in the input phrase; the numbers are here to illustrate how long happens to be the list. Just the list is always entered as a specific kind of sentence.
– Guido Jorg
Mar 22 at 22:13
Splitting such an input at spaces is easy, and testing for some regular expression too (with expl3) but your description is a bit confusing.
– Ulrike Fischer
Mar 22 at 22:19
Without knowing the rules for applyingformit's really difficult to answer.
– egreg
Mar 22 at 22:22
@GuidoJorg I'm not asking whatformshould do, but to which parts it should be applied. Some real world examples might help to understand. As the question stands, it's impossible to guess.
– egreg
Mar 22 at 22:41
@egreg to the 3rd, 8th, 13th, 18th ... word in the sentence. Separator can be assumed to repeat. form affects only these parts. And sentence can be arbitrarily long and will end without the separator.
– Guido Jorg
Mar 22 at 22:46
add a comment |
funabc1 EDF1 xyz1 efg jkl abc2 EDF2 xyz2 efg jkl abc3 EDF3 xyz3 efg jkl abc4 EDF2 xyz4andfunabc1 EDF1 xyz1andfunabc1 EDF1 xyz1 efg jkl abc2 EDF2 xyz2 efg jkl abc3 EDF3 xyz3 efg jkl abc4 EDF2 xyz4 ... efg jkl abc12 EDF12 xyz12, etc, equally possible. Some kind of loop required. But note that there would not appear any numbers in the input phrase; the numbers are here to illustrate how long happens to be the list. Just the list is always entered as a specific kind of sentence.
– Guido Jorg
Mar 22 at 22:13
Splitting such an input at spaces is easy, and testing for some regular expression too (with expl3) but your description is a bit confusing.
– Ulrike Fischer
Mar 22 at 22:19
Without knowing the rules for applyingformit's really difficult to answer.
– egreg
Mar 22 at 22:22
@GuidoJorg I'm not asking whatformshould do, but to which parts it should be applied. Some real world examples might help to understand. As the question stands, it's impossible to guess.
– egreg
Mar 22 at 22:41
@egreg to the 3rd, 8th, 13th, 18th ... word in the sentence. Separator can be assumed to repeat. form affects only these parts. And sentence can be arbitrarily long and will end without the separator.
– Guido Jorg
Mar 22 at 22:46
funabc1 EDF1 xyz1 efg jkl abc2 EDF2 xyz2 efg jkl abc3 EDF3 xyz3 efg jkl abc4 EDF2 xyz4 and funabc1 EDF1 xyz1 and funabc1 EDF1 xyz1 efg jkl abc2 EDF2 xyz2 efg jkl abc3 EDF3 xyz3 efg jkl abc4 EDF2 xyz4 ... efg jkl abc12 EDF12 xyz12, etc, equally possible. Some kind of loop required. But note that there would not appear any numbers in the input phrase; the numbers are here to illustrate how long happens to be the list. Just the list is always entered as a specific kind of sentence.– Guido Jorg
Mar 22 at 22:13
funabc1 EDF1 xyz1 efg jkl abc2 EDF2 xyz2 efg jkl abc3 EDF3 xyz3 efg jkl abc4 EDF2 xyz4 and funabc1 EDF1 xyz1 and funabc1 EDF1 xyz1 efg jkl abc2 EDF2 xyz2 efg jkl abc3 EDF3 xyz3 efg jkl abc4 EDF2 xyz4 ... efg jkl abc12 EDF12 xyz12, etc, equally possible. Some kind of loop required. But note that there would not appear any numbers in the input phrase; the numbers are here to illustrate how long happens to be the list. Just the list is always entered as a specific kind of sentence.– Guido Jorg
Mar 22 at 22:13
Splitting such an input at spaces is easy, and testing for some regular expression too (with expl3) but your description is a bit confusing.
– Ulrike Fischer
Mar 22 at 22:19
Splitting such an input at spaces is easy, and testing for some regular expression too (with expl3) but your description is a bit confusing.
– Ulrike Fischer
Mar 22 at 22:19
Without knowing the rules for applying
form it's really difficult to answer.– egreg
Mar 22 at 22:22
Without knowing the rules for applying
form it's really difficult to answer.– egreg
Mar 22 at 22:22
@GuidoJorg I'm not asking what
form should do, but to which parts it should be applied. Some real world examples might help to understand. As the question stands, it's impossible to guess.– egreg
Mar 22 at 22:41
@GuidoJorg I'm not asking what
form should do, but to which parts it should be applied. Some real world examples might help to understand. As the question stands, it's impossible to guess.– egreg
Mar 22 at 22:41
@egreg to the 3rd, 8th, 13th, 18th ... word in the sentence. Separator can be assumed to repeat. form affects only these parts. And sentence can be arbitrarily long and will end without the separator.
– Guido Jorg
Mar 22 at 22:46
@egreg to the 3rd, 8th, 13th, 18th ... word in the sentence. Separator can be assumed to repeat. form affects only these parts. And sentence can be arbitrarily long and will end without the separator.
– Guido Jorg
Mar 22 at 22:46
add a comment |
3 Answers
3
active
oldest
votes
documentclassarticle
usepackagexparse
ExplSyntaxOn
NewDocumentCommandfunm
% split the input at the spaces
seq_set_split:Nnn l_tmpa_seq ~ #1
% use a counter for knowing where we are
int_zero:N l_tmpa_int
% map the sequence
seq_map_inline:Nn l_tmpa_seq
% one more step
int_incr:N l_tmpa_int
int_compare:nTF int_mod:nn l_tmpa_int - 3 5 = 0
% if we're at the 3rd, 5th, 8th, 13th, ... item, apply form
form ##1
% otherwise just deliver the item
##1
% if not at the last, add a space
int_compare:nT l_tmpa_int < seq_count:N l_tmpa_seq ~
ExplSyntaxOff
NewDocumentCommandformmemph#1
begindocument
raggedright
funNon eram nescius Brute cum quae summis ingeniis exquisitaque
doctrina philosophi Graeco sermone tractavissent ea Latinis
litteris mandaremus fore ut hic noster labor in varias
reprehensiones incurreret Nam quibusdam et iis quidem non
admodum indoctis totum hoc displicet philosophari Quidam
autem non tam id reprehendunt si remissius agatur sed tantum
studium tamque multam operam ponendam in eo non arbitrantur
Erunt etiam et ii quidem eruditi Graecis litteris contemnentes
Latinas qui se dicant in Graecis legendis operam malle consumere
Postremo aliquos futuros suspicor qui me ad alias litteras
vocent genus hoc scribendi etsi sit elegans personae tamen
et dignitatis esse negent
enddocument
answered Mar 22 at 23:28
egregegreg
738k8919393269
@GuidoJorg That's very vague.
– egreg
Mar 23 at 11:10
@GuidoJorg That makes things even more obscure.
– egreg
Mar 23 at 13:52
Simplest example:funNon eram nescius Brute cum quae summis ingeniis exquisitaque doctrina philosophi Graeco' displaysNon eram nescius Brute cum quae summis ingeniis exquisitaque doctrina philosophi Graeco` not the result offunNon eram nescius Brute cum quae summis ingeniis exquisitaque doctrina philosophi Graeco. Due to extra. What should be done sofunNon eram nescius Brute cum quae summis ingeniis exquisitaque doctrina philosophi Graecodisplays whenfunNon eram nescius Brute cum quae summis ingeniis exquisitaque doctrina philosophi Graecois entered?
– Guido Jorg
Mar 23 at 14:05
@GuidoJorg Why shouldfun...give the same result asfun...? I see no reason to.
– egreg
Mar 23 at 14:06
By itself: A displays as A. In the use case, composition is desirable. If the text intofunis generated by some macro, not directly entered,funwon't process it. Because it seems the result is treated as A rather than A. Even though it is A. Single object. fun sees no separators when Ab Cd Ef = macrotest and funmacrotest.
– Guido Jorg
Mar 23 at 14:13
|
show 2 more comments
(updated this answer signficantly to allow for multiple (expandable) macros in the argument of fun.)
Here's a LuaLaTeX-based solution. It can handle multiple, expandable macros in the argument of fun. The Lua code first splits the (expanded) input string into separate words, taking note of punctuation characters, if present. It then proceeds to print them, encasing the 3rd, 8th, 13th, 18th words in the form macro. (Mathematically speaking, the selection criterion is that the word's position in the table, modulo 4, equals 3.) Non-ASCII UTF8-encoded characters are fine (because the unicode.utf8.gmatch function rather than the "basic" string.gmatch function is employed.)
% !TEX TS-program = lualatex
documentclassarticle
usepackageluacode % for 'luacode' environment and 'luastring' macro
%% Lua-side code
beginluacode
function do_fun ( s )
words = -- initialize a Lua table
-- split 's' into constituent words
for word in unicode.utf8.gmatch ( s , "%w+%p?" ) do
table.insert ( words , word )
end
-- apply "form" macro at 3rd, 8th, 13th, etc words
for i = 1 , #words do
if i%5 == 3 then
tex.sprint ( "\form"..words[i].." " )
else
tex.sprint ( words[i].." " )
end
end
end
endluacode
%% TeX-side code
newcommandfun[1]directluado_fun(luastring#1)
newcommandform[1]emph#1
newcommandblurbALorem ipsum dolor sit amet, consectetuer adipiscing elit. Ut purus elit, vestibulum ut, placerat ac, adipiscing vitae, felis. Curabitur dictum gravida mauris.
newcommandblurbBNam arcu libero, nonummy eget, consectetuer id, vulputate a, magna. Donec vehicula augue eu neque. Pellentesque habitant.
newcommandblurbCabc1 EDF1 xyz1 efg jkl abc2 EDF2 xyz2 efg jkl abc3 EDF3 xyz3 efg jkl abc4 EDF4 xyz4 efg jkl abc5 EDF5 xyz5 efg jkl abc6 EDF6 xyz6 efg jkl abc7 EDF7 xyz7 efg jkl abc8 EDF8 xyz8 efg jkl abc9 EDF9 xyz9 efg jkl abc10 EDF10 xyz10 efg jkl abc11 EDF11 xyz11 efg jkl abc12 EDF12 xyz12 efg jkl abc13 EDF13 xyz13
begindocument
raggedright
funblurbAblurbBblurbC
enddocument
answered Mar 22 at 22:57
MicoMico
289k32396784
Probably cannot use for a journal but LuaLaTex solutions are very elegant. I will look at LuaTex some more for personal use, have not used it much before.
– Guido Jorg
Mar 22 at 23:02
1
@GuidoJorg - Some, but certainly not all, journals by now allow LuaLaTeX in addition to pdfLaTeX.
– Mico
Mar 22 at 23:24
add a comment |
documentclassarticle
usepackage[T1]fontenc
usepackagelistofitems,tabto
newcounterformtrigger
newcommandform[1]emph#1
newcommandfun[1]%
setsepchar %
readlist*funlist#1%
setcounterformtrigger2%
foreachitemxinfunlist[]%
stepcounterformtrigger%
ifnumtheformtrigger=5relax
formxsetcounterformtrigger0%
else%
x%
fi%
%
begindocument
funabc1 EDF1 xyz1 efg jkl abc2 EDF2 xyz2 efg jkl abc3 EDF3 xyz3 efg jkl abc4 EDF2 xyz4 ...
enddocument
ORIGINAL ANSWER
The listofitems package can grab these inputs very easily, preserving the original tokens without expansion.
documentclassarticle
usepackage[T1]fontenc
usepackagelistofitems,tabto
newcommandform[1]emph#1
newcommandfun[1]%
setsepchar %
readlistfunlist#1%
foreachitemxinfunlist[]%
Argument xcnt istabto1.3in``detokenizeexpandafterx'':
tabto2.5inxpar
%
begindocument
funabc1 EDF1 xyz1 efg jkl abc2 EDF2 xyz2 efg jkl abc3 EDF3 xyz3
efg jkl abc4 EDF2 xyz4 ... abc1 EDF1 formxyz1 efg jkl abc2
EDF2 formxyz2 efg jkl abc3 EDF3 formxyz3 efg jkl abc4
EDF2 formxyz4 ...
enddocument
If you need multi-layer parsing, say that efg jkl is the trigger to separate larger subgroups of arguments, then we have the following (note: efg jkl is not considered an argument, but an argument separator):
documentclassarticle
usepackage[T1]fontenc
usepackagelistofitems,tabto
newcommandform[1]emph#1
newcommandfun[1]%
setsepcharefg jkl/ %
readlist*funlist#1%
foreachitemxinfunlist[]%
foreachitemyinfunlist[xcnt]%
Group xcnt sub-argument ycnt istabto2in``detokenize
expandafterexpandafterexpandafterfunlist[xcnt,ycnt]'':
tabto3.2infunlist[xcnt,ycnt]par
%
begindocument
funabc1 EDF1 xyz1 efg jkl abc2 EDF2 xyz2 efg jkl abc3 EDF3 xyz3
efg jkl abc4 EDF2 xyz4 ... abc1 EDF1 formxyz1 efg jkl abc2
EDF2 formxyz2 efg jkl abc3 EDF3 formxyz3 efg jkl abc4
EDF2 formxyz4 ...
enddocument
answered Mar 22 at 22:20
Steven B. SegletesSteven B. Segletes
164k9209422
Can you say how to get a sentence in one line to occur, rather than a list? Of the rightmost list in the image? (Also for learning how to write such macros, how does listofitems pull this off, can you suggest? I assume it checks ifx style whether the argument separator occurs or not to decide to loop and relies on a def that that takes one argument and has two cases ... Or calls a package with check for ifempty?)
– Guido Jorg
Mar 22 at 22:36
@GuidoJorg To learn about the package: ctan.org/pkg/listofitems
– Steven B. Segletes
Mar 22 at 22:39
@GuidoJorg As to your request, to make a sentence of the right hand column is not really to parse the list at all, but just to typeset the argument. So could you clarify what you are asking?
– Steven B. Segletes
Mar 22 at 22:40
The result looking for is what would be printed hadabc1 EDF1 formxyz1 efg jkl abc2 EDF2 formxyz2 efg jkl abc3 EDF3 formxyz3 efg jkl abc4 EDF2 formxyz4 ...been entered manually. When in factfunabc1 EDF1 xyz1 efg jkl abc2 EDF2 xyz2 efg jkl abc3 EDF3 xyz3 efg jkl abc4 EDF2 xyz4 ...was entered manually. Though the knowledge of how to parse the list completely is useful to know, as is the package, didn't know about it :)
– Guido Jorg
Mar 22 at 22:42
1
@GuidoJorg Please see my revision.
– Steven B. Segletes
Mar 23 at 1:14
|
show 3 more comments
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3 Answers
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3 Answers
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documentclassarticle
usepackagexparse
ExplSyntaxOn
NewDocumentCommandfunm
% split the input at the spaces
seq_set_split:Nnn l_tmpa_seq ~ #1
% use a counter for knowing where we are
int_zero:N l_tmpa_int
% map the sequence
seq_map_inline:Nn l_tmpa_seq
% one more step
int_incr:N l_tmpa_int
int_compare:nTF int_mod:nn l_tmpa_int - 3 5 = 0
% if we're at the 3rd, 5th, 8th, 13th, ... item, apply form
form ##1
% otherwise just deliver the item
##1
% if not at the last, add a space
int_compare:nT l_tmpa_int < seq_count:N l_tmpa_seq ~
ExplSyntaxOff
NewDocumentCommandformmemph#1
begindocument
raggedright
funNon eram nescius Brute cum quae summis ingeniis exquisitaque
doctrina philosophi Graeco sermone tractavissent ea Latinis
litteris mandaremus fore ut hic noster labor in varias
reprehensiones incurreret Nam quibusdam et iis quidem non
admodum indoctis totum hoc displicet philosophari Quidam
autem non tam id reprehendunt si remissius agatur sed tantum
studium tamque multam operam ponendam in eo non arbitrantur
Erunt etiam et ii quidem eruditi Graecis litteris contemnentes
Latinas qui se dicant in Graecis legendis operam malle consumere
Postremo aliquos futuros suspicor qui me ad alias litteras
vocent genus hoc scribendi etsi sit elegans personae tamen
et dignitatis esse negent
enddocument
answered Mar 22 at 23:28
egregegreg
738k8919393269
@GuidoJorg That's very vague.
– egreg
Mar 23 at 11:10
@GuidoJorg That makes things even more obscure.
– egreg
Mar 23 at 13:52
Simplest example:funNon eram nescius Brute cum quae summis ingeniis exquisitaque doctrina philosophi Graeco' displaysNon eram nescius Brute cum quae summis ingeniis exquisitaque doctrina philosophi Graeco` not the result offunNon eram nescius Brute cum quae summis ingeniis exquisitaque doctrina philosophi Graeco. Due to extra. What should be done sofunNon eram nescius Brute cum quae summis ingeniis exquisitaque doctrina philosophi Graecodisplays whenfunNon eram nescius Brute cum quae summis ingeniis exquisitaque doctrina philosophi Graecois entered?
– Guido Jorg
Mar 23 at 14:05
@GuidoJorg Why shouldfun...give the same result asfun...? I see no reason to.
– egreg
Mar 23 at 14:06
By itself: A displays as A. In the use case, composition is desirable. If the text intofunis generated by some macro, not directly entered,funwon't process it. Because it seems the result is treated as A rather than A. Even though it is A. Single object. fun sees no separators when Ab Cd Ef = macrotest and funmacrotest.
– Guido Jorg
Mar 23 at 14:13
|
show 2 more comments
documentclassarticle
usepackagexparse
ExplSyntaxOn
NewDocumentCommandfunm
% split the input at the spaces
seq_set_split:Nnn l_tmpa_seq ~ #1
% use a counter for knowing where we are
int_zero:N l_tmpa_int
% map the sequence
seq_map_inline:Nn l_tmpa_seq
% one more step
int_incr:N l_tmpa_int
int_compare:nTF int_mod:nn l_tmpa_int - 3 5 = 0
% if we're at the 3rd, 5th, 8th, 13th, ... item, apply form
form ##1
% otherwise just deliver the item
##1
% if not at the last, add a space
int_compare:nT l_tmpa_int < seq_count:N l_tmpa_seq ~
ExplSyntaxOff
NewDocumentCommandformmemph#1
begindocument
raggedright
funNon eram nescius Brute cum quae summis ingeniis exquisitaque
doctrina philosophi Graeco sermone tractavissent ea Latinis
litteris mandaremus fore ut hic noster labor in varias
reprehensiones incurreret Nam quibusdam et iis quidem non
admodum indoctis totum hoc displicet philosophari Quidam
autem non tam id reprehendunt si remissius agatur sed tantum
studium tamque multam operam ponendam in eo non arbitrantur
Erunt etiam et ii quidem eruditi Graecis litteris contemnentes
Latinas qui se dicant in Graecis legendis operam malle consumere
Postremo aliquos futuros suspicor qui me ad alias litteras
vocent genus hoc scribendi etsi sit elegans personae tamen
et dignitatis esse negent
enddocument
answered Mar 22 at 23:28
egregegreg
738k8919393269
@GuidoJorg That's very vague.
– egreg
Mar 23 at 11:10
@GuidoJorg That makes things even more obscure.
– egreg
Mar 23 at 13:52
Simplest example:funNon eram nescius Brute cum quae summis ingeniis exquisitaque doctrina philosophi Graeco' displaysNon eram nescius Brute cum quae summis ingeniis exquisitaque doctrina philosophi Graeco` not the result offunNon eram nescius Brute cum quae summis ingeniis exquisitaque doctrina philosophi Graeco. Due to extra. What should be done sofunNon eram nescius Brute cum quae summis ingeniis exquisitaque doctrina philosophi Graecodisplays whenfunNon eram nescius Brute cum quae summis ingeniis exquisitaque doctrina philosophi Graecois entered?
– Guido Jorg
Mar 23 at 14:05
@GuidoJorg Why shouldfun...give the same result asfun...? I see no reason to.
– egreg
Mar 23 at 14:06
By itself: A displays as A. In the use case, composition is desirable. If the text intofunis generated by some macro, not directly entered,funwon't process it. Because it seems the result is treated as A rather than A. Even though it is A. Single object. fun sees no separators when Ab Cd Ef = macrotest and funmacrotest.
– Guido Jorg
Mar 23 at 14:13
|
show 2 more comments
documentclassarticle
usepackagexparse
ExplSyntaxOn
NewDocumentCommandfunm
% split the input at the spaces
seq_set_split:Nnn l_tmpa_seq ~ #1
% use a counter for knowing where we are
int_zero:N l_tmpa_int
% map the sequence
seq_map_inline:Nn l_tmpa_seq
% one more step
int_incr:N l_tmpa_int
int_compare:nTF int_mod:nn l_tmpa_int - 3 5 = 0
% if we're at the 3rd, 5th, 8th, 13th, ... item, apply form
form ##1
% otherwise just deliver the item
##1
% if not at the last, add a space
int_compare:nT l_tmpa_int < seq_count:N l_tmpa_seq ~
ExplSyntaxOff
NewDocumentCommandformmemph#1
begindocument
raggedright
funNon eram nescius Brute cum quae summis ingeniis exquisitaque
doctrina philosophi Graeco sermone tractavissent ea Latinis
litteris mandaremus fore ut hic noster labor in varias
reprehensiones incurreret Nam quibusdam et iis quidem non
admodum indoctis totum hoc displicet philosophari Quidam
autem non tam id reprehendunt si remissius agatur sed tantum
studium tamque multam operam ponendam in eo non arbitrantur
Erunt etiam et ii quidem eruditi Graecis litteris contemnentes
Latinas qui se dicant in Graecis legendis operam malle consumere
Postremo aliquos futuros suspicor qui me ad alias litteras
vocent genus hoc scribendi etsi sit elegans personae tamen
et dignitatis esse negent
enddocument
answered Mar 22 at 23:28
egregegreg
738k8919393269
documentclassarticle
usepackagexparse
ExplSyntaxOn
NewDocumentCommandfunm
% split the input at the spaces
seq_set_split:Nnn l_tmpa_seq ~ #1
% use a counter for knowing where we are
int_zero:N l_tmpa_int
% map the sequence
seq_map_inline:Nn l_tmpa_seq
% one more step
int_incr:N l_tmpa_int
int_compare:nTF int_mod:nn l_tmpa_int - 3 5 = 0
% if we're at the 3rd, 5th, 8th, 13th, ... item, apply form
form ##1
% otherwise just deliver the item
##1
% if not at the last, add a space
int_compare:nT l_tmpa_int < seq_count:N l_tmpa_seq ~
ExplSyntaxOff
NewDocumentCommandformmemph#1
begindocument
raggedright
funNon eram nescius Brute cum quae summis ingeniis exquisitaque
doctrina philosophi Graeco sermone tractavissent ea Latinis
litteris mandaremus fore ut hic noster labor in varias
reprehensiones incurreret Nam quibusdam et iis quidem non
admodum indoctis totum hoc displicet philosophari Quidam
autem non tam id reprehendunt si remissius agatur sed tantum
studium tamque multam operam ponendam in eo non arbitrantur
Erunt etiam et ii quidem eruditi Graecis litteris contemnentes
Latinas qui se dicant in Graecis legendis operam malle consumere
Postremo aliquos futuros suspicor qui me ad alias litteras
vocent genus hoc scribendi etsi sit elegans personae tamen
et dignitatis esse negent
enddocument
answered Mar 22 at 23:28
egregegreg
738k8919393269
answered Mar 22 at 23:28
egregegreg
738k8919393269
answered Mar 22 at 23:28
egregegreg
738k8919393269
answered Mar 22 at 23:28
egregegreg
738k8919393269
738k8919393269
@GuidoJorg That's very vague.
– egreg
Mar 23 at 11:10
@GuidoJorg That makes things even more obscure.
– egreg
Mar 23 at 13:52
Simplest example:funNon eram nescius Brute cum quae summis ingeniis exquisitaque doctrina philosophi Graeco' displaysNon eram nescius Brute cum quae summis ingeniis exquisitaque doctrina philosophi Graeco` not the result offunNon eram nescius Brute cum quae summis ingeniis exquisitaque doctrina philosophi Graeco. Due to extra. What should be done sofunNon eram nescius Brute cum quae summis ingeniis exquisitaque doctrina philosophi Graecodisplays whenfunNon eram nescius Brute cum quae summis ingeniis exquisitaque doctrina philosophi Graecois entered?
– Guido Jorg
Mar 23 at 14:05
@GuidoJorg Why shouldfun...give the same result asfun...? I see no reason to.
– egreg
Mar 23 at 14:06
By itself: A displays as A. In the use case, composition is desirable. If the text intofunis generated by some macro, not directly entered,funwon't process it. Because it seems the result is treated as A rather than A. Even though it is A. Single object. fun sees no separators when Ab Cd Ef = macrotest and funmacrotest.
– Guido Jorg
Mar 23 at 14:13
|
show 2 more comments
@GuidoJorg That's very vague.
– egreg
Mar 23 at 11:10
@GuidoJorg That makes things even more obscure.
– egreg
Mar 23 at 13:52
Simplest example:funNon eram nescius Brute cum quae summis ingeniis exquisitaque doctrina philosophi Graeco' displaysNon eram nescius Brute cum quae summis ingeniis exquisitaque doctrina philosophi Graeco` not the result offunNon eram nescius Brute cum quae summis ingeniis exquisitaque doctrina philosophi Graeco. Due to extra. What should be done sofunNon eram nescius Brute cum quae summis ingeniis exquisitaque doctrina philosophi Graecodisplays whenfunNon eram nescius Brute cum quae summis ingeniis exquisitaque doctrina philosophi Graecois entered?
– Guido Jorg
Mar 23 at 14:05
@GuidoJorg Why shouldfun...give the same result asfun...? I see no reason to.
– egreg
Mar 23 at 14:06
By itself: A displays as A. In the use case, composition is desirable. If the text intofunis generated by some macro, not directly entered,funwon't process it. Because it seems the result is treated as A rather than A. Even though it is A. Single object. fun sees no separators when Ab Cd Ef = macrotest and funmacrotest.
– Guido Jorg
Mar 23 at 14:13
@GuidoJorg That's very vague.
– egreg
Mar 23 at 11:10
@GuidoJorg That's very vague.
– egreg
Mar 23 at 11:10
@GuidoJorg That makes things even more obscure.
– egreg
Mar 23 at 13:52
@GuidoJorg That makes things even more obscure.
– egreg
Mar 23 at 13:52
Simplest example:
funNon eram nescius Brute cum quae summis ingeniis exquisitaque doctrina philosophi Graeco' displays Non eram nescius Brute cum quae summis ingeniis exquisitaque doctrina philosophi Graeco` not the result of funNon eram nescius Brute cum quae summis ingeniis exquisitaque doctrina philosophi Graeco. Due to extra funNon eram nescius Brute cum quae summis ingeniis exquisitaque doctrina philosophi Graeco displays when funNon eram nescius Brute cum quae summis ingeniis exquisitaque doctrina philosophi Graeco is entered?– Guido Jorg
Mar 23 at 14:05
Simplest example:
funNon eram nescius Brute cum quae summis ingeniis exquisitaque doctrina philosophi Graeco' displays Non eram nescius Brute cum quae summis ingeniis exquisitaque doctrina philosophi Graeco` not the result of funNon eram nescius Brute cum quae summis ingeniis exquisitaque doctrina philosophi Graeco. Due to extra funNon eram nescius Brute cum quae summis ingeniis exquisitaque doctrina philosophi Graeco displays when funNon eram nescius Brute cum quae summis ingeniis exquisitaque doctrina philosophi Graeco is entered?– Guido Jorg
Mar 23 at 14:05
@GuidoJorg Why should
fun... give the same result as fun...? I see no reason to.– egreg
Mar 23 at 14:06
@GuidoJorg Why should
fun... give the same result as fun...? I see no reason to.– egreg
Mar 23 at 14:06
By itself: A displays as A. In the use case, composition is desirable. If the text into
fun is generated by some macro, not directly entered, fun won't process it. Because it seems the result is treated as A rather than A. Even though it is A. Single object. fun sees no separators when Ab Cd Ef = macrotest and funmacrotest.– Guido Jorg
Mar 23 at 14:13
By itself: A displays as A. In the use case, composition is desirable. If the text into
fun is generated by some macro, not directly entered, fun won't process it. Because it seems the result is treated as A rather than A. Even though it is A. Single object. fun sees no separators when Ab Cd Ef = macrotest and funmacrotest.– Guido Jorg
Mar 23 at 14:13
|
show 2 more comments
(updated this answer signficantly to allow for multiple (expandable) macros in the argument of fun.)
Here's a LuaLaTeX-based solution. It can handle multiple, expandable macros in the argument of fun. The Lua code first splits the (expanded) input string into separate words, taking note of punctuation characters, if present. It then proceeds to print them, encasing the 3rd, 8th, 13th, 18th words in the form macro. (Mathematically speaking, the selection criterion is that the word's position in the table, modulo 4, equals 3.) Non-ASCII UTF8-encoded characters are fine (because the unicode.utf8.gmatch function rather than the "basic" string.gmatch function is employed.)
% !TEX TS-program = lualatex
documentclassarticle
usepackageluacode % for 'luacode' environment and 'luastring' macro
%% Lua-side code
beginluacode
function do_fun ( s )
words = -- initialize a Lua table
-- split 's' into constituent words
for word in unicode.utf8.gmatch ( s , "%w+%p?" ) do
table.insert ( words , word )
end
-- apply "form" macro at 3rd, 8th, 13th, etc words
for i = 1 , #words do
if i%5 == 3 then
tex.sprint ( "\form"..words[i].." " )
else
tex.sprint ( words[i].." " )
end
end
end
endluacode
%% TeX-side code
newcommandfun[1]directluado_fun(luastring#1)
newcommandform[1]emph#1
newcommandblurbALorem ipsum dolor sit amet, consectetuer adipiscing elit. Ut purus elit, vestibulum ut, placerat ac, adipiscing vitae, felis. Curabitur dictum gravida mauris.
newcommandblurbBNam arcu libero, nonummy eget, consectetuer id, vulputate a, magna. Donec vehicula augue eu neque. Pellentesque habitant.
newcommandblurbCabc1 EDF1 xyz1 efg jkl abc2 EDF2 xyz2 efg jkl abc3 EDF3 xyz3 efg jkl abc4 EDF4 xyz4 efg jkl abc5 EDF5 xyz5 efg jkl abc6 EDF6 xyz6 efg jkl abc7 EDF7 xyz7 efg jkl abc8 EDF8 xyz8 efg jkl abc9 EDF9 xyz9 efg jkl abc10 EDF10 xyz10 efg jkl abc11 EDF11 xyz11 efg jkl abc12 EDF12 xyz12 efg jkl abc13 EDF13 xyz13
begindocument
raggedright
funblurbAblurbBblurbC
enddocument
answered Mar 22 at 22:57
MicoMico
289k32396784
Probably cannot use for a journal but LuaLaTex solutions are very elegant. I will look at LuaTex some more for personal use, have not used it much before.
– Guido Jorg
Mar 22 at 23:02
1
@GuidoJorg - Some, but certainly not all, journals by now allow LuaLaTeX in addition to pdfLaTeX.
– Mico
Mar 22 at 23:24
add a comment |
(updated this answer signficantly to allow for multiple (expandable) macros in the argument of fun.)
Here's a LuaLaTeX-based solution. It can handle multiple, expandable macros in the argument of fun. The Lua code first splits the (expanded) input string into separate words, taking note of punctuation characters, if present. It then proceeds to print them, encasing the 3rd, 8th, 13th, 18th words in the form macro. (Mathematically speaking, the selection criterion is that the word's position in the table, modulo 4, equals 3.) Non-ASCII UTF8-encoded characters are fine (because the unicode.utf8.gmatch function rather than the "basic" string.gmatch function is employed.)
% !TEX TS-program = lualatex
documentclassarticle
usepackageluacode % for 'luacode' environment and 'luastring' macro
%% Lua-side code
beginluacode
function do_fun ( s )
words = -- initialize a Lua table
-- split 's' into constituent words
for word in unicode.utf8.gmatch ( s , "%w+%p?" ) do
table.insert ( words , word )
end
-- apply "form" macro at 3rd, 8th, 13th, etc words
for i = 1 , #words do
if i%5 == 3 then
tex.sprint ( "\form"..words[i].." " )
else
tex.sprint ( words[i].." " )
end
end
end
endluacode
%% TeX-side code
newcommandfun[1]directluado_fun(luastring#1)
newcommandform[1]emph#1
newcommandblurbALorem ipsum dolor sit amet, consectetuer adipiscing elit. Ut purus elit, vestibulum ut, placerat ac, adipiscing vitae, felis. Curabitur dictum gravida mauris.
newcommandblurbBNam arcu libero, nonummy eget, consectetuer id, vulputate a, magna. Donec vehicula augue eu neque. Pellentesque habitant.
newcommandblurbCabc1 EDF1 xyz1 efg jkl abc2 EDF2 xyz2 efg jkl abc3 EDF3 xyz3 efg jkl abc4 EDF4 xyz4 efg jkl abc5 EDF5 xyz5 efg jkl abc6 EDF6 xyz6 efg jkl abc7 EDF7 xyz7 efg jkl abc8 EDF8 xyz8 efg jkl abc9 EDF9 xyz9 efg jkl abc10 EDF10 xyz10 efg jkl abc11 EDF11 xyz11 efg jkl abc12 EDF12 xyz12 efg jkl abc13 EDF13 xyz13
begindocument
raggedright
funblurbAblurbBblurbC
enddocument
answered Mar 22 at 22:57
MicoMico
289k32396784
Probably cannot use for a journal but LuaLaTex solutions are very elegant. I will look at LuaTex some more for personal use, have not used it much before.
– Guido Jorg
Mar 22 at 23:02
1
@GuidoJorg - Some, but certainly not all, journals by now allow LuaLaTeX in addition to pdfLaTeX.
– Mico
Mar 22 at 23:24
add a comment |
(updated this answer signficantly to allow for multiple (expandable) macros in the argument of fun.)
Here's a LuaLaTeX-based solution. It can handle multiple, expandable macros in the argument of fun. The Lua code first splits the (expanded) input string into separate words, taking note of punctuation characters, if present. It then proceeds to print them, encasing the 3rd, 8th, 13th, 18th words in the form macro. (Mathematically speaking, the selection criterion is that the word's position in the table, modulo 4, equals 3.) Non-ASCII UTF8-encoded characters are fine (because the unicode.utf8.gmatch function rather than the "basic" string.gmatch function is employed.)
% !TEX TS-program = lualatex
documentclassarticle
usepackageluacode % for 'luacode' environment and 'luastring' macro
%% Lua-side code
beginluacode
function do_fun ( s )
words = -- initialize a Lua table
-- split 's' into constituent words
for word in unicode.utf8.gmatch ( s , "%w+%p?" ) do
table.insert ( words , word )
end
-- apply "form" macro at 3rd, 8th, 13th, etc words
for i = 1 , #words do
if i%5 == 3 then
tex.sprint ( "\form"..words[i].." " )
else
tex.sprint ( words[i].." " )
end
end
end
endluacode
%% TeX-side code
newcommandfun[1]directluado_fun(luastring#1)
newcommandform[1]emph#1
newcommandblurbALorem ipsum dolor sit amet, consectetuer adipiscing elit. Ut purus elit, vestibulum ut, placerat ac, adipiscing vitae, felis. Curabitur dictum gravida mauris.
newcommandblurbBNam arcu libero, nonummy eget, consectetuer id, vulputate a, magna. Donec vehicula augue eu neque. Pellentesque habitant.
newcommandblurbCabc1 EDF1 xyz1 efg jkl abc2 EDF2 xyz2 efg jkl abc3 EDF3 xyz3 efg jkl abc4 EDF4 xyz4 efg jkl abc5 EDF5 xyz5 efg jkl abc6 EDF6 xyz6 efg jkl abc7 EDF7 xyz7 efg jkl abc8 EDF8 xyz8 efg jkl abc9 EDF9 xyz9 efg jkl abc10 EDF10 xyz10 efg jkl abc11 EDF11 xyz11 efg jkl abc12 EDF12 xyz12 efg jkl abc13 EDF13 xyz13
begindocument
raggedright
funblurbAblurbBblurbC
enddocument
answered Mar 22 at 22:57
MicoMico
289k32396784
(updated this answer signficantly to allow for multiple (expandable) macros in the argument of fun.)
Here's a LuaLaTeX-based solution. It can handle multiple, expandable macros in the argument of fun. The Lua code first splits the (expanded) input string into separate words, taking note of punctuation characters, if present. It then proceeds to print them, encasing the 3rd, 8th, 13th, 18th words in the form macro. (Mathematically speaking, the selection criterion is that the word's position in the table, modulo 4, equals 3.) Non-ASCII UTF8-encoded characters are fine (because the unicode.utf8.gmatch function rather than the "basic" string.gmatch function is employed.)
% !TEX TS-program = lualatex
documentclassarticle
usepackageluacode % for 'luacode' environment and 'luastring' macro
%% Lua-side code
beginluacode
function do_fun ( s )
words = -- initialize a Lua table
-- split 's' into constituent words
for word in unicode.utf8.gmatch ( s , "%w+%p?" ) do
table.insert ( words , word )
end
-- apply "form" macro at 3rd, 8th, 13th, etc words
for i = 1 , #words do
if i%5 == 3 then
tex.sprint ( "\form"..words[i].." " )
else
tex.sprint ( words[i].." " )
end
end
end
endluacode
%% TeX-side code
newcommandfun[1]directluado_fun(luastring#1)
newcommandform[1]emph#1
newcommandblurbALorem ipsum dolor sit amet, consectetuer adipiscing elit. Ut purus elit, vestibulum ut, placerat ac, adipiscing vitae, felis. Curabitur dictum gravida mauris.
newcommandblurbBNam arcu libero, nonummy eget, consectetuer id, vulputate a, magna. Donec vehicula augue eu neque. Pellentesque habitant.
newcommandblurbCabc1 EDF1 xyz1 efg jkl abc2 EDF2 xyz2 efg jkl abc3 EDF3 xyz3 efg jkl abc4 EDF4 xyz4 efg jkl abc5 EDF5 xyz5 efg jkl abc6 EDF6 xyz6 efg jkl abc7 EDF7 xyz7 efg jkl abc8 EDF8 xyz8 efg jkl abc9 EDF9 xyz9 efg jkl abc10 EDF10 xyz10 efg jkl abc11 EDF11 xyz11 efg jkl abc12 EDF12 xyz12 efg jkl abc13 EDF13 xyz13
begindocument
raggedright
funblurbAblurbBblurbC
enddocument
answered Mar 22 at 22:57
MicoMico
289k32396784
edited Mar 23 at 10:14
answered Mar 22 at 22:57
MicoMico
289k32396784
answered Mar 22 at 22:57
MicoMico
289k32396784
answered Mar 22 at 22:57
MicoMico
289k32396784
289k32396784
Probably cannot use for a journal but LuaLaTex solutions are very elegant. I will look at LuaTex some more for personal use, have not used it much before.
– Guido Jorg
Mar 22 at 23:02
1
@GuidoJorg - Some, but certainly not all, journals by now allow LuaLaTeX in addition to pdfLaTeX.
– Mico
Mar 22 at 23:24
add a comment |
Probably cannot use for a journal but LuaLaTex solutions are very elegant. I will look at LuaTex some more for personal use, have not used it much before.
– Guido Jorg
Mar 22 at 23:02
1
@GuidoJorg - Some, but certainly not all, journals by now allow LuaLaTeX in addition to pdfLaTeX.
– Mico
Mar 22 at 23:24
Probably cannot use for a journal but LuaLaTex solutions are very elegant. I will look at LuaTex some more for personal use, have not used it much before.
– Guido Jorg
Mar 22 at 23:02
Probably cannot use for a journal but LuaLaTex solutions are very elegant. I will look at LuaTex some more for personal use, have not used it much before.
– Guido Jorg
Mar 22 at 23:02
1
1
@GuidoJorg - Some, but certainly not all, journals by now allow LuaLaTeX in addition to pdfLaTeX.
– Mico
Mar 22 at 23:24
@GuidoJorg - Some, but certainly not all, journals by now allow LuaLaTeX in addition to pdfLaTeX.
– Mico
Mar 22 at 23:24
add a comment |
documentclassarticle
usepackage[T1]fontenc
usepackagelistofitems,tabto
newcounterformtrigger
newcommandform[1]emph#1
newcommandfun[1]%
setsepchar %
readlist*funlist#1%
setcounterformtrigger2%
foreachitemxinfunlist[]%
stepcounterformtrigger%
ifnumtheformtrigger=5relax
formxsetcounterformtrigger0%
else%
x%
fi%
%
begindocument
funabc1 EDF1 xyz1 efg jkl abc2 EDF2 xyz2 efg jkl abc3 EDF3 xyz3 efg jkl abc4 EDF2 xyz4 ...
enddocument
ORIGINAL ANSWER
The listofitems package can grab these inputs very easily, preserving the original tokens without expansion.
documentclassarticle
usepackage[T1]fontenc
usepackagelistofitems,tabto
newcommandform[1]emph#1
newcommandfun[1]%
setsepchar %
readlistfunlist#1%
foreachitemxinfunlist[]%
Argument xcnt istabto1.3in``detokenizeexpandafterx'':
tabto2.5inxpar
%
begindocument
funabc1 EDF1 xyz1 efg jkl abc2 EDF2 xyz2 efg jkl abc3 EDF3 xyz3
efg jkl abc4 EDF2 xyz4 ... abc1 EDF1 formxyz1 efg jkl abc2
EDF2 formxyz2 efg jkl abc3 EDF3 formxyz3 efg jkl abc4
EDF2 formxyz4 ...
enddocument
If you need multi-layer parsing, say that efg jkl is the trigger to separate larger subgroups of arguments, then we have the following (note: efg jkl is not considered an argument, but an argument separator):
documentclassarticle
usepackage[T1]fontenc
usepackagelistofitems,tabto
newcommandform[1]emph#1
newcommandfun[1]%
setsepcharefg jkl/ %
readlist*funlist#1%
foreachitemxinfunlist[]%
foreachitemyinfunlist[xcnt]%
Group xcnt sub-argument ycnt istabto2in``detokenize
expandafterexpandafterexpandafterfunlist[xcnt,ycnt]'':
tabto3.2infunlist[xcnt,ycnt]par
%
begindocument
funabc1 EDF1 xyz1 efg jkl abc2 EDF2 xyz2 efg jkl abc3 EDF3 xyz3
efg jkl abc4 EDF2 xyz4 ... abc1 EDF1 formxyz1 efg jkl abc2
EDF2 formxyz2 efg jkl abc3 EDF3 formxyz3 efg jkl abc4
EDF2 formxyz4 ...
enddocument
answered Mar 22 at 22:20
Steven B. SegletesSteven B. Segletes
164k9209422
Can you say how to get a sentence in one line to occur, rather than a list? Of the rightmost list in the image? (Also for learning how to write such macros, how does listofitems pull this off, can you suggest? I assume it checks ifx style whether the argument separator occurs or not to decide to loop and relies on a def that that takes one argument and has two cases ... Or calls a package with check for ifempty?)
– Guido Jorg
Mar 22 at 22:36
@GuidoJorg To learn about the package: ctan.org/pkg/listofitems
– Steven B. Segletes
Mar 22 at 22:39
@GuidoJorg As to your request, to make a sentence of the right hand column is not really to parse the list at all, but just to typeset the argument. So could you clarify what you are asking?
– Steven B. Segletes
Mar 22 at 22:40
The result looking for is what would be printed hadabc1 EDF1 formxyz1 efg jkl abc2 EDF2 formxyz2 efg jkl abc3 EDF3 formxyz3 efg jkl abc4 EDF2 formxyz4 ...been entered manually. When in factfunabc1 EDF1 xyz1 efg jkl abc2 EDF2 xyz2 efg jkl abc3 EDF3 xyz3 efg jkl abc4 EDF2 xyz4 ...was entered manually. Though the knowledge of how to parse the list completely is useful to know, as is the package, didn't know about it :)
– Guido Jorg
Mar 22 at 22:42
1
@GuidoJorg Please see my revision.
– Steven B. Segletes
Mar 23 at 1:14
|
show 3 more comments
documentclassarticle
usepackage[T1]fontenc
usepackagelistofitems,tabto
newcounterformtrigger
newcommandform[1]emph#1
newcommandfun[1]%
setsepchar %
readlist*funlist#1%
setcounterformtrigger2%
foreachitemxinfunlist[]%
stepcounterformtrigger%
ifnumtheformtrigger=5relax
formxsetcounterformtrigger0%
else%
x%
fi%
%
begindocument
funabc1 EDF1 xyz1 efg jkl abc2 EDF2 xyz2 efg jkl abc3 EDF3 xyz3 efg jkl abc4 EDF2 xyz4 ...
enddocument
ORIGINAL ANSWER
The listofitems package can grab these inputs very easily, preserving the original tokens without expansion.
documentclassarticle
usepackage[T1]fontenc
usepackagelistofitems,tabto
newcommandform[1]emph#1
newcommandfun[1]%
setsepchar %
readlistfunlist#1%
foreachitemxinfunlist[]%
Argument xcnt istabto1.3in``detokenizeexpandafterx'':
tabto2.5inxpar
%
begindocument
funabc1 EDF1 xyz1 efg jkl abc2 EDF2 xyz2 efg jkl abc3 EDF3 xyz3
efg jkl abc4 EDF2 xyz4 ... abc1 EDF1 formxyz1 efg jkl abc2
EDF2 formxyz2 efg jkl abc3 EDF3 formxyz3 efg jkl abc4
EDF2 formxyz4 ...
enddocument
If you need multi-layer parsing, say that efg jkl is the trigger to separate larger subgroups of arguments, then we have the following (note: efg jkl is not considered an argument, but an argument separator):
documentclassarticle
usepackage[T1]fontenc
usepackagelistofitems,tabto
newcommandform[1]emph#1
newcommandfun[1]%
setsepcharefg jkl/ %
readlist*funlist#1%
foreachitemxinfunlist[]%
foreachitemyinfunlist[xcnt]%
Group xcnt sub-argument ycnt istabto2in``detokenize
expandafterexpandafterexpandafterfunlist[xcnt,ycnt]'':
tabto3.2infunlist[xcnt,ycnt]par
%
begindocument
funabc1 EDF1 xyz1 efg jkl abc2 EDF2 xyz2 efg jkl abc3 EDF3 xyz3
efg jkl abc4 EDF2 xyz4 ... abc1 EDF1 formxyz1 efg jkl abc2
EDF2 formxyz2 efg jkl abc3 EDF3 formxyz3 efg jkl abc4
EDF2 formxyz4 ...
enddocument
answered Mar 22 at 22:20
Steven B. SegletesSteven B. Segletes
164k9209422
Can you say how to get a sentence in one line to occur, rather than a list? Of the rightmost list in the image? (Also for learning how to write such macros, how does listofitems pull this off, can you suggest? I assume it checks ifx style whether the argument separator occurs or not to decide to loop and relies on a def that that takes one argument and has two cases ... Or calls a package with check for ifempty?)
– Guido Jorg
Mar 22 at 22:36
@GuidoJorg To learn about the package: ctan.org/pkg/listofitems
– Steven B. Segletes
Mar 22 at 22:39
@GuidoJorg As to your request, to make a sentence of the right hand column is not really to parse the list at all, but just to typeset the argument. So could you clarify what you are asking?
– Steven B. Segletes
Mar 22 at 22:40
The result looking for is what would be printed hadabc1 EDF1 formxyz1 efg jkl abc2 EDF2 formxyz2 efg jkl abc3 EDF3 formxyz3 efg jkl abc4 EDF2 formxyz4 ...been entered manually. When in factfunabc1 EDF1 xyz1 efg jkl abc2 EDF2 xyz2 efg jkl abc3 EDF3 xyz3 efg jkl abc4 EDF2 xyz4 ...was entered manually. Though the knowledge of how to parse the list completely is useful to know, as is the package, didn't know about it :)
– Guido Jorg
Mar 22 at 22:42
1
@GuidoJorg Please see my revision.
– Steven B. Segletes
Mar 23 at 1:14
|
show 3 more comments
documentclassarticle
usepackage[T1]fontenc
usepackagelistofitems,tabto
newcounterformtrigger
newcommandform[1]emph#1
newcommandfun[1]%
setsepchar %
readlist*funlist#1%
setcounterformtrigger2%
foreachitemxinfunlist[]%
stepcounterformtrigger%
ifnumtheformtrigger=5relax
formxsetcounterformtrigger0%
else%
x%
fi%
%
begindocument
funabc1 EDF1 xyz1 efg jkl abc2 EDF2 xyz2 efg jkl abc3 EDF3 xyz3 efg jkl abc4 EDF2 xyz4 ...
enddocument
ORIGINAL ANSWER
The listofitems package can grab these inputs very easily, preserving the original tokens without expansion.
documentclassarticle
usepackage[T1]fontenc
usepackagelistofitems,tabto
newcommandform[1]emph#1
newcommandfun[1]%
setsepchar %
readlistfunlist#1%
foreachitemxinfunlist[]%
Argument xcnt istabto1.3in``detokenizeexpandafterx'':
tabto2.5inxpar
%
begindocument
funabc1 EDF1 xyz1 efg jkl abc2 EDF2 xyz2 efg jkl abc3 EDF3 xyz3
efg jkl abc4 EDF2 xyz4 ... abc1 EDF1 formxyz1 efg jkl abc2
EDF2 formxyz2 efg jkl abc3 EDF3 formxyz3 efg jkl abc4
EDF2 formxyz4 ...
enddocument
If you need multi-layer parsing, say that efg jkl is the trigger to separate larger subgroups of arguments, then we have the following (note: efg jkl is not considered an argument, but an argument separator):
documentclassarticle
usepackage[T1]fontenc
usepackagelistofitems,tabto
newcommandform[1]emph#1
newcommandfun[1]%
setsepcharefg jkl/ %
readlist*funlist#1%
foreachitemxinfunlist[]%
foreachitemyinfunlist[xcnt]%
Group xcnt sub-argument ycnt istabto2in``detokenize
expandafterexpandafterexpandafterfunlist[xcnt,ycnt]'':
tabto3.2infunlist[xcnt,ycnt]par
%
begindocument
funabc1 EDF1 xyz1 efg jkl abc2 EDF2 xyz2 efg jkl abc3 EDF3 xyz3
efg jkl abc4 EDF2 xyz4 ... abc1 EDF1 formxyz1 efg jkl abc2
EDF2 formxyz2 efg jkl abc3 EDF3 formxyz3 efg jkl abc4
EDF2 formxyz4 ...
enddocument
answered Mar 22 at 22:20
Steven B. SegletesSteven B. Segletes
164k9209422
documentclassarticle
usepackage[T1]fontenc
usepackagelistofitems,tabto
newcounterformtrigger
newcommandform[1]emph#1
newcommandfun[1]%
setsepchar %
readlist*funlist#1%
setcounterformtrigger2%
foreachitemxinfunlist[]%
stepcounterformtrigger%
ifnumtheformtrigger=5relax
formxsetcounterformtrigger0%
else%
x%
fi%
%
begindocument
funabc1 EDF1 xyz1 efg jkl abc2 EDF2 xyz2 efg jkl abc3 EDF3 xyz3 efg jkl abc4 EDF2 xyz4 ...
enddocument
ORIGINAL ANSWER
The listofitems package can grab these inputs very easily, preserving the original tokens without expansion.
documentclassarticle
usepackage[T1]fontenc
usepackagelistofitems,tabto
newcommandform[1]emph#1
newcommandfun[1]%
setsepchar %
readlistfunlist#1%
foreachitemxinfunlist[]%
Argument xcnt istabto1.3in``detokenizeexpandafterx'':
tabto2.5inxpar
%
begindocument
funabc1 EDF1 xyz1 efg jkl abc2 EDF2 xyz2 efg jkl abc3 EDF3 xyz3
efg jkl abc4 EDF2 xyz4 ... abc1 EDF1 formxyz1 efg jkl abc2
EDF2 formxyz2 efg jkl abc3 EDF3 formxyz3 efg jkl abc4
EDF2 formxyz4 ...
enddocument
If you need multi-layer parsing, say that efg jkl is the trigger to separate larger subgroups of arguments, then we have the following (note: efg jkl is not considered an argument, but an argument separator):
documentclassarticle
usepackage[T1]fontenc
usepackagelistofitems,tabto
newcommandform[1]emph#1
newcommandfun[1]%
setsepcharefg jkl/ %
readlist*funlist#1%
foreachitemxinfunlist[]%
foreachitemyinfunlist[xcnt]%
Group xcnt sub-argument ycnt istabto2in``detokenize
expandafterexpandafterexpandafterfunlist[xcnt,ycnt]'':
tabto3.2infunlist[xcnt,ycnt]par
%
begindocument
funabc1 EDF1 xyz1 efg jkl abc2 EDF2 xyz2 efg jkl abc3 EDF3 xyz3
efg jkl abc4 EDF2 xyz4 ... abc1 EDF1 formxyz1 efg jkl abc2
EDF2 formxyz2 efg jkl abc3 EDF3 formxyz3 efg jkl abc4
EDF2 formxyz4 ...
enddocument
answered Mar 22 at 22:20
Steven B. SegletesSteven B. Segletes
164k9209422
edited Mar 23 at 1:13
answered Mar 22 at 22:20
Steven B. SegletesSteven B. Segletes
164k9209422
answered Mar 22 at 22:20
Steven B. SegletesSteven B. Segletes
164k9209422
answered Mar 22 at 22:20
Steven B. SegletesSteven B. Segletes
164k9209422
164k9209422
Can you say how to get a sentence in one line to occur, rather than a list? Of the rightmost list in the image? (Also for learning how to write such macros, how does listofitems pull this off, can you suggest? I assume it checks ifx style whether the argument separator occurs or not to decide to loop and relies on a def that that takes one argument and has two cases ... Or calls a package with check for ifempty?)
– Guido Jorg
Mar 22 at 22:36
@GuidoJorg To learn about the package: ctan.org/pkg/listofitems
– Steven B. Segletes
Mar 22 at 22:39
@GuidoJorg As to your request, to make a sentence of the right hand column is not really to parse the list at all, but just to typeset the argument. So could you clarify what you are asking?
– Steven B. Segletes
Mar 22 at 22:40
The result looking for is what would be printed hadabc1 EDF1 formxyz1 efg jkl abc2 EDF2 formxyz2 efg jkl abc3 EDF3 formxyz3 efg jkl abc4 EDF2 formxyz4 ...been entered manually. When in factfunabc1 EDF1 xyz1 efg jkl abc2 EDF2 xyz2 efg jkl abc3 EDF3 xyz3 efg jkl abc4 EDF2 xyz4 ...was entered manually. Though the knowledge of how to parse the list completely is useful to know, as is the package, didn't know about it :)
– Guido Jorg
Mar 22 at 22:42
1
@GuidoJorg Please see my revision.
– Steven B. Segletes
Mar 23 at 1:14
|
show 3 more comments
Can you say how to get a sentence in one line to occur, rather than a list? Of the rightmost list in the image? (Also for learning how to write such macros, how does listofitems pull this off, can you suggest? I assume it checks ifx style whether the argument separator occurs or not to decide to loop and relies on a def that that takes one argument and has two cases ... Or calls a package with check for ifempty?)
– Guido Jorg
Mar 22 at 22:36
@GuidoJorg To learn about the package: ctan.org/pkg/listofitems
– Steven B. Segletes
Mar 22 at 22:39
@GuidoJorg As to your request, to make a sentence of the right hand column is not really to parse the list at all, but just to typeset the argument. So could you clarify what you are asking?
– Steven B. Segletes
Mar 22 at 22:40
The result looking for is what would be printed hadabc1 EDF1 formxyz1 efg jkl abc2 EDF2 formxyz2 efg jkl abc3 EDF3 formxyz3 efg jkl abc4 EDF2 formxyz4 ...been entered manually. When in factfunabc1 EDF1 xyz1 efg jkl abc2 EDF2 xyz2 efg jkl abc3 EDF3 xyz3 efg jkl abc4 EDF2 xyz4 ...was entered manually. Though the knowledge of how to parse the list completely is useful to know, as is the package, didn't know about it :)
– Guido Jorg
Mar 22 at 22:42
1
@GuidoJorg Please see my revision.
– Steven B. Segletes
Mar 23 at 1:14
Can you say how to get a sentence in one line to occur, rather than a list? Of the rightmost list in the image? (Also for learning how to write such macros, how does listofitems pull this off, can you suggest? I assume it checks ifx style whether the argument separator occurs or not to decide to loop and relies on a def that that takes one argument and has two cases ... Or calls a package with check for ifempty?)
– Guido Jorg
Mar 22 at 22:36
Can you say how to get a sentence in one line to occur, rather than a list? Of the rightmost list in the image? (Also for learning how to write such macros, how does listofitems pull this off, can you suggest? I assume it checks ifx style whether the argument separator occurs or not to decide to loop and relies on a def that that takes one argument and has two cases ... Or calls a package with check for ifempty?)
– Guido Jorg
Mar 22 at 22:36
@GuidoJorg To learn about the package: ctan.org/pkg/listofitems
– Steven B. Segletes
Mar 22 at 22:39
@GuidoJorg To learn about the package: ctan.org/pkg/listofitems
– Steven B. Segletes
Mar 22 at 22:39
@GuidoJorg As to your request, to make a sentence of the right hand column is not really to parse the list at all, but just to typeset the argument. So could you clarify what you are asking?
– Steven B. Segletes
Mar 22 at 22:40
@GuidoJorg As to your request, to make a sentence of the right hand column is not really to parse the list at all, but just to typeset the argument. So could you clarify what you are asking?
– Steven B. Segletes
Mar 22 at 22:40
The result looking for is what would be printed had
abc1 EDF1 formxyz1 efg jkl abc2 EDF2 formxyz2 efg jkl abc3 EDF3 formxyz3 efg jkl abc4 EDF2 formxyz4 ... been entered manually. When in fact funabc1 EDF1 xyz1 efg jkl abc2 EDF2 xyz2 efg jkl abc3 EDF3 xyz3 efg jkl abc4 EDF2 xyz4 ... was entered manually. Though the knowledge of how to parse the list completely is useful to know, as is the package, didn't know about it :)– Guido Jorg
Mar 22 at 22:42
The result looking for is what would be printed had
abc1 EDF1 formxyz1 efg jkl abc2 EDF2 formxyz2 efg jkl abc3 EDF3 formxyz3 efg jkl abc4 EDF2 formxyz4 ... been entered manually. When in fact funabc1 EDF1 xyz1 efg jkl abc2 EDF2 xyz2 efg jkl abc3 EDF3 xyz3 efg jkl abc4 EDF2 xyz4 ... was entered manually. Though the knowledge of how to parse the list completely is useful to know, as is the package, didn't know about it :)– Guido Jorg
Mar 22 at 22:42
1
1
@GuidoJorg Please see my revision.
– Steven B. Segletes
Mar 23 at 1:14
@GuidoJorg Please see my revision.
– Steven B. Segletes
Mar 23 at 1:14
|
show 3 more comments
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funabc1 EDF1 xyz1 efg jkl abc2 EDF2 xyz2 efg jkl abc3 EDF3 xyz3 efg jkl abc4 EDF2 xyz4andfunabc1 EDF1 xyz1andfunabc1 EDF1 xyz1 efg jkl abc2 EDF2 xyz2 efg jkl abc3 EDF3 xyz3 efg jkl abc4 EDF2 xyz4 ... efg jkl abc12 EDF12 xyz12, etc, equally possible. Some kind of loop required. But note that there would not appear any numbers in the input phrase; the numbers are here to illustrate how long happens to be the list. Just the list is always entered as a specific kind of sentence.– Guido Jorg
Mar 22 at 22:13
Splitting such an input at spaces is easy, and testing for some regular expression too (with expl3) but your description is a bit confusing.
– Ulrike Fischer
Mar 22 at 22:19
Without knowing the rules for applying
formit's really difficult to answer.– egreg
Mar 22 at 22:22
@GuidoJorg I'm not asking what
formshould do, but to which parts it should be applied. Some real world examples might help to understand. As the question stands, it's impossible to guess.– egreg
Mar 22 at 22:41
@egreg to the 3rd, 8th, 13th, 18th ... word in the sentence. Separator can be assumed to repeat. form affects only these parts. And sentence can be arbitrarily long and will end without the separator.
– Guido Jorg
Mar 22 at 22:46