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Filling an area below a curve with a colormap defined by the function of the curve
how to get vertical gradient fill in matlab plotPlot Shaded Area Between Two User-Defined Lines and Beneath Preexisting DataMatlab: contourf or colormap to plot filled ellipses according to radiusMatlab Area Plot: Adjusting box style and tick marksHow do I plot one curve with two different units (y-axes) in the same plot window in MATLAB?How to shade area between horizontal line and curve in Matlab plotArea between line and curve (no function)Matlab - try to get the same curve with Matlab numerical function and ezplotPyhon - Fill under curve, based on the value of the functionPython Matplotlib - Filling Area Between Two Concentric Circles
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty height:90px;width:728px;box-sizing:border-box;
Consider the following plot:
On the left you can see the fill of a circle with respect to a profile of a function using patch command
t = linspace(-pi,pi,100);
c = exp(-cos(t));
figure(1)
patch(cos(t),sin(t),c)
axis equal
On the right you see the profile of the function along the dashed line axis on the left, which is filled using the area command.
figure(2)
area(cos(t),c,0);
what I'm trying to do is fill the area below the curve (right panel) with the colors defined by the colormap of the representation in the left panel. The results should look like this
matlab plot colors matlab-figure area
edited Mar 24 at 13:17
Dev-iL
18.4k64579
asked Mar 24 at 10:44
jarheadjarhead
62541436
add a comment |
Consider the following plot:
On the left you can see the fill of a circle with respect to a profile of a function using patch command
t = linspace(-pi,pi,100);
c = exp(-cos(t));
figure(1)
patch(cos(t),sin(t),c)
axis equal
On the right you see the profile of the function along the dashed line axis on the left, which is filled using the area command.
figure(2)
area(cos(t),c,0);
what I'm trying to do is fill the area below the curve (right panel) with the colors defined by the colormap of the representation in the left panel. The results should look like this
matlab plot colors matlab-figure area
edited Mar 24 at 13:17
Dev-iL
18.4k64579
asked Mar 24 at 10:44
jarheadjarhead
62541436
add a comment |
Consider the following plot:
On the left you can see the fill of a circle with respect to a profile of a function using patch command
t = linspace(-pi,pi,100);
c = exp(-cos(t));
figure(1)
patch(cos(t),sin(t),c)
axis equal
On the right you see the profile of the function along the dashed line axis on the left, which is filled using the area command.
figure(2)
area(cos(t),c,0);
what I'm trying to do is fill the area below the curve (right panel) with the colors defined by the colormap of the representation in the left panel. The results should look like this
matlab plot colors matlab-figure area
edited Mar 24 at 13:17
Dev-iL
18.4k64579
asked Mar 24 at 10:44
jarheadjarhead
62541436
Consider the following plot:
On the left you can see the fill of a circle with respect to a profile of a function using patch command
t = linspace(-pi,pi,100);
c = exp(-cos(t));
figure(1)
patch(cos(t),sin(t),c)
axis equal
On the right you see the profile of the function along the dashed line axis on the left, which is filled using the area command.
figure(2)
area(cos(t),c,0);
what I'm trying to do is fill the area below the curve (right panel) with the colors defined by the colormap of the representation in the left panel. The results should look like this
matlab plot colors matlab-figure area
matlab plot colors matlab-figure area
edited Mar 24 at 13:17
Dev-iL
18.4k64579
asked Mar 24 at 10:44
jarheadjarhead
62541436
edited Mar 24 at 13:17
Dev-iL
18.4k64579
asked Mar 24 at 10:44
jarheadjarhead
62541436
edited Mar 24 at 13:17
Dev-iL
18.4k64579
edited Mar 24 at 13:17
Dev-iL
18.4k64579
edited Mar 24 at 13:17
Dev-iL
18.4k64579
18.4k64579
asked Mar 24 at 10:44
jarheadjarhead
62541436
asked Mar 24 at 10:44
jarheadjarhead
62541436
asked Mar 24 at 10:44
jarheadjarhead
62541436
62541436
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
The closest thing I could come up with is this:
function q55322965
% Evaluate the equation (half domain!)
t = linspace(-pi,0,50);
c = exp(-cos(t));
% Turn vectors into a mesh:
[TT,CC] = meshgrid(cos(t),c);
% Clear all points that are above the curve:
CC(CC > c) = NaN;
% Fill in the rectangle between the chart and zero:
CC(end+1,:) = 0;
TT(end+1,:) = TT(end,:);
% Plot:
figure(); mesh(TT,CC,CC,'FaceColor','interp','EdgeColor','interp'); view([0,90]);
Which yields:
If you want a less jagged look when plotting with this method, you can increase the resolution in t. For example, if we use 500 instead of 50 in the linspace we get:
answered Mar 24 at 12:55
Dev-iLDev-iL
18.4k64579
why did you choose only half of the domain and not the full range [-pi,pi]?
– jarhead
Mar 24 at 15:16
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
The closest thing I could come up with is this:
function q55322965
% Evaluate the equation (half domain!)
t = linspace(-pi,0,50);
c = exp(-cos(t));
% Turn vectors into a mesh:
[TT,CC] = meshgrid(cos(t),c);
% Clear all points that are above the curve:
CC(CC > c) = NaN;
% Fill in the rectangle between the chart and zero:
CC(end+1,:) = 0;
TT(end+1,:) = TT(end,:);
% Plot:
figure(); mesh(TT,CC,CC,'FaceColor','interp','EdgeColor','interp'); view([0,90]);
Which yields:
If you want a less jagged look when plotting with this method, you can increase the resolution in t. For example, if we use 500 instead of 50 in the linspace we get:
answered Mar 24 at 12:55
Dev-iLDev-iL
18.4k64579
why did you choose only half of the domain and not the full range [-pi,pi]?
– jarhead
Mar 24 at 15:16
add a comment |
The closest thing I could come up with is this:
function q55322965
% Evaluate the equation (half domain!)
t = linspace(-pi,0,50);
c = exp(-cos(t));
% Turn vectors into a mesh:
[TT,CC] = meshgrid(cos(t),c);
% Clear all points that are above the curve:
CC(CC > c) = NaN;
% Fill in the rectangle between the chart and zero:
CC(end+1,:) = 0;
TT(end+1,:) = TT(end,:);
% Plot:
figure(); mesh(TT,CC,CC,'FaceColor','interp','EdgeColor','interp'); view([0,90]);
Which yields:
If you want a less jagged look when plotting with this method, you can increase the resolution in t. For example, if we use 500 instead of 50 in the linspace we get:
answered Mar 24 at 12:55
Dev-iLDev-iL
18.4k64579
why did you choose only half of the domain and not the full range [-pi,pi]?
– jarhead
Mar 24 at 15:16
add a comment |
The closest thing I could come up with is this:
function q55322965
% Evaluate the equation (half domain!)
t = linspace(-pi,0,50);
c = exp(-cos(t));
% Turn vectors into a mesh:
[TT,CC] = meshgrid(cos(t),c);
% Clear all points that are above the curve:
CC(CC > c) = NaN;
% Fill in the rectangle between the chart and zero:
CC(end+1,:) = 0;
TT(end+1,:) = TT(end,:);
% Plot:
figure(); mesh(TT,CC,CC,'FaceColor','interp','EdgeColor','interp'); view([0,90]);
Which yields:
If you want a less jagged look when plotting with this method, you can increase the resolution in t. For example, if we use 500 instead of 50 in the linspace we get:
answered Mar 24 at 12:55
Dev-iLDev-iL
18.4k64579
The closest thing I could come up with is this:
function q55322965
% Evaluate the equation (half domain!)
t = linspace(-pi,0,50);
c = exp(-cos(t));
% Turn vectors into a mesh:
[TT,CC] = meshgrid(cos(t),c);
% Clear all points that are above the curve:
CC(CC > c) = NaN;
% Fill in the rectangle between the chart and zero:
CC(end+1,:) = 0;
TT(end+1,:) = TT(end,:);
% Plot:
figure(); mesh(TT,CC,CC,'FaceColor','interp','EdgeColor','interp'); view([0,90]);
Which yields:
If you want a less jagged look when plotting with this method, you can increase the resolution in t. For example, if we use 500 instead of 50 in the linspace we get:
answered Mar 24 at 12:55
Dev-iLDev-iL
18.4k64579
edited Mar 24 at 13:13
answered Mar 24 at 12:55
Dev-iLDev-iL
18.4k64579
answered Mar 24 at 12:55
Dev-iLDev-iL
18.4k64579
answered Mar 24 at 12:55
Dev-iLDev-iL
18.4k64579
18.4k64579
why did you choose only half of the domain and not the full range [-pi,pi]?
– jarhead
Mar 24 at 15:16
add a comment |
why did you choose only half of the domain and not the full range [-pi,pi]?
– jarhead
Mar 24 at 15:16
why did you choose only half of the domain and not the full range [-pi,pi]?
– jarhead
Mar 24 at 15:16
why did you choose only half of the domain and not the full range [-pi,pi]?
– jarhead
Mar 24 at 15:16
add a comment |
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