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There is a logic error in a simple counting algorithm in my java code
How to avoid Java code in JSP files?Can't start Eclipse - Java was started but returned exit code=13How can I “delimit” an integer from a given string?What is the difference between canonical name, simple name and class name in Java Class?How to read characters in a string in javaCount the number of occurrencesWhy is executing Java code in comments with certain Unicode characters allowed?I/P-a string S.O/P: For each digit start from 0-9,print count of their occurrence in S.Print10 lines,each line contain 2 space separated integersHow to print a line and type input in the same lineWould it make any difference giving arguments using scanner class instead of command line arguments?
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So there is a logic error inside my simple java counting words, first of in cmd, it's asking me to type the string twice, when it should show once
I run this in cmd, here is the output:
C:UsersMeDocuments>java count
shapeshifting
shapeshifting
Number of Occurrence of s is 2 in string shapeshifting
s
2
import java.util.Scanner;
public class count5
public static void main(String[] args)
Scanner input = new Scanner(System.in);
String str = input.nextLine();
char key = input.nextLine().charAt(0);
countString(str, key);
public static void countString(String str, char key)
int count = 0;
for (int i = 0; i < str.length(); i++)
if (str.charAt(i) == key)
count++;
System.out.println("Number of Occurrence of "
+ key + " is " + count + " in string " + str);
for (int i = 0; i < count; i++)
System.out.println(key);
if (count > 0)
System.out.println(count);
So here some thing that confuses me:
why is there 3 lines needed allow user to type an input. I thought the previous line already let me enter the input. What is
char key = input.nextLine().charAt(0);needed for, and the previous line? Shouldn't there be only input entering line?Why is there 2 for loops inside the code, don't they do same thing?
java count
edited Mar 24 at 10:59
Ivar
3,026113344
asked Mar 24 at 10:57
javaloverjavalover
31
|
show 1 more comment
So there is a logic error inside my simple java counting words, first of in cmd, it's asking me to type the string twice, when it should show once
I run this in cmd, here is the output:
C:UsersMeDocuments>java count
shapeshifting
shapeshifting
Number of Occurrence of s is 2 in string shapeshifting
s
2
import java.util.Scanner;
public class count5
public static void main(String[] args)
Scanner input = new Scanner(System.in);
String str = input.nextLine();
char key = input.nextLine().charAt(0);
countString(str, key);
public static void countString(String str, char key)
int count = 0;
for (int i = 0; i < str.length(); i++)
if (str.charAt(i) == key)
count++;
System.out.println("Number of Occurrence of "
+ key + " is " + count + " in string " + str);
for (int i = 0; i < count; i++)
System.out.println(key);
if (count > 0)
System.out.println(count);
So here some thing that confuses me:
why is there 3 lines needed allow user to type an input. I thought the previous line already let me enter the input. What is
char key = input.nextLine().charAt(0);needed for, and the previous line? Shouldn't there be only input entering line?Why is there 2 for loops inside the code, don't they do same thing?
java count
edited Mar 24 at 10:59
Ivar
3,026113344
asked Mar 24 at 10:57
javaloverjavalover
31
1
"Why is there 2 for loops inside the code", this is your code so why are you asking this?
– Joakim Danielson
Mar 24 at 11:02
1. What is char key = input.nextLine().charAt(0); needed for : it is getting the first character of the input, thought change it to char key = str.charAt(0); 2. Why is there 2 for loops inside the code, don't they do same thing? .. the first loop is checking if there is match for the first letter form the string, and the second loop is printing the match found the same number of times.
– VSB
Mar 24 at 11:02
@VinodSinghBist can you write a full answer and I will accept it?
– javalover
Mar 24 at 11:07
@javalover please check below, and let me know if that works for you
– VSB
Mar 24 at 11:09
@VinodSinghBist thank you! so one last thing, String str = input.nextLine(); is just to make the input into string and then display at the next line? Is there way to combine the two line into one? Scanner input and string str = input.nextLine():?
– javalover
Mar 24 at 11:13
|
show 1 more comment
So there is a logic error inside my simple java counting words, first of in cmd, it's asking me to type the string twice, when it should show once
I run this in cmd, here is the output:
C:UsersMeDocuments>java count
shapeshifting
shapeshifting
Number of Occurrence of s is 2 in string shapeshifting
s
2
import java.util.Scanner;
public class count5
public static void main(String[] args)
Scanner input = new Scanner(System.in);
String str = input.nextLine();
char key = input.nextLine().charAt(0);
countString(str, key);
public static void countString(String str, char key)
int count = 0;
for (int i = 0; i < str.length(); i++)
if (str.charAt(i) == key)
count++;
System.out.println("Number of Occurrence of "
+ key + " is " + count + " in string " + str);
for (int i = 0; i < count; i++)
System.out.println(key);
if (count > 0)
System.out.println(count);
So here some thing that confuses me:
why is there 3 lines needed allow user to type an input. I thought the previous line already let me enter the input. What is
char key = input.nextLine().charAt(0);needed for, and the previous line? Shouldn't there be only input entering line?Why is there 2 for loops inside the code, don't they do same thing?
java count
edited Mar 24 at 10:59
Ivar
3,026113344
asked Mar 24 at 10:57
javaloverjavalover
31
So there is a logic error inside my simple java counting words, first of in cmd, it's asking me to type the string twice, when it should show once
I run this in cmd, here is the output:
C:UsersMeDocuments>java count
shapeshifting
shapeshifting
Number of Occurrence of s is 2 in string shapeshifting
s
2
import java.util.Scanner;
public class count5
public static void main(String[] args)
Scanner input = new Scanner(System.in);
String str = input.nextLine();
char key = input.nextLine().charAt(0);
countString(str, key);
public static void countString(String str, char key)
int count = 0;
for (int i = 0; i < str.length(); i++)
if (str.charAt(i) == key)
count++;
System.out.println("Number of Occurrence of "
+ key + " is " + count + " in string " + str);
for (int i = 0; i < count; i++)
System.out.println(key);
if (count > 0)
System.out.println(count);
So here some thing that confuses me:
why is there 3 lines needed allow user to type an input. I thought the previous line already let me enter the input. What is
char key = input.nextLine().charAt(0);needed for, and the previous line? Shouldn't there be only input entering line?Why is there 2 for loops inside the code, don't they do same thing?
java count
java count
edited Mar 24 at 10:59
Ivar
3,026113344
asked Mar 24 at 10:57
javaloverjavalover
31
edited Mar 24 at 10:59
Ivar
3,026113344
asked Mar 24 at 10:57
javaloverjavalover
31
edited Mar 24 at 10:59
Ivar
3,026113344
edited Mar 24 at 10:59
Ivar
3,026113344
edited Mar 24 at 10:59
Ivar
3,026113344
3,026113344
asked Mar 24 at 10:57
javaloverjavalover
31
asked Mar 24 at 10:57
javaloverjavalover
31
asked Mar 24 at 10:57
javaloverjavalover
31
31
1
"Why is there 2 for loops inside the code", this is your code so why are you asking this?
– Joakim Danielson
Mar 24 at 11:02
1. What is char key = input.nextLine().charAt(0); needed for : it is getting the first character of the input, thought change it to char key = str.charAt(0); 2. Why is there 2 for loops inside the code, don't they do same thing? .. the first loop is checking if there is match for the first letter form the string, and the second loop is printing the match found the same number of times.
– VSB
Mar 24 at 11:02
@VinodSinghBist can you write a full answer and I will accept it?
– javalover
Mar 24 at 11:07
@javalover please check below, and let me know if that works for you
– VSB
Mar 24 at 11:09
@VinodSinghBist thank you! so one last thing, String str = input.nextLine(); is just to make the input into string and then display at the next line? Is there way to combine the two line into one? Scanner input and string str = input.nextLine():?
– javalover
Mar 24 at 11:13
|
show 1 more comment
1
"Why is there 2 for loops inside the code", this is your code so why are you asking this?
– Joakim Danielson
Mar 24 at 11:02
1. What is char key = input.nextLine().charAt(0); needed for : it is getting the first character of the input, thought change it to char key = str.charAt(0); 2. Why is there 2 for loops inside the code, don't they do same thing? .. the first loop is checking if there is match for the first letter form the string, and the second loop is printing the match found the same number of times.
– VSB
Mar 24 at 11:02
@VinodSinghBist can you write a full answer and I will accept it?
– javalover
Mar 24 at 11:07
@javalover please check below, and let me know if that works for you
– VSB
Mar 24 at 11:09
@VinodSinghBist thank you! so one last thing, String str = input.nextLine(); is just to make the input into string and then display at the next line? Is there way to combine the two line into one? Scanner input and string str = input.nextLine():?
– javalover
Mar 24 at 11:13
1
1
"Why is there 2 for loops inside the code", this is your code so why are you asking this?
– Joakim Danielson
Mar 24 at 11:02
"Why is there 2 for loops inside the code", this is your code so why are you asking this?
– Joakim Danielson
Mar 24 at 11:02
1. What is char key = input.nextLine().charAt(0); needed for : it is getting the first character of the input, thought change it to char key = str.charAt(0); 2. Why is there 2 for loops inside the code, don't they do same thing? .. the first loop is checking if there is match for the first letter form the string, and the second loop is printing the match found the same number of times.
– VSB
Mar 24 at 11:02
1. What is char key = input.nextLine().charAt(0); needed for : it is getting the first character of the input, thought change it to char key = str.charAt(0); 2. Why is there 2 for loops inside the code, don't they do same thing? .. the first loop is checking if there is match for the first letter form the string, and the second loop is printing the match found the same number of times.
– VSB
Mar 24 at 11:02
@VinodSinghBist can you write a full answer and I will accept it?
– javalover
Mar 24 at 11:07
@VinodSinghBist can you write a full answer and I will accept it?
– javalover
Mar 24 at 11:07
@javalover please check below, and let me know if that works for you
– VSB
Mar 24 at 11:09
@javalover please check below, and let me know if that works for you
– VSB
Mar 24 at 11:09
@VinodSinghBist thank you! so one last thing, String str = input.nextLine(); is just to make the input into string and then display at the next line? Is there way to combine the two line into one? Scanner input and string str = input.nextLine():?
– javalover
Mar 24 at 11:13
@VinodSinghBist thank you! so one last thing, String str = input.nextLine(); is just to make the input into string and then display at the next line? Is there way to combine the two line into one? Scanner input and string str = input.nextLine():?
– javalover
Mar 24 at 11:13
|
show 1 more comment
1 Answer
1
active
oldest
votes
Try this solution which should ask for one time input and traverse the complete input string entered for the match
import java.util.Scanner;
public class stringCompair
public static void main(String[] args)
Scanner input = new Scanner(System.in);
String str = input.nextLine();
for(int i=0 ; i < str.length();i++)
char key = str.charAt(i);
countString(str, key);
public static void countString(String str, char key)
int count = 0;
for (int i = 0; i < str.length(); i++)
if (str.charAt(i) == key)
count++;
System.out.println("Number of Occurrence of "
+ key + " is " + count + " in string " + str);
answered Mar 24 at 11:08
VSBVSB
25229
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Try this solution which should ask for one time input and traverse the complete input string entered for the match
import java.util.Scanner;
public class stringCompair
public static void main(String[] args)
Scanner input = new Scanner(System.in);
String str = input.nextLine();
for(int i=0 ; i < str.length();i++)
char key = str.charAt(i);
countString(str, key);
public static void countString(String str, char key)
int count = 0;
for (int i = 0; i < str.length(); i++)
if (str.charAt(i) == key)
count++;
System.out.println("Number of Occurrence of "
+ key + " is " + count + " in string " + str);
answered Mar 24 at 11:08
VSBVSB
25229
add a comment |
Try this solution which should ask for one time input and traverse the complete input string entered for the match
import java.util.Scanner;
public class stringCompair
public static void main(String[] args)
Scanner input = new Scanner(System.in);
String str = input.nextLine();
for(int i=0 ; i < str.length();i++)
char key = str.charAt(i);
countString(str, key);
public static void countString(String str, char key)
int count = 0;
for (int i = 0; i < str.length(); i++)
if (str.charAt(i) == key)
count++;
System.out.println("Number of Occurrence of "
+ key + " is " + count + " in string " + str);
answered Mar 24 at 11:08
VSBVSB
25229
add a comment |
Try this solution which should ask for one time input and traverse the complete input string entered for the match
import java.util.Scanner;
public class stringCompair
public static void main(String[] args)
Scanner input = new Scanner(System.in);
String str = input.nextLine();
for(int i=0 ; i < str.length();i++)
char key = str.charAt(i);
countString(str, key);
public static void countString(String str, char key)
int count = 0;
for (int i = 0; i < str.length(); i++)
if (str.charAt(i) == key)
count++;
System.out.println("Number of Occurrence of "
+ key + " is " + count + " in string " + str);
answered Mar 24 at 11:08
VSBVSB
25229
Try this solution which should ask for one time input and traverse the complete input string entered for the match
import java.util.Scanner;
public class stringCompair
public static void main(String[] args)
Scanner input = new Scanner(System.in);
String str = input.nextLine();
for(int i=0 ; i < str.length();i++)
char key = str.charAt(i);
countString(str, key);
public static void countString(String str, char key)
int count = 0;
for (int i = 0; i < str.length(); i++)
if (str.charAt(i) == key)
count++;
System.out.println("Number of Occurrence of "
+ key + " is " + count + " in string " + str);
answered Mar 24 at 11:08
VSBVSB
25229
answered Mar 24 at 11:08
VSBVSB
25229
answered Mar 24 at 11:08
VSBVSB
25229
answered Mar 24 at 11:08
VSBVSB
25229
25229
add a comment |
add a comment |
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1
"Why is there 2 for loops inside the code", this is your code so why are you asking this?
– Joakim Danielson
Mar 24 at 11:02
1. What is char key = input.nextLine().charAt(0); needed for : it is getting the first character of the input, thought change it to char key = str.charAt(0); 2. Why is there 2 for loops inside the code, don't they do same thing? .. the first loop is checking if there is match for the first letter form the string, and the second loop is printing the match found the same number of times.
– VSB
Mar 24 at 11:02
@VinodSinghBist can you write a full answer and I will accept it?
– javalover
Mar 24 at 11:07
@javalover please check below, and let me know if that works for you
– VSB
Mar 24 at 11:09
@VinodSinghBist thank you! so one last thing, String str = input.nextLine(); is just to make the input into string and then display at the next line? Is there way to combine the two line into one? Scanner input and string str = input.nextLine():?
– javalover
Mar 24 at 11:13