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1

I have a column within a data.frame with multiple occurrences of each of its unique values which i need to replace with different values. How can I achieve this?

I created a factor of the unique values and tried replacing each element by looping over the factor levels using the gsub function

nf <- factor(1, 2, 3, 4, 5, 6)
let <- c("a", "b", "c", "d", "e", "f")

dat <- c(1, 2, 2, 3, 3, 3, 4, 4, 4, 4, 5, 5, 5, 5, 5, 6, 6, 6, 6, 6, 6)

dat <- for (i in levels(nf))
gsub(i,let[i], dat

I expected an output of :

"a" "b" "b" "c" "c" "c" "d" "d" "d" "d" "e" "e" "e" "e" "e" "f" "f" "f" "f" "f" "f" 

but instead I get: NULL.

r vector

share|improve this question

edited Mar 24 at 14:00

NelsonGon

5,2244934

asked Mar 24 at 10:29

Gboyega.AGboyega.A

82

add a comment | 

1

I have a column within a data.frame with multiple occurrences of each of its unique values which i need to replace with different values. How can I achieve this?

I created a factor of the unique values and tried replacing each element by looping over the factor levels using the gsub function

nf <- factor(1, 2, 3, 4, 5, 6)
let <- c("a", "b", "c", "d", "e", "f")

dat <- c(1, 2, 2, 3, 3, 3, 4, 4, 4, 4, 5, 5, 5, 5, 5, 6, 6, 6, 6, 6, 6)

dat <- for (i in levels(nf))
gsub(i,let[i], dat

I expected an output of :

"a" "b" "b" "c" "c" "c" "d" "d" "d" "d" "e" "e" "e" "e" "e" "f" "f" "f" "f" "f" "f" 

but instead I get: NULL.

r vector

share|improve this question

edited Mar 24 at 14:00

NelsonGon

5,2244934

asked Mar 24 at 10:29

Gboyega.AGboyega.A

82

add a comment | 

I have a column within a data.frame with multiple occurrences of each of its unique values which i need to replace with different values. How can I achieve this?

I created a factor of the unique values and tried replacing each element by looping over the factor levels using the gsub function

nf <- factor(1, 2, 3, 4, 5, 6)
let <- c("a", "b", "c", "d", "e", "f")

dat <- c(1, 2, 2, 3, 3, 3, 4, 4, 4, 4, 5, 5, 5, 5, 5, 6, 6, 6, 6, 6, 6)

dat <- for (i in levels(nf))
gsub(i,let[i], dat

I expected an output of :

"a" "b" "b" "c" "c" "c" "d" "d" "d" "d" "e" "e" "e" "e" "e" "f" "f" "f" "f" "f" "f" 

but instead I get: NULL.

r vector

share|improve this question

edited Mar 24 at 14:00

NelsonGon

5,2244934

asked Mar 24 at 10:29

Gboyega.AGboyega.A

82

nf <- factor(1, 2, 3, 4, 5, 6)
let <- c("a", "b", "c", "d", "e", "f")

dat <- c(1, 2, 2, 3, 3, 3, 4, 4, 4, 4, 5, 5, 5, 5, 5, 6, 6, 6, 6, 6, 6)

dat <- for (i in levels(nf))
gsub(i,let[i], dat

"a" "b" "b" "c" "c" "c" "d" "d" "d" "d" "e" "e" "e" "e" "e" "f" "f" "f" "f" "f" "f" 

share|improve this question

edited Mar 24 at 14:00

NelsonGon

5,2244934

asked Mar 24 at 10:29

Gboyega.AGboyega.A

82

share|improve this question

edited Mar 24 at 14:00

NelsonGon

5,2244934

asked Mar 24 at 10:29

Gboyega.AGboyega.A

82

edited Mar 24 at 14:00

NelsonGon

5,2244934

edited Mar 24 at 14:00

NelsonGon

5,2244934

asked Mar 24 at 10:29

Gboyega.AGboyega.A

82

asked Mar 24 at 10:29

Gboyega.AGboyega.A

82

1 Answer
1

active

oldest

votes

2

Are you just after

let[dat]
#[1] "a" "b" "b" "c" "c" "c" "d" "d" "d" "d" "e" "e" "e" "e" "e" "f" "f" "f" "f"
#[20] "f" "f"

Or if you prefer a factor

factor(dat, labels = let)

share|improve this answer

edited Mar 24 at 10:39

answered Mar 24 at 10:35

Maurits EversMaurits Evers

32.6k41738

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @Gboyega.A If this answers your question please consider closing the question by setting the green checkmark next to the answer. That way you help keeping SO tidy and make it easier for future SO users to identify relevant questions. It also awards a small reputation bonus to both the original poster and answerer.
  
  – Maurits Evers
  Mar 26 at 7:51
  
  

  
  
  
  

add a comment | 

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2

Are you just after

let[dat]
#[1] "a" "b" "b" "c" "c" "c" "d" "d" "d" "d" "e" "e" "e" "e" "e" "f" "f" "f" "f"
#[20] "f" "f"

Or if you prefer a factor

factor(dat, labels = let)

share|improve this answer

edited Mar 24 at 10:39

answered Mar 24 at 10:35

Maurits EversMaurits Evers

32.6k41738

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @Gboyega.A If this answers your question please consider closing the question by setting the green checkmark next to the answer. That way you help keeping SO tidy and make it easier for future SO users to identify relevant questions. It also awards a small reputation bonus to both the original poster and answerer.
  
  – Maurits Evers
  Mar 26 at 7:51
  
  

  
  
  
  

add a comment | 

2

Are you just after

let[dat]
#[1] "a" "b" "b" "c" "c" "c" "d" "d" "d" "d" "e" "e" "e" "e" "e" "f" "f" "f" "f"
#[20] "f" "f"

Or if you prefer a factor

factor(dat, labels = let)

share|improve this answer

edited Mar 24 at 10:39

answered Mar 24 at 10:35

Maurits EversMaurits Evers

32.6k41738

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @Gboyega.A If this answers your question please consider closing the question by setting the green checkmark next to the answer. That way you help keeping SO tidy and make it easier for future SO users to identify relevant questions. It also awards a small reputation bonus to both the original poster and answerer.
  
  – Maurits Evers
  Mar 26 at 7:51
  
  

  
  
  
  

add a comment | 

Are you just after

let[dat]
#[1] "a" "b" "b" "c" "c" "c" "d" "d" "d" "d" "e" "e" "e" "e" "e" "f" "f" "f" "f"
#[20] "f" "f"

Or if you prefer a factor

factor(dat, labels = let)

share|improve this answer

edited Mar 24 at 10:39

answered Mar 24 at 10:35

Maurits EversMaurits Evers

32.6k41738

let[dat]
#[1] "a" "b" "b" "c" "c" "c" "d" "d" "d" "d" "e" "e" "e" "e" "e" "f" "f" "f" "f"
#[20] "f" "f"

factor(dat, labels = let)

share|improve this answer

edited Mar 24 at 10:39

answered Mar 24 at 10:35

Maurits EversMaurits Evers

32.6k41738

answered Mar 24 at 10:35

Maurits EversMaurits Evers

32.6k41738

answered Mar 24 at 10:35

Maurits EversMaurits Evers

32.6k41738