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How to provoke an error in my program to display the printstacktrace
How do I efficiently iterate over each entry in a Java Map?How do I call one constructor from another in Java?How do I read / convert an InputStream into a String in Java?How do I generate random integers within a specific range in Java?The case against checked exceptionsHow do I determine whether an array contains a particular value in Java?How to set java_home on Windows 7?How do I convert a String to an int in Java?How do I fix android.os.NetworkOnMainThreadException?Can't start Eclipse - Java was started but returned exit code=13
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How do I provoke an error so that the exc.printStackTrace(System.out); is displayed when I run the program:
public String getName()
try
if(haveName()) return Name;
else
throw new CorrectNameException("no name");
catch (ExistException e)
return e.getExc();
catch (CorrectNameException exc)
exc.printStackTrace(System.out);
return "nameless";
java printstacktrace
edited Mar 24 at 13:40
Tobias Wilfert
83931122
asked Mar 24 at 13:21
TaraTara
32
add a comment |
How do I provoke an error so that the exc.printStackTrace(System.out); is displayed when I run the program:
public String getName()
try
if(haveName()) return Name;
else
throw new CorrectNameException("no name");
catch (ExistException e)
return e.getExc();
catch (CorrectNameException exc)
exc.printStackTrace(System.out);
return "nameless";
java printstacktrace
edited Mar 24 at 13:40
Tobias Wilfert
83931122
asked Mar 24 at 13:21
TaraTara
32
What is wrong with what you have?
– Andronicus
Mar 24 at 13:22
nothing's wrong, my professor asked me to provoke an error in my program so that the stacktrace from the attached program is printed on the console when the program is executed
– Tara
Mar 24 at 13:31
You need to understand your own code. The stack trace is printed when a CorrectNameException is caught. Such an exception is thrown and then caught if the else block is executed. The else block is executed ifhaveName()returns false. So, for the stack trace to be printed, haveName() must return false. You haven't posted its code, so we don't know when it returns false and when it returns true. Read its code, and make logical deductions.
– JB Nizet
Mar 24 at 14:01
thanks) i managed
– Tara
Mar 24 at 14:40
Although there is some sort of entertaining irony in that, the nameCorrectNameExceptionmakes me shudder. Sounds like anEverythingIsFineException, and the usual case is that everything is not fine... However, just a remark: In the pain of debugging, I consider it as legitimate to occasionally throw in anew Exception().printStackTrace()anywhere in the code, just to see where the call came from (although usually, a debugger shows you that, when you add a breakpoint)
– Marco13
Mar 24 at 16:13
add a comment |
How do I provoke an error so that the exc.printStackTrace(System.out); is displayed when I run the program:
public String getName()
try
if(haveName()) return Name;
else
throw new CorrectNameException("no name");
catch (ExistException e)
return e.getExc();
catch (CorrectNameException exc)
exc.printStackTrace(System.out);
return "nameless";
java printstacktrace
edited Mar 24 at 13:40
Tobias Wilfert
83931122
asked Mar 24 at 13:21
TaraTara
32
How do I provoke an error so that the exc.printStackTrace(System.out); is displayed when I run the program:
public String getName()
try
if(haveName()) return Name;
else
throw new CorrectNameException("no name");
catch (ExistException e)
return e.getExc();
catch (CorrectNameException exc)
exc.printStackTrace(System.out);
return "nameless";
java printstacktrace
java printstacktrace
edited Mar 24 at 13:40
Tobias Wilfert
83931122
asked Mar 24 at 13:21
TaraTara
32
edited Mar 24 at 13:40
Tobias Wilfert
83931122
asked Mar 24 at 13:21
TaraTara
32
edited Mar 24 at 13:40
Tobias Wilfert
83931122
edited Mar 24 at 13:40
Tobias Wilfert
83931122
edited Mar 24 at 13:40
Tobias Wilfert
83931122
83931122
asked Mar 24 at 13:21
TaraTara
32
asked Mar 24 at 13:21
TaraTara
32
asked Mar 24 at 13:21
TaraTara
32
32
What is wrong with what you have?
– Andronicus
Mar 24 at 13:22
nothing's wrong, my professor asked me to provoke an error in my program so that the stacktrace from the attached program is printed on the console when the program is executed
– Tara
Mar 24 at 13:31
You need to understand your own code. The stack trace is printed when a CorrectNameException is caught. Such an exception is thrown and then caught if the else block is executed. The else block is executed ifhaveName()returns false. So, for the stack trace to be printed, haveName() must return false. You haven't posted its code, so we don't know when it returns false and when it returns true. Read its code, and make logical deductions.
– JB Nizet
Mar 24 at 14:01
thanks) i managed
– Tara
Mar 24 at 14:40
Although there is some sort of entertaining irony in that, the nameCorrectNameExceptionmakes me shudder. Sounds like anEverythingIsFineException, and the usual case is that everything is not fine... However, just a remark: In the pain of debugging, I consider it as legitimate to occasionally throw in anew Exception().printStackTrace()anywhere in the code, just to see where the call came from (although usually, a debugger shows you that, when you add a breakpoint)
– Marco13
Mar 24 at 16:13
add a comment |
What is wrong with what you have?
– Andronicus
Mar 24 at 13:22
nothing's wrong, my professor asked me to provoke an error in my program so that the stacktrace from the attached program is printed on the console when the program is executed
– Tara
Mar 24 at 13:31
You need to understand your own code. The stack trace is printed when a CorrectNameException is caught. Such an exception is thrown and then caught if the else block is executed. The else block is executed ifhaveName()returns false. So, for the stack trace to be printed, haveName() must return false. You haven't posted its code, so we don't know when it returns false and when it returns true. Read its code, and make logical deductions.
– JB Nizet
Mar 24 at 14:01
thanks) i managed
– Tara
Mar 24 at 14:40
Although there is some sort of entertaining irony in that, the nameCorrectNameExceptionmakes me shudder. Sounds like anEverythingIsFineException, and the usual case is that everything is not fine... However, just a remark: In the pain of debugging, I consider it as legitimate to occasionally throw in anew Exception().printStackTrace()anywhere in the code, just to see where the call came from (although usually, a debugger shows you that, when you add a breakpoint)
– Marco13
Mar 24 at 16:13
What is wrong with what you have?
– Andronicus
Mar 24 at 13:22
What is wrong with what you have?
– Andronicus
Mar 24 at 13:22
nothing's wrong, my professor asked me to provoke an error in my program so that the stacktrace from the attached program is printed on the console when the program is executed
– Tara
Mar 24 at 13:31
nothing's wrong, my professor asked me to provoke an error in my program so that the stacktrace from the attached program is printed on the console when the program is executed
– Tara
Mar 24 at 13:31
You need to understand your own code. The stack trace is printed when a CorrectNameException is caught. Such an exception is thrown and then caught if the else block is executed. The else block is executed if
haveName() returns false. So, for the stack trace to be printed, haveName() must return false. You haven't posted its code, so we don't know when it returns false and when it returns true. Read its code, and make logical deductions.– JB Nizet
Mar 24 at 14:01
You need to understand your own code. The stack trace is printed when a CorrectNameException is caught. Such an exception is thrown and then caught if the else block is executed. The else block is executed if
haveName() returns false. So, for the stack trace to be printed, haveName() must return false. You haven't posted its code, so we don't know when it returns false and when it returns true. Read its code, and make logical deductions.– JB Nizet
Mar 24 at 14:01
thanks) i managed
– Tara
Mar 24 at 14:40
thanks) i managed
– Tara
Mar 24 at 14:40
Although there is some sort of entertaining irony in that, the name
CorrectNameException makes me shudder. Sounds like an EverythingIsFineException, and the usual case is that everything is not fine... However, just a remark: In the pain of debugging, I consider it as legitimate to occasionally throw in a new Exception().printStackTrace() anywhere in the code, just to see where the call came from (although usually, a debugger shows you that, when you add a breakpoint)– Marco13
Mar 24 at 16:13
Although there is some sort of entertaining irony in that, the name
CorrectNameException makes me shudder. Sounds like an EverythingIsFineException, and the usual case is that everything is not fine... However, just a remark: In the pain of debugging, I consider it as legitimate to occasionally throw in a new Exception().printStackTrace() anywhere in the code, just to see where the call came from (although usually, a debugger shows you that, when you add a breakpoint)– Marco13
Mar 24 at 16:13
add a comment |
2 Answers
2
active
oldest
votes
Make haveName() return false. Simple.
answered Mar 24 at 13:29
Benjamin UrquhartBenjamin Urquhart
1,290514
well i'm not too smart, how do i do that? like this " if(haveName()) return false;"
– Tara
Mar 24 at 13:56
public boolean haveName()return false;?
– Benjamin Urquhart
Mar 24 at 13:56
add a comment |
According to what you posted in question, answer would be "When haveName() method returns false"
But If you explain complete use case, we can rectify your code a little bit. As per my understanding your method is checking two things.
- Name exist or not?
- Name is valid or not?
So I have couple of question regarding your query:
- Does method haveName() check for existence and validity both? (or only for existence).
- Are you throwing any exception inside haveName() method?
answered Mar 24 at 14:09
Piyush NPiyush N
746
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
Make haveName() return false. Simple.
answered Mar 24 at 13:29
Benjamin UrquhartBenjamin Urquhart
1,290514
well i'm not too smart, how do i do that? like this " if(haveName()) return false;"
– Tara
Mar 24 at 13:56
public boolean haveName()return false;?
– Benjamin Urquhart
Mar 24 at 13:56
add a comment |
Make haveName() return false. Simple.
answered Mar 24 at 13:29
Benjamin UrquhartBenjamin Urquhart
1,290514
well i'm not too smart, how do i do that? like this " if(haveName()) return false;"
– Tara
Mar 24 at 13:56
public boolean haveName()return false;?
– Benjamin Urquhart
Mar 24 at 13:56
add a comment |
Make haveName() return false. Simple.
answered Mar 24 at 13:29
Benjamin UrquhartBenjamin Urquhart
1,290514
Make haveName() return false. Simple.
answered Mar 24 at 13:29
Benjamin UrquhartBenjamin Urquhart
1,290514
answered Mar 24 at 13:29
Benjamin UrquhartBenjamin Urquhart
1,290514
answered Mar 24 at 13:29
Benjamin UrquhartBenjamin Urquhart
1,290514
answered Mar 24 at 13:29
Benjamin UrquhartBenjamin Urquhart
1,290514
1,290514
well i'm not too smart, how do i do that? like this " if(haveName()) return false;"
– Tara
Mar 24 at 13:56
public boolean haveName()return false;?
– Benjamin Urquhart
Mar 24 at 13:56
add a comment |
well i'm not too smart, how do i do that? like this " if(haveName()) return false;"
– Tara
Mar 24 at 13:56
public boolean haveName()return false;?
– Benjamin Urquhart
Mar 24 at 13:56
well i'm not too smart, how do i do that? like this " if(haveName()) return false;"
– Tara
Mar 24 at 13:56
well i'm not too smart, how do i do that? like this " if(haveName()) return false;"
– Tara
Mar 24 at 13:56
public boolean haveName()return false;?– Benjamin Urquhart
Mar 24 at 13:56
public boolean haveName()return false;?– Benjamin Urquhart
Mar 24 at 13:56
add a comment |
According to what you posted in question, answer would be "When haveName() method returns false"
But If you explain complete use case, we can rectify your code a little bit. As per my understanding your method is checking two things.
- Name exist or not?
- Name is valid or not?
So I have couple of question regarding your query:
- Does method haveName() check for existence and validity both? (or only for existence).
- Are you throwing any exception inside haveName() method?
answered Mar 24 at 14:09
Piyush NPiyush N
746
add a comment |
According to what you posted in question, answer would be "When haveName() method returns false"
But If you explain complete use case, we can rectify your code a little bit. As per my understanding your method is checking two things.
- Name exist or not?
- Name is valid or not?
So I have couple of question regarding your query:
- Does method haveName() check for existence and validity both? (or only for existence).
- Are you throwing any exception inside haveName() method?
answered Mar 24 at 14:09
Piyush NPiyush N
746
add a comment |
According to what you posted in question, answer would be "When haveName() method returns false"
But If you explain complete use case, we can rectify your code a little bit. As per my understanding your method is checking two things.
- Name exist or not?
- Name is valid or not?
So I have couple of question regarding your query:
- Does method haveName() check for existence and validity both? (or only for existence).
- Are you throwing any exception inside haveName() method?
answered Mar 24 at 14:09
Piyush NPiyush N
746
According to what you posted in question, answer would be "When haveName() method returns false"
But If you explain complete use case, we can rectify your code a little bit. As per my understanding your method is checking two things.
- Name exist or not?
- Name is valid or not?
So I have couple of question regarding your query:
- Does method haveName() check for existence and validity both? (or only for existence).
- Are you throwing any exception inside haveName() method?
answered Mar 24 at 14:09
Piyush NPiyush N
746
answered Mar 24 at 14:09
Piyush NPiyush N
746
answered Mar 24 at 14:09
Piyush NPiyush N
746
answered Mar 24 at 14:09
Piyush NPiyush N
746
746
add a comment |
add a comment |
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What is wrong with what you have?
– Andronicus
Mar 24 at 13:22
nothing's wrong, my professor asked me to provoke an error in my program so that the stacktrace from the attached program is printed on the console when the program is executed
– Tara
Mar 24 at 13:31
You need to understand your own code. The stack trace is printed when a CorrectNameException is caught. Such an exception is thrown and then caught if the else block is executed. The else block is executed if
haveName()returns false. So, for the stack trace to be printed, haveName() must return false. You haven't posted its code, so we don't know when it returns false and when it returns true. Read its code, and make logical deductions.– JB Nizet
Mar 24 at 14:01
thanks) i managed
– Tara
Mar 24 at 14:40
Although there is some sort of entertaining irony in that, the name
CorrectNameExceptionmakes me shudder. Sounds like anEverythingIsFineException, and the usual case is that everything is not fine... However, just a remark: In the pain of debugging, I consider it as legitimate to occasionally throw in anew Exception().printStackTrace()anywhere in the code, just to see where the call came from (although usually, a debugger shows you that, when you add a breakpoint)– Marco13
Mar 24 at 16:13