Select key from jsonb postgreSQL using Hibernate Criteria query in JavaJPA and Hibernate - Criteria vs. JPQL or HQLHow do I call one constructor from another in Java?How do I create a Java string from the contents of a file?How to get an enum value from a string value in Java?Wrong ordering in generated table in jpaSave PL/pgSQL output from PostgreSQL to a CSV filehow to select value from database using hibernate?want to add two different tables(classes) in one hibernate criteriaHow to exit from PostgreSQL command line utility: psqlExplanation of JSONB introduced by PostgreSQL

Create less file for custom Theme

How is CoreiX like Corei5, i7 is related to Haswell, Ivy Bridge?

Further factorisation of a difference of cubes?

How are one-time password generators like Google Authenticator different from having two passwords?

How do I compare the result of "1d20+x, with advantage" to "1d20+y, without advantage", assuming x < y?

Are there variations of the regular runtimes of the Big-O-Notation?

Company threw a surprise party for the CEO, 3 weeks later management says we have to pay for it, do I have to?

Why can't I prove summation identities without guessing?

Is a vertical stabiliser needed for straight line flight in a glider?

Early arrival in Australia, early check in not available

Passport stamps art, can it be done?

Why do unstable nuclei form?

Can more than one creature benefit from multiple Hunter's Mark spells cast on the same target?

Thesis' "Future Work" section – is it acceptable to omit personal involvement in a mentioned project?

Remove color cast in darktable?

Why are low spin tetrahedral complexes so rare?

Why are parallelograms defined as quadrilaterals? What term would encompass polygons with greater than two parallel pairs?

What is the name of meteoroids which hit Moon, Mars, or pretty much anything that isn’t the Earth?

Two researchers want to work on the same extension to my paper. Who to help?

Can 'sudo apt-get remove [write]' destroy my Ubuntu?

Is there any evidence to support the claim that the United States was "suckered into WW1" by Zionists, made by Benjamin Freedman in his 1961 speech

What does formal training in a field mean?

How to slow yourself down (for playing nice with others)

Is it a Munchausen Number?

Select key from jsonb postgreSQL using Hibernate Criteria query in Java

JPA and Hibernate - Criteria vs. JPQL or HQLHow do I call one constructor from another in Java?How do I create a Java string from the contents of a file?How to get an enum value from a string value in Java?Wrong ordering in generated table in jpaSave PL/pgSQL output from PostgreSQL to a CSV filehow to select value from database using hibernate?want to add two different tables(classes) in one hibernate criteriaHow to exit from PostgreSQL command line utility: psqlExplanation of JSONB introduced by PostgreSQL

.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty height:90px;width:728px;box-sizing:border-box;

I am writing the criteria query to get results for jsonb in postgres.I can query the jsonb column through hibernate.I am unable to fetch jsonb specific keys.I am not able to find a way.

I have tried native query but i want some wayout in hibernate criteria query.The commonjson argument is the jsonb in postgresql is this --

"appl_id": 726516, "applied_by": "pankajkumarnnl94@gmail.com", "service_id": 9880004, "version_no": 4, "appl_ref_no": "BSEH/2018/00728", "sub_version": 1, "payment_date": "2018-12-04T11:54:20.24+05:30", "payment_mode": "PayUbizz", "reference_no": "7726929249", "service_name": "Migration Certificate Board of School Education Haryana, Bhiwani", "department_id": 784, "location_value": 1218758, "base_service_id": 988, "department_name": " Board of School Education Haryana", "registration_id": "", "submission_date": "2018-12-04", "submission_mode": "online", "no_of_attachment": 2, "submission_location": "1578947~1218758~Board of School Education Haryana"

Model Class ->ApplInfoJson

package com.saral.reporting.model;

import java.util.Map;

import javax.persistence.Column;
import javax.persistence.Entity;
import javax.persistence.GeneratedValue;
import javax.persistence.GenerationType;
import javax.persistence.Id;
import javax.persistence.Table;

import org.hibernate.annotations.Type;

import com.fasterxml.jackson.annotation.JsonProperty;

@Entity
@Table(name = "r_app_json",schema="saral1", catalog="saral1")

public class ApplInfoJson 

 @Id
 @Column(name = "aid")
 @GeneratedValue(strategy = GenerationType.IDENTITY)
 private Long aid;

 @Column(name = "id")
 private Long id;

 @JsonProperty("appl_info")
 @Column(name = "appl_info")
 private String applInfo;


 @Column(name = "application_form_attributes")
 private String applicationFormAttributes;

 @Column(name = "enclosure_data")
 private String enclosureData;

 @Column(name = "service_id")
 private Long serviceId;

 @Column(name = "combined_json")
 @Type(type = "JsonDataUserType")
 private Map<String , Object> combinedJson;

 @Column(name ="location_value")
 private Long locationValue;


 public Long getLocationValue() 
 return locationValue;
 

 public void setLocationValue(Long locationValue) 
 this.locationValue = locationValue;
 

 public Long getServiceId() 
 return serviceId;
 

 public void setServiceId(Long serviceId) 
 this.serviceId = serviceId;
 

 public Long getAid() 
 return aid;
 

 public void setAid(Long aid) 
 this.aid = aid;
 

 public Long getId() 
 return id;
 

 public void setId(Long id) 
 this.id = id;
 

 public String getApplInfo() 
 return applInfo;
 

 public void setApplInfo(String applInfo) 
 this.applInfo = applInfo;
 

 public String getApplicationFormAttributes() 
 return applicationFormAttributes;
 

 public void setApplicationFormAttributes(String applicationFormAttributes) 
 this.applicationFormAttributes = applicationFormAttributes;
 

 public String getEnclosureData() 
 return enclosureData;
 

 public void setEnclosureData(String enclosureData) 
 this.enclosureData = enclosureData;
 




 public Map<String, Object> getCombinedJson() 
 return combinedJson;
 

 public void setCombinedJson(Map<String, Object> combinedJson) 
 this.combinedJson = combinedJson;
 

 @Override
 public String toString() 
 return "ApplInfoJson [aid=" + aid + ", id=" + id + ", applInfo=" + applInfo + ", applicationFormAttributes="
 + applicationFormAttributes + ", enclosureData=" + enclosureData + ", serviceId=" + serviceId
 + ", combinedJson=" + combinedJson + ", locationValue=" + locationValue + "]";

Function Used->

public List<ApplInfoJson> findByCombinedJson(String commonJson) 

 DetachedCriteria criteria = DetachedCriteria.forClass(ApplInfoJson.class);

 List<ApplInfoJson> results = (List<ApplInfoJson>) getHibernateTemplate().findByCriteria(criteria);

 return results;

I want some thing to pass key name and get data with specific key.

edited Mar 28 at 9:30

asked Mar 23 at 10:01

shanu dua

113

You can use functions which are available since JPA 2.1.

– Ancoron
Mar 23 at 10:59

@Ancoron how can i do that ??

– shanu dua
Mar 25 at 4:17

Use the standard CriteriaBuilder#function. Example: github.com/thjanssen/HibernateTips/blob/master/…

– Ancoron
Mar 25 at 5:53

Thanks i have seen the code but i want to select appl_id from json .how can i do that @Ancoron

– shanu dua
Mar 25 at 10:12

You need to use function json_extract_path_text(combined_json, 'appl_info') (assuming that column combined_json contains the JSON. Translated into Criteria Query, this means something like: cb.function("json_extract_path_text", String.class, root.get(ApplInfoJson_.combinedJson), "appl_info")

– Ancoron
Mar 28 at 22:13

add a comment |

I am writing the criteria query to get results for jsonb in postgres.I can query the jsonb column through hibernate.I am unable to fetch jsonb specific keys.I am not able to find a way.

I have tried native query but i want some wayout in hibernate criteria query.The commonjson argument is the jsonb in postgresql is this --

"appl_id": 726516, "applied_by": "pankajkumarnnl94@gmail.com", "service_id": 9880004, "version_no": 4, "appl_ref_no": "BSEH/2018/00728", "sub_version": 1, "payment_date": "2018-12-04T11:54:20.24+05:30", "payment_mode": "PayUbizz", "reference_no": "7726929249", "service_name": "Migration Certificate Board of School Education Haryana, Bhiwani", "department_id": 784, "location_value": 1218758, "base_service_id": 988, "department_name": " Board of School Education Haryana", "registration_id": "", "submission_date": "2018-12-04", "submission_mode": "online", "no_of_attachment": 2, "submission_location": "1578947~1218758~Board of School Education Haryana"

Model Class ->ApplInfoJson

package com.saral.reporting.model;

import java.util.Map;

import javax.persistence.Column;
import javax.persistence.Entity;
import javax.persistence.GeneratedValue;
import javax.persistence.GenerationType;
import javax.persistence.Id;
import javax.persistence.Table;

import org.hibernate.annotations.Type;

import com.fasterxml.jackson.annotation.JsonProperty;

@Entity
@Table(name = "r_app_json",schema="saral1", catalog="saral1")

public class ApplInfoJson 

 @Id
 @Column(name = "aid")
 @GeneratedValue(strategy = GenerationType.IDENTITY)
 private Long aid;

 @Column(name = "id")
 private Long id;

 @JsonProperty("appl_info")
 @Column(name = "appl_info")
 private String applInfo;


 @Column(name = "application_form_attributes")
 private String applicationFormAttributes;

 @Column(name = "enclosure_data")
 private String enclosureData;

 @Column(name = "service_id")
 private Long serviceId;

 @Column(name = "combined_json")
 @Type(type = "JsonDataUserType")
 private Map<String , Object> combinedJson;

 @Column(name ="location_value")
 private Long locationValue;


 public Long getLocationValue() 
 return locationValue;
 

 public void setLocationValue(Long locationValue) 
 this.locationValue = locationValue;
 

 public Long getServiceId() 
 return serviceId;
 

 public void setServiceId(Long serviceId) 
 this.serviceId = serviceId;
 

 public Long getAid() 
 return aid;
 

 public void setAid(Long aid) 
 this.aid = aid;
 

 public Long getId() 
 return id;
 

 public void setId(Long id) 
 this.id = id;
 

 public String getApplInfo() 
 return applInfo;
 

 public void setApplInfo(String applInfo) 
 this.applInfo = applInfo;
 

 public String getApplicationFormAttributes() 
 return applicationFormAttributes;
 

 public void setApplicationFormAttributes(String applicationFormAttributes) 
 this.applicationFormAttributes = applicationFormAttributes;
 

 public String getEnclosureData() 
 return enclosureData;
 

 public void setEnclosureData(String enclosureData) 
 this.enclosureData = enclosureData;
 




 public Map<String, Object> getCombinedJson() 
 return combinedJson;
 

 public void setCombinedJson(Map<String, Object> combinedJson) 
 this.combinedJson = combinedJson;
 

 @Override
 public String toString() 
 return "ApplInfoJson [aid=" + aid + ", id=" + id + ", applInfo=" + applInfo + ", applicationFormAttributes="
 + applicationFormAttributes + ", enclosureData=" + enclosureData + ", serviceId=" + serviceId
 + ", combinedJson=" + combinedJson + ", locationValue=" + locationValue + "]";

Function Used->

public List<ApplInfoJson> findByCombinedJson(String commonJson) 

 DetachedCriteria criteria = DetachedCriteria.forClass(ApplInfoJson.class);

 List<ApplInfoJson> results = (List<ApplInfoJson>) getHibernateTemplate().findByCriteria(criteria);

 return results;

I want some thing to pass key name and get data with specific key.

edited Mar 28 at 9:30

asked Mar 23 at 10:01

shanu dua

113

You can use functions which are available since JPA 2.1.

– Ancoron
Mar 23 at 10:59

@Ancoron how can i do that ??

– shanu dua
Mar 25 at 4:17

Use the standard CriteriaBuilder#function. Example: github.com/thjanssen/HibernateTips/blob/master/…

– Ancoron
Mar 25 at 5:53

Thanks i have seen the code but i want to select appl_id from json .how can i do that @Ancoron

– shanu dua
Mar 25 at 10:12

You need to use function json_extract_path_text(combined_json, 'appl_info') (assuming that column combined_json contains the JSON. Translated into Criteria Query, this means something like: cb.function("json_extract_path_text", String.class, root.get(ApplInfoJson_.combinedJson), "appl_info")

– Ancoron
Mar 28 at 22:13

add a comment |

I am writing the criteria query to get results for jsonb in postgres.I can query the jsonb column through hibernate.I am unable to fetch jsonb specific keys.I am not able to find a way.

I have tried native query but i want some wayout in hibernate criteria query.The commonjson argument is the jsonb in postgresql is this --

"appl_id": 726516, "applied_by": "pankajkumarnnl94@gmail.com", "service_id": 9880004, "version_no": 4, "appl_ref_no": "BSEH/2018/00728", "sub_version": 1, "payment_date": "2018-12-04T11:54:20.24+05:30", "payment_mode": "PayUbizz", "reference_no": "7726929249", "service_name": "Migration Certificate Board of School Education Haryana, Bhiwani", "department_id": 784, "location_value": 1218758, "base_service_id": 988, "department_name": " Board of School Education Haryana", "registration_id": "", "submission_date": "2018-12-04", "submission_mode": "online", "no_of_attachment": 2, "submission_location": "1578947~1218758~Board of School Education Haryana"

Model Class ->ApplInfoJson

package com.saral.reporting.model;

import java.util.Map;

import javax.persistence.Column;
import javax.persistence.Entity;
import javax.persistence.GeneratedValue;
import javax.persistence.GenerationType;
import javax.persistence.Id;
import javax.persistence.Table;

import org.hibernate.annotations.Type;

import com.fasterxml.jackson.annotation.JsonProperty;

@Entity
@Table(name = "r_app_json",schema="saral1", catalog="saral1")

public class ApplInfoJson 

 @Id
 @Column(name = "aid")
 @GeneratedValue(strategy = GenerationType.IDENTITY)
 private Long aid;

 @Column(name = "id")
 private Long id;

 @JsonProperty("appl_info")
 @Column(name = "appl_info")
 private String applInfo;


 @Column(name = "application_form_attributes")
 private String applicationFormAttributes;

 @Column(name = "enclosure_data")
 private String enclosureData;

 @Column(name = "service_id")
 private Long serviceId;

 @Column(name = "combined_json")
 @Type(type = "JsonDataUserType")
 private Map<String , Object> combinedJson;

 @Column(name ="location_value")
 private Long locationValue;


 public Long getLocationValue() 
 return locationValue;
 

 public void setLocationValue(Long locationValue) 
 this.locationValue = locationValue;
 

 public Long getServiceId() 
 return serviceId;
 

 public void setServiceId(Long serviceId) 
 this.serviceId = serviceId;
 

 public Long getAid() 
 return aid;
 

 public void setAid(Long aid) 
 this.aid = aid;
 

 public Long getId() 
 return id;
 

 public void setId(Long id) 
 this.id = id;
 

 public String getApplInfo() 
 return applInfo;
 

 public void setApplInfo(String applInfo) 
 this.applInfo = applInfo;
 

 public String getApplicationFormAttributes() 
 return applicationFormAttributes;
 

 public void setApplicationFormAttributes(String applicationFormAttributes) 
 this.applicationFormAttributes = applicationFormAttributes;
 

 public String getEnclosureData() 
 return enclosureData;
 

 public void setEnclosureData(String enclosureData) 
 this.enclosureData = enclosureData;
 




 public Map<String, Object> getCombinedJson() 
 return combinedJson;
 

 public void setCombinedJson(Map<String, Object> combinedJson) 
 this.combinedJson = combinedJson;
 

 @Override
 public String toString() 
 return "ApplInfoJson [aid=" + aid + ", id=" + id + ", applInfo=" + applInfo + ", applicationFormAttributes="
 + applicationFormAttributes + ", enclosureData=" + enclosureData + ", serviceId=" + serviceId
 + ", combinedJson=" + combinedJson + ", locationValue=" + locationValue + "]";

Function Used->

public List<ApplInfoJson> findByCombinedJson(String commonJson) 

 DetachedCriteria criteria = DetachedCriteria.forClass(ApplInfoJson.class);

 List<ApplInfoJson> results = (List<ApplInfoJson>) getHibernateTemplate().findByCriteria(criteria);

 return results;

I want some thing to pass key name and get data with specific key.

edited Mar 28 at 9:30

asked Mar 23 at 10:01

shanu dua

113

I am writing the criteria query to get results for jsonb in postgres.I can query the jsonb column through hibernate.I am unable to fetch jsonb specific keys.I am not able to find a way.

I have tried native query but i want some wayout in hibernate criteria query.The commonjson argument is the jsonb in postgresql is this --

"appl_id": 726516, "applied_by": "pankajkumarnnl94@gmail.com", "service_id": 9880004, "version_no": 4, "appl_ref_no": "BSEH/2018/00728", "sub_version": 1, "payment_date": "2018-12-04T11:54:20.24+05:30", "payment_mode": "PayUbizz", "reference_no": "7726929249", "service_name": "Migration Certificate Board of School Education Haryana, Bhiwani", "department_id": 784, "location_value": 1218758, "base_service_id": 988, "department_name": " Board of School Education Haryana", "registration_id": "", "submission_date": "2018-12-04", "submission_mode": "online", "no_of_attachment": 2, "submission_location": "1578947~1218758~Board of School Education Haryana"

Model Class ->ApplInfoJson

package com.saral.reporting.model;

import java.util.Map;

import javax.persistence.Column;
import javax.persistence.Entity;
import javax.persistence.GeneratedValue;
import javax.persistence.GenerationType;
import javax.persistence.Id;
import javax.persistence.Table;

import org.hibernate.annotations.Type;

import com.fasterxml.jackson.annotation.JsonProperty;

@Entity
@Table(name = "r_app_json",schema="saral1", catalog="saral1")

public class ApplInfoJson 

 @Id
 @Column(name = "aid")
 @GeneratedValue(strategy = GenerationType.IDENTITY)
 private Long aid;

 @Column(name = "id")
 private Long id;

 @JsonProperty("appl_info")
 @Column(name = "appl_info")
 private String applInfo;


 @Column(name = "application_form_attributes")
 private String applicationFormAttributes;

 @Column(name = "enclosure_data")
 private String enclosureData;

 @Column(name = "service_id")
 private Long serviceId;

 @Column(name = "combined_json")
 @Type(type = "JsonDataUserType")
 private Map<String , Object> combinedJson;

 @Column(name ="location_value")
 private Long locationValue;


 public Long getLocationValue() 
 return locationValue;
 

 public void setLocationValue(Long locationValue) 
 this.locationValue = locationValue;
 

 public Long getServiceId() 
 return serviceId;
 

 public void setServiceId(Long serviceId) 
 this.serviceId = serviceId;
 

 public Long getAid() 
 return aid;
 

 public void setAid(Long aid) 
 this.aid = aid;
 

 public Long getId() 
 return id;
 

 public void setId(Long id) 
 this.id = id;
 

 public String getApplInfo() 
 return applInfo;
 

 public void setApplInfo(String applInfo) 
 this.applInfo = applInfo;
 

 public String getApplicationFormAttributes() 
 return applicationFormAttributes;
 

 public void setApplicationFormAttributes(String applicationFormAttributes) 
 this.applicationFormAttributes = applicationFormAttributes;
 

 public String getEnclosureData() 
 return enclosureData;
 

 public void setEnclosureData(String enclosureData) 
 this.enclosureData = enclosureData;
 




 public Map<String, Object> getCombinedJson() 
 return combinedJson;
 

 public void setCombinedJson(Map<String, Object> combinedJson) 
 this.combinedJson = combinedJson;
 

 @Override
 public String toString() 
 return "ApplInfoJson [aid=" + aid + ", id=" + id + ", applInfo=" + applInfo + ", applicationFormAttributes="
 + applicationFormAttributes + ", enclosureData=" + enclosureData + ", serviceId=" + serviceId
 + ", combinedJson=" + combinedJson + ", locationValue=" + locationValue + "]";

Function Used->

public List<ApplInfoJson> findByCombinedJson(String commonJson) 

 DetachedCriteria criteria = DetachedCriteria.forClass(ApplInfoJson.class);

 List<ApplInfoJson> results = (List<ApplInfoJson>) getHibernateTemplate().findByCriteria(criteria);

 return results;

I want some thing to pass key name and get data with specific key.

java json postgresql hibernate hibernate-criteria

edited Mar 28 at 9:30

asked Mar 23 at 10:01

shanu dua

113

edited Mar 28 at 9:30

asked Mar 23 at 10:01

shanu dua

113

edited Mar 28 at 9:30

asked Mar 23 at 10:01

shanu dua

113

asked Mar 23 at 10:01

shanu dua

113

asked Mar 23 at 10:01

shanu dua

113

You can use functions which are available since JPA 2.1.

– Ancoron
Mar 23 at 10:59

@Ancoron how can i do that ??

– shanu dua
Mar 25 at 4:17

Use the standard CriteriaBuilder#function. Example: github.com/thjanssen/HibernateTips/blob/master/…

– Ancoron
Mar 25 at 5:53

Thanks i have seen the code but i want to select appl_id from json .how can i do that @Ancoron

– shanu dua
Mar 25 at 10:12

You need to use function json_extract_path_text(combined_json, 'appl_info') (assuming that column combined_json contains the JSON. Translated into Criteria Query, this means something like: cb.function("json_extract_path_text", String.class, root.get(ApplInfoJson_.combinedJson), "appl_info")

– Ancoron
Mar 28 at 22:13

add a comment |

You can use functions which are available since JPA 2.1.

– Ancoron
Mar 23 at 10:59

@Ancoron how can i do that ??

– shanu dua
Mar 25 at 4:17

Use the standard CriteriaBuilder#function. Example: github.com/thjanssen/HibernateTips/blob/master/…

– Ancoron
Mar 25 at 5:53

Thanks i have seen the code but i want to select appl_id from json .how can i do that @Ancoron

– shanu dua
Mar 25 at 10:12

You need to use function json_extract_path_text(combined_json, 'appl_info') (assuming that column combined_json contains the JSON. Translated into Criteria Query, this means something like: cb.function("json_extract_path_text", String.class, root.get(ApplInfoJson_.combinedJson), "appl_info")

– Ancoron
Mar 28 at 22:13

You can use functions which are available since JPA 2.1.

– Ancoron
Mar 23 at 10:59

@Ancoron how can i do that ??

– shanu dua
Mar 25 at 4:17

Use the standard CriteriaBuilder#function. Example: github.com/thjanssen/HibernateTips/blob/master/…

– Ancoron
Mar 25 at 5:53

Thanks i have seen the code but i want to select appl_id from json .how can i do that @Ancoron

– shanu dua
Mar 25 at 10:12

You need to use function json_extract_path_text(combined_json, 'appl_info') (assuming that column combined_json contains the JSON. Translated into Criteria Query, this means something like: cb.function("json_extract_path_text", String.class, root.get(ApplInfoJson_.combinedJson), "appl_info")

– Ancoron
Mar 28 at 22:13

add a comment |

0

active

oldest

votes

Your Answer

StackExchange.ifUsing("editor", function ()
StackExchange.using("externalEditor", function ()
StackExchange.using("snippets", function ()
StackExchange.snippets.init();
);
);
, "code-snippets");

StackExchange.ready(function()
var channelOptions =
tags: "".split(" "),
id: "1"
;
initTagRenderer("".split(" "), "".split(" "), channelOptions);

StackExchange.using("externalEditor", function()
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled)
StackExchange.using("snippets", function()
createEditor();
);

else
createEditor();

);

function createEditor()
StackExchange.prepareEditor(
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader:
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
,
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
);

);

draft saved

draft discarded

StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f55312571%2fselect-key-from-jsonb-postgresql-using-hibernate-criteria-query-in-java%23new-answer', 'question_page');

);

Post as a guest

Name

Required, but never shown

0

active

oldest

votes

0

active

oldest

votes

draft saved

draft discarded

Thanks for contributing an answer to Stack Overflow!

Please be sure to answer the question. Provide details and share your research!

But avoid …

Asking for help, clarification, or responding to other answers.

Making statements based on opinion; back them up with references or personal experience.

To learn more, see our tips on writing great answers.

draft saved

draft discarded

Post as a guest

Name

Required, but never shown

Name

Required, but never shown

Name

Required, but never shown

This page is only for reference, If you need detailed information, please check here

搜尋此網誌

Styjun

0

Your Answer

Post as a guest

0

0

Post as a guest

Popular posts from this blog

Kamusi Yaliyomo Aina za kamusi | Muundo wa kamusi | Faida za kamusi | Dhima ya picha katika kamusi | Marejeo | Tazama pia | Viungo vya nje | UrambazajiKuhusu kamusiGo-SwahiliWiki-KamusiKamusi ya Kiswahili na Kiingerezakuihariri na kuongeza habari

0

Your Answer

Sign up or log in

Post as a guest

Post as a guest

0

0

Sign up or log in

Post as a guest

Post as a guest

Sign up or log in

Post as a guest

Sign up or log in

Post as a guest

Sign up or log in

Post as a guest

Popular posts from this blog

Kamusi Yaliyomo Aina za kamusi | Muundo wa kamusi | Faida za kamusi | Dhima ya picha katika kamusi | Marejeo | Tazama pia | Viungo vya nje | UrambazajiKuhusu kamusiGo-SwahiliWiki-KamusiKamusi ya Kiswahili na Kiingerezakuihariri na kuongeza habari