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What does the following declaration means? [duplicate]

How do you read C declarations?What is the difference between #include <filename> and #include “filename”?What does “static” mean in C?What is the effect of extern “C” in C++?What is the difference between a definition and a declaration?How does free know how much to free?Improve INSERT-per-second performance of SQLite?What does the question mark and the colon (?: ternary operator) mean in objective-c?What does the C ??!??! operator do?Why are elementwise additions much faster in separate loops than in a combined loop?What is “:-!!” in C code?

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2

This question already has an answer here:

• 
  How do you read C declarations?
  
  10 answers
  
  

I'm new to programming world and i'm studying about pointers and array. and i read this code on a website. what does this line of mean?

 int(*ptr)[10];

Is it a pointer or an array of size 10?

c

share|improve this question

edited Mar 23 at 10:13

paxdiablo

648k17912691695

asked Mar 23 at 10:02

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marked as duplicate by paxdiablo c
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Mar 23 at 10:14

This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.

• 
  
  
  

  
  2
  

  
  
  
  
  
  

  
  
  Both. It's a pointer to an array of size 10. And conversely int* ptr[10] would be an array (of size 10) of pointers.
  
  – john
  Mar 23 at 10:04
  
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  Also abandon the site you are reading.
  
  – Michael Chourdakis
  Mar 23 at 10:05
  

  
  
  
  


• 
  
  
  

  
  2
  

  
  
  
  
  
  

  
  
  A handy website for some of this: cdecl.org
  
  – Tas
  Mar 23 at 10:05
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  Removed the C++ tag since no-one in their right mind would use this :-) Also closed as dupe since there is a perfectly good canonical question on how to read C types.
  
  – paxdiablo
  Mar 23 at 10:14
  
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  The ``Clockwise/Spiral Rule''
  
  – Ayxan
  Mar 23 at 10:24
  

  
  
  
  

 | 
show 2 more comments

2

This question already has an answer here:

• 
  How do you read C declarations?
  
  10 answers
  
  

I'm new to programming world and i'm studying about pointers and array. and i read this code on a website. what does this line of mean?

 int(*ptr)[10];

Is it a pointer or an array of size 10?

c

share|improve this question

edited Mar 23 at 10:13

paxdiablo

648k17912691695

asked Mar 23 at 10:02

Umer ArifUmer Arif

22411

marked as duplicate by paxdiablo c
Users with the  c badge can single-handedly close c questions as duplicates and reopen them as needed.

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Mar 23 at 10:14

This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.

• 
  
  
  

  
  2
  

  
  
  
  
  
  

  
  
  Both. It's a pointer to an array of size 10. And conversely int* ptr[10] would be an array (of size 10) of pointers.
  
  – john
  Mar 23 at 10:04
  
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  Also abandon the site you are reading.
  
  – Michael Chourdakis
  Mar 23 at 10:05
  

  
  
  
  


• 
  
  
  

  
  2
  

  
  
  
  
  
  

  
  
  A handy website for some of this: cdecl.org
  
  – Tas
  Mar 23 at 10:05
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  Removed the C++ tag since no-one in their right mind would use this :-) Also closed as dupe since there is a perfectly good canonical question on how to read C types.
  
  – paxdiablo
  Mar 23 at 10:14
  
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  The ``Clockwise/Spiral Rule''
  
  – Ayxan
  Mar 23 at 10:24
  

  
  
  
  

 | 
show 2 more comments

This question already has an answer here:

• 
  How do you read C declarations?
  
  10 answers
  
  

I'm new to programming world and i'm studying about pointers and array. and i read this code on a website. what does this line of mean?

 int(*ptr)[10];

Is it a pointer or an array of size 10?

c

share|improve this question

edited Mar 23 at 10:13

paxdiablo

648k17912691695

asked Mar 23 at 10:02

Umer ArifUmer Arif

22411

 int(*ptr)[10];

share|improve this question

edited Mar 23 at 10:13

paxdiablo

648k17912691695

asked Mar 23 at 10:02

Umer ArifUmer Arif

22411

share|improve this question

edited Mar 23 at 10:13

paxdiablo

648k17912691695

asked Mar 23 at 10:02

Umer ArifUmer Arif

22411

edited Mar 23 at 10:13

paxdiablo

648k17912691695

edited Mar 23 at 10:13

paxdiablo

648k17912691695

asked Mar 23 at 10:02

Umer ArifUmer Arif

22411

asked Mar 23 at 10:02

Umer ArifUmer Arif

22411

3 Answers
3

active

oldest

votes

2

It is a pointer to an array of 10 int.

Instead int *ptr[10] is an array of 10 int pointers.

share|improve this answer

answered Mar 23 at 10:08

dariofacdariofac

386

add a comment | 

0

https://stackoverflow.com/a/89100/5596981

Therefore it's a pointer to an array.

For another example, in int main(int argc, char* argv[]), argv is an array of pointers.

share|improve this answer

answered Mar 23 at 10:13

W2aW2a

321215

add a comment | 

-1

It's a pointer to an int array of size 10.

share|improve this answer

answered Mar 23 at 10:07

DeviatioNDeviatioN

9926

add a comment | 

2

It is a pointer to an array of 10 int.

Instead int *ptr[10] is an array of 10 int pointers.

share|improve this answer

answered Mar 23 at 10:08

dariofacdariofac

386

add a comment | 

2

It is a pointer to an array of 10 int.

Instead int *ptr[10] is an array of 10 int pointers.

share|improve this answer

answered Mar 23 at 10:08

dariofacdariofac

386

add a comment | 

It is a pointer to an array of 10 int.

Instead int *ptr[10] is an array of 10 int pointers.

share|improve this answer

answered Mar 23 at 10:08

dariofacdariofac

386

share|improve this answer

answered Mar 23 at 10:08

dariofacdariofac

386

answered Mar 23 at 10:08

dariofacdariofac

386

answered Mar 23 at 10:08

dariofacdariofac

386

0

https://stackoverflow.com/a/89100/5596981

Therefore it's a pointer to an array.

For another example, in int main(int argc, char* argv[]), argv is an array of pointers.

share|improve this answer

answered Mar 23 at 10:13

W2aW2a

321215

add a comment | 

0

https://stackoverflow.com/a/89100/5596981

Therefore it's a pointer to an array.

For another example, in int main(int argc, char* argv[]), argv is an array of pointers.

share|improve this answer

answered Mar 23 at 10:13

W2aW2a

321215

add a comment | 

https://stackoverflow.com/a/89100/5596981

Therefore it's a pointer to an array.

For another example, in int main(int argc, char* argv[]), argv is an array of pointers.

share|improve this answer

answered Mar 23 at 10:13

W2aW2a

321215

share|improve this answer

answered Mar 23 at 10:13

W2aW2a

321215

answered Mar 23 at 10:13

W2aW2a

321215

answered Mar 23 at 10:13

W2aW2a

321215

-1

It's a pointer to an int array of size 10.

share|improve this answer

answered Mar 23 at 10:07

DeviatioNDeviatioN

9926

add a comment | 

-1

It's a pointer to an int array of size 10.

share|improve this answer

answered Mar 23 at 10:07

DeviatioNDeviatioN

9926

add a comment | 

It's a pointer to an int array of size 10.

share|improve this answer

answered Mar 23 at 10:07

DeviatioNDeviatioN

9926

share|improve this answer

answered Mar 23 at 10:07

DeviatioNDeviatioN

9926

answered Mar 23 at 10:07

DeviatioNDeviatioN

9926

answered Mar 23 at 10:07

DeviatioNDeviatioN

9926