Styjun

Responsibility for visa checking

What flavor of zksnark in tezos

Linux tr to convert vertical text to horizontal

Is it OK to bring delicacies from hometown as tokens of gratitude for an out-of-town interview?

Is it possible for people to live in the eye of a permanent hypercane?

How to make thick Asian sauces?

Pros and cons of writing a book review?

Old black and white movie: glowing black rocks slowly turn you into stone upon touch

Can Green-Flame Blade be cast twice with the Hunter ranger's Horde Breaker ability?

Do I include animal companions when calculating difficulty of an encounter?

I completed a difficult task using a tool I developed before joining my employer. What is my obligation?

How could a possessed body begin to rot and decay while it is still alive?

What's the most polite way to tell a manager "shut up and let me work"?

Secure offsite backup, even in the case of hacker root access

Credit card offering 0.5 miles for every cent rounded up. Too good to be true?

3 as a Sum of 3 Pan Digital Expressions

Bent spoke design wheels — feasible?

How to search all Apex Classes in IntelliJ Illuminated Cloud?

Does any lore text explain why the planes of Acheron, Gehenna, and Carceri are the alignment they are?

It possible to have subscript and super script that does not shrink the font size?

What are the words for people who cause trouble believing they know better?

Convert camelCase and PascalCase to Title Case

California: "For quality assurance, this phone call is being recorded"

Can a magnetic field of an object be stronger than its gravity?

Two character Integer to char?

Comparing two byte arrays in .NETHow can I decode HTML characters in C#?Best way to repeat a character in C#What do two question marks together mean in C#?How would you count occurrences of a string (actually a char) within a string?C# convert integer to hex and back again.NET / C# - Convert char[] to stringCalculate difference between two dates (number of days)?Simple problem with replacing string value C#Change specific characters in large string array

.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty height:90px;width:728px;box-sizing:border-box;

3

So I am making a program that calculates X in an expression, e.g if I type 2*x=6 then it will say x = 3.
My code:

 string[] exps = textBox1.Text.Split('=');
 DataTable dt = new DataTable();
 for (int i = 0; i < 50; i++)
 
 string s = exps[0].Replace('x', Convert.ToChar(i.ToString())); //<- problem is there
 var v = dt.Compute(s, "");
 if (int.Parse(v.ToString()) == int.Parse(exps[1]))
 
 listBox1.Items.Add("x = " + i);
 break;
 
 

But I have a problem when X is more than 9 (so it is two characters) e.g 12 or 27, It can't convert it to char. Can you help me how can I do this easier? Thank you!

And sorry for my bad English

c#

share|improve this question

asked Mar 24 at 13:27

SchollerScholler

365

add a comment | 

3

So I am making a program that calculates X in an expression, e.g if I type 2*x=6 then it will say x = 3.
My code:

 string[] exps = textBox1.Text.Split('=');
 DataTable dt = new DataTable();
 for (int i = 0; i < 50; i++)
 
 string s = exps[0].Replace('x', Convert.ToChar(i.ToString())); //<- problem is there
 var v = dt.Compute(s, "");
 if (int.Parse(v.ToString()) == int.Parse(exps[1]))
 
 listBox1.Items.Add("x = " + i);
 break;
 
 

But I have a problem when X is more than 9 (so it is two characters) e.g 12 or 27, It can't convert it to char. Can you help me how can I do this easier? Thank you!

And sorry for my bad English

c#

share|improve this question

asked Mar 24 at 13:27

SchollerScholler

365

add a comment | 

So I am making a program that calculates X in an expression, e.g if I type 2*x=6 then it will say x = 3.
My code:

 string[] exps = textBox1.Text.Split('=');
 DataTable dt = new DataTable();
 for (int i = 0; i < 50; i++)
 
 string s = exps[0].Replace('x', Convert.ToChar(i.ToString())); //<- problem is there
 var v = dt.Compute(s, "");
 if (int.Parse(v.ToString()) == int.Parse(exps[1]))
 
 listBox1.Items.Add("x = " + i);
 break;
 
 

But I have a problem when X is more than 9 (so it is two characters) e.g 12 or 27, It can't convert it to char. Can you help me how can I do this easier? Thank you!

And sorry for my bad English

c#

share|improve this question

asked Mar 24 at 13:27

SchollerScholler

365

 string[] exps = textBox1.Text.Split('=');
 DataTable dt = new DataTable();
 for (int i = 0; i < 50; i++)
 
 string s = exps[0].Replace('x', Convert.ToChar(i.ToString())); //<- problem is there
 var v = dt.Compute(s, "");
 if (int.Parse(v.ToString()) == int.Parse(exps[1]))
 
 listBox1.Items.Add("x = " + i);
 break;
 
 

share|improve this question

asked Mar 24 at 13:27

SchollerScholler

365

share|improve this question

asked Mar 24 at 13:27

SchollerScholler

365

asked Mar 24 at 13:27

SchollerScholler

365

asked Mar 24 at 13:27

SchollerScholler

365

3 Answers
3

active

oldest

votes

6

You don't have to use the Replace(char, char) overload. There is also a Replace(string, string) overload:

string s = exps[0].Replace("x", i.ToString());

You are probably aware of this already, but your way of solving equations only works for a very specific kind of equations. Mainly it has these problems:

• the solution must be an integer between 0 and 49


• there must be only one solution


• Multiplication must be clearly indicated i.e. 5x doesn't mean 5 times x.


• The right hand side must be an integer. This problem can be easily fixed by calling Compute with exps[1] (with the x substitutes in of course).

share|improve this answer

edited Mar 24 at 14:04

answered Mar 24 at 13:31

SweeperSweeper

76.8k1176148

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Can you explain me how can I make it with float numbers, e.g 5.10+x=5.20 ?
  
  – Scholler
  Mar 24 at 14:25
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @Scholler then you can’t use your current method - trying a bunch of values and see which works. You probably need some kind of algorithm to rearrange the equation. The problem becomes much much harder.
  
  – Sweeper
  Mar 24 at 14:33
  

  
  
  
  

add a comment | 

2

Instead of char just convert it to string:

exps[0].Replace("x", i.ToString());

share|improve this answer

answered Mar 24 at 13:32

Ashkan Mobayen KhiabaniAshkan Mobayen Khiabani

23.7k1968125

add a comment | 

1

You can create a datatable with two columns

(1) with column name 'X', this will keep value and

(2) a Computed column which will have expression.

Sample Code:

 var dt=new DataTable();
 dt.Columns.Add(new DataColumn("X", typeof(float)));

 var exprCol=new DataColumn("Expr");
 exprCol.Expression="X+10";

 dt.Columns.Add(exprCol);

 var row = dt.NewRow();
 row["X"] = 5;
 dt.Rows.Add(row);
 var calculatedValue=row["Expr"];

share|improve this answer

answered Mar 24 at 17:15

Amit KumarAmit Kumar

1498

add a comment | 

Your Answer

StackExchange.ifUsing("editor", function ()
StackExchange.using("externalEditor", function ()
StackExchange.using("snippets", function ()
StackExchange.snippets.init();
);
);
, "code-snippets");

StackExchange.ready(function()
var channelOptions =
tags: "".split(" "),
id: "1"
;
initTagRenderer("".split(" "), "".split(" "), channelOptions);

StackExchange.using("externalEditor", function()
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled)
StackExchange.using("snippets", function()
createEditor();
);

else
createEditor();

);

function createEditor()
StackExchange.prepareEditor(
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader:
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
,
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
);



);

draft saved

draft discarded

Sign up or log in

StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);

Sign up using Google

Sign up using Facebook

Sign up using Email and Password

Post as a guest

Name

Email

Required, but never shown

StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f55324270%2ftwo-character-integer-to-char%23new-answer', 'question_page');

);

Post as a guest

Name

Email

Required, but never shown

6

You don't have to use the Replace(char, char) overload. There is also a Replace(string, string) overload:

string s = exps[0].Replace("x", i.ToString());

You are probably aware of this already, but your way of solving equations only works for a very specific kind of equations. Mainly it has these problems:

• the solution must be an integer between 0 and 49


• there must be only one solution


• Multiplication must be clearly indicated i.e. 5x doesn't mean 5 times x.


• The right hand side must be an integer. This problem can be easily fixed by calling Compute with exps[1] (with the x substitutes in of course).

share|improve this answer

edited Mar 24 at 14:04

answered Mar 24 at 13:31

SweeperSweeper

76.8k1176148

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Can you explain me how can I make it with float numbers, e.g 5.10+x=5.20 ?
  
  – Scholler
  Mar 24 at 14:25
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @Scholler then you can’t use your current method - trying a bunch of values and see which works. You probably need some kind of algorithm to rearrange the equation. The problem becomes much much harder.
  
  – Sweeper
  Mar 24 at 14:33
  

  
  
  
  

add a comment | 

6

You don't have to use the Replace(char, char) overload. There is also a Replace(string, string) overload:

string s = exps[0].Replace("x", i.ToString());

You are probably aware of this already, but your way of solving equations only works for a very specific kind of equations. Mainly it has these problems:

• the solution must be an integer between 0 and 49


• there must be only one solution


• Multiplication must be clearly indicated i.e. 5x doesn't mean 5 times x.


• The right hand side must be an integer. This problem can be easily fixed by calling Compute with exps[1] (with the x substitutes in of course).

share|improve this answer

edited Mar 24 at 14:04

answered Mar 24 at 13:31

SweeperSweeper

76.8k1176148

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Can you explain me how can I make it with float numbers, e.g 5.10+x=5.20 ?
  
  – Scholler
  Mar 24 at 14:25
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @Scholler then you can’t use your current method - trying a bunch of values and see which works. You probably need some kind of algorithm to rearrange the equation. The problem becomes much much harder.
  
  – Sweeper
  Mar 24 at 14:33
  

  
  
  
  

add a comment | 

You don't have to use the Replace(char, char) overload. There is also a Replace(string, string) overload:

string s = exps[0].Replace("x", i.ToString());

You are probably aware of this already, but your way of solving equations only works for a very specific kind of equations. Mainly it has these problems:

• the solution must be an integer between 0 and 49


• there must be only one solution


• Multiplication must be clearly indicated i.e. 5x doesn't mean 5 times x.


• The right hand side must be an integer. This problem can be easily fixed by calling Compute with exps[1] (with the x substitutes in of course).

share|improve this answer

edited Mar 24 at 14:04

answered Mar 24 at 13:31

SweeperSweeper

76.8k1176148

string s = exps[0].Replace("x", i.ToString());

share|improve this answer

edited Mar 24 at 14:04

answered Mar 24 at 13:31

SweeperSweeper

76.8k1176148

answered Mar 24 at 13:31

SweeperSweeper

76.8k1176148

answered Mar 24 at 13:31

SweeperSweeper

76.8k1176148

2

Instead of char just convert it to string:

exps[0].Replace("x", i.ToString());

share|improve this answer

answered Mar 24 at 13:32

Ashkan Mobayen KhiabaniAshkan Mobayen Khiabani

23.7k1968125

add a comment | 

2

Instead of char just convert it to string:

exps[0].Replace("x", i.ToString());

share|improve this answer

answered Mar 24 at 13:32

Ashkan Mobayen KhiabaniAshkan Mobayen Khiabani

23.7k1968125

add a comment | 

Instead of char just convert it to string:

exps[0].Replace("x", i.ToString());

share|improve this answer

answered Mar 24 at 13:32

Ashkan Mobayen KhiabaniAshkan Mobayen Khiabani

23.7k1968125

exps[0].Replace("x", i.ToString());

share|improve this answer

answered Mar 24 at 13:32

Ashkan Mobayen KhiabaniAshkan Mobayen Khiabani

23.7k1968125

answered Mar 24 at 13:32

Ashkan Mobayen KhiabaniAshkan Mobayen Khiabani

23.7k1968125

answered Mar 24 at 13:32

Ashkan Mobayen KhiabaniAshkan Mobayen Khiabani

23.7k1968125

1

You can create a datatable with two columns

(1) with column name 'X', this will keep value and

(2) a Computed column which will have expression.

Sample Code:

 var dt=new DataTable();
 dt.Columns.Add(new DataColumn("X", typeof(float)));

 var exprCol=new DataColumn("Expr");
 exprCol.Expression="X+10";

 dt.Columns.Add(exprCol);

 var row = dt.NewRow();
 row["X"] = 5;
 dt.Rows.Add(row);
 var calculatedValue=row["Expr"];

share|improve this answer

answered Mar 24 at 17:15

Amit KumarAmit Kumar

1498

add a comment | 

1

You can create a datatable with two columns

(1) with column name 'X', this will keep value and

(2) a Computed column which will have expression.

Sample Code:

 var dt=new DataTable();
 dt.Columns.Add(new DataColumn("X", typeof(float)));

 var exprCol=new DataColumn("Expr");
 exprCol.Expression="X+10";

 dt.Columns.Add(exprCol);

 var row = dt.NewRow();
 row["X"] = 5;
 dt.Rows.Add(row);
 var calculatedValue=row["Expr"];

share|improve this answer

answered Mar 24 at 17:15

Amit KumarAmit Kumar

1498

add a comment | 

You can create a datatable with two columns

(1) with column name 'X', this will keep value and

(2) a Computed column which will have expression.

Sample Code:

 var dt=new DataTable();
 dt.Columns.Add(new DataColumn("X", typeof(float)));

 var exprCol=new DataColumn("Expr");
 exprCol.Expression="X+10";

 dt.Columns.Add(exprCol);

 var row = dt.NewRow();
 row["X"] = 5;
 dt.Rows.Add(row);
 var calculatedValue=row["Expr"];

share|improve this answer

answered Mar 24 at 17:15

Amit KumarAmit Kumar

1498

 var dt=new DataTable();
 dt.Columns.Add(new DataColumn("X", typeof(float)));

 var exprCol=new DataColumn("Expr");
 exprCol.Expression="X+10";

 dt.Columns.Add(exprCol);

 var row = dt.NewRow();
 row["X"] = 5;
 dt.Rows.Add(row);
 var calculatedValue=row["Expr"];

share|improve this answer

answered Mar 24 at 17:15

Amit KumarAmit Kumar

1498

answered Mar 24 at 17:15

Amit KumarAmit Kumar

1498

answered Mar 24 at 17:15

Amit KumarAmit Kumar

1498