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How can i store images in an array and with a for loop print them? PHP
How can I prevent SQL injection in PHP?How do I check if an array includes an object in JavaScript?How to append something to an array?Deleting an element from an array in PHPWhat's the simplest way to print a Java array?How to insert an item into an array at a specific index (JavaScript)?How do I empty an array in JavaScript?Loop through an array in JavaScriptHow to check if an object is an array?How do I remove a particular element from an array in JavaScript?
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty height:90px;width:728px;box-sizing:border-box;
I try to print images with a for loop but the images dont load.
<?php
$imagenes = array('1.png', '2.jpg', '3.png', '4.jpg','IMG_0105.JPG');
?>
<div class="container">
<div class="row">
<div class="col-md">
<?php
for ($i=0; $i < 4; $i++)
echo '<img src = "$imagenes[$i]" width = '100px' height = '100px';>';
?>
</div>
</div>
</div>
The images are in the same folder as the .php file
php html arrays
asked Mar 24 at 23:02
Juan Pedro Pont VergésJuan Pedro Pont Vergés
156
add a comment |
I try to print images with a for loop but the images dont load.
<?php
$imagenes = array('1.png', '2.jpg', '3.png', '4.jpg','IMG_0105.JPG');
?>
<div class="container">
<div class="row">
<div class="col-md">
<?php
for ($i=0; $i < 4; $i++)
echo '<img src = "$imagenes[$i]" width = '100px' height = '100px';>';
?>
</div>
</div>
</div>
The images are in the same folder as the .php file
php html arrays
asked Mar 24 at 23:02
Juan Pedro Pont VergésJuan Pedro Pont Vergés
156
echo "<img src='$imagenes[$i]' width='100px' height='100px'>";
– RiggsFolly
Mar 24 at 23:05
add a comment |
I try to print images with a for loop but the images dont load.
<?php
$imagenes = array('1.png', '2.jpg', '3.png', '4.jpg','IMG_0105.JPG');
?>
<div class="container">
<div class="row">
<div class="col-md">
<?php
for ($i=0; $i < 4; $i++)
echo '<img src = "$imagenes[$i]" width = '100px' height = '100px';>';
?>
</div>
</div>
</div>
The images are in the same folder as the .php file
php html arrays
asked Mar 24 at 23:02
Juan Pedro Pont VergésJuan Pedro Pont Vergés
156
I try to print images with a for loop but the images dont load.
<?php
$imagenes = array('1.png', '2.jpg', '3.png', '4.jpg','IMG_0105.JPG');
?>
<div class="container">
<div class="row">
<div class="col-md">
<?php
for ($i=0; $i < 4; $i++)
echo '<img src = "$imagenes[$i]" width = '100px' height = '100px';>';
?>
</div>
</div>
</div>
The images are in the same folder as the .php file
php html arrays
php html arrays
asked Mar 24 at 23:02
Juan Pedro Pont VergésJuan Pedro Pont Vergés
156
asked Mar 24 at 23:02
Juan Pedro Pont VergésJuan Pedro Pont Vergés
156
asked Mar 24 at 23:02
Juan Pedro Pont VergésJuan Pedro Pont Vergés
156
asked Mar 24 at 23:02
Juan Pedro Pont VergésJuan Pedro Pont Vergés
156
asked Mar 24 at 23:02
Juan Pedro Pont VergésJuan Pedro Pont Vergés
156
156
echo "<img src='$imagenes[$i]' width='100px' height='100px'>";
– RiggsFolly
Mar 24 at 23:05
add a comment |
echo "<img src='$imagenes[$i]' width='100px' height='100px'>";
– RiggsFolly
Mar 24 at 23:05
echo "<img src='$imagenes[$i]' width='100px' height='100px'>";– RiggsFolly
Mar 24 at 23:05
echo "<img src='$imagenes[$i]' width='100px' height='100px'>";– RiggsFolly
Mar 24 at 23:05
add a comment |
4 Answers
4
active
oldest
votes
This will never work because variables are not evaluated inside of single quoted strings.
Make sure that your use a string inside double quotes. Or use string concatenation to build the HTML tag. Also, you image tag has a semicolon inside of it that might break the tag.
So you can do this ...
echo "<img src="$imagenes[$i]" width="100px" height="100px">";
or
echo "<img src="" . $imagenes[$i] . "" width="100px" height="100px">";
answered Mar 24 at 23:09
asibyasiby
1,6801722
add a comment |
Use foreach for this. And for concatinate string with var - use . (dot)
<?php
foreach ($imagenes as $image)
echo '<img src = "'.$image.'" width = "100px" height = "100px">';
?>
answered Mar 24 at 23:08
MaksimMaksim
598
add a comment |
This would make it simplier:
<div class="container">
<div class="row">
<div class="col-md">
<?php foreach ($imagenes as $url) ?>
<img src="<?php echo $url ?>" width="100px" height="100px">
<?php ?>
</div>
</div>
</div>
answered Mar 25 at 0:31
NikNik
1,136717
add a comment |
I think its the way you're escaping the characters, you can just use concatenation on $images:
<div class="container">
<div class="row">
<div class="col-md">
<?php
for ($i=0; $i < 4; $i++)
echo '<img src = '.$imagenes[$i].' width="100px" height ="100px";>';
?>
</div>
</div>
</div>
answered Mar 24 at 23:09
giolliano sulitgiolliano sulit
8271611
add a comment |
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4 Answers
4
active
oldest
votes
4 Answers
4
active
oldest
votes
active
oldest
votes
active
oldest
votes
This will never work because variables are not evaluated inside of single quoted strings.
Make sure that your use a string inside double quotes. Or use string concatenation to build the HTML tag. Also, you image tag has a semicolon inside of it that might break the tag.
So you can do this ...
echo "<img src="$imagenes[$i]" width="100px" height="100px">";
or
echo "<img src="" . $imagenes[$i] . "" width="100px" height="100px">";
answered Mar 24 at 23:09
asibyasiby
1,6801722
add a comment |
This will never work because variables are not evaluated inside of single quoted strings.
Make sure that your use a string inside double quotes. Or use string concatenation to build the HTML tag. Also, you image tag has a semicolon inside of it that might break the tag.
So you can do this ...
echo "<img src="$imagenes[$i]" width="100px" height="100px">";
or
echo "<img src="" . $imagenes[$i] . "" width="100px" height="100px">";
answered Mar 24 at 23:09
asibyasiby
1,6801722
add a comment |
This will never work because variables are not evaluated inside of single quoted strings.
Make sure that your use a string inside double quotes. Or use string concatenation to build the HTML tag. Also, you image tag has a semicolon inside of it that might break the tag.
So you can do this ...
echo "<img src="$imagenes[$i]" width="100px" height="100px">";
or
echo "<img src="" . $imagenes[$i] . "" width="100px" height="100px">";
answered Mar 24 at 23:09
asibyasiby
1,6801722
This will never work because variables are not evaluated inside of single quoted strings.
Make sure that your use a string inside double quotes. Or use string concatenation to build the HTML tag. Also, you image tag has a semicolon inside of it that might break the tag.
So you can do this ...
echo "<img src="$imagenes[$i]" width="100px" height="100px">";
or
echo "<img src="" . $imagenes[$i] . "" width="100px" height="100px">";
answered Mar 24 at 23:09
asibyasiby
1,6801722
answered Mar 24 at 23:09
asibyasiby
1,6801722
answered Mar 24 at 23:09
asibyasiby
1,6801722
answered Mar 24 at 23:09
asibyasiby
1,6801722
1,6801722
add a comment |
add a comment |
Use foreach for this. And for concatinate string with var - use . (dot)
<?php
foreach ($imagenes as $image)
echo '<img src = "'.$image.'" width = "100px" height = "100px">';
?>
answered Mar 24 at 23:08
MaksimMaksim
598
add a comment |
Use foreach for this. And for concatinate string with var - use . (dot)
<?php
foreach ($imagenes as $image)
echo '<img src = "'.$image.'" width = "100px" height = "100px">';
?>
answered Mar 24 at 23:08
MaksimMaksim
598
add a comment |
Use foreach for this. And for concatinate string with var - use . (dot)
<?php
foreach ($imagenes as $image)
echo '<img src = "'.$image.'" width = "100px" height = "100px">';
?>
answered Mar 24 at 23:08
MaksimMaksim
598
Use foreach for this. And for concatinate string with var - use . (dot)
<?php
foreach ($imagenes as $image)
echo '<img src = "'.$image.'" width = "100px" height = "100px">';
?>
answered Mar 24 at 23:08
MaksimMaksim
598
answered Mar 24 at 23:08
MaksimMaksim
598
answered Mar 24 at 23:08
MaksimMaksim
598
answered Mar 24 at 23:08
MaksimMaksim
598
598
add a comment |
add a comment |
This would make it simplier:
<div class="container">
<div class="row">
<div class="col-md">
<?php foreach ($imagenes as $url) ?>
<img src="<?php echo $url ?>" width="100px" height="100px">
<?php ?>
</div>
</div>
</div>
answered Mar 25 at 0:31
NikNik
1,136717
add a comment |
This would make it simplier:
<div class="container">
<div class="row">
<div class="col-md">
<?php foreach ($imagenes as $url) ?>
<img src="<?php echo $url ?>" width="100px" height="100px">
<?php ?>
</div>
</div>
</div>
answered Mar 25 at 0:31
NikNik
1,136717
add a comment |
This would make it simplier:
<div class="container">
<div class="row">
<div class="col-md">
<?php foreach ($imagenes as $url) ?>
<img src="<?php echo $url ?>" width="100px" height="100px">
<?php ?>
</div>
</div>
</div>
answered Mar 25 at 0:31
NikNik
1,136717
This would make it simplier:
<div class="container">
<div class="row">
<div class="col-md">
<?php foreach ($imagenes as $url) ?>
<img src="<?php echo $url ?>" width="100px" height="100px">
<?php ?>
</div>
</div>
</div>
answered Mar 25 at 0:31
NikNik
1,136717
answered Mar 25 at 0:31
NikNik
1,136717
answered Mar 25 at 0:31
NikNik
1,136717
answered Mar 25 at 0:31
NikNik
1,136717
1,136717
add a comment |
add a comment |
I think its the way you're escaping the characters, you can just use concatenation on $images:
<div class="container">
<div class="row">
<div class="col-md">
<?php
for ($i=0; $i < 4; $i++)
echo '<img src = '.$imagenes[$i].' width="100px" height ="100px";>';
?>
</div>
</div>
</div>
answered Mar 24 at 23:09
giolliano sulitgiolliano sulit
8271611
add a comment |
I think its the way you're escaping the characters, you can just use concatenation on $images:
<div class="container">
<div class="row">
<div class="col-md">
<?php
for ($i=0; $i < 4; $i++)
echo '<img src = '.$imagenes[$i].' width="100px" height ="100px";>';
?>
</div>
</div>
</div>
answered Mar 24 at 23:09
giolliano sulitgiolliano sulit
8271611
add a comment |
I think its the way you're escaping the characters, you can just use concatenation on $images:
<div class="container">
<div class="row">
<div class="col-md">
<?php
for ($i=0; $i < 4; $i++)
echo '<img src = '.$imagenes[$i].' width="100px" height ="100px";>';
?>
</div>
</div>
</div>
answered Mar 24 at 23:09
giolliano sulitgiolliano sulit
8271611
I think its the way you're escaping the characters, you can just use concatenation on $images:
<div class="container">
<div class="row">
<div class="col-md">
<?php
for ($i=0; $i < 4; $i++)
echo '<img src = '.$imagenes[$i].' width="100px" height ="100px";>';
?>
</div>
</div>
</div>
answered Mar 24 at 23:09
giolliano sulitgiolliano sulit
8271611
answered Mar 24 at 23:09
giolliano sulitgiolliano sulit
8271611
answered Mar 24 at 23:09
giolliano sulitgiolliano sulit
8271611
answered Mar 24 at 23:09
giolliano sulitgiolliano sulit
8271611
8271611
add a comment |
add a comment |
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echo "<img src='$imagenes[$i]' width='100px' height='100px'>";– RiggsFolly
Mar 24 at 23:05