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What would be the Regex expression to get the first letter after a group of character and some integers?

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1

0

I have a string that the following structure:

ABCD123456EFGHIJ78 but sometimes it's missing a number or a character like:

ABC123456EFGHIJ78 or
ABCD123456E or
ABCD12345EFGHIJ78
etc.

That's why I need regular expressions.

What I want to extract is the first letter of the third group, in this case 'E'.

I have the following regex:

(D+)+(d+)+(D1)3

but I don't get the letter E.

regex

share|improve this question

asked Mar 22 at 18:25

esgesg

255

• 
  
  
  

  
  2
  

  
  
  
  
  
  

  
  
  See regex101.com/r/5GA6YQ/1
  
  – Wiktor Stribiżew
  Mar 22 at 18:27
  

  
  
  
  

add a comment | 

1

0

I have a string that the following structure:

ABCD123456EFGHIJ78 but sometimes it's missing a number or a character like:

ABC123456EFGHIJ78 or
ABCD123456E or
ABCD12345EFGHIJ78
etc.

That's why I need regular expressions.

What I want to extract is the first letter of the third group, in this case 'E'.

I have the following regex:

(D+)+(d+)+(D1)3

but I don't get the letter E.

regex

share|improve this question

asked Mar 22 at 18:25

esgesg

255

• 
  
  
  

  
  2
  

  
  
  
  
  
  

  
  
  See regex101.com/r/5GA6YQ/1
  
  – Wiktor Stribiżew
  Mar 22 at 18:27
  

  
  
  
  

add a comment | 

I have a string that the following structure:

ABCD123456EFGHIJ78 but sometimes it's missing a number or a character like:

ABC123456EFGHIJ78 or
ABCD123456E or
ABCD12345EFGHIJ78
etc.

That's why I need regular expressions.

What I want to extract is the first letter of the third group, in this case 'E'.

I have the following regex:

(D+)+(d+)+(D1)3

but I don't get the letter E.

regex

share|improve this question

asked Mar 22 at 18:25

esgesg

255

(D+)+(d+)+(D1)3

share|improve this question

asked Mar 22 at 18:25

esgesg

255

share|improve this question

asked Mar 22 at 18:25

esgesg

255

asked Mar 22 at 18:25

esgesg

255

asked Mar 22 at 18:25

esgesg

255

2 Answers
2

active

oldest

votes

2

This seems to work for the example cases you provided.

^(?:[A-Za-z]+)(?:d+)(.)

It assumes that the first group is only letters and that the second group is only digits.

share|improve this answer

answered Mar 22 at 18:46

Russ BrownRuss Brown

1516

add a comment | 

0

There's already a nice answer.

But for the records, your initial proposal was very close to work. You just needed to say that the character matching the 3rd group can repeat several times by adding a star:

^(D+)(d+)(D1)3*

The main weakness is that D matches any char except digits, so also spaces. Making it more robust leads us to explicit the range of chars accepted:

^([A-Za-z]+)(d+)([A-Za-z]1)3*

It's much better, but my favourite uses w to match at the end of the pattern any non white character:

([A-Za-z]+)(d+)([A-Za-z]1)w*

share|improve this answer

answered Mar 24 at 22:50

ChristopheChristophe

43.3k43883

add a comment | 

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2

This seems to work for the example cases you provided.

^(?:[A-Za-z]+)(?:d+)(.)

It assumes that the first group is only letters and that the second group is only digits.

share|improve this answer

answered Mar 22 at 18:46

Russ BrownRuss Brown

1516

add a comment | 

2

This seems to work for the example cases you provided.

^(?:[A-Za-z]+)(?:d+)(.)

It assumes that the first group is only letters and that the second group is only digits.

share|improve this answer

answered Mar 22 at 18:46

Russ BrownRuss Brown

1516

add a comment | 

This seems to work for the example cases you provided.

^(?:[A-Za-z]+)(?:d+)(.)

It assumes that the first group is only letters and that the second group is only digits.

share|improve this answer

answered Mar 22 at 18:46

Russ BrownRuss Brown

1516

^(?:[A-Za-z]+)(?:d+)(.)

share|improve this answer

answered Mar 22 at 18:46

Russ BrownRuss Brown

1516

answered Mar 22 at 18:46

Russ BrownRuss Brown

1516

answered Mar 22 at 18:46

Russ BrownRuss Brown

1516

0

There's already a nice answer.

But for the records, your initial proposal was very close to work. You just needed to say that the character matching the 3rd group can repeat several times by adding a star:

^(D+)(d+)(D1)3*

The main weakness is that D matches any char except digits, so also spaces. Making it more robust leads us to explicit the range of chars accepted:

^([A-Za-z]+)(d+)([A-Za-z]1)3*

It's much better, but my favourite uses w to match at the end of the pattern any non white character:

([A-Za-z]+)(d+)([A-Za-z]1)w*

share|improve this answer

answered Mar 24 at 22:50

ChristopheChristophe

43.3k43883

add a comment | 

0

There's already a nice answer.

But for the records, your initial proposal was very close to work. You just needed to say that the character matching the 3rd group can repeat several times by adding a star:

^(D+)(d+)(D1)3*

The main weakness is that D matches any char except digits, so also spaces. Making it more robust leads us to explicit the range of chars accepted:

^([A-Za-z]+)(d+)([A-Za-z]1)3*

It's much better, but my favourite uses w to match at the end of the pattern any non white character:

([A-Za-z]+)(d+)([A-Za-z]1)w*

share|improve this answer

answered Mar 24 at 22:50

ChristopheChristophe

43.3k43883

add a comment | 

There's already a nice answer.

But for the records, your initial proposal was very close to work. You just needed to say that the character matching the 3rd group can repeat several times by adding a star:

^(D+)(d+)(D1)3*

The main weakness is that D matches any char except digits, so also spaces. Making it more robust leads us to explicit the range of chars accepted:

^([A-Za-z]+)(d+)([A-Za-z]1)3*

It's much better, but my favourite uses w to match at the end of the pattern any non white character:

([A-Za-z]+)(d+)([A-Za-z]1)w*

share|improve this answer

answered Mar 24 at 22:50

ChristopheChristophe

43.3k43883

^(D+)(d+)(D1)3*

^([A-Za-z]+)(d+)([A-Za-z]1)3*

([A-Za-z]+)(d+)([A-Za-z]1)w*

share|improve this answer

answered Mar 24 at 22:50

ChristopheChristophe

43.3k43883

answered Mar 24 at 22:50

ChristopheChristophe

43.3k43883

answered Mar 24 at 22:50

ChristopheChristophe

43.3k43883