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How to make density plot correctly show area near the limits?


How to set limits for axes in ggplot2 R plots?How to make a great R reproducible exampleHow to save a plot as image on the disk?How can we make xkcd style graphs?Splitting distribution visualisations on the y-axis in ggplot2 in rAsymmetric density plot of outcomes of 2 dices rolledsaving multiple ggplots created in a for loop to a single plotShiny & ggplot: Numeric variables not recognized in ggplot's aes() mapping statementPlot Gaussian Mixture in R using ggplot2Decimal seprarator is changed by ggplot2 in R Kernel of jupyter






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2















When I plot densities with ggplot, it seems to be very wrong around the limits. I see that geom_density and other functions allow specifying various density kernels, but none of them seem to fix the issue.



How do you correctly plot densities around the limits with ggplot?




As an example, let's plot the Chi-square distribution with 2 degrees of freedom. Using the builtin probability densities:



library(ggplot2)

u = seq(0, 2, by=0.01)
v = dchisq(u, df=2)

df = data.frame(x=u, p=v)

p = ggplot(df) +
geom_line(aes(x=x, y=p), size=1) +
theme_classic() +
coord_cartesian(xlim=c(0, 2), ylim=c(0, 0.5))

show(p)


We get the expected plot:



enter image description here



Now let's try simulating it and plotting the empirical distribution:



library(ggplot2)

u = rchisq(10000, df=2)

df = data.frame(x=u)

p = ggplot(df) +
geom_density(aes(x=x)) +
theme_classic() +
coord_cartesian(xlim=c(0, 2))

show(p)


We get an incorrect plot:



enter image description here



We can try to visualize the actual distribution:



library(ggplot2, dplyr, tidyr)

u = rchisq(10000, df=2)

df = data.frame(x=u)

p = ggplot(df) +
geom_point(aes(x=x, y=0.5), position=position_jitter(height=0.2), shape='.', alpha=1) +
theme_classic() +
coord_cartesian(xlim=c(0, 2), ylim=c(0, 1))

show(p)


And it seems to look correct, contrary to the density plot:



enter image description here



It seems like the problem has to do with kernels, and geom_density does allow using different kernels. But they don't really correct the limit problem. For example, the code above with triangular looks about the same:



enter image description here



Here's an idea of what I'm expecting to see (of course, I want a density, not a histogram):



library(ggplot2)

u = rchisq(10000, df=2)

df = data.frame(x=u)

p = ggplot(df) +
geom_histogram(aes(x=x), center=0.1, binwidth=0.2, fill='white', color='black') +
theme_classic() +
coord_cartesian(xlim=c(0, 2))

show(p)


enter image description here










share|improve this question



















  • 1





    I'm a bit confused by your use of geom_violin - it's usually used where you would use a boxplot, e.g. showing the distribution across multiple discrete categories. When I run the code I also get something that looks different to the image you posted.

    – Marius
    Mar 24 at 23:15











  • @Marius I just pasted the wrong code by mistake, man. No need for the stats lecture.

    – Wassinger
    Apr 10 at 22:21

















2















When I plot densities with ggplot, it seems to be very wrong around the limits. I see that geom_density and other functions allow specifying various density kernels, but none of them seem to fix the issue.



How do you correctly plot densities around the limits with ggplot?




As an example, let's plot the Chi-square distribution with 2 degrees of freedom. Using the builtin probability densities:



library(ggplot2)

u = seq(0, 2, by=0.01)
v = dchisq(u, df=2)

df = data.frame(x=u, p=v)

p = ggplot(df) +
geom_line(aes(x=x, y=p), size=1) +
theme_classic() +
coord_cartesian(xlim=c(0, 2), ylim=c(0, 0.5))

show(p)


We get the expected plot:



enter image description here



Now let's try simulating it and plotting the empirical distribution:



library(ggplot2)

u = rchisq(10000, df=2)

df = data.frame(x=u)

p = ggplot(df) +
geom_density(aes(x=x)) +
theme_classic() +
coord_cartesian(xlim=c(0, 2))

show(p)


We get an incorrect plot:



enter image description here



We can try to visualize the actual distribution:



library(ggplot2, dplyr, tidyr)

u = rchisq(10000, df=2)

df = data.frame(x=u)

p = ggplot(df) +
geom_point(aes(x=x, y=0.5), position=position_jitter(height=0.2), shape='.', alpha=1) +
theme_classic() +
coord_cartesian(xlim=c(0, 2), ylim=c(0, 1))

show(p)


And it seems to look correct, contrary to the density plot:



enter image description here



It seems like the problem has to do with kernels, and geom_density does allow using different kernels. But they don't really correct the limit problem. For example, the code above with triangular looks about the same:



enter image description here



Here's an idea of what I'm expecting to see (of course, I want a density, not a histogram):



library(ggplot2)

u = rchisq(10000, df=2)

df = data.frame(x=u)

p = ggplot(df) +
geom_histogram(aes(x=x), center=0.1, binwidth=0.2, fill='white', color='black') +
theme_classic() +
coord_cartesian(xlim=c(0, 2))

show(p)


enter image description here










share|improve this question



















  • 1





    I'm a bit confused by your use of geom_violin - it's usually used where you would use a boxplot, e.g. showing the distribution across multiple discrete categories. When I run the code I also get something that looks different to the image you posted.

    – Marius
    Mar 24 at 23:15











  • @Marius I just pasted the wrong code by mistake, man. No need for the stats lecture.

    – Wassinger
    Apr 10 at 22:21













2












2








2








When I plot densities with ggplot, it seems to be very wrong around the limits. I see that geom_density and other functions allow specifying various density kernels, but none of them seem to fix the issue.



How do you correctly plot densities around the limits with ggplot?




As an example, let's plot the Chi-square distribution with 2 degrees of freedom. Using the builtin probability densities:



library(ggplot2)

u = seq(0, 2, by=0.01)
v = dchisq(u, df=2)

df = data.frame(x=u, p=v)

p = ggplot(df) +
geom_line(aes(x=x, y=p), size=1) +
theme_classic() +
coord_cartesian(xlim=c(0, 2), ylim=c(0, 0.5))

show(p)


We get the expected plot:



enter image description here



Now let's try simulating it and plotting the empirical distribution:



library(ggplot2)

u = rchisq(10000, df=2)

df = data.frame(x=u)

p = ggplot(df) +
geom_density(aes(x=x)) +
theme_classic() +
coord_cartesian(xlim=c(0, 2))

show(p)


We get an incorrect plot:



enter image description here



We can try to visualize the actual distribution:



library(ggplot2, dplyr, tidyr)

u = rchisq(10000, df=2)

df = data.frame(x=u)

p = ggplot(df) +
geom_point(aes(x=x, y=0.5), position=position_jitter(height=0.2), shape='.', alpha=1) +
theme_classic() +
coord_cartesian(xlim=c(0, 2), ylim=c(0, 1))

show(p)


And it seems to look correct, contrary to the density plot:



enter image description here



It seems like the problem has to do with kernels, and geom_density does allow using different kernels. But they don't really correct the limit problem. For example, the code above with triangular looks about the same:



enter image description here



Here's an idea of what I'm expecting to see (of course, I want a density, not a histogram):



library(ggplot2)

u = rchisq(10000, df=2)

df = data.frame(x=u)

p = ggplot(df) +
geom_histogram(aes(x=x), center=0.1, binwidth=0.2, fill='white', color='black') +
theme_classic() +
coord_cartesian(xlim=c(0, 2))

show(p)


enter image description here










share|improve this question
















When I plot densities with ggplot, it seems to be very wrong around the limits. I see that geom_density and other functions allow specifying various density kernels, but none of them seem to fix the issue.



How do you correctly plot densities around the limits with ggplot?




As an example, let's plot the Chi-square distribution with 2 degrees of freedom. Using the builtin probability densities:



library(ggplot2)

u = seq(0, 2, by=0.01)
v = dchisq(u, df=2)

df = data.frame(x=u, p=v)

p = ggplot(df) +
geom_line(aes(x=x, y=p), size=1) +
theme_classic() +
coord_cartesian(xlim=c(0, 2), ylim=c(0, 0.5))

show(p)


We get the expected plot:



enter image description here



Now let's try simulating it and plotting the empirical distribution:



library(ggplot2)

u = rchisq(10000, df=2)

df = data.frame(x=u)

p = ggplot(df) +
geom_density(aes(x=x)) +
theme_classic() +
coord_cartesian(xlim=c(0, 2))

show(p)


We get an incorrect plot:



enter image description here



We can try to visualize the actual distribution:



library(ggplot2, dplyr, tidyr)

u = rchisq(10000, df=2)

df = data.frame(x=u)

p = ggplot(df) +
geom_point(aes(x=x, y=0.5), position=position_jitter(height=0.2), shape='.', alpha=1) +
theme_classic() +
coord_cartesian(xlim=c(0, 2), ylim=c(0, 1))

show(p)


And it seems to look correct, contrary to the density plot:



enter image description here



It seems like the problem has to do with kernels, and geom_density does allow using different kernels. But they don't really correct the limit problem. For example, the code above with triangular looks about the same:



enter image description here



Here's an idea of what I'm expecting to see (of course, I want a density, not a histogram):



library(ggplot2)

u = rchisq(10000, df=2)

df = data.frame(x=u)

p = ggplot(df) +
geom_histogram(aes(x=x), center=0.1, binwidth=0.2, fill='white', color='black') +
theme_classic() +
coord_cartesian(xlim=c(0, 2))

show(p)


enter image description here







r ggplot2 kernel-density






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Apr 10 at 23:11







Wassinger

















asked Mar 24 at 23:08









WassingerWassinger

957




957







  • 1





    I'm a bit confused by your use of geom_violin - it's usually used where you would use a boxplot, e.g. showing the distribution across multiple discrete categories. When I run the code I also get something that looks different to the image you posted.

    – Marius
    Mar 24 at 23:15











  • @Marius I just pasted the wrong code by mistake, man. No need for the stats lecture.

    – Wassinger
    Apr 10 at 22:21












  • 1





    I'm a bit confused by your use of geom_violin - it's usually used where you would use a boxplot, e.g. showing the distribution across multiple discrete categories. When I run the code I also get something that looks different to the image you posted.

    – Marius
    Mar 24 at 23:15











  • @Marius I just pasted the wrong code by mistake, man. No need for the stats lecture.

    – Wassinger
    Apr 10 at 22:21







1




1





I'm a bit confused by your use of geom_violin - it's usually used where you would use a boxplot, e.g. showing the distribution across multiple discrete categories. When I run the code I also get something that looks different to the image you posted.

– Marius
Mar 24 at 23:15





I'm a bit confused by your use of geom_violin - it's usually used where you would use a boxplot, e.g. showing the distribution across multiple discrete categories. When I run the code I also get something that looks different to the image you posted.

– Marius
Mar 24 at 23:15













@Marius I just pasted the wrong code by mistake, man. No need for the stats lecture.

– Wassinger
Apr 10 at 22:21





@Marius I just pasted the wrong code by mistake, man. No need for the stats lecture.

– Wassinger
Apr 10 at 22:21












1 Answer
1






active

oldest

votes


















1














The usual kernel density methods have trouble when there is a constraint such as in this case for a density with only support above zero. The usual recommendation for handling this has been to use the logspline package:



install.packages("logspline")
library(logspline)
png(); fit <- logspline(rchisq(10000, 3))
plot(fit) ; dev.off()


enter image description here



If this needed to be done in the ggplot2 environment there is a dlogspline function:



densdf <- data.frame( y=dlogspline(seq(0,12,length=1000), fit), 
x=seq(0,12,length=1000))

ggplot(densdf, aes(y=y,x=x))+geom_line()


Perhaps you were insisting on one with 2 degrees of freedom?



enter image description here






share|improve this answer

























  • This looks even less accurate than the density plot in my question.

    – Wassinger
    Apr 10 at 22:30











  • I plotted a distribution with three degrees of freedom. You plotted one with 2.

    – 42-
    Apr 11 at 5:04











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1 Answer
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active

oldest

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1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









1














The usual kernel density methods have trouble when there is a constraint such as in this case for a density with only support above zero. The usual recommendation for handling this has been to use the logspline package:



install.packages("logspline")
library(logspline)
png(); fit <- logspline(rchisq(10000, 3))
plot(fit) ; dev.off()


enter image description here



If this needed to be done in the ggplot2 environment there is a dlogspline function:



densdf <- data.frame( y=dlogspline(seq(0,12,length=1000), fit), 
x=seq(0,12,length=1000))

ggplot(densdf, aes(y=y,x=x))+geom_line()


Perhaps you were insisting on one with 2 degrees of freedom?



enter image description here






share|improve this answer

























  • This looks even less accurate than the density plot in my question.

    – Wassinger
    Apr 10 at 22:30











  • I plotted a distribution with three degrees of freedom. You plotted one with 2.

    – 42-
    Apr 11 at 5:04















1














The usual kernel density methods have trouble when there is a constraint such as in this case for a density with only support above zero. The usual recommendation for handling this has been to use the logspline package:



install.packages("logspline")
library(logspline)
png(); fit <- logspline(rchisq(10000, 3))
plot(fit) ; dev.off()


enter image description here



If this needed to be done in the ggplot2 environment there is a dlogspline function:



densdf <- data.frame( y=dlogspline(seq(0,12,length=1000), fit), 
x=seq(0,12,length=1000))

ggplot(densdf, aes(y=y,x=x))+geom_line()


Perhaps you were insisting on one with 2 degrees of freedom?



enter image description here






share|improve this answer

























  • This looks even less accurate than the density plot in my question.

    – Wassinger
    Apr 10 at 22:30











  • I plotted a distribution with three degrees of freedom. You plotted one with 2.

    – 42-
    Apr 11 at 5:04













1












1








1







The usual kernel density methods have trouble when there is a constraint such as in this case for a density with only support above zero. The usual recommendation for handling this has been to use the logspline package:



install.packages("logspline")
library(logspline)
png(); fit <- logspline(rchisq(10000, 3))
plot(fit) ; dev.off()


enter image description here



If this needed to be done in the ggplot2 environment there is a dlogspline function:



densdf <- data.frame( y=dlogspline(seq(0,12,length=1000), fit), 
x=seq(0,12,length=1000))

ggplot(densdf, aes(y=y,x=x))+geom_line()


Perhaps you were insisting on one with 2 degrees of freedom?



enter image description here






share|improve this answer















The usual kernel density methods have trouble when there is a constraint such as in this case for a density with only support above zero. The usual recommendation for handling this has been to use the logspline package:



install.packages("logspline")
library(logspline)
png(); fit <- logspline(rchisq(10000, 3))
plot(fit) ; dev.off()


enter image description here



If this needed to be done in the ggplot2 environment there is a dlogspline function:



densdf <- data.frame( y=dlogspline(seq(0,12,length=1000), fit), 
x=seq(0,12,length=1000))

ggplot(densdf, aes(y=y,x=x))+geom_line()


Perhaps you were insisting on one with 2 degrees of freedom?



enter image description here







share|improve this answer














share|improve this answer



share|improve this answer








edited Apr 11 at 5:06

























answered Mar 24 at 23:52









42-42-

218k16272409




218k16272409












  • This looks even less accurate than the density plot in my question.

    – Wassinger
    Apr 10 at 22:30











  • I plotted a distribution with three degrees of freedom. You plotted one with 2.

    – 42-
    Apr 11 at 5:04

















  • This looks even less accurate than the density plot in my question.

    – Wassinger
    Apr 10 at 22:30











  • I plotted a distribution with three degrees of freedom. You plotted one with 2.

    – 42-
    Apr 11 at 5:04
















This looks even less accurate than the density plot in my question.

– Wassinger
Apr 10 at 22:30





This looks even less accurate than the density plot in my question.

– Wassinger
Apr 10 at 22:30













I plotted a distribution with three degrees of freedom. You plotted one with 2.

– 42-
Apr 11 at 5:04





I plotted a distribution with three degrees of freedom. You plotted one with 2.

– 42-
Apr 11 at 5:04



















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