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How to exclude rows based on multi column value conditions in pandas dataframe?
Add one row to pandas DataFrameSelecting multiple columns in a pandas dataframeAdding new column to existing DataFrame in Python pandasDelete column from pandas DataFrameHow to drop rows of Pandas DataFrame whose value in certain columns is NaNHow do I get the row count of a pandas DataFrame?How to iterate over rows in a DataFrame in Pandas?Select rows from a DataFrame based on values in a column in pandasDeleting DataFrame row in Pandas based on column valueGet list from pandas DataFrame column headers
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty height:90px;width:728px;box-sizing:border-box;
There's pandas dataframe ad below:
email score
a@domain.com A
b@domain.com A
c@domain.com C
d@domain.com B
I want to exclude rows with email a@domain.com and c@domain.com.Expect result as below:
email score
b@domain.com A
d@domain.com B
I tried 3 times but failed:
df=df[df.email !='a@domain.com' & df.email !='c@domain.com' ]
TypeError: cannot compare a dtyped [object] array with a scalar of type [bool]
df=df[df.email !='a@domain.com' && df.email !='c@domain.com' ]
SyntaxError: invalid syntax
df=df[df.email !='a@domain.com' | 'c@domain.com' ]
TypeError: unsupported operand type(s) for |: 'str' and 'str'
What's the problem?
python pandas
add a comment |
There's pandas dataframe ad below:
email score
a@domain.com A
b@domain.com A
c@domain.com C
d@domain.com B
I want to exclude rows with email a@domain.com and c@domain.com.Expect result as below:
email score
b@domain.com A
d@domain.com B
I tried 3 times but failed:
df=df[df.email !='a@domain.com' & df.email !='c@domain.com' ]
TypeError: cannot compare a dtyped [object] array with a scalar of type [bool]
df=df[df.email !='a@domain.com' && df.email !='c@domain.com' ]
SyntaxError: invalid syntax
df=df[df.email !='a@domain.com' | 'c@domain.com' ]
TypeError: unsupported operand type(s) for |: 'str' and 'str'
What's the problem?
python pandas
add a comment |
There's pandas dataframe ad below:
email score
a@domain.com A
b@domain.com A
c@domain.com C
d@domain.com B
I want to exclude rows with email a@domain.com and c@domain.com.Expect result as below:
email score
b@domain.com A
d@domain.com B
I tried 3 times but failed:
df=df[df.email !='a@domain.com' & df.email !='c@domain.com' ]
TypeError: cannot compare a dtyped [object] array with a scalar of type [bool]
df=df[df.email !='a@domain.com' && df.email !='c@domain.com' ]
SyntaxError: invalid syntax
df=df[df.email !='a@domain.com' | 'c@domain.com' ]
TypeError: unsupported operand type(s) for |: 'str' and 'str'
What's the problem?
python pandas
There's pandas dataframe ad below:
email score
a@domain.com A
b@domain.com A
c@domain.com C
d@domain.com B
I want to exclude rows with email a@domain.com and c@domain.com.Expect result as below:
email score
b@domain.com A
d@domain.com B
I tried 3 times but failed:
df=df[df.email !='a@domain.com' & df.email !='c@domain.com' ]
TypeError: cannot compare a dtyped [object] array with a scalar of type [bool]
df=df[df.email !='a@domain.com' && df.email !='c@domain.com' ]
SyntaxError: invalid syntax
df=df[df.email !='a@domain.com' | 'c@domain.com' ]
TypeError: unsupported operand type(s) for |: 'str' and 'str'
What's the problem?
python pandas
python pandas
edited Mar 25 at 2:34
kittygirl
asked Mar 25 at 2:33
kittygirlkittygirl
597618
597618
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
You have to surround it by parenthesis:
df = df[(df.email != 'a@domain.com') & (df.email != 'c@domain.com')]
That said, it would be easier with isin:
df = df[~df.email.isin(['a@domain.com', 'c@domain.com'])]
And now:
print(df)
Is gonna be the expected output.
1
what's~indf = df[~df.email.isin(['a@domain.com', 'c@domain.com'])]?
– kittygirl
Mar 25 at 2:36
@kittygirl theisinmeans if it contains any element in the list, but since those are the ones you don't want, use that sign to get the opposite of it and remove those.
– U9-Forward
Mar 25 at 2:37
1
Why not!but~?
– kittygirl
Mar 25 at 2:39
@kittygirl That's a very good point, but in pandas, it is different, you have to use~
– U9-Forward
Mar 25 at 2:40
add a comment |
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1 Answer
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active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
You have to surround it by parenthesis:
df = df[(df.email != 'a@domain.com') & (df.email != 'c@domain.com')]
That said, it would be easier with isin:
df = df[~df.email.isin(['a@domain.com', 'c@domain.com'])]
And now:
print(df)
Is gonna be the expected output.
1
what's~indf = df[~df.email.isin(['a@domain.com', 'c@domain.com'])]?
– kittygirl
Mar 25 at 2:36
@kittygirl theisinmeans if it contains any element in the list, but since those are the ones you don't want, use that sign to get the opposite of it and remove those.
– U9-Forward
Mar 25 at 2:37
1
Why not!but~?
– kittygirl
Mar 25 at 2:39
@kittygirl That's a very good point, but in pandas, it is different, you have to use~
– U9-Forward
Mar 25 at 2:40
add a comment |
You have to surround it by parenthesis:
df = df[(df.email != 'a@domain.com') & (df.email != 'c@domain.com')]
That said, it would be easier with isin:
df = df[~df.email.isin(['a@domain.com', 'c@domain.com'])]
And now:
print(df)
Is gonna be the expected output.
1
what's~indf = df[~df.email.isin(['a@domain.com', 'c@domain.com'])]?
– kittygirl
Mar 25 at 2:36
@kittygirl theisinmeans if it contains any element in the list, but since those are the ones you don't want, use that sign to get the opposite of it and remove those.
– U9-Forward
Mar 25 at 2:37
1
Why not!but~?
– kittygirl
Mar 25 at 2:39
@kittygirl That's a very good point, but in pandas, it is different, you have to use~
– U9-Forward
Mar 25 at 2:40
add a comment |
You have to surround it by parenthesis:
df = df[(df.email != 'a@domain.com') & (df.email != 'c@domain.com')]
That said, it would be easier with isin:
df = df[~df.email.isin(['a@domain.com', 'c@domain.com'])]
And now:
print(df)
Is gonna be the expected output.
You have to surround it by parenthesis:
df = df[(df.email != 'a@domain.com') & (df.email != 'c@domain.com')]
That said, it would be easier with isin:
df = df[~df.email.isin(['a@domain.com', 'c@domain.com'])]
And now:
print(df)
Is gonna be the expected output.
answered Mar 25 at 2:34
U9-ForwardU9-Forward
21.7k51847
21.7k51847
1
what's~indf = df[~df.email.isin(['a@domain.com', 'c@domain.com'])]?
– kittygirl
Mar 25 at 2:36
@kittygirl theisinmeans if it contains any element in the list, but since those are the ones you don't want, use that sign to get the opposite of it and remove those.
– U9-Forward
Mar 25 at 2:37
1
Why not!but~?
– kittygirl
Mar 25 at 2:39
@kittygirl That's a very good point, but in pandas, it is different, you have to use~
– U9-Forward
Mar 25 at 2:40
add a comment |
1
what's~indf = df[~df.email.isin(['a@domain.com', 'c@domain.com'])]?
– kittygirl
Mar 25 at 2:36
@kittygirl theisinmeans if it contains any element in the list, but since those are the ones you don't want, use that sign to get the opposite of it and remove those.
– U9-Forward
Mar 25 at 2:37
1
Why not!but~?
– kittygirl
Mar 25 at 2:39
@kittygirl That's a very good point, but in pandas, it is different, you have to use~
– U9-Forward
Mar 25 at 2:40
1
1
what's
~ in df = df[~df.email.isin(['a@domain.com', 'c@domain.com'])]?– kittygirl
Mar 25 at 2:36
what's
~ in df = df[~df.email.isin(['a@domain.com', 'c@domain.com'])]?– kittygirl
Mar 25 at 2:36
@kittygirl the
isin means if it contains any element in the list, but since those are the ones you don't want, use that sign to get the opposite of it and remove those.– U9-Forward
Mar 25 at 2:37
@kittygirl the
isin means if it contains any element in the list, but since those are the ones you don't want, use that sign to get the opposite of it and remove those.– U9-Forward
Mar 25 at 2:37
1
1
Why not
! but ~?– kittygirl
Mar 25 at 2:39
Why not
! but ~?– kittygirl
Mar 25 at 2:39
@kittygirl That's a very good point, but in pandas, it is different, you have to use
~– U9-Forward
Mar 25 at 2:40
@kittygirl That's a very good point, but in pandas, it is different, you have to use
~– U9-Forward
Mar 25 at 2:40
add a comment |
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