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How to show data from mysql in json response


How do I format a Microsoft JSON date?How can I pretty-print JSON in a shell script?How to parse JSON in JavaWhy does Google prepend while(1); to their JSON responses?Why can't Python parse this JSON data?How can I pretty-print JSON using JavaScript?How to parse JSON using Node.js?How do I POST JSON data with Curl from a terminal/commandline to Test Spring REST?How do I get ASP.NET Web API to return JSON instead of XML using Chrome?How do I write JSON data to a file?






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0















Hi all i am working on json to send data i had from a mysql query back to facebook bot, i just want o know if this looks right as i cant get the data to show in the results area



app.get("/Getcompany", function(request, response) 
const cname = request.query.cname, query = `select * from clientdata_nsw where companyname = $connection.escape(
cname
)`;
connection.query(query, function(err, rows)
if (err)
console.log(err);
return;

console.log(cname);

rows.forEach(function(result)
console.log(
result.companyname,
result.service,
result.phone,
result.open_times,
result.rating_facebook,
result.rating_goggle
);
);
response.json(

"version": "v2",
"content":
"messages": [

"type": "text",
"text": "Company: result.companynamenPhone: result.phonenService:  result.servicenOpen: result.open_timesnFacebook: result.rating_facebook StarnGoogle: result.rating_goggle Star",



]

)
);

)









share|improve this question






















  • result.companyname will just be a string. use template literal instead, `$somevariable`

    – 1556089774
    Mar 25 at 16:50

















0















Hi all i am working on json to send data i had from a mysql query back to facebook bot, i just want o know if this looks right as i cant get the data to show in the results area



app.get("/Getcompany", function(request, response) 
const cname = request.query.cname, query = `select * from clientdata_nsw where companyname = $connection.escape(
cname
)`;
connection.query(query, function(err, rows)
if (err)
console.log(err);
return;

console.log(cname);

rows.forEach(function(result)
console.log(
result.companyname,
result.service,
result.phone,
result.open_times,
result.rating_facebook,
result.rating_goggle
);
);
response.json(

"version": "v2",
"content":
"messages": [

"type": "text",
"text": "Company: result.companynamenPhone: result.phonenService:  result.servicenOpen: result.open_timesnFacebook: result.rating_facebook StarnGoogle: result.rating_goggle Star",



]

)
);

)









share|improve this question






















  • result.companyname will just be a string. use template literal instead, `$somevariable`

    – 1556089774
    Mar 25 at 16:50













0












0








0








Hi all i am working on json to send data i had from a mysql query back to facebook bot, i just want o know if this looks right as i cant get the data to show in the results area



app.get("/Getcompany", function(request, response) 
const cname = request.query.cname, query = `select * from clientdata_nsw where companyname = $connection.escape(
cname
)`;
connection.query(query, function(err, rows)
if (err)
console.log(err);
return;

console.log(cname);

rows.forEach(function(result)
console.log(
result.companyname,
result.service,
result.phone,
result.open_times,
result.rating_facebook,
result.rating_goggle
);
);
response.json(

"version": "v2",
"content":
"messages": [

"type": "text",
"text": "Company: result.companynamenPhone: result.phonenService:  result.servicenOpen: result.open_timesnFacebook: result.rating_facebook StarnGoogle: result.rating_goggle Star",



]

)
);

)









share|improve this question














Hi all i am working on json to send data i had from a mysql query back to facebook bot, i just want o know if this looks right as i cant get the data to show in the results area



app.get("/Getcompany", function(request, response) 
const cname = request.query.cname, query = `select * from clientdata_nsw where companyname = $connection.escape(
cname
)`;
connection.query(query, function(err, rows)
if (err)
console.log(err);
return;

console.log(cname);

rows.forEach(function(result)
console.log(
result.companyname,
result.service,
result.phone,
result.open_times,
result.rating_facebook,
result.rating_goggle
);
);
response.json(

"version": "v2",
"content":
"messages": [

"type": "text",
"text": "Company: result.companynamenPhone: result.phonenService:  result.servicenOpen: result.open_timesnFacebook: result.rating_facebook StarnGoogle: result.rating_goggle Star",



]

)
);

)






node.js json






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Mar 25 at 2:36









Adam WolarczukAdam Wolarczuk

136




136












  • result.companyname will just be a string. use template literal instead, `$somevariable`

    – 1556089774
    Mar 25 at 16:50

















  • result.companyname will just be a string. use template literal instead, `$somevariable`

    – 1556089774
    Mar 25 at 16:50
















result.companyname will just be a string. use template literal instead, `$somevariable`

– 1556089774
Mar 25 at 16:50





result.companyname will just be a string. use template literal instead, `$somevariable`

– 1556089774
Mar 25 at 16:50












0






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