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JSON data type for like column


How do you set a default value for a MySQL Datetime column?Which MySQL data type to use for storing boolean valuesShould I use the datetime or timestamp data type in MySQL?How do I change the data type for a column in MySQL?SQL select only rows with max value on a columnReference - What does this error mean in PHP?Storing JSON in database vs. having a new column for each keySELECT all and ORDER by Column A without duplicate of Column B and then ORDER by Column CINSERT INTO table SELECT & Append a columnIs the MySQL JSON data type bad for performance for data retrieval?






.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;








0















I'm trying to make like column.



like column is used when users like the content they push like button and users can do 1 like for 1 content.



So I decided to use JSON data type for like in order to prevent duplication of like.



but, here is my problem: I've read document, functions are seemed to be required original data as first parameter.



ex:)



mysql> SET @j = '"a": 1'; //this is original data
mysql> SELECT JSON_ARRAY_APPEND(@j, '$', 'z') as result;
+---------------------------------+
| result |
+---------------------------------+
| ["a": 1, "z"] |
+---------------------------------+


If I want to add "b":2 then I need to fetch all json data, all I want to do is just push a data to it not fetching all json data from like column.



I want to do this :



mysql> SELECT database.table.`like`.JSON_ARRAY_APPEND('$', '"b":2') as result;
+---------------------------------+
| result |
+---------------------------------+
| ["a": 1, "z"] |
+---------------------------------+


Let me know if you need more information.
Thanks.










share|improve this question




























    0















    I'm trying to make like column.



    like column is used when users like the content they push like button and users can do 1 like for 1 content.



    So I decided to use JSON data type for like in order to prevent duplication of like.



    but, here is my problem: I've read document, functions are seemed to be required original data as first parameter.



    ex:)



    mysql> SET @j = '"a": 1'; //this is original data
    mysql> SELECT JSON_ARRAY_APPEND(@j, '$', 'z') as result;
    +---------------------------------+
    | result |
    +---------------------------------+
    | ["a": 1, "z"] |
    +---------------------------------+


    If I want to add "b":2 then I need to fetch all json data, all I want to do is just push a data to it not fetching all json data from like column.



    I want to do this :



    mysql> SELECT database.table.`like`.JSON_ARRAY_APPEND('$', '"b":2') as result;
    +---------------------------------+
    | result |
    +---------------------------------+
    | ["a": 1, "z"] |
    +---------------------------------+


    Let me know if you need more information.
    Thanks.










    share|improve this question
























      0












      0








      0








      I'm trying to make like column.



      like column is used when users like the content they push like button and users can do 1 like for 1 content.



      So I decided to use JSON data type for like in order to prevent duplication of like.



      but, here is my problem: I've read document, functions are seemed to be required original data as first parameter.



      ex:)



      mysql> SET @j = '"a": 1'; //this is original data
      mysql> SELECT JSON_ARRAY_APPEND(@j, '$', 'z') as result;
      +---------------------------------+
      | result |
      +---------------------------------+
      | ["a": 1, "z"] |
      +---------------------------------+


      If I want to add "b":2 then I need to fetch all json data, all I want to do is just push a data to it not fetching all json data from like column.



      I want to do this :



      mysql> SELECT database.table.`like`.JSON_ARRAY_APPEND('$', '"b":2') as result;
      +---------------------------------+
      | result |
      +---------------------------------+
      | ["a": 1, "z"] |
      +---------------------------------+


      Let me know if you need more information.
      Thanks.










      share|improve this question














      I'm trying to make like column.



      like column is used when users like the content they push like button and users can do 1 like for 1 content.



      So I decided to use JSON data type for like in order to prevent duplication of like.



      but, here is my problem: I've read document, functions are seemed to be required original data as first parameter.



      ex:)



      mysql> SET @j = '"a": 1'; //this is original data
      mysql> SELECT JSON_ARRAY_APPEND(@j, '$', 'z') as result;
      +---------------------------------+
      | result |
      +---------------------------------+
      | ["a": 1, "z"] |
      +---------------------------------+


      If I want to add "b":2 then I need to fetch all json data, all I want to do is just push a data to it not fetching all json data from like column.



      I want to do this :



      mysql> SELECT database.table.`like`.JSON_ARRAY_APPEND('$', '"b":2') as result;
      +---------------------------------+
      | result |
      +---------------------------------+
      | ["a": 1, "z"] |
      +---------------------------------+


      Let me know if you need more information.
      Thanks.







      mysql






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked Mar 25 at 9:34









      JillAndMeJillAndMe

      1481 silver badge10 bronze badges




      1481 silver badge10 bronze badges






















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          @JillAndMe! you can use the JSON_ARRAY_APPEND() method. I hope this will help you JSON_ARRAY_APPEND()






          share|improve this answer

























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            @JillAndMe! you can use the JSON_ARRAY_APPEND() method. I hope this will help you JSON_ARRAY_APPEND()






            share|improve this answer



























              1














              @JillAndMe! you can use the JSON_ARRAY_APPEND() method. I hope this will help you JSON_ARRAY_APPEND()






              share|improve this answer

























                1












                1








                1







                @JillAndMe! you can use the JSON_ARRAY_APPEND() method. I hope this will help you JSON_ARRAY_APPEND()






                share|improve this answer













                @JillAndMe! you can use the JSON_ARRAY_APPEND() method. I hope this will help you JSON_ARRAY_APPEND()







                share|improve this answer












                share|improve this answer



                share|improve this answer










                answered Mar 25 at 9:40









                MKJMKJ

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