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return the uppercase alphabets
compare the length of two list and append in racketParsing through a list in racket(Racket) Interpreting Seq to return last expression in listLearning DrRacket, Why will this not return false?Converting numbers to english letter listReturn an integer literal from a Scheme functionIN Racket Define a function that takes two argumentsString on empty-scene (racket)Scheme - returning first n-elements of an arrayTrying to get this code to work, can't understand where to put the argument in and keep getting errors
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I am writing a function which can return the uppercase alphabets from an input string. And it works well when I display it. However, can anyone tell me how to return the output string rather than just display it?
(define (convert input)
(define s(string))
(for ([i (string->list input)])
(when (char-alphabetic? i)
(let ((s(string-append s (string i))))
(display (string-upcase s))))))
racket
add a comment |
I am writing a function which can return the uppercase alphabets from an input string. And it works well when I display it. However, can anyone tell me how to return the output string rather than just display it?
(define (convert input)
(define s(string))
(for ([i (string->list input)])
(when (char-alphabetic? i)
(let ((s(string-append s (string i))))
(display (string-upcase s))))))
racket
it's racket it seems.
– mallikarjun
Mar 25 at 6:01
Looking to see if IntelliJ has a 'racket' plugin, lol...
– Steve
Mar 25 at 6:04
add a comment |
I am writing a function which can return the uppercase alphabets from an input string. And it works well when I display it. However, can anyone tell me how to return the output string rather than just display it?
(define (convert input)
(define s(string))
(for ([i (string->list input)])
(when (char-alphabetic? i)
(let ((s(string-append s (string i))))
(display (string-upcase s))))))
racket
I am writing a function which can return the uppercase alphabets from an input string. And it works well when I display it. However, can anyone tell me how to return the output string rather than just display it?
(define (convert input)
(define s(string))
(for ([i (string->list input)])
(when (char-alphabetic? i)
(let ((s(string-append s (string i))))
(display (string-upcase s))))))
racket
racket
edited Mar 25 at 6:09
eyllanesc
96.8k123770
96.8k123770
asked Mar 25 at 5:58
user11104854
it's racket it seems.
– mallikarjun
Mar 25 at 6:01
Looking to see if IntelliJ has a 'racket' plugin, lol...
– Steve
Mar 25 at 6:04
add a comment |
it's racket it seems.
– mallikarjun
Mar 25 at 6:01
Looking to see if IntelliJ has a 'racket' plugin, lol...
– Steve
Mar 25 at 6:04
it's racket it seems.
– mallikarjun
Mar 25 at 6:01
it's racket it seems.
– mallikarjun
Mar 25 at 6:01
Looking to see if IntelliJ has a 'racket' plugin, lol...
– Steve
Mar 25 at 6:04
Looking to see if IntelliJ has a 'racket' plugin, lol...
– Steve
Mar 25 at 6:04
add a comment |
2 Answers
2
active
oldest
votes
If you want to return data from a function, like you are here with returning a string, I suggest you look past the basic for loop to its variants, such as for/list, for/vector, for/hash, and for/fold. In this case for/list can help:
(define (convert input)
(list->string
(for/list ([i input] #:when (char-alphabetic? i))
(char-upcase i))))
Using it:
> (convert "ab1c23")
"ABC"
add a comment |
Here's one possible solution:
(define (convert input)
(list->string
(foldr (lambda (chr acc)
(if (char-alphabetic? chr)
(cons (char-upcase chr) acc)
acc))
'()
(string->list input))))
We need to accumulate the result somewhere, instead of printing char by char. For that, we use foldr to process a list of chars, uppercasing alphabetic chars and ignoring the others. This produces a list of chars that we convert back to a string using list->string. It works as expected:
(convert "ab1c23")
=> "ABC"
add a comment |
Your Answer
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
If you want to return data from a function, like you are here with returning a string, I suggest you look past the basic for loop to its variants, such as for/list, for/vector, for/hash, and for/fold. In this case for/list can help:
(define (convert input)
(list->string
(for/list ([i input] #:when (char-alphabetic? i))
(char-upcase i))))
Using it:
> (convert "ab1c23")
"ABC"
add a comment |
If you want to return data from a function, like you are here with returning a string, I suggest you look past the basic for loop to its variants, such as for/list, for/vector, for/hash, and for/fold. In this case for/list can help:
(define (convert input)
(list->string
(for/list ([i input] #:when (char-alphabetic? i))
(char-upcase i))))
Using it:
> (convert "ab1c23")
"ABC"
add a comment |
If you want to return data from a function, like you are here with returning a string, I suggest you look past the basic for loop to its variants, such as for/list, for/vector, for/hash, and for/fold. In this case for/list can help:
(define (convert input)
(list->string
(for/list ([i input] #:when (char-alphabetic? i))
(char-upcase i))))
Using it:
> (convert "ab1c23")
"ABC"
If you want to return data from a function, like you are here with returning a string, I suggest you look past the basic for loop to its variants, such as for/list, for/vector, for/hash, and for/fold. In this case for/list can help:
(define (convert input)
(list->string
(for/list ([i input] #:when (char-alphabetic? i))
(char-upcase i))))
Using it:
> (convert "ab1c23")
"ABC"
answered Mar 25 at 12:16
Alex KnauthAlex Knauth
5,3881823
5,3881823
add a comment |
add a comment |
Here's one possible solution:
(define (convert input)
(list->string
(foldr (lambda (chr acc)
(if (char-alphabetic? chr)
(cons (char-upcase chr) acc)
acc))
'()
(string->list input))))
We need to accumulate the result somewhere, instead of printing char by char. For that, we use foldr to process a list of chars, uppercasing alphabetic chars and ignoring the others. This produces a list of chars that we convert back to a string using list->string. It works as expected:
(convert "ab1c23")
=> "ABC"
add a comment |
Here's one possible solution:
(define (convert input)
(list->string
(foldr (lambda (chr acc)
(if (char-alphabetic? chr)
(cons (char-upcase chr) acc)
acc))
'()
(string->list input))))
We need to accumulate the result somewhere, instead of printing char by char. For that, we use foldr to process a list of chars, uppercasing alphabetic chars and ignoring the others. This produces a list of chars that we convert back to a string using list->string. It works as expected:
(convert "ab1c23")
=> "ABC"
add a comment |
Here's one possible solution:
(define (convert input)
(list->string
(foldr (lambda (chr acc)
(if (char-alphabetic? chr)
(cons (char-upcase chr) acc)
acc))
'()
(string->list input))))
We need to accumulate the result somewhere, instead of printing char by char. For that, we use foldr to process a list of chars, uppercasing alphabetic chars and ignoring the others. This produces a list of chars that we convert back to a string using list->string. It works as expected:
(convert "ab1c23")
=> "ABC"
Here's one possible solution:
(define (convert input)
(list->string
(foldr (lambda (chr acc)
(if (char-alphabetic? chr)
(cons (char-upcase chr) acc)
acc))
'()
(string->list input))))
We need to accumulate the result somewhere, instead of printing char by char. For that, we use foldr to process a list of chars, uppercasing alphabetic chars and ignoring the others. This produces a list of chars that we convert back to a string using list->string. It works as expected:
(convert "ab1c23")
=> "ABC"
answered Mar 25 at 10:35
Óscar LópezÓscar López
185k26241332
185k26241332
add a comment |
add a comment |
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it's racket it seems.
– mallikarjun
Mar 25 at 6:01
Looking to see if IntelliJ has a 'racket' plugin, lol...
– Steve
Mar 25 at 6:04