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There are a way to calculate matematically the preorder-sucessor of a node by its label?


How to find the lowest common ancestor of two nodes in any binary tree?saving a tree as preorderbinary tree construction from preorderWhen to use Preorder, Postorder, and Inorder Binary Search Tree Traversal strategiesIterative preorder traversal (Debug)BFS in python from a preorder and inorderPreorder printing Binary Tree with indentationsBinary trees, returning the next node in a preorder traversalPreOrder Tree Traversal in PrologConverting a list of nodes in preorder back into a binary tree






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0















There are a bitwise function that calculates the sucessor of any node of this (labelled) complete binary tree of depth k?





The labels are bit strings. For each level l, with 0>lk, there are 2l labels of l bits. In the illustration k=3. The order of the labels is lexicographical (same as preorder in binary-tree terminology).



It is not possible to use a bynary-tree data structure, the function must use only the label (!). The successor function use also the parameter k, so it is s(x,k). Some examples of results of the function:




  • 00 == s(0,3)


  • 001 == s(000,3)


  • 1 == s(011,3)


  • 10 == s(1,3)

  • null == s(111,3)

It is an inference based on the syntax rules of the labels, not on a data structure.



The aim is bitwise function for a binary representation.



PS: the solution can be a link to a library... Any language. Can use internal binary buffer or usual integer (e.g. 64 bits) to labels; can use Javascript, C, or any other language...




No problem to map to other label representation if there are a simple bijective relation. For example we can represent labels by a pair of integers (size,value)



(size,value) BitString representation
(1,0) 0
(2,0) 00
(3,0) 000
(4,0) 0000
(4,1) 0001
(3,1) 001
(4,2) 0010
(4,3) 0011
(2,1) 01
... ...



For ASCII strings, of course, there are a "visual solution". Expressing with Javascript:



function s(x,k) 
let l = x.length
if (l<k)
return x+'0';
l--;
if (x[l]=='0')
return x.slice(0,l)+'1'
else
return (x=='1'.padEnd(k,'1'))? null: x.slice(1)










share|improve this question






























    0















    There are a bitwise function that calculates the sucessor of any node of this (labelled) complete binary tree of depth k?





    The labels are bit strings. For each level l, with 0>lk, there are 2l labels of l bits. In the illustration k=3. The order of the labels is lexicographical (same as preorder in binary-tree terminology).



    It is not possible to use a bynary-tree data structure, the function must use only the label (!). The successor function use also the parameter k, so it is s(x,k). Some examples of results of the function:




    • 00 == s(0,3)


    • 001 == s(000,3)


    • 1 == s(011,3)


    • 10 == s(1,3)

    • null == s(111,3)

    It is an inference based on the syntax rules of the labels, not on a data structure.



    The aim is bitwise function for a binary representation.



    PS: the solution can be a link to a library... Any language. Can use internal binary buffer or usual integer (e.g. 64 bits) to labels; can use Javascript, C, or any other language...




    No problem to map to other label representation if there are a simple bijective relation. For example we can represent labels by a pair of integers (size,value)



    (size,value) BitString representation
    (1,0) 0
    (2,0) 00
    (3,0) 000
    (4,0) 0000
    (4,1) 0001
    (3,1) 001
    (4,2) 0010
    (4,3) 0011
    (2,1) 01
    ... ...



    For ASCII strings, of course, there are a "visual solution". Expressing with Javascript:



    function s(x,k) 
    let l = x.length
    if (l<k)
    return x+'0';
    l--;
    if (x[l]=='0')
    return x.slice(0,l)+'1'
    else
    return (x=='1'.padEnd(k,'1'))? null: x.slice(1)










    share|improve this question


























      0












      0








      0








      There are a bitwise function that calculates the sucessor of any node of this (labelled) complete binary tree of depth k?





      The labels are bit strings. For each level l, with 0>lk, there are 2l labels of l bits. In the illustration k=3. The order of the labels is lexicographical (same as preorder in binary-tree terminology).



      It is not possible to use a bynary-tree data structure, the function must use only the label (!). The successor function use also the parameter k, so it is s(x,k). Some examples of results of the function:




      • 00 == s(0,3)


      • 001 == s(000,3)


      • 1 == s(011,3)


      • 10 == s(1,3)

      • null == s(111,3)

      It is an inference based on the syntax rules of the labels, not on a data structure.



      The aim is bitwise function for a binary representation.



      PS: the solution can be a link to a library... Any language. Can use internal binary buffer or usual integer (e.g. 64 bits) to labels; can use Javascript, C, or any other language...




      No problem to map to other label representation if there are a simple bijective relation. For example we can represent labels by a pair of integers (size,value)



      (size,value) BitString representation
      (1,0) 0
      (2,0) 00
      (3,0) 000
      (4,0) 0000
      (4,1) 0001
      (3,1) 001
      (4,2) 0010
      (4,3) 0011
      (2,1) 01
      ... ...



      For ASCII strings, of course, there are a "visual solution". Expressing with Javascript:



      function s(x,k) 
      let l = x.length
      if (l<k)
      return x+'0';
      l--;
      if (x[l]=='0')
      return x.slice(0,l)+'1'
      else
      return (x=='1'.padEnd(k,'1'))? null: x.slice(1)










      share|improve this question
















      There are a bitwise function that calculates the sucessor of any node of this (labelled) complete binary tree of depth k?





      The labels are bit strings. For each level l, with 0>lk, there are 2l labels of l bits. In the illustration k=3. The order of the labels is lexicographical (same as preorder in binary-tree terminology).



      It is not possible to use a bynary-tree data structure, the function must use only the label (!). The successor function use also the parameter k, so it is s(x,k). Some examples of results of the function:




      • 00 == s(0,3)


      • 001 == s(000,3)


      • 1 == s(011,3)


      • 10 == s(1,3)

      • null == s(111,3)

      It is an inference based on the syntax rules of the labels, not on a data structure.



      The aim is bitwise function for a binary representation.



      PS: the solution can be a link to a library... Any language. Can use internal binary buffer or usual integer (e.g. 64 bits) to labels; can use Javascript, C, or any other language...




      No problem to map to other label representation if there are a simple bijective relation. For example we can represent labels by a pair of integers (size,value)



      (size,value) BitString representation
      (1,0) 0
      (2,0) 00
      (3,0) 000
      (4,0) 0000
      (4,1) 0001
      (3,1) 001
      (4,2) 0010
      (4,3) 0011
      (2,1) 01
      ... ...



      For ASCII strings, of course, there are a "visual solution". Expressing with Javascript:



      function s(x,k) 
      let l = x.length
      if (l<k)
      return x+'0';
      l--;
      if (x[l]=='0')
      return x.slice(0,l)+'1'
      else
      return (x=='1'.padEnd(k,'1'))? null: x.slice(1)







      binary-tree






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited Mar 26 at 0:46







      Peter Krauss

















      asked Mar 25 at 22:19









      Peter KraussPeter Krauss

      5,83111 gold badges88 silver badges191 bronze badges




      5,83111 gold badges88 silver badges191 bronze badges






















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