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1

I'm trying to generate a function that returns an object-literal type (not sure if that's the correct term). I currently use the following:

ts.createFunctionDeclaration(
 undefined, //decorators
 [], //modifiers
 undefined, //asterisk
 'foo',
 undefined, //name
 [], //parameters

 ts.createTypeLiteralNode( //return type
 [
 ts.createPropertySignature(
 undefined, //modifiers
 ts.createIdentifier('bar'),
 undefined, //question token
 ts.createTypeReferenceNode(
 'string',
 undefined //generics
 ),
 undefined //initializer
 ),
 ts.createPropertySignature(
 undefined, //modifiers
 ts.createIdentifier('baz'),
 undefined, //question token
 ts.createTypeReferenceNode(
 'string',
 undefined //generics
 ),
 undefined //initializer
 )
 ]
 ),

 ts.createBlock([
 //some interesting statements
 ])
);

This generates this code:

function foo(): 
 bar: string;
 baz: string;
 
 //interesting statements

It works, but I'd like the return type literal to be on a single line like this:

function foo(): bar: string, baz: string 
 //interesting statements

Is this possible using just the Typescript compiler API, or do I need to use an external linter/formatter?

typescript typescript-compiler-api

share|improve this question

asked Mar 26 at 17:11

superbadcodemonkeysuperbadcodemonkey

8788 bronze badges

add a comment | 

1

I'm trying to generate a function that returns an object-literal type (not sure if that's the correct term). I currently use the following:

ts.createFunctionDeclaration(
 undefined, //decorators
 [], //modifiers
 undefined, //asterisk
 'foo',
 undefined, //name
 [], //parameters

 ts.createTypeLiteralNode( //return type
 [
 ts.createPropertySignature(
 undefined, //modifiers
 ts.createIdentifier('bar'),
 undefined, //question token
 ts.createTypeReferenceNode(
 'string',
 undefined //generics
 ),
 undefined //initializer
 ),
 ts.createPropertySignature(
 undefined, //modifiers
 ts.createIdentifier('baz'),
 undefined, //question token
 ts.createTypeReferenceNode(
 'string',
 undefined //generics
 ),
 undefined //initializer
 )
 ]
 ),

 ts.createBlock([
 //some interesting statements
 ])
);

This generates this code:

function foo(): 
 bar: string;
 baz: string;
 
 //interesting statements

It works, but I'd like the return type literal to be on a single line like this:

function foo(): bar: string, baz: string 
 //interesting statements

Is this possible using just the Typescript compiler API, or do I need to use an external linter/formatter?

typescript typescript-compiler-api

share|improve this question

asked Mar 26 at 17:11

superbadcodemonkeysuperbadcodemonkey

8788 bronze badges

add a comment | 

I'm trying to generate a function that returns an object-literal type (not sure if that's the correct term). I currently use the following:

ts.createFunctionDeclaration(
 undefined, //decorators
 [], //modifiers
 undefined, //asterisk
 'foo',
 undefined, //name
 [], //parameters

 ts.createTypeLiteralNode( //return type
 [
 ts.createPropertySignature(
 undefined, //modifiers
 ts.createIdentifier('bar'),
 undefined, //question token
 ts.createTypeReferenceNode(
 'string',
 undefined //generics
 ),
 undefined //initializer
 ),
 ts.createPropertySignature(
 undefined, //modifiers
 ts.createIdentifier('baz'),
 undefined, //question token
 ts.createTypeReferenceNode(
 'string',
 undefined //generics
 ),
 undefined //initializer
 )
 ]
 ),

 ts.createBlock([
 //some interesting statements
 ])
);

This generates this code:

function foo(): 
 bar: string;
 baz: string;
 
 //interesting statements

It works, but I'd like the return type literal to be on a single line like this:

function foo(): bar: string, baz: string 
 //interesting statements

Is this possible using just the Typescript compiler API, or do I need to use an external linter/formatter?

typescript typescript-compiler-api

share|improve this question

asked Mar 26 at 17:11

superbadcodemonkeysuperbadcodemonkey

8788 bronze badges

ts.createFunctionDeclaration(
 undefined, //decorators
 [], //modifiers
 undefined, //asterisk
 'foo',
 undefined, //name
 [], //parameters

 ts.createTypeLiteralNode( //return type
 [
 ts.createPropertySignature(
 undefined, //modifiers
 ts.createIdentifier('bar'),
 undefined, //question token
 ts.createTypeReferenceNode(
 'string',
 undefined //generics
 ),
 undefined //initializer
 ),
 ts.createPropertySignature(
 undefined, //modifiers
 ts.createIdentifier('baz'),
 undefined, //question token
 ts.createTypeReferenceNode(
 'string',
 undefined //generics
 ),
 undefined //initializer
 )
 ]
 ),

 ts.createBlock([
 //some interesting statements
 ])
);

function foo(): 
 bar: string;
 baz: string;
 
 //interesting statements

function foo(): bar: string, baz: string 
 //interesting statements

share|improve this question

asked Mar 26 at 17:11

superbadcodemonkeysuperbadcodemonkey

8788 bronze badges

share|improve this question

asked Mar 26 at 17:11

superbadcodemonkeysuperbadcodemonkey

8788 bronze badges

asked Mar 26 at 17:11

superbadcodemonkeysuperbadcodemonkey

8788 bronze badges

asked Mar 26 at 17:11

superbadcodemonkeysuperbadcodemonkey

8788 bronze badges

1 Answer
1

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0

Try setting the emit flag EmitFlags.SingleLine on the type literal node:

const typeLiteralNode = ts.createTypeLiteralNode(...);
ts.setEmitFlags(typeLiteralNode, EmitFlags.SingleLine);

emitTypeLiteral in emitter.ts seems to indicate it's possible to do this.

share|improve this answer

answered Mar 26 at 17:39

David SherretDavid Sherret

57.8k1818 gold badges133133 silver badges133133 bronze badges

add a comment | 

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0

Try setting the emit flag EmitFlags.SingleLine on the type literal node:

const typeLiteralNode = ts.createTypeLiteralNode(...);
ts.setEmitFlags(typeLiteralNode, EmitFlags.SingleLine);

emitTypeLiteral in emitter.ts seems to indicate it's possible to do this.

share|improve this answer

answered Mar 26 at 17:39

David SherretDavid Sherret

57.8k1818 gold badges133133 silver badges133133 bronze badges

add a comment | 

0

Try setting the emit flag EmitFlags.SingleLine on the type literal node:

const typeLiteralNode = ts.createTypeLiteralNode(...);
ts.setEmitFlags(typeLiteralNode, EmitFlags.SingleLine);

emitTypeLiteral in emitter.ts seems to indicate it's possible to do this.

share|improve this answer

answered Mar 26 at 17:39

David SherretDavid Sherret

57.8k1818 gold badges133133 silver badges133133 bronze badges

add a comment | 

Try setting the emit flag EmitFlags.SingleLine on the type literal node:

const typeLiteralNode = ts.createTypeLiteralNode(...);
ts.setEmitFlags(typeLiteralNode, EmitFlags.SingleLine);

emitTypeLiteral in emitter.ts seems to indicate it's possible to do this.

share|improve this answer

answered Mar 26 at 17:39

David SherretDavid Sherret

57.8k1818 gold badges133133 silver badges133133 bronze badges

const typeLiteralNode = ts.createTypeLiteralNode(...);
ts.setEmitFlags(typeLiteralNode, EmitFlags.SingleLine);

share|improve this answer

answered Mar 26 at 17:39

David SherretDavid Sherret

57.8k1818 gold badges133133 silver badges133133 bronze badges

answered Mar 26 at 17:39

David SherretDavid Sherret

57.8k1818 gold badges133133 silver badges133133 bronze badges

answered Mar 26 at 17:39

David SherretDavid Sherret

57.8k1818 gold badges133133 silver badges133133 bronze badges