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Why do I get he error: argument is of length 0 for dffits?


How can I get useful error messages in PHP?What's a good way to extend Error in JavaScript?Where does PHP store the error log? (php5, apache, fastcgi, cpanel)Why is `[` better than `subset`?How to find the length of a string in R400 BAD request HTTP error code meaning?“argument is of length zero” error in RandomForest tuneRF()R Function for Rounding Imputed Binary VariablesError in if (object$offset) { : argument is of length zero in relaxnet R packageError in if (pvals[minp] <= pent) { : argument is of length zero






.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;








1















I have a problem when I try to run the dffits() function for an object of my own logistic regression.
When I'm running dffits(log) I get the error message:
error in if (model$rank == 0) { : Argument is of length 0



However, when I'm using the inbuilt gym function (family = binomial), then dffits(glm) works just fine.



Here is my function for the logistic regression and a short example of my problem:



mydata <- read.csv("https://stats.idre.ucla.edu/stat/data/binary.csv")
mydata$rank <- factor(mydata$rank)
mydata$admit <- factor(mydata$admit)

logRegEst <- function(x, y, threshold = 1e-10, maxIter = 100)

calcPi <- function(x, beta)

beta <- as.vector(beta)
return(exp(x %*% beta) / (1 + exp(x %*% beta)))


beta <- rep(0, ncol(x)) # initial guess for beta

diff <- 1000
# initial value bigger than threshold so that we can enter our while loop

iterCount = 0
# counter to ensure we're not stuck in an infinite loop

while(diff > threshold) # tests for convergence

pi <- as.vector(calcPi(x, beta))
# calculate pi by using the current estimate of beta

W <- diag(pi * (1 - pi)) # calculate matrix of weights W

beta_change <- solve(t(x) %*% W %*% x) %*% t(x) %*% (y - pi)
# calculate the change in beta

beta <- beta + beta_change # new beta
diff <- sum(beta_change^2)
# calculate how much we changed beta by in this iteration
# if this is less than threshold, we'll break the while loop

iterCount <- iterCount + 1
# see if we've hit the maximum number of iterations
if(iterCount > maxIter)
stop("This isn't converging.")

# stop if we have hit the maximum number of iterations

df <- length(y) - ncol(x)
# calculating the degrees of freedom by taking the length of y minus
# the number of x columns
vcov <- solve(t(x) %*% W %*% x)
list(coefficients = beta, vcov = vcov, df = df)
# returning results


logReg <- function(formula, data)

mf <- model.frame(formula = formula, data = data)
# model.frame() returns us a data.frame with the variables needed to use the
# formula.
x <- model.matrix(attr(mf, "terms"), data = mf)
# model.matrix() creates a disign matrix. That means that for example the
#"Sex"-variable is given as a dummy variable with ones and zeros.
y <- as.numeric(model.response(mf)) - 1
# model.response gives us the response variable.
est <- logRegEst(x, y)
# Now we have the starting position to apply our function from above.
est$formula <- formula
est$call <- match.call()
est$data <- data
# We add the formular and the call to the list.
est$x <- x
est$y <- y
# We add x and y to the list.
class(est) <- "logReg"
# defining the class
est



log <- logReg(admit ~ gre + gpa, data= mydata)
glm <- glm(admit ~ gre + gpa, data= mydata, family = binomial)
dffits(glm)
dffits(log)

log$data
glm$data


I don't understand why mydata$rank == 0, because when I look at log$data I see that the rank is just defined as in glm$data.



I really appreciate your help!










share|improve this question





















  • 1





    rank is not one of the names of the list log, so log$rank will return NULL -- the condition NULL == 0 returns a length 0 logical vector which is why that error is being thrown.

    – DiceboyT
    Mar 26 at 21:00











  • Thanks for your answer @DiceboyT! Now I saw that the object glm contains something called rank. I already found out that rank is the numeric rank of the fitted linear model. But could you tell me what this is exactly? And how can I calculate it?

    – Nicki
    Mar 26 at 21:21







  • 2





    I believe it's just the number of regressors (including the intercept).

    – DiceboyT
    Mar 26 at 21:55











  • thanks, I could easily calculate the rank via ncol(x)!

    – Nicki
    Mar 26 at 23:20

















1















I have a problem when I try to run the dffits() function for an object of my own logistic regression.
When I'm running dffits(log) I get the error message:
error in if (model$rank == 0) { : Argument is of length 0



However, when I'm using the inbuilt gym function (family = binomial), then dffits(glm) works just fine.



Here is my function for the logistic regression and a short example of my problem:



mydata <- read.csv("https://stats.idre.ucla.edu/stat/data/binary.csv")
mydata$rank <- factor(mydata$rank)
mydata$admit <- factor(mydata$admit)

logRegEst <- function(x, y, threshold = 1e-10, maxIter = 100)

calcPi <- function(x, beta)

beta <- as.vector(beta)
return(exp(x %*% beta) / (1 + exp(x %*% beta)))


beta <- rep(0, ncol(x)) # initial guess for beta

diff <- 1000
# initial value bigger than threshold so that we can enter our while loop

iterCount = 0
# counter to ensure we're not stuck in an infinite loop

while(diff > threshold) # tests for convergence

pi <- as.vector(calcPi(x, beta))
# calculate pi by using the current estimate of beta

W <- diag(pi * (1 - pi)) # calculate matrix of weights W

beta_change <- solve(t(x) %*% W %*% x) %*% t(x) %*% (y - pi)
# calculate the change in beta

beta <- beta + beta_change # new beta
diff <- sum(beta_change^2)
# calculate how much we changed beta by in this iteration
# if this is less than threshold, we'll break the while loop

iterCount <- iterCount + 1
# see if we've hit the maximum number of iterations
if(iterCount > maxIter)
stop("This isn't converging.")

# stop if we have hit the maximum number of iterations

df <- length(y) - ncol(x)
# calculating the degrees of freedom by taking the length of y minus
# the number of x columns
vcov <- solve(t(x) %*% W %*% x)
list(coefficients = beta, vcov = vcov, df = df)
# returning results


logReg <- function(formula, data)

mf <- model.frame(formula = formula, data = data)
# model.frame() returns us a data.frame with the variables needed to use the
# formula.
x <- model.matrix(attr(mf, "terms"), data = mf)
# model.matrix() creates a disign matrix. That means that for example the
#"Sex"-variable is given as a dummy variable with ones and zeros.
y <- as.numeric(model.response(mf)) - 1
# model.response gives us the response variable.
est <- logRegEst(x, y)
# Now we have the starting position to apply our function from above.
est$formula <- formula
est$call <- match.call()
est$data <- data
# We add the formular and the call to the list.
est$x <- x
est$y <- y
# We add x and y to the list.
class(est) <- "logReg"
# defining the class
est



log <- logReg(admit ~ gre + gpa, data= mydata)
glm <- glm(admit ~ gre + gpa, data= mydata, family = binomial)
dffits(glm)
dffits(log)

log$data
glm$data


I don't understand why mydata$rank == 0, because when I look at log$data I see that the rank is just defined as in glm$data.



I really appreciate your help!










share|improve this question





















  • 1





    rank is not one of the names of the list log, so log$rank will return NULL -- the condition NULL == 0 returns a length 0 logical vector which is why that error is being thrown.

    – DiceboyT
    Mar 26 at 21:00











  • Thanks for your answer @DiceboyT! Now I saw that the object glm contains something called rank. I already found out that rank is the numeric rank of the fitted linear model. But could you tell me what this is exactly? And how can I calculate it?

    – Nicki
    Mar 26 at 21:21







  • 2





    I believe it's just the number of regressors (including the intercept).

    – DiceboyT
    Mar 26 at 21:55











  • thanks, I could easily calculate the rank via ncol(x)!

    – Nicki
    Mar 26 at 23:20













1












1








1








I have a problem when I try to run the dffits() function for an object of my own logistic regression.
When I'm running dffits(log) I get the error message:
error in if (model$rank == 0) { : Argument is of length 0



However, when I'm using the inbuilt gym function (family = binomial), then dffits(glm) works just fine.



Here is my function for the logistic regression and a short example of my problem:



mydata <- read.csv("https://stats.idre.ucla.edu/stat/data/binary.csv")
mydata$rank <- factor(mydata$rank)
mydata$admit <- factor(mydata$admit)

logRegEst <- function(x, y, threshold = 1e-10, maxIter = 100)

calcPi <- function(x, beta)

beta <- as.vector(beta)
return(exp(x %*% beta) / (1 + exp(x %*% beta)))


beta <- rep(0, ncol(x)) # initial guess for beta

diff <- 1000
# initial value bigger than threshold so that we can enter our while loop

iterCount = 0
# counter to ensure we're not stuck in an infinite loop

while(diff > threshold) # tests for convergence

pi <- as.vector(calcPi(x, beta))
# calculate pi by using the current estimate of beta

W <- diag(pi * (1 - pi)) # calculate matrix of weights W

beta_change <- solve(t(x) %*% W %*% x) %*% t(x) %*% (y - pi)
# calculate the change in beta

beta <- beta + beta_change # new beta
diff <- sum(beta_change^2)
# calculate how much we changed beta by in this iteration
# if this is less than threshold, we'll break the while loop

iterCount <- iterCount + 1
# see if we've hit the maximum number of iterations
if(iterCount > maxIter)
stop("This isn't converging.")

# stop if we have hit the maximum number of iterations

df <- length(y) - ncol(x)
# calculating the degrees of freedom by taking the length of y minus
# the number of x columns
vcov <- solve(t(x) %*% W %*% x)
list(coefficients = beta, vcov = vcov, df = df)
# returning results


logReg <- function(formula, data)

mf <- model.frame(formula = formula, data = data)
# model.frame() returns us a data.frame with the variables needed to use the
# formula.
x <- model.matrix(attr(mf, "terms"), data = mf)
# model.matrix() creates a disign matrix. That means that for example the
#"Sex"-variable is given as a dummy variable with ones and zeros.
y <- as.numeric(model.response(mf)) - 1
# model.response gives us the response variable.
est <- logRegEst(x, y)
# Now we have the starting position to apply our function from above.
est$formula <- formula
est$call <- match.call()
est$data <- data
# We add the formular and the call to the list.
est$x <- x
est$y <- y
# We add x and y to the list.
class(est) <- "logReg"
# defining the class
est



log <- logReg(admit ~ gre + gpa, data= mydata)
glm <- glm(admit ~ gre + gpa, data= mydata, family = binomial)
dffits(glm)
dffits(log)

log$data
glm$data


I don't understand why mydata$rank == 0, because when I look at log$data I see that the rank is just defined as in glm$data.



I really appreciate your help!










share|improve this question
















I have a problem when I try to run the dffits() function for an object of my own logistic regression.
When I'm running dffits(log) I get the error message:
error in if (model$rank == 0) { : Argument is of length 0



However, when I'm using the inbuilt gym function (family = binomial), then dffits(glm) works just fine.



Here is my function for the logistic regression and a short example of my problem:



mydata <- read.csv("https://stats.idre.ucla.edu/stat/data/binary.csv")
mydata$rank <- factor(mydata$rank)
mydata$admit <- factor(mydata$admit)

logRegEst <- function(x, y, threshold = 1e-10, maxIter = 100)

calcPi <- function(x, beta)

beta <- as.vector(beta)
return(exp(x %*% beta) / (1 + exp(x %*% beta)))


beta <- rep(0, ncol(x)) # initial guess for beta

diff <- 1000
# initial value bigger than threshold so that we can enter our while loop

iterCount = 0
# counter to ensure we're not stuck in an infinite loop

while(diff > threshold) # tests for convergence

pi <- as.vector(calcPi(x, beta))
# calculate pi by using the current estimate of beta

W <- diag(pi * (1 - pi)) # calculate matrix of weights W

beta_change <- solve(t(x) %*% W %*% x) %*% t(x) %*% (y - pi)
# calculate the change in beta

beta <- beta + beta_change # new beta
diff <- sum(beta_change^2)
# calculate how much we changed beta by in this iteration
# if this is less than threshold, we'll break the while loop

iterCount <- iterCount + 1
# see if we've hit the maximum number of iterations
if(iterCount > maxIter)
stop("This isn't converging.")

# stop if we have hit the maximum number of iterations

df <- length(y) - ncol(x)
# calculating the degrees of freedom by taking the length of y minus
# the number of x columns
vcov <- solve(t(x) %*% W %*% x)
list(coefficients = beta, vcov = vcov, df = df)
# returning results


logReg <- function(formula, data)

mf <- model.frame(formula = formula, data = data)
# model.frame() returns us a data.frame with the variables needed to use the
# formula.
x <- model.matrix(attr(mf, "terms"), data = mf)
# model.matrix() creates a disign matrix. That means that for example the
#"Sex"-variable is given as a dummy variable with ones and zeros.
y <- as.numeric(model.response(mf)) - 1
# model.response gives us the response variable.
est <- logRegEst(x, y)
# Now we have the starting position to apply our function from above.
est$formula <- formula
est$call <- match.call()
est$data <- data
# We add the formular and the call to the list.
est$x <- x
est$y <- y
# We add x and y to the list.
class(est) <- "logReg"
# defining the class
est



log <- logReg(admit ~ gre + gpa, data= mydata)
glm <- glm(admit ~ gre + gpa, data= mydata, family = binomial)
dffits(glm)
dffits(log)

log$data
glm$data


I don't understand why mydata$rank == 0, because when I look at log$data I see that the rank is just defined as in glm$data.



I really appreciate your help!







r error-handling regression logistic-regression






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Mar 26 at 20:51







Nicki

















asked Mar 26 at 20:31









NickiNicki

357 bronze badges




357 bronze badges










  • 1





    rank is not one of the names of the list log, so log$rank will return NULL -- the condition NULL == 0 returns a length 0 logical vector which is why that error is being thrown.

    – DiceboyT
    Mar 26 at 21:00











  • Thanks for your answer @DiceboyT! Now I saw that the object glm contains something called rank. I already found out that rank is the numeric rank of the fitted linear model. But could you tell me what this is exactly? And how can I calculate it?

    – Nicki
    Mar 26 at 21:21







  • 2





    I believe it's just the number of regressors (including the intercept).

    – DiceboyT
    Mar 26 at 21:55











  • thanks, I could easily calculate the rank via ncol(x)!

    – Nicki
    Mar 26 at 23:20












  • 1





    rank is not one of the names of the list log, so log$rank will return NULL -- the condition NULL == 0 returns a length 0 logical vector which is why that error is being thrown.

    – DiceboyT
    Mar 26 at 21:00











  • Thanks for your answer @DiceboyT! Now I saw that the object glm contains something called rank. I already found out that rank is the numeric rank of the fitted linear model. But could you tell me what this is exactly? And how can I calculate it?

    – Nicki
    Mar 26 at 21:21







  • 2





    I believe it's just the number of regressors (including the intercept).

    – DiceboyT
    Mar 26 at 21:55











  • thanks, I could easily calculate the rank via ncol(x)!

    – Nicki
    Mar 26 at 23:20







1




1





rank is not one of the names of the list log, so log$rank will return NULL -- the condition NULL == 0 returns a length 0 logical vector which is why that error is being thrown.

– DiceboyT
Mar 26 at 21:00





rank is not one of the names of the list log, so log$rank will return NULL -- the condition NULL == 0 returns a length 0 logical vector which is why that error is being thrown.

– DiceboyT
Mar 26 at 21:00













Thanks for your answer @DiceboyT! Now I saw that the object glm contains something called rank. I already found out that rank is the numeric rank of the fitted linear model. But could you tell me what this is exactly? And how can I calculate it?

– Nicki
Mar 26 at 21:21






Thanks for your answer @DiceboyT! Now I saw that the object glm contains something called rank. I already found out that rank is the numeric rank of the fitted linear model. But could you tell me what this is exactly? And how can I calculate it?

– Nicki
Mar 26 at 21:21





2




2





I believe it's just the number of regressors (including the intercept).

– DiceboyT
Mar 26 at 21:55





I believe it's just the number of regressors (including the intercept).

– DiceboyT
Mar 26 at 21:55













thanks, I could easily calculate the rank via ncol(x)!

– Nicki
Mar 26 at 23:20





thanks, I could easily calculate the rank via ncol(x)!

– Nicki
Mar 26 at 23:20












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