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Media object doesn't respond to cookie containing object

Media object doesn't accept to cookie containing objectWhy Signaling Server needed for WebRTC?WebRTC, ice candidates connectionDetecting an undefined object propertyWhat is the most efficient way to deep clone an object in JavaScript?How do I remove a property from a JavaScript object?How do I check if an array includes an object in JavaScript?How do I correctly clone a JavaScript object?Checking if a key exists in a JavaScript object?How do I set/unset a cookie with jQuery?How to check whether a string contains a substring in JavaScript?How to check if an object is an array?Iterate through object properties

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1

Sorry if the question is very stupid
I am trying to show the stream from a person to another user using js

I have tried putting it in a cookie but it doesnt work even then.Even when the object in video is the same as the other

File 1

var video = document.querySelector("#videoElement");
var x=document.cookie
console.log(x)
video.srcObject = x;

File 2

var video = document.querySelector("#videoElement");

if (navigator.mediaDevices.getUserMedia) 
 navigator.mediaDevices.getUserMedia( video: true )
 .then(function (stream) 
 video.srcObject = stream;
 document.cookie=video.srcObject 
 console.log(stream,video.srcObject)
 )
 .catch(function (err0r) 
 console.log("Something went wrong!");
 );
console.log(stream,video.srcObject)

I would like to just for now show it on two pages but for future what language should i use to store the video if you know you can share it

javascript object video cookies media

share|improve this question

edited Mar 26 at 21:04

Zobia Kanwal

94511 gold badge44 silver badges2525 bronze badges

asked Mar 26 at 20:28

HimoHimo

1566 bronze badges

add a comment | 

1

Sorry if the question is very stupid
I am trying to show the stream from a person to another user using js

I have tried putting it in a cookie but it doesnt work even then.Even when the object in video is the same as the other

File 1

var video = document.querySelector("#videoElement");
var x=document.cookie
console.log(x)
video.srcObject = x;

File 2

var video = document.querySelector("#videoElement");

if (navigator.mediaDevices.getUserMedia) 
 navigator.mediaDevices.getUserMedia( video: true )
 .then(function (stream) 
 video.srcObject = stream;
 document.cookie=video.srcObject 
 console.log(stream,video.srcObject)
 )
 .catch(function (err0r) 
 console.log("Something went wrong!");
 );
console.log(stream,video.srcObject)

I would like to just for now show it on two pages but for future what language should i use to store the video if you know you can share it

javascript object video cookies media

share|improve this question

edited Mar 26 at 21:04

Zobia Kanwal

94511 gold badge44 silver badges2525 bronze badges

asked Mar 26 at 20:28

HimoHimo

1566 bronze badges

add a comment | 

Sorry if the question is very stupid
I am trying to show the stream from a person to another user using js

I have tried putting it in a cookie but it doesnt work even then.Even when the object in video is the same as the other

File 1

var video = document.querySelector("#videoElement");
var x=document.cookie
console.log(x)
video.srcObject = x;

File 2

var video = document.querySelector("#videoElement");

if (navigator.mediaDevices.getUserMedia) 
 navigator.mediaDevices.getUserMedia( video: true )
 .then(function (stream) 
 video.srcObject = stream;
 document.cookie=video.srcObject 
 console.log(stream,video.srcObject)
 )
 .catch(function (err0r) 
 console.log("Something went wrong!");
 );
console.log(stream,video.srcObject)

I would like to just for now show it on two pages but for future what language should i use to store the video if you know you can share it

javascript object video cookies media

share|improve this question

edited Mar 26 at 21:04

Zobia Kanwal

94511 gold badge44 silver badges2525 bronze badges

asked Mar 26 at 20:28

HimoHimo

1566 bronze badges

var video = document.querySelector("#videoElement");
var x=document.cookie
console.log(x)
video.srcObject = x;

var video = document.querySelector("#videoElement");

if (navigator.mediaDevices.getUserMedia) 
 navigator.mediaDevices.getUserMedia( video: true )
 .then(function (stream) 
 video.srcObject = stream;
 document.cookie=video.srcObject 
 console.log(stream,video.srcObject)
 )
 .catch(function (err0r) 
 console.log("Something went wrong!");
 );
console.log(stream,video.srcObject)

share|improve this question

edited Mar 26 at 21:04

Zobia Kanwal

94511 gold badge44 silver badges2525 bronze badges

asked Mar 26 at 20:28

HimoHimo

1566 bronze badges

share|improve this question

edited Mar 26 at 21:04

Zobia Kanwal

94511 gold badge44 silver badges2525 bronze badges

asked Mar 26 at 20:28

HimoHimo

1566 bronze badges

edited Mar 26 at 21:04

Zobia Kanwal

94511 gold badge44 silver badges2525 bronze badges

edited Mar 26 at 21:04

Zobia Kanwal

94511 gold badge44 silver badges2525 bronze badges

asked Mar 26 at 20:28

HimoHimo

1566 bronze badges

asked Mar 26 at 20:28

HimoHimo

1566 bronze badges

1 Answer
1

active

oldest

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0

A cookie is not a centralized universal camera access repository on the web. Thank goodness.

A MediaStream is a local resource object representing active camera use, not a shareable URL.

This object lives solely in your local JS page, and isn't addressable on the web.

Since it doesn't live on any server, transporting the graphical bits from your camera to a friend's system, requires quite a bit of heavy lifting. This includes establishing an RTCPeerConnection which is the domain of WebRTC:

navigator.mediaDevices.getUserMedia( video: true )
 .then(function (stream) {
 const iceServers = [urls: "stun:stun.l.google.com:19302"];
 const pc = new RTCPeerConnection(iceServers);

 for (const track of stream.getTracks())
 pc.addTrack(track, stream);

 /* lots of other WebRTC negotiation code */

You'll also typically need a server of some kind, both to solve discovery, i.e. point of contact, as well as a web socket server to exchange critcal offer/answer session descriptions that are necessary for connection establishment, between the two peers.

Perhaps the simplest proof of concept is this cut'n'paste demo, which let you and a friend exchange the required WebRTC offer/answer session descriptions manually, letting you establish a connection without any server, to see and talk to each other.

That has about a 70% chance of working. If you're both behind symmetric NATs (most mobile networks), then it gets harder still (you'll need a TURN server, which costs money).

share|improve this answer

edited Apr 11 at 21:03

answered Apr 11 at 20:54

jibjib

23.7k66 gold badges4848 silver badges9898 bronze badges

add a comment | 

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0

A cookie is not a centralized universal camera access repository on the web. Thank goodness.

A MediaStream is a local resource object representing active camera use, not a shareable URL.

This object lives solely in your local JS page, and isn't addressable on the web.

Since it doesn't live on any server, transporting the graphical bits from your camera to a friend's system, requires quite a bit of heavy lifting. This includes establishing an RTCPeerConnection which is the domain of WebRTC:

navigator.mediaDevices.getUserMedia( video: true )
 .then(function (stream) {
 const iceServers = [urls: "stun:stun.l.google.com:19302"];
 const pc = new RTCPeerConnection(iceServers);

 for (const track of stream.getTracks())
 pc.addTrack(track, stream);

 /* lots of other WebRTC negotiation code */

You'll also typically need a server of some kind, both to solve discovery, i.e. point of contact, as well as a web socket server to exchange critcal offer/answer session descriptions that are necessary for connection establishment, between the two peers.

Perhaps the simplest proof of concept is this cut'n'paste demo, which let you and a friend exchange the required WebRTC offer/answer session descriptions manually, letting you establish a connection without any server, to see and talk to each other.

That has about a 70% chance of working. If you're both behind symmetric NATs (most mobile networks), then it gets harder still (you'll need a TURN server, which costs money).

share|improve this answer

edited Apr 11 at 21:03

answered Apr 11 at 20:54

jibjib

23.7k66 gold badges4848 silver badges9898 bronze badges

add a comment | 

0

A cookie is not a centralized universal camera access repository on the web. Thank goodness.

A MediaStream is a local resource object representing active camera use, not a shareable URL.

This object lives solely in your local JS page, and isn't addressable on the web.

Since it doesn't live on any server, transporting the graphical bits from your camera to a friend's system, requires quite a bit of heavy lifting. This includes establishing an RTCPeerConnection which is the domain of WebRTC:

navigator.mediaDevices.getUserMedia( video: true )
 .then(function (stream) {
 const iceServers = [urls: "stun:stun.l.google.com:19302"];
 const pc = new RTCPeerConnection(iceServers);

 for (const track of stream.getTracks())
 pc.addTrack(track, stream);

 /* lots of other WebRTC negotiation code */

You'll also typically need a server of some kind, both to solve discovery, i.e. point of contact, as well as a web socket server to exchange critcal offer/answer session descriptions that are necessary for connection establishment, between the two peers.

Perhaps the simplest proof of concept is this cut'n'paste demo, which let you and a friend exchange the required WebRTC offer/answer session descriptions manually, letting you establish a connection without any server, to see and talk to each other.

That has about a 70% chance of working. If you're both behind symmetric NATs (most mobile networks), then it gets harder still (you'll need a TURN server, which costs money).

share|improve this answer

edited Apr 11 at 21:03

answered Apr 11 at 20:54

jibjib

23.7k66 gold badges4848 silver badges9898 bronze badges

add a comment | 

A cookie is not a centralized universal camera access repository on the web. Thank goodness.

A MediaStream is a local resource object representing active camera use, not a shareable URL.

This object lives solely in your local JS page, and isn't addressable on the web.

Since it doesn't live on any server, transporting the graphical bits from your camera to a friend's system, requires quite a bit of heavy lifting. This includes establishing an RTCPeerConnection which is the domain of WebRTC:

navigator.mediaDevices.getUserMedia( video: true )
 .then(function (stream) {
 const iceServers = [urls: "stun:stun.l.google.com:19302"];
 const pc = new RTCPeerConnection(iceServers);

 for (const track of stream.getTracks())
 pc.addTrack(track, stream);

 /* lots of other WebRTC negotiation code */

You'll also typically need a server of some kind, both to solve discovery, i.e. point of contact, as well as a web socket server to exchange critcal offer/answer session descriptions that are necessary for connection establishment, between the two peers.

Perhaps the simplest proof of concept is this cut'n'paste demo, which let you and a friend exchange the required WebRTC offer/answer session descriptions manually, letting you establish a connection without any server, to see and talk to each other.

That has about a 70% chance of working. If you're both behind symmetric NATs (most mobile networks), then it gets harder still (you'll need a TURN server, which costs money).

share|improve this answer

edited Apr 11 at 21:03

answered Apr 11 at 20:54

jibjib

23.7k66 gold badges4848 silver badges9898 bronze badges

navigator.mediaDevices.getUserMedia( video: true )
 .then(function (stream) {
 const iceServers = [urls: "stun:stun.l.google.com:19302"];
 const pc = new RTCPeerConnection(iceServers);

 for (const track of stream.getTracks())
 pc.addTrack(track, stream);

 /* lots of other WebRTC negotiation code */

share|improve this answer

edited Apr 11 at 21:03

answered Apr 11 at 20:54

jibjib

23.7k66 gold badges4848 silver badges9898 bronze badges

answered Apr 11 at 20:54

jibjib

23.7k66 gold badges4848 silver badges9898 bronze badges

answered Apr 11 at 20:54

jibjib

23.7k66 gold badges4848 silver badges9898 bronze badges