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Checking for keyboard inputs uses too much cpu usage, Is there something wrong with my code?

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-1

Im making a simple music player so i can pause music when i am in full screen applications. The code works fine but i noticed that it uses around 15% cpu usage. Im just wondering if i did something wrong with my code.

import keyboard

listedSongs = []
currentSong = "idk"
while True:
 if keyboard.is_pressed('alt+k'):
 i = 1
 paused = False
 elif keyboard.is_pressed('alt+q'):
 break
 elif keyboard.is_pressed('alt+s'):
 if currentSong not in listedSongs:
 listedSongs.append(currentSong)
 print(listedSongs)

Any help would be appreciated :)

python

share|improve this question

asked Mar 27 at 2:51

predupredu

311 bronze badge

add a comment | 

-1

Im making a simple music player so i can pause music when i am in full screen applications. The code works fine but i noticed that it uses around 15% cpu usage. Im just wondering if i did something wrong with my code.

import keyboard

listedSongs = []
currentSong = "idk"
while True:
 if keyboard.is_pressed('alt+k'):
 i = 1
 paused = False
 elif keyboard.is_pressed('alt+q'):
 break
 elif keyboard.is_pressed('alt+s'):
 if currentSong not in listedSongs:
 listedSongs.append(currentSong)
 print(listedSongs)

Any help would be appreciated :)

python

share|improve this question

asked Mar 27 at 2:51

predupredu

311 bronze badge

add a comment | 

Im making a simple music player so i can pause music when i am in full screen applications. The code works fine but i noticed that it uses around 15% cpu usage. Im just wondering if i did something wrong with my code.

import keyboard

listedSongs = []
currentSong = "idk"
while True:
 if keyboard.is_pressed('alt+k'):
 i = 1
 paused = False
 elif keyboard.is_pressed('alt+q'):
 break
 elif keyboard.is_pressed('alt+s'):
 if currentSong not in listedSongs:
 listedSongs.append(currentSong)
 print(listedSongs)

Any help would be appreciated :)

python

share|improve this question

asked Mar 27 at 2:51

predupredu

311 bronze badge

import keyboard

listedSongs = []
currentSong = "idk"
while True:
 if keyboard.is_pressed('alt+k'):
 i = 1
 paused = False
 elif keyboard.is_pressed('alt+q'):
 break
 elif keyboard.is_pressed('alt+s'):
 if currentSong not in listedSongs:
 listedSongs.append(currentSong)
 print(listedSongs)

share|improve this question

asked Mar 27 at 2:51

predupredu

311 bronze badge

share|improve this question

asked Mar 27 at 2:51

predupredu

311 bronze badge

asked Mar 27 at 2:51

predupredu

311 bronze badge

asked Mar 27 at 2:51

predupredu

311 bronze badge

1 Answer
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0

The biggest reason it's consuming so many resources is this:

while True:

In essence, the program never stops to wait for anything. It's checking constantly, over and over, to see if the buttons on the keyboard are pressed. A better way, that's much less costly on the computer, is to assign a "callback" to be called whenever your desired key is pressed, and have the program sleep in between key presses. The keyboard library provides this functionality:

import keyboard
import time

listedSongs = []
currentSong = "idk"
exit = False # make a loop control variable

def alt_k():
 i = 1
 paused = False

def alt_q(): 
 exit = True

def alt_s():
 if currentSong not in listedSongs:
 listedSongs.append(currentSong)
 print(listedSongs)

# assign hooks to the keyboard
keyboard.on_press_key("alt+k", alt_k) # on press alt+k, execute alt_k()
keyboard.on_press_key("alt+q", alt_q)
keyboard.on_press_key("alt+s", alt_s)

# main loop
while not exit:
 keyboard.wait() # "block" for input (essentially, do nothing until a key is pressed and yield CPU resources to anything else that wants them)

share|improve this answer

answered Mar 27 at 3:04

Green Cloak GuyGreen Cloak Guy

7,59511 gold badge1111 silver badges2626 bronze badges

add a comment | 

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0

The biggest reason it's consuming so many resources is this:

while True:

In essence, the program never stops to wait for anything. It's checking constantly, over and over, to see if the buttons on the keyboard are pressed. A better way, that's much less costly on the computer, is to assign a "callback" to be called whenever your desired key is pressed, and have the program sleep in between key presses. The keyboard library provides this functionality:

import keyboard
import time

listedSongs = []
currentSong = "idk"
exit = False # make a loop control variable

def alt_k():
 i = 1
 paused = False

def alt_q(): 
 exit = True

def alt_s():
 if currentSong not in listedSongs:
 listedSongs.append(currentSong)
 print(listedSongs)

# assign hooks to the keyboard
keyboard.on_press_key("alt+k", alt_k) # on press alt+k, execute alt_k()
keyboard.on_press_key("alt+q", alt_q)
keyboard.on_press_key("alt+s", alt_s)

# main loop
while not exit:
 keyboard.wait() # "block" for input (essentially, do nothing until a key is pressed and yield CPU resources to anything else that wants them)

share|improve this answer

answered Mar 27 at 3:04

Green Cloak GuyGreen Cloak Guy

7,59511 gold badge1111 silver badges2626 bronze badges

add a comment | 

0

The biggest reason it's consuming so many resources is this:

while True:

In essence, the program never stops to wait for anything. It's checking constantly, over and over, to see if the buttons on the keyboard are pressed. A better way, that's much less costly on the computer, is to assign a "callback" to be called whenever your desired key is pressed, and have the program sleep in between key presses. The keyboard library provides this functionality:

import keyboard
import time

listedSongs = []
currentSong = "idk"
exit = False # make a loop control variable

def alt_k():
 i = 1
 paused = False

def alt_q(): 
 exit = True

def alt_s():
 if currentSong not in listedSongs:
 listedSongs.append(currentSong)
 print(listedSongs)

# assign hooks to the keyboard
keyboard.on_press_key("alt+k", alt_k) # on press alt+k, execute alt_k()
keyboard.on_press_key("alt+q", alt_q)
keyboard.on_press_key("alt+s", alt_s)

# main loop
while not exit:
 keyboard.wait() # "block" for input (essentially, do nothing until a key is pressed and yield CPU resources to anything else that wants them)

share|improve this answer

answered Mar 27 at 3:04

Green Cloak GuyGreen Cloak Guy

7,59511 gold badge1111 silver badges2626 bronze badges

add a comment | 

The biggest reason it's consuming so many resources is this:

while True:

In essence, the program never stops to wait for anything. It's checking constantly, over and over, to see if the buttons on the keyboard are pressed. A better way, that's much less costly on the computer, is to assign a "callback" to be called whenever your desired key is pressed, and have the program sleep in between key presses. The keyboard library provides this functionality:

import keyboard
import time

listedSongs = []
currentSong = "idk"
exit = False # make a loop control variable

def alt_k():
 i = 1
 paused = False

def alt_q(): 
 exit = True

def alt_s():
 if currentSong not in listedSongs:
 listedSongs.append(currentSong)
 print(listedSongs)

# assign hooks to the keyboard
keyboard.on_press_key("alt+k", alt_k) # on press alt+k, execute alt_k()
keyboard.on_press_key("alt+q", alt_q)
keyboard.on_press_key("alt+s", alt_s)

# main loop
while not exit:
 keyboard.wait() # "block" for input (essentially, do nothing until a key is pressed and yield CPU resources to anything else that wants them)

share|improve this answer

answered Mar 27 at 3:04

Green Cloak GuyGreen Cloak Guy

7,59511 gold badge1111 silver badges2626 bronze badges

while True:

import keyboard
import time

listedSongs = []
currentSong = "idk"
exit = False # make a loop control variable

def alt_k():
 i = 1
 paused = False

def alt_q(): 
 exit = True

def alt_s():
 if currentSong not in listedSongs:
 listedSongs.append(currentSong)
 print(listedSongs)

# assign hooks to the keyboard
keyboard.on_press_key("alt+k", alt_k) # on press alt+k, execute alt_k()
keyboard.on_press_key("alt+q", alt_q)
keyboard.on_press_key("alt+s", alt_s)

# main loop
while not exit:
 keyboard.wait() # "block" for input (essentially, do nothing until a key is pressed and yield CPU resources to anything else that wants them)

share|improve this answer

answered Mar 27 at 3:04

Green Cloak GuyGreen Cloak Guy

7,59511 gold badge1111 silver badges2626 bronze badges

answered Mar 27 at 3:04

Green Cloak GuyGreen Cloak Guy

7,59511 gold badge1111 silver badges2626 bronze badges

answered Mar 27 at 3:04

Green Cloak GuyGreen Cloak Guy

7,59511 gold badge1111 silver badges2626 bronze badges