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Xcode 10.2 Swift Error: Function types cannot be represented in Objective-C unless their parameters and returns can be

How do you document the parameters of a function's closure parameter in Swift 3?Swift to Objective-C header not created in Xcode 6How can method in Swift with inout parameter be used in Objective-C?Protocol with associatedtype doesn't play nice with optionalSwift 2.0 Method cannot be marked @objc because the type of the parameter cannot be represented in Objective-CExpose swift variadic parameter to Objective-CUnable to convert Swift protocol in Objective-C || How to write 'Self' return type of a protocol method of Swift in Objective-CMethod cannot be marked @objc because the type of the parameter 2 cannot be represented in Objective-CMethod cannot be marked @objc because its result type cannot be represented in Objective-CCannot access Swift Framework in Objective-Cfunc in swift for “self” causes error in Xcode

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1

I updated Xcode to 10.2 today and I got the following errors:

Method cannot be marked @objc because the type of the parameter 2
cannot be represented in Objective-C

Function types cannot be represented in Objective-C unless their parameters and returns can be
I don't understand why

It was perfectly fine in 10.1.
This is an example that I have been using for years without any issues.
How can I make this code to compile without errors?

@objc public func myFunction(inputString: String, handler:@escaping ((success: Bool, outPut: NSArray)) -> Void) 
 // do stuff

objective-c swift xcode xcode10.2

share|improve this question

edited Mar 27 at 12:48

Tibidabo

asked Mar 27 at 2:38

TibidaboTibidabo

19.6k44 gold badges8181 silver badges8282 bronze badges

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  Is that a member function of a class? – My Xcode 10.2 complains “Cannot create a single-element tuple with an element label” with the Fix-it “Replace 'outPut: ' with ''”
  
  – Martin R
  Mar 27 at 2:43
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @MartinR I removed the element label and that solved the issue see the answer from matt
  
  – Tibidabo
  Mar 27 at 2:59
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  I know that is does. But if I cannot reproduce the exact error message as reported then I wonder if the exact code was posted :)
  
  – Martin R
  Mar 27 at 3:09
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @MartinR Sorry, you are right. I simplified it... It should have more than one element in the tuple. it should be: func myFunction(inputString: String, handler:@escaping ((success: Bool, outPut: NSArray)) -> Void) // do stuff
  
  – Tibidabo
  Mar 27 at 6:18
  
  

  
  
  
  


• 
  
  
  

  
  2
  

  
  
  
  
  
  

  
  
  Now it gets interesting: Your closure argument has an extra pair of parentheses, apparently Swift 4 ignores that but Swift 5 does not. If you remove that extra pair: handler:@escaping (success: Bool, outPut: NSArray) -> Void then you'll get a clear error message “Function types cannot have argument labels; use '_' before 'outPut'” already in Swift 4/Xcode 10.1. – So what changed is not the forbidden external parameter names (they are already forbidden in Swift 4), but how the compiler treats the extra pair of parentheses.
  
  – Martin R
  Mar 27 at 12:59
  

  
  
  
  

 | 
show 2 more comments

1

I updated Xcode to 10.2 today and I got the following errors:

Method cannot be marked @objc because the type of the parameter 2
cannot be represented in Objective-C

Function types cannot be represented in Objective-C unless their parameters and returns can be
I don't understand why

It was perfectly fine in 10.1.
This is an example that I have been using for years without any issues.
How can I make this code to compile without errors?

@objc public func myFunction(inputString: String, handler:@escaping ((success: Bool, outPut: NSArray)) -> Void) 
 // do stuff

objective-c swift xcode xcode10.2

share|improve this question

edited Mar 27 at 12:48

Tibidabo

asked Mar 27 at 2:38

TibidaboTibidabo

19.6k44 gold badges8181 silver badges8282 bronze badges

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  Is that a member function of a class? – My Xcode 10.2 complains “Cannot create a single-element tuple with an element label” with the Fix-it “Replace 'outPut: ' with ''”
  
  – Martin R
  Mar 27 at 2:43
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @MartinR I removed the element label and that solved the issue see the answer from matt
  
  – Tibidabo
  Mar 27 at 2:59
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  I know that is does. But if I cannot reproduce the exact error message as reported then I wonder if the exact code was posted :)
  
  – Martin R
  Mar 27 at 3:09
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @MartinR Sorry, you are right. I simplified it... It should have more than one element in the tuple. it should be: func myFunction(inputString: String, handler:@escaping ((success: Bool, outPut: NSArray)) -> Void) // do stuff
  
  – Tibidabo
  Mar 27 at 6:18
  
  

  
  
  
  


• 
  
  
  

  
  2
  

  
  
  
  
  
  

  
  
  Now it gets interesting: Your closure argument has an extra pair of parentheses, apparently Swift 4 ignores that but Swift 5 does not. If you remove that extra pair: handler:@escaping (success: Bool, outPut: NSArray) -> Void then you'll get a clear error message “Function types cannot have argument labels; use '_' before 'outPut'” already in Swift 4/Xcode 10.1. – So what changed is not the forbidden external parameter names (they are already forbidden in Swift 4), but how the compiler treats the extra pair of parentheses.
  
  – Martin R
  Mar 27 at 12:59
  

  
  
  
  

 | 
show 2 more comments

I updated Xcode to 10.2 today and I got the following errors:

Method cannot be marked @objc because the type of the parameter 2
cannot be represented in Objective-C

Function types cannot be represented in Objective-C unless their parameters and returns can be
I don't understand why

It was perfectly fine in 10.1.
This is an example that I have been using for years without any issues.
How can I make this code to compile without errors?

@objc public func myFunction(inputString: String, handler:@escaping ((success: Bool, outPut: NSArray)) -> Void) 
 // do stuff

objective-c swift xcode xcode10.2

share|improve this question

edited Mar 27 at 12:48

Tibidabo

asked Mar 27 at 2:38

TibidaboTibidabo

19.6k44 gold badges8181 silver badges8282 bronze badges

@objc public func myFunction(inputString: String, handler:@escaping ((success: Bool, outPut: NSArray)) -> Void) 
 // do stuff

share|improve this question

edited Mar 27 at 12:48

Tibidabo

asked Mar 27 at 2:38

TibidaboTibidabo

19.6k44 gold badges8181 silver badges8282 bronze badges

share|improve this question

edited Mar 27 at 12:48

Tibidabo

asked Mar 27 at 2:38

TibidaboTibidabo

19.6k44 gold badges8181 silver badges8282 bronze badges

asked Mar 27 at 2:38

TibidaboTibidabo

19.6k44 gold badges8181 silver badges8282 bronze badges

asked Mar 27 at 2:38

TibidaboTibidabo

19.6k44 gold badges8181 silver badges8282 bronze badges

1 Answer
1

active

oldest

votes

2

Delete the phrase outPut:. It was always illegal; Swift 5 just tightens up at last.

So:

@objc public func myFunction(inputString: String, handler:@escaping (NSArray) -> Void) {

share|improve this answer

answered Mar 27 at 2:40

mattmatt

352k5353 gold badges576576 silver badges769769 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  You should not be using NSArray either but that’s a different issue.
  
  – matt
  Mar 27 at 2:43
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Thank you Matt. It did the trick. Is there any way to assign phrases to the variables that is not illegal?
  
  – Tibidabo
  Mar 27 at 2:57
  

  
  
  
  


• 
  
  
  

  
  2
  

  
  
  
  
  
  

  
  
  @Tibidabo: You can define the parameter as handler: @escaping (_ output: NSArray) -> Void. That also allows to document the parameter, see stackoverflow.com/a/38669796/1187415.
  
  – Martin R
  Mar 27 at 3:01
  
  

  
  
  
  

add a comment | 

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2

Delete the phrase outPut:. It was always illegal; Swift 5 just tightens up at last.

So:

@objc public func myFunction(inputString: String, handler:@escaping (NSArray) -> Void) {

share|improve this answer

answered Mar 27 at 2:40

mattmatt

352k5353 gold badges576576 silver badges769769 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  You should not be using NSArray either but that’s a different issue.
  
  – matt
  Mar 27 at 2:43
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Thank you Matt. It did the trick. Is there any way to assign phrases to the variables that is not illegal?
  
  – Tibidabo
  Mar 27 at 2:57
  

  
  
  
  


• 
  
  
  

  
  2
  

  
  
  
  
  
  

  
  
  @Tibidabo: You can define the parameter as handler: @escaping (_ output: NSArray) -> Void. That also allows to document the parameter, see stackoverflow.com/a/38669796/1187415.
  
  – Martin R
  Mar 27 at 3:01
  
  

  
  
  
  

add a comment | 

2

Delete the phrase outPut:. It was always illegal; Swift 5 just tightens up at last.

So:

@objc public func myFunction(inputString: String, handler:@escaping (NSArray) -> Void) {

share|improve this answer

answered Mar 27 at 2:40

mattmatt

352k5353 gold badges576576 silver badges769769 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  You should not be using NSArray either but that’s a different issue.
  
  – matt
  Mar 27 at 2:43
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Thank you Matt. It did the trick. Is there any way to assign phrases to the variables that is not illegal?
  
  – Tibidabo
  Mar 27 at 2:57
  

  
  
  
  


• 
  
  
  

  
  2
  

  
  
  
  
  
  

  
  
  @Tibidabo: You can define the parameter as handler: @escaping (_ output: NSArray) -> Void. That also allows to document the parameter, see stackoverflow.com/a/38669796/1187415.
  
  – Martin R
  Mar 27 at 3:01
  
  

  
  
  
  

add a comment | 

Delete the phrase outPut:. It was always illegal; Swift 5 just tightens up at last.

So:

@objc public func myFunction(inputString: String, handler:@escaping (NSArray) -> Void) {

share|improve this answer

answered Mar 27 at 2:40

mattmatt

352k5353 gold badges576576 silver badges769769 bronze badges

@objc public func myFunction(inputString: String, handler:@escaping (NSArray) -> Void) {

share|improve this answer

answered Mar 27 at 2:40

mattmatt

352k5353 gold badges576576 silver badges769769 bronze badges

answered Mar 27 at 2:40

mattmatt

352k5353 gold badges576576 silver badges769769 bronze badges

answered Mar 27 at 2:40

mattmatt

352k5353 gold badges576576 silver badges769769 bronze badges