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How to upload the file that has been detected as a new addition to an URL?


How to detect if JavaScript is disabled?How do I detect a click outside an element?How can I upload files asynchronously?How do I modify the URL without reloading the page?How do I include a JavaScript file in another JavaScript file?jQuery Ajax File UploadOpen a URL in a new tab (and not a new window) using JavaScriptHow can I add new array elements at the beginning of an array in Javascript?Call to xmlhttprequest from page onload event is not working OK when Back from another pageFile upload to pre-signed url of S3 in React Native - Header is getting appended






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0















I need to upload to a URL a file notified as a new addition to the folder I am watching. How do I do this without forms?



I am writing a basic file synchroniser that uses an Electron desktop app as client, Python server and AWS endpoint. I am using presigned URL for upload/download requests and have chokidar to watch the folder set up for sync.



When I get notified of Add through Chokidar, I make a call to my Python server and get a presigned URL for upload. This part works fine.



Once I get the URL, I need to upload the file. I have no HTML component associated with this operation (and do not want to add) I read that I can upload file using AJAX with formdata but it requires "data" column. How do I fill this?



 watcher
.on('add', function(dir)
console.log('File', dir, 'has been added');
xhr.open("POST", url, true);
xhr.setRequestHeader("Content-Type", "application/json");
results.innerHTML = '';

data = JSON.stringify("operation": "uploadFile", "bucketName": "deadlinefighters", "fileDetails": "fileName": dir.replace(/^.*[\/]/, ''));

xhr.onreadystatechange = function ()
if (xhr.readyState === 4 && xhr.status === 200)
jsonResponse = JSON.parse(xhr.responseText);

var content;

fs.readFile(dir, function read(err, data)
if (err)
throw err;

content = data;
);

$.ajax(
url: jsonResponse["url"],
type: 'PUT',
data: content, //This is the part I do not know how to fill right
async: false,
success: function ()
results.innerHTML = "Uploaded!"

);
listObjectsinServer();

else if(xhr.status!=200)
results.innerHTML = 'ERROR!';

;
xhr.send(data);

)


I tried fs.readFile but it does not work either. Based on some SO answers, I put the AJAX call inside but even that did not work. I feel like I might be misunderstanding this field.










share|improve this question






























    0















    I need to upload to a URL a file notified as a new addition to the folder I am watching. How do I do this without forms?



    I am writing a basic file synchroniser that uses an Electron desktop app as client, Python server and AWS endpoint. I am using presigned URL for upload/download requests and have chokidar to watch the folder set up for sync.



    When I get notified of Add through Chokidar, I make a call to my Python server and get a presigned URL for upload. This part works fine.



    Once I get the URL, I need to upload the file. I have no HTML component associated with this operation (and do not want to add) I read that I can upload file using AJAX with formdata but it requires "data" column. How do I fill this?



     watcher
    .on('add', function(dir)
    console.log('File', dir, 'has been added');
    xhr.open("POST", url, true);
    xhr.setRequestHeader("Content-Type", "application/json");
    results.innerHTML = '';

    data = JSON.stringify("operation": "uploadFile", "bucketName": "deadlinefighters", "fileDetails": "fileName": dir.replace(/^.*[\/]/, ''));

    xhr.onreadystatechange = function ()
    if (xhr.readyState === 4 && xhr.status === 200)
    jsonResponse = JSON.parse(xhr.responseText);

    var content;

    fs.readFile(dir, function read(err, data)
    if (err)
    throw err;

    content = data;
    );

    $.ajax(
    url: jsonResponse["url"],
    type: 'PUT',
    data: content, //This is the part I do not know how to fill right
    async: false,
    success: function ()
    results.innerHTML = "Uploaded!"

    );
    listObjectsinServer();

    else if(xhr.status!=200)
    results.innerHTML = 'ERROR!';

    ;
    xhr.send(data);

    )


    I tried fs.readFile but it does not work either. Based on some SO answers, I put the AJAX call inside but even that did not work. I feel like I might be misunderstanding this field.










    share|improve this question


























      0












      0








      0








      I need to upload to a URL a file notified as a new addition to the folder I am watching. How do I do this without forms?



      I am writing a basic file synchroniser that uses an Electron desktop app as client, Python server and AWS endpoint. I am using presigned URL for upload/download requests and have chokidar to watch the folder set up for sync.



      When I get notified of Add through Chokidar, I make a call to my Python server and get a presigned URL for upload. This part works fine.



      Once I get the URL, I need to upload the file. I have no HTML component associated with this operation (and do not want to add) I read that I can upload file using AJAX with formdata but it requires "data" column. How do I fill this?



       watcher
      .on('add', function(dir)
      console.log('File', dir, 'has been added');
      xhr.open("POST", url, true);
      xhr.setRequestHeader("Content-Type", "application/json");
      results.innerHTML = '';

      data = JSON.stringify("operation": "uploadFile", "bucketName": "deadlinefighters", "fileDetails": "fileName": dir.replace(/^.*[\/]/, ''));

      xhr.onreadystatechange = function ()
      if (xhr.readyState === 4 && xhr.status === 200)
      jsonResponse = JSON.parse(xhr.responseText);

      var content;

      fs.readFile(dir, function read(err, data)
      if (err)
      throw err;

      content = data;
      );

      $.ajax(
      url: jsonResponse["url"],
      type: 'PUT',
      data: content, //This is the part I do not know how to fill right
      async: false,
      success: function ()
      results.innerHTML = "Uploaded!"

      );
      listObjectsinServer();

      else if(xhr.status!=200)
      results.innerHTML = 'ERROR!';

      ;
      xhr.send(data);

      )


      I tried fs.readFile but it does not work either. Based on some SO answers, I put the AJAX call inside but even that did not work. I feel like I might be misunderstanding this field.










      share|improve this question














      I need to upload to a URL a file notified as a new addition to the folder I am watching. How do I do this without forms?



      I am writing a basic file synchroniser that uses an Electron desktop app as client, Python server and AWS endpoint. I am using presigned URL for upload/download requests and have chokidar to watch the folder set up for sync.



      When I get notified of Add through Chokidar, I make a call to my Python server and get a presigned URL for upload. This part works fine.



      Once I get the URL, I need to upload the file. I have no HTML component associated with this operation (and do not want to add) I read that I can upload file using AJAX with formdata but it requires "data" column. How do I fill this?



       watcher
      .on('add', function(dir)
      console.log('File', dir, 'has been added');
      xhr.open("POST", url, true);
      xhr.setRequestHeader("Content-Type", "application/json");
      results.innerHTML = '';

      data = JSON.stringify("operation": "uploadFile", "bucketName": "deadlinefighters", "fileDetails": "fileName": dir.replace(/^.*[\/]/, ''));

      xhr.onreadystatechange = function ()
      if (xhr.readyState === 4 && xhr.status === 200)
      jsonResponse = JSON.parse(xhr.responseText);

      var content;

      fs.readFile(dir, function read(err, data)
      if (err)
      throw err;

      content = data;
      );

      $.ajax(
      url: jsonResponse["url"],
      type: 'PUT',
      data: content, //This is the part I do not know how to fill right
      async: false,
      success: function ()
      results.innerHTML = "Uploaded!"

      );
      listObjectsinServer();

      else if(xhr.status!=200)
      results.innerHTML = 'ERROR!';

      ;
      xhr.send(data);

      )


      I tried fs.readFile but it does not work either. Based on some SO answers, I put the AJAX call inside but even that did not work. I feel like I might be misunderstanding this field.







      javascript electron chokidar






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked Mar 26 at 23:40









      BhargBharg

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