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How to derive a function that has an integration with it?

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0

I want to derive a function that has an integration within it. How can I do it symbolically and numerically?

everything I've tried didn't work.

import sympy as sp
import math
from scipy import integrate
from scipy.misc import derivative`

t = sp.Symbol('t')
beta = 0.4
t0 = 0.3
w = 0.5
lambda1 = 0.1
lambda2 = 1.5
lambda3 = 1
lambda4 = 0.1`

def ru(t):
 ru_value = lambda1*lambda2*((lambda1*t)* *(lambda2-1))+lambda3*lambda4*((lambda3*t)**(lambda4-1))
 return (ru_value)`

def F1u (t):
 F1u_value=1-math.exp(-integrate.quad(ru, t+beta*t0, t+beta*t0+w)[0])
 return (F1u_value)`

print (sp.diff(F1u,t))`

It says:

SyntaxError: invalid syntax.

python sympy derivative

share|improve this question

edited Mar 26 at 23:35

Evan M

2,0312222 silver badges3333 bronze badges

asked Mar 26 at 16:02

Flávio FreireFlávio Freire

111 bronze badge

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Can you provide the full stacktrace ? and please, before, remove the ` on the end of some lines
  
  – Paulo Pessoa
  Mar 26 at 19:23
  

  
  
  
  

add a comment | 

0

I want to derive a function that has an integration within it. How can I do it symbolically and numerically?

everything I've tried didn't work.

import sympy as sp
import math
from scipy import integrate
from scipy.misc import derivative`

t = sp.Symbol('t')
beta = 0.4
t0 = 0.3
w = 0.5
lambda1 = 0.1
lambda2 = 1.5
lambda3 = 1
lambda4 = 0.1`

def ru(t):
 ru_value = lambda1*lambda2*((lambda1*t)* *(lambda2-1))+lambda3*lambda4*((lambda3*t)**(lambda4-1))
 return (ru_value)`

def F1u (t):
 F1u_value=1-math.exp(-integrate.quad(ru, t+beta*t0, t+beta*t0+w)[0])
 return (F1u_value)`

print (sp.diff(F1u,t))`

It says:

SyntaxError: invalid syntax.

python sympy derivative

share|improve this question

edited Mar 26 at 23:35

Evan M

2,0312222 silver badges3333 bronze badges

asked Mar 26 at 16:02

Flávio FreireFlávio Freire

111 bronze badge

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Can you provide the full stacktrace ? and please, before, remove the ` on the end of some lines
  
  – Paulo Pessoa
  Mar 26 at 19:23
  

  
  
  
  

add a comment | 

I want to derive a function that has an integration within it. How can I do it symbolically and numerically?

everything I've tried didn't work.

import sympy as sp
import math
from scipy import integrate
from scipy.misc import derivative`

t = sp.Symbol('t')
beta = 0.4
t0 = 0.3
w = 0.5
lambda1 = 0.1
lambda2 = 1.5
lambda3 = 1
lambda4 = 0.1`

def ru(t):
 ru_value = lambda1*lambda2*((lambda1*t)* *(lambda2-1))+lambda3*lambda4*((lambda3*t)**(lambda4-1))
 return (ru_value)`

def F1u (t):
 F1u_value=1-math.exp(-integrate.quad(ru, t+beta*t0, t+beta*t0+w)[0])
 return (F1u_value)`

print (sp.diff(F1u,t))`

It says:

SyntaxError: invalid syntax.

python sympy derivative

share|improve this question

edited Mar 26 at 23:35

Evan M

2,0312222 silver badges3333 bronze badges

asked Mar 26 at 16:02

Flávio FreireFlávio Freire

111 bronze badge

import sympy as sp
import math
from scipy import integrate
from scipy.misc import derivative`

t = sp.Symbol('t')
beta = 0.4
t0 = 0.3
w = 0.5
lambda1 = 0.1
lambda2 = 1.5
lambda3 = 1
lambda4 = 0.1`

def ru(t):
 ru_value = lambda1*lambda2*((lambda1*t)* *(lambda2-1))+lambda3*lambda4*((lambda3*t)**(lambda4-1))
 return (ru_value)`

def F1u (t):
 F1u_value=1-math.exp(-integrate.quad(ru, t+beta*t0, t+beta*t0+w)[0])
 return (F1u_value)`

print (sp.diff(F1u,t))`

share|improve this question

edited Mar 26 at 23:35

Evan M

2,0312222 silver badges3333 bronze badges

asked Mar 26 at 16:02

Flávio FreireFlávio Freire

111 bronze badge

share|improve this question

edited Mar 26 at 23:35

Evan M

2,0312222 silver badges3333 bronze badges

asked Mar 26 at 16:02

Flávio FreireFlávio Freire

111 bronze badge

edited Mar 26 at 23:35

Evan M

2,0312222 silver badges3333 bronze badges

edited Mar 26 at 23:35

Evan M

2,0312222 silver badges3333 bronze badges

asked Mar 26 at 16:02

Flávio FreireFlávio Freire

111 bronze badge

asked Mar 26 at 16:02

Flávio FreireFlávio Freire

111 bronze badge