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Sort by deep document field in MongoDb


Sorting an array of JavaScript objects by propertySort array of objects by string property valueHow to query MongoDB with “like”?How do I drop a MongoDB database from the command line?MongoDB: How to find out if an array field contains an element?Sorting aggregation addToSet resultOrder by nested document MongodbHow to sort documents by custom (non-natural ordered) fieldquery array of sub documents to remove them in Java Spring Data Mongodb






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1















I have a collection called Visitor which has an array of chats and each array has a document called user.

I need to find some documents on this collection and sort them by if they have some specific user in their chats first.



The path for the user id is:
chats.user._id



where:



chats // array
user // document
_id // ObjectId


The below script does sort the documents correctly, however, it expands the chats array and multiplies the document for each chat in the array.



I only need the sorting, so can I sort and not use the unwind pipeline or make it somehow not multiply the documents?



db.getCollection('Visitor').aggregate([
$unwind: "$chats",
$match: 'event._id':ObjectId('5c942a3591deb389bfd92579'), 'chats.enabled': $exists: true,

"$project":
"_id": 1,
"chats.user._id": 1,
"weight":
"$cond": [
"$eq": [ "$chats.user._id", ObjectId("5c942a3591deb389bfd92579") ] ,
10,
0
]


,
"$sort": "weight": -1 ,
])


EDIT: I don't need to sort the inner array, but sort the find command by checking if a specific user is in the chats array.



Some sample of Visitor collection:



[

"_id" : ObjectId("5c9a3a1bd86e0ba64106e90e"),
"event" :
"_id" : ObjectId("5c942a3591deb389bfd92579")
,
"chats" : [

"enabled" : false,
"user" :
"_id" : ObjectId("5c81232f09a923b559763418")
,
"_id" : ObjectId("5c9a3a1bd86e0ba64106e915")

]
,

"_id" : ObjectId("5c9a3a35d86e0ba64106e950"),
"event" :
"_id" : ObjectId("5c942a3591deb389bfd92579")
,
"chats" : [

"enabled" : true,
"user" :
"_id" : ObjectId("5c81232f09a923b559763418")
,
"_id" : ObjectId("5c9a3a35d86e0ba64106e957")
,

"enabled" : true,
"user" :
"_id" : ObjectId("5c942a3591deb389bfd92579")
,
"_id" : ObjectId("5c9a3a34d86e0ba64106e91d")

]

]


In the above sample, I need to make the second document to be sorted first because it has the user with the _id ObjectId("5c942a3591deb389bfd92579").










share|improve this question


























  • Could you show sample document from your collection ?

    – mickl
    Mar 27 at 16:39











  • added two documents where the second one should come first @mickl

    – Jonathan
    Mar 27 at 16:43

















1















I have a collection called Visitor which has an array of chats and each array has a document called user.

I need to find some documents on this collection and sort them by if they have some specific user in their chats first.



The path for the user id is:
chats.user._id



where:



chats // array
user // document
_id // ObjectId


The below script does sort the documents correctly, however, it expands the chats array and multiplies the document for each chat in the array.



I only need the sorting, so can I sort and not use the unwind pipeline or make it somehow not multiply the documents?



db.getCollection('Visitor').aggregate([
$unwind: "$chats",
$match: 'event._id':ObjectId('5c942a3591deb389bfd92579'), 'chats.enabled': $exists: true,

"$project":
"_id": 1,
"chats.user._id": 1,
"weight":
"$cond": [
"$eq": [ "$chats.user._id", ObjectId("5c942a3591deb389bfd92579") ] ,
10,
0
]


,
"$sort": "weight": -1 ,
])


EDIT: I don't need to sort the inner array, but sort the find command by checking if a specific user is in the chats array.



Some sample of Visitor collection:



[

"_id" : ObjectId("5c9a3a1bd86e0ba64106e90e"),
"event" :
"_id" : ObjectId("5c942a3591deb389bfd92579")
,
"chats" : [

"enabled" : false,
"user" :
"_id" : ObjectId("5c81232f09a923b559763418")
,
"_id" : ObjectId("5c9a3a1bd86e0ba64106e915")

]
,

"_id" : ObjectId("5c9a3a35d86e0ba64106e950"),
"event" :
"_id" : ObjectId("5c942a3591deb389bfd92579")
,
"chats" : [

"enabled" : true,
"user" :
"_id" : ObjectId("5c81232f09a923b559763418")
,
"_id" : ObjectId("5c9a3a35d86e0ba64106e957")
,

"enabled" : true,
"user" :
"_id" : ObjectId("5c942a3591deb389bfd92579")
,
"_id" : ObjectId("5c9a3a34d86e0ba64106e91d")

]

]


In the above sample, I need to make the second document to be sorted first because it has the user with the _id ObjectId("5c942a3591deb389bfd92579").










share|improve this question


























  • Could you show sample document from your collection ?

    – mickl
    Mar 27 at 16:39











  • added two documents where the second one should come first @mickl

    – Jonathan
    Mar 27 at 16:43













1












1








1








I have a collection called Visitor which has an array of chats and each array has a document called user.

I need to find some documents on this collection and sort them by if they have some specific user in their chats first.



The path for the user id is:
chats.user._id



where:



chats // array
user // document
_id // ObjectId


The below script does sort the documents correctly, however, it expands the chats array and multiplies the document for each chat in the array.



I only need the sorting, so can I sort and not use the unwind pipeline or make it somehow not multiply the documents?



db.getCollection('Visitor').aggregate([
$unwind: "$chats",
$match: 'event._id':ObjectId('5c942a3591deb389bfd92579'), 'chats.enabled': $exists: true,

"$project":
"_id": 1,
"chats.user._id": 1,
"weight":
"$cond": [
"$eq": [ "$chats.user._id", ObjectId("5c942a3591deb389bfd92579") ] ,
10,
0
]


,
"$sort": "weight": -1 ,
])


EDIT: I don't need to sort the inner array, but sort the find command by checking if a specific user is in the chats array.



Some sample of Visitor collection:



[

"_id" : ObjectId("5c9a3a1bd86e0ba64106e90e"),
"event" :
"_id" : ObjectId("5c942a3591deb389bfd92579")
,
"chats" : [

"enabled" : false,
"user" :
"_id" : ObjectId("5c81232f09a923b559763418")
,
"_id" : ObjectId("5c9a3a1bd86e0ba64106e915")

]
,

"_id" : ObjectId("5c9a3a35d86e0ba64106e950"),
"event" :
"_id" : ObjectId("5c942a3591deb389bfd92579")
,
"chats" : [

"enabled" : true,
"user" :
"_id" : ObjectId("5c81232f09a923b559763418")
,
"_id" : ObjectId("5c9a3a35d86e0ba64106e957")
,

"enabled" : true,
"user" :
"_id" : ObjectId("5c942a3591deb389bfd92579")
,
"_id" : ObjectId("5c9a3a34d86e0ba64106e91d")

]

]


In the above sample, I need to make the second document to be sorted first because it has the user with the _id ObjectId("5c942a3591deb389bfd92579").










share|improve this question
















I have a collection called Visitor which has an array of chats and each array has a document called user.

I need to find some documents on this collection and sort them by if they have some specific user in their chats first.



The path for the user id is:
chats.user._id



where:



chats // array
user // document
_id // ObjectId


The below script does sort the documents correctly, however, it expands the chats array and multiplies the document for each chat in the array.



I only need the sorting, so can I sort and not use the unwind pipeline or make it somehow not multiply the documents?



db.getCollection('Visitor').aggregate([
$unwind: "$chats",
$match: 'event._id':ObjectId('5c942a3591deb389bfd92579'), 'chats.enabled': $exists: true,

"$project":
"_id": 1,
"chats.user._id": 1,
"weight":
"$cond": [
"$eq": [ "$chats.user._id", ObjectId("5c942a3591deb389bfd92579") ] ,
10,
0
]


,
"$sort": "weight": -1 ,
])


EDIT: I don't need to sort the inner array, but sort the find command by checking if a specific user is in the chats array.



Some sample of Visitor collection:



[

"_id" : ObjectId("5c9a3a1bd86e0ba64106e90e"),
"event" :
"_id" : ObjectId("5c942a3591deb389bfd92579")
,
"chats" : [

"enabled" : false,
"user" :
"_id" : ObjectId("5c81232f09a923b559763418")
,
"_id" : ObjectId("5c9a3a1bd86e0ba64106e915")

]
,

"_id" : ObjectId("5c9a3a35d86e0ba64106e950"),
"event" :
"_id" : ObjectId("5c942a3591deb389bfd92579")
,
"chats" : [

"enabled" : true,
"user" :
"_id" : ObjectId("5c81232f09a923b559763418")
,
"_id" : ObjectId("5c9a3a35d86e0ba64106e957")
,

"enabled" : true,
"user" :
"_id" : ObjectId("5c942a3591deb389bfd92579")
,
"_id" : ObjectId("5c9a3a34d86e0ba64106e91d")

]

]


In the above sample, I need to make the second document to be sorted first because it has the user with the _id ObjectId("5c942a3591deb389bfd92579").







arrays mongodb aggregation-framework






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Mar 27 at 16:48









mickl

20.3k6 gold badges20 silver badges42 bronze badges




20.3k6 gold badges20 silver badges42 bronze badges










asked Mar 27 at 16:38









JonathanJonathan

2,1577 gold badges32 silver badges52 bronze badges




2,1577 gold badges32 silver badges52 bronze badges















  • Could you show sample document from your collection ?

    – mickl
    Mar 27 at 16:39











  • added two documents where the second one should come first @mickl

    – Jonathan
    Mar 27 at 16:43

















  • Could you show sample document from your collection ?

    – mickl
    Mar 27 at 16:39











  • added two documents where the second one should come first @mickl

    – Jonathan
    Mar 27 at 16:43
















Could you show sample document from your collection ?

– mickl
Mar 27 at 16:39





Could you show sample document from your collection ?

– mickl
Mar 27 at 16:39













added two documents where the second one should come first @mickl

– Jonathan
Mar 27 at 16:43





added two documents where the second one should come first @mickl

– Jonathan
Mar 27 at 16:43












1 Answer
1






active

oldest

votes


















1















The problem here is that using $unwind you modify initial structure of your documents (you will get one document per chats. I would suggest using $map to get an array of weights based on specified userId and then you can use $max to get final weight



db.col.aggregate([
$match: 'event._id':ObjectId('5c942a3591deb389bfd92579'), 'chats.enabled': $exists: true,

"$project":
"_id": 1,
"chats.user._id": 1,
"weight":
$max: $map: input: "$chats", in: $cond: [ $eq: [ "$$this.user._id", ObjectId("5c942a3591deb389bfd92579") ] , 10, 0 ]


,
"$sort": "weight": -1 ,
])





share|improve this answer

























  • could you add an example if there was a list users instead of one object user? Like if it was a chats array and nested users array and then some ID

    – Jonathan
    Mar 27 at 17:02






  • 1





    @Jonathan you need double $map and $max then. Please give it a try and open another question if you still need some assistance, I will try to take a look later

    – mickl
    Mar 27 at 17:06










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1 Answer
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1 Answer
1






active

oldest

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active

oldest

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active

oldest

votes









1















The problem here is that using $unwind you modify initial structure of your documents (you will get one document per chats. I would suggest using $map to get an array of weights based on specified userId and then you can use $max to get final weight



db.col.aggregate([
$match: 'event._id':ObjectId('5c942a3591deb389bfd92579'), 'chats.enabled': $exists: true,

"$project":
"_id": 1,
"chats.user._id": 1,
"weight":
$max: $map: input: "$chats", in: $cond: [ $eq: [ "$$this.user._id", ObjectId("5c942a3591deb389bfd92579") ] , 10, 0 ]


,
"$sort": "weight": -1 ,
])





share|improve this answer

























  • could you add an example if there was a list users instead of one object user? Like if it was a chats array and nested users array and then some ID

    – Jonathan
    Mar 27 at 17:02






  • 1





    @Jonathan you need double $map and $max then. Please give it a try and open another question if you still need some assistance, I will try to take a look later

    – mickl
    Mar 27 at 17:06















1















The problem here is that using $unwind you modify initial structure of your documents (you will get one document per chats. I would suggest using $map to get an array of weights based on specified userId and then you can use $max to get final weight



db.col.aggregate([
$match: 'event._id':ObjectId('5c942a3591deb389bfd92579'), 'chats.enabled': $exists: true,

"$project":
"_id": 1,
"chats.user._id": 1,
"weight":
$max: $map: input: "$chats", in: $cond: [ $eq: [ "$$this.user._id", ObjectId("5c942a3591deb389bfd92579") ] , 10, 0 ]


,
"$sort": "weight": -1 ,
])





share|improve this answer

























  • could you add an example if there was a list users instead of one object user? Like if it was a chats array and nested users array and then some ID

    – Jonathan
    Mar 27 at 17:02






  • 1





    @Jonathan you need double $map and $max then. Please give it a try and open another question if you still need some assistance, I will try to take a look later

    – mickl
    Mar 27 at 17:06













1














1










1









The problem here is that using $unwind you modify initial structure of your documents (you will get one document per chats. I would suggest using $map to get an array of weights based on specified userId and then you can use $max to get final weight



db.col.aggregate([
$match: 'event._id':ObjectId('5c942a3591deb389bfd92579'), 'chats.enabled': $exists: true,

"$project":
"_id": 1,
"chats.user._id": 1,
"weight":
$max: $map: input: "$chats", in: $cond: [ $eq: [ "$$this.user._id", ObjectId("5c942a3591deb389bfd92579") ] , 10, 0 ]


,
"$sort": "weight": -1 ,
])





share|improve this answer













The problem here is that using $unwind you modify initial structure of your documents (you will get one document per chats. I would suggest using $map to get an array of weights based on specified userId and then you can use $max to get final weight



db.col.aggregate([
$match: 'event._id':ObjectId('5c942a3591deb389bfd92579'), 'chats.enabled': $exists: true,

"$project":
"_id": 1,
"chats.user._id": 1,
"weight":
$max: $map: input: "$chats", in: $cond: [ $eq: [ "$$this.user._id", ObjectId("5c942a3591deb389bfd92579") ] , 10, 0 ]


,
"$sort": "weight": -1 ,
])






share|improve this answer












share|improve this answer



share|improve this answer










answered Mar 27 at 16:47









micklmickl

20.3k6 gold badges20 silver badges42 bronze badges




20.3k6 gold badges20 silver badges42 bronze badges















  • could you add an example if there was a list users instead of one object user? Like if it was a chats array and nested users array and then some ID

    – Jonathan
    Mar 27 at 17:02






  • 1





    @Jonathan you need double $map and $max then. Please give it a try and open another question if you still need some assistance, I will try to take a look later

    – mickl
    Mar 27 at 17:06

















  • could you add an example if there was a list users instead of one object user? Like if it was a chats array and nested users array and then some ID

    – Jonathan
    Mar 27 at 17:02






  • 1





    @Jonathan you need double $map and $max then. Please give it a try and open another question if you still need some assistance, I will try to take a look later

    – mickl
    Mar 27 at 17:06
















could you add an example if there was a list users instead of one object user? Like if it was a chats array and nested users array and then some ID

– Jonathan
Mar 27 at 17:02





could you add an example if there was a list users instead of one object user? Like if it was a chats array and nested users array and then some ID

– Jonathan
Mar 27 at 17:02




1




1





@Jonathan you need double $map and $max then. Please give it a try and open another question if you still need some assistance, I will try to take a look later

– mickl
Mar 27 at 17:06





@Jonathan you need double $map and $max then. Please give it a try and open another question if you still need some assistance, I will try to take a look later

– mickl
Mar 27 at 17:06






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