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Emit Signal in Constructor of Qml Registered Type doesn't Work
Exposing an enum in a QML signalHow to catch C++ signal in QML signal handler after type registration?Accessing properties of a C++ object passed as signal parameter to QMLHow to call slot with QFlags argument from QMLManage the lifetime of C++ QObjects passed to QML in SignalsAfter instantiating c++ object in QML its parent is nullQt Qml connect to a signal of a QObject property of a Context PropertyConnecting callback to QML Singleton Type declared in C++C++ signal not catched on QML sideHow can i use Model c++ class in cascade with 2 other repeater in .qml file
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I am setting up a resource manager class for my application. to manage all state of resources, i need to emmit a Signal from constructor if it don't succeed to catch resource.
In fact i want to emit signal from constructor of QObject Derived Class that registered for qml via qmlRegisterType.
this is code i have tested on Linux runnng MySql and Qt 5.12.2. but the emit signal doesn't work.
myresoureces.cpp ---- my Class that manage resources
MyResource::MyResource(QObject *parent) : QObject(parent)
if(!openResource())
// qDebug() << "Check Permission of FileSystem For Example.";
emit openResourceFailed("Check Permission of FileSystem For Example.");
bool MyResource::openResource()
// on situation opening resource failed
return false;
main.qml ---- usage of it in qml
// ...
import My.Company.Core 1.0
// ...
MyResource
onOpenResourceFailed:
msgDialog.title = "Open Resource Failed!"
msgDialog.text = error
msgDialog.open()
MessageDialog
id: msgDialog
// ...
main.cpp ---- where i register the class
qmlRegisterType<MyResource>("My.Company.Core", 1, 0, "MyResource");
I expect the Message Dialog to be opened but nothing happened.
qt constructor qml qt5 qt-signals
add a comment |
I am setting up a resource manager class for my application. to manage all state of resources, i need to emmit a Signal from constructor if it don't succeed to catch resource.
In fact i want to emit signal from constructor of QObject Derived Class that registered for qml via qmlRegisterType.
this is code i have tested on Linux runnng MySql and Qt 5.12.2. but the emit signal doesn't work.
myresoureces.cpp ---- my Class that manage resources
MyResource::MyResource(QObject *parent) : QObject(parent)
if(!openResource())
// qDebug() << "Check Permission of FileSystem For Example.";
emit openResourceFailed("Check Permission of FileSystem For Example.");
bool MyResource::openResource()
// on situation opening resource failed
return false;
main.qml ---- usage of it in qml
// ...
import My.Company.Core 1.0
// ...
MyResource
onOpenResourceFailed:
msgDialog.title = "Open Resource Failed!"
msgDialog.text = error
msgDialog.open()
MessageDialog
id: msgDialog
// ...
main.cpp ---- where i register the class
qmlRegisterType<MyResource>("My.Company.Core", 1, 0, "MyResource");
I expect the Message Dialog to be opened but nothing happened.
qt constructor qml qt5 qt-signals
add a comment |
I am setting up a resource manager class for my application. to manage all state of resources, i need to emmit a Signal from constructor if it don't succeed to catch resource.
In fact i want to emit signal from constructor of QObject Derived Class that registered for qml via qmlRegisterType.
this is code i have tested on Linux runnng MySql and Qt 5.12.2. but the emit signal doesn't work.
myresoureces.cpp ---- my Class that manage resources
MyResource::MyResource(QObject *parent) : QObject(parent)
if(!openResource())
// qDebug() << "Check Permission of FileSystem For Example.";
emit openResourceFailed("Check Permission of FileSystem For Example.");
bool MyResource::openResource()
// on situation opening resource failed
return false;
main.qml ---- usage of it in qml
// ...
import My.Company.Core 1.0
// ...
MyResource
onOpenResourceFailed:
msgDialog.title = "Open Resource Failed!"
msgDialog.text = error
msgDialog.open()
MessageDialog
id: msgDialog
// ...
main.cpp ---- where i register the class
qmlRegisterType<MyResource>("My.Company.Core", 1, 0, "MyResource");
I expect the Message Dialog to be opened but nothing happened.
qt constructor qml qt5 qt-signals
I am setting up a resource manager class for my application. to manage all state of resources, i need to emmit a Signal from constructor if it don't succeed to catch resource.
In fact i want to emit signal from constructor of QObject Derived Class that registered for qml via qmlRegisterType.
this is code i have tested on Linux runnng MySql and Qt 5.12.2. but the emit signal doesn't work.
myresoureces.cpp ---- my Class that manage resources
MyResource::MyResource(QObject *parent) : QObject(parent)
if(!openResource())
// qDebug() << "Check Permission of FileSystem For Example.";
emit openResourceFailed("Check Permission of FileSystem For Example.");
bool MyResource::openResource()
// on situation opening resource failed
return false;
main.qml ---- usage of it in qml
// ...
import My.Company.Core 1.0
// ...
MyResource
onOpenResourceFailed:
msgDialog.title = "Open Resource Failed!"
msgDialog.text = error
msgDialog.open()
MessageDialog
id: msgDialog
// ...
main.cpp ---- where i register the class
qmlRegisterType<MyResource>("My.Company.Core", 1, 0, "MyResource");
I expect the Message Dialog to be opened but nothing happened.
qt constructor qml qt5 qt-signals
qt constructor qml qt5 qt-signals
edited Mar 27 at 17:40
eyllanesc
106k12 gold badges38 silver badges70 bronze badges
106k12 gold badges38 silver badges70 bronze badges
asked Mar 27 at 16:42
Aliakbar RashidiAliakbar Rashidi
159 bronze badges
159 bronze badges
add a comment |
add a comment |
1 Answer
1
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oldest
votes
The signals will invoke the methods that are connected at the time of the signal emission, in your case in the constructor is not connected to any slot so the data will be lost, a possible solution is to use a QTimer::singleShot(0, ...)
to be emitted a moment after the creation:
MyResource::MyResource(QObject *parent=nullptr) : QObject(parent)
if(!openResource())
QTimer::singleShot(0, this, [this]()
emit openResourceFailed("Check Permission of FileSystem For Example.");
);
Another alternative solution is to use QQmlParserStatus as an interface and emit the signal in the componentComplete()
method:
*.h
#ifndef MYRESOURCE_H
#define MYRESOURCE_H
#include <QObject>
#include <QQmlParserStatus>
class MyResource: public QObject, public QQmlParserStatus
Q_OBJECT
Q_INTERFACES(QQmlParserStatus)
public:
MyResource(QObject *parent=nullptr);
void classBegin();
void componentComplete();
signals:
void openResourceFailed(const QString & error);
private:
bool openResource();
;
#endif // MYRESOURCE_H
*.cpp
#include "myresource.h"
MyResource::MyResource(QObject *parent) : QObject(parent)
void MyResource::classBegin()
void MyResource::componentComplete()
if(!openResource())
emit openResourceFailed("Check Permission of FileSystem For Example.");
bool MyResource::openResource()
// on situation opening resource failed
return false;
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
The signals will invoke the methods that are connected at the time of the signal emission, in your case in the constructor is not connected to any slot so the data will be lost, a possible solution is to use a QTimer::singleShot(0, ...)
to be emitted a moment after the creation:
MyResource::MyResource(QObject *parent=nullptr) : QObject(parent)
if(!openResource())
QTimer::singleShot(0, this, [this]()
emit openResourceFailed("Check Permission of FileSystem For Example.");
);
Another alternative solution is to use QQmlParserStatus as an interface and emit the signal in the componentComplete()
method:
*.h
#ifndef MYRESOURCE_H
#define MYRESOURCE_H
#include <QObject>
#include <QQmlParserStatus>
class MyResource: public QObject, public QQmlParserStatus
Q_OBJECT
Q_INTERFACES(QQmlParserStatus)
public:
MyResource(QObject *parent=nullptr);
void classBegin();
void componentComplete();
signals:
void openResourceFailed(const QString & error);
private:
bool openResource();
;
#endif // MYRESOURCE_H
*.cpp
#include "myresource.h"
MyResource::MyResource(QObject *parent) : QObject(parent)
void MyResource::classBegin()
void MyResource::componentComplete()
if(!openResource())
emit openResourceFailed("Check Permission of FileSystem For Example.");
bool MyResource::openResource()
// on situation opening resource failed
return false;
add a comment |
The signals will invoke the methods that are connected at the time of the signal emission, in your case in the constructor is not connected to any slot so the data will be lost, a possible solution is to use a QTimer::singleShot(0, ...)
to be emitted a moment after the creation:
MyResource::MyResource(QObject *parent=nullptr) : QObject(parent)
if(!openResource())
QTimer::singleShot(0, this, [this]()
emit openResourceFailed("Check Permission of FileSystem For Example.");
);
Another alternative solution is to use QQmlParserStatus as an interface and emit the signal in the componentComplete()
method:
*.h
#ifndef MYRESOURCE_H
#define MYRESOURCE_H
#include <QObject>
#include <QQmlParserStatus>
class MyResource: public QObject, public QQmlParserStatus
Q_OBJECT
Q_INTERFACES(QQmlParserStatus)
public:
MyResource(QObject *parent=nullptr);
void classBegin();
void componentComplete();
signals:
void openResourceFailed(const QString & error);
private:
bool openResource();
;
#endif // MYRESOURCE_H
*.cpp
#include "myresource.h"
MyResource::MyResource(QObject *parent) : QObject(parent)
void MyResource::classBegin()
void MyResource::componentComplete()
if(!openResource())
emit openResourceFailed("Check Permission of FileSystem For Example.");
bool MyResource::openResource()
// on situation opening resource failed
return false;
add a comment |
The signals will invoke the methods that are connected at the time of the signal emission, in your case in the constructor is not connected to any slot so the data will be lost, a possible solution is to use a QTimer::singleShot(0, ...)
to be emitted a moment after the creation:
MyResource::MyResource(QObject *parent=nullptr) : QObject(parent)
if(!openResource())
QTimer::singleShot(0, this, [this]()
emit openResourceFailed("Check Permission of FileSystem For Example.");
);
Another alternative solution is to use QQmlParserStatus as an interface and emit the signal in the componentComplete()
method:
*.h
#ifndef MYRESOURCE_H
#define MYRESOURCE_H
#include <QObject>
#include <QQmlParserStatus>
class MyResource: public QObject, public QQmlParserStatus
Q_OBJECT
Q_INTERFACES(QQmlParserStatus)
public:
MyResource(QObject *parent=nullptr);
void classBegin();
void componentComplete();
signals:
void openResourceFailed(const QString & error);
private:
bool openResource();
;
#endif // MYRESOURCE_H
*.cpp
#include "myresource.h"
MyResource::MyResource(QObject *parent) : QObject(parent)
void MyResource::classBegin()
void MyResource::componentComplete()
if(!openResource())
emit openResourceFailed("Check Permission of FileSystem For Example.");
bool MyResource::openResource()
// on situation opening resource failed
return false;
The signals will invoke the methods that are connected at the time of the signal emission, in your case in the constructor is not connected to any slot so the data will be lost, a possible solution is to use a QTimer::singleShot(0, ...)
to be emitted a moment after the creation:
MyResource::MyResource(QObject *parent=nullptr) : QObject(parent)
if(!openResource())
QTimer::singleShot(0, this, [this]()
emit openResourceFailed("Check Permission of FileSystem For Example.");
);
Another alternative solution is to use QQmlParserStatus as an interface and emit the signal in the componentComplete()
method:
*.h
#ifndef MYRESOURCE_H
#define MYRESOURCE_H
#include <QObject>
#include <QQmlParserStatus>
class MyResource: public QObject, public QQmlParserStatus
Q_OBJECT
Q_INTERFACES(QQmlParserStatus)
public:
MyResource(QObject *parent=nullptr);
void classBegin();
void componentComplete();
signals:
void openResourceFailed(const QString & error);
private:
bool openResource();
;
#endif // MYRESOURCE_H
*.cpp
#include "myresource.h"
MyResource::MyResource(QObject *parent) : QObject(parent)
void MyResource::classBegin()
void MyResource::componentComplete()
if(!openResource())
emit openResourceFailed("Check Permission of FileSystem For Example.");
bool MyResource::openResource()
// on situation opening resource failed
return false;
answered Mar 27 at 17:13
eyllanesceyllanesc
106k12 gold badges38 silver badges70 bronze badges
106k12 gold badges38 silver badges70 bronze badges
add a comment |
add a comment |
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