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Emit Signal in Constructor of Qml Registered Type doesn't Work


Exposing an enum in a QML signalHow to catch C++ signal in QML signal handler after type registration?Accessing properties of a C++ object passed as signal parameter to QMLHow to call slot with QFlags argument from QMLManage the lifetime of C++ QObjects passed to QML in SignalsAfter instantiating c++ object in QML its parent is nullQt Qml connect to a signal of a QObject property of a Context PropertyConnecting callback to QML Singleton Type declared in C++C++ signal not catched on QML sideHow can i use Model c++ class in cascade with 2 other repeater in .qml file






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1















I am setting up a resource manager class for my application. to manage all state of resources, i need to emmit a Signal from constructor if it don't succeed to catch resource.



In fact i want to emit signal from constructor of QObject Derived Class that registered for qml via qmlRegisterType.



this is code i have tested on Linux runnng MySql and Qt 5.12.2. but the emit signal doesn't work.



myresoureces.cpp ---- my Class that manage resources



MyResource::MyResource(QObject *parent) : QObject(parent)

if(!openResource())
// qDebug() << "Check Permission of FileSystem For Example.";
emit openResourceFailed("Check Permission of FileSystem For Example.");



bool MyResource::openResource()

// on situation opening resource failed
return false;





main.qml ---- usage of it in qml



// ...
import My.Company.Core 1.0
// ...

MyResource
onOpenResourceFailed:
msgDialog.title = "Open Resource Failed!"
msgDialog.text = error
msgDialog.open()



MessageDialog
id: msgDialog


// ...



main.cpp ---- where i register the class



qmlRegisterType<MyResource>("My.Company.Core", 1, 0, "MyResource");



I expect the Message Dialog to be opened but nothing happened.










share|improve this question
































    1















    I am setting up a resource manager class for my application. to manage all state of resources, i need to emmit a Signal from constructor if it don't succeed to catch resource.



    In fact i want to emit signal from constructor of QObject Derived Class that registered for qml via qmlRegisterType.



    this is code i have tested on Linux runnng MySql and Qt 5.12.2. but the emit signal doesn't work.



    myresoureces.cpp ---- my Class that manage resources



    MyResource::MyResource(QObject *parent) : QObject(parent)

    if(!openResource())
    // qDebug() << "Check Permission of FileSystem For Example.";
    emit openResourceFailed("Check Permission of FileSystem For Example.");



    bool MyResource::openResource()

    // on situation opening resource failed
    return false;





    main.qml ---- usage of it in qml



    // ...
    import My.Company.Core 1.0
    // ...

    MyResource
    onOpenResourceFailed:
    msgDialog.title = "Open Resource Failed!"
    msgDialog.text = error
    msgDialog.open()



    MessageDialog
    id: msgDialog


    // ...



    main.cpp ---- where i register the class



    qmlRegisterType<MyResource>("My.Company.Core", 1, 0, "MyResource");



    I expect the Message Dialog to be opened but nothing happened.










    share|improve this question




























      1












      1








      1


      0






      I am setting up a resource manager class for my application. to manage all state of resources, i need to emmit a Signal from constructor if it don't succeed to catch resource.



      In fact i want to emit signal from constructor of QObject Derived Class that registered for qml via qmlRegisterType.



      this is code i have tested on Linux runnng MySql and Qt 5.12.2. but the emit signal doesn't work.



      myresoureces.cpp ---- my Class that manage resources



      MyResource::MyResource(QObject *parent) : QObject(parent)

      if(!openResource())
      // qDebug() << "Check Permission of FileSystem For Example.";
      emit openResourceFailed("Check Permission of FileSystem For Example.");



      bool MyResource::openResource()

      // on situation opening resource failed
      return false;





      main.qml ---- usage of it in qml



      // ...
      import My.Company.Core 1.0
      // ...

      MyResource
      onOpenResourceFailed:
      msgDialog.title = "Open Resource Failed!"
      msgDialog.text = error
      msgDialog.open()



      MessageDialog
      id: msgDialog


      // ...



      main.cpp ---- where i register the class



      qmlRegisterType<MyResource>("My.Company.Core", 1, 0, "MyResource");



      I expect the Message Dialog to be opened but nothing happened.










      share|improve this question
















      I am setting up a resource manager class for my application. to manage all state of resources, i need to emmit a Signal from constructor if it don't succeed to catch resource.



      In fact i want to emit signal from constructor of QObject Derived Class that registered for qml via qmlRegisterType.



      this is code i have tested on Linux runnng MySql and Qt 5.12.2. but the emit signal doesn't work.



      myresoureces.cpp ---- my Class that manage resources



      MyResource::MyResource(QObject *parent) : QObject(parent)

      if(!openResource())
      // qDebug() << "Check Permission of FileSystem For Example.";
      emit openResourceFailed("Check Permission of FileSystem For Example.");



      bool MyResource::openResource()

      // on situation opening resource failed
      return false;





      main.qml ---- usage of it in qml



      // ...
      import My.Company.Core 1.0
      // ...

      MyResource
      onOpenResourceFailed:
      msgDialog.title = "Open Resource Failed!"
      msgDialog.text = error
      msgDialog.open()



      MessageDialog
      id: msgDialog


      // ...



      main.cpp ---- where i register the class



      qmlRegisterType<MyResource>("My.Company.Core", 1, 0, "MyResource");



      I expect the Message Dialog to be opened but nothing happened.







      qt constructor qml qt5 qt-signals






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited Mar 27 at 17:40









      eyllanesc

      106k12 gold badges38 silver badges70 bronze badges




      106k12 gold badges38 silver badges70 bronze badges










      asked Mar 27 at 16:42









      Aliakbar RashidiAliakbar Rashidi

      159 bronze badges




      159 bronze badges

























          1 Answer
          1






          active

          oldest

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          1















          The signals will invoke the methods that are connected at the time of the signal emission, in your case in the constructor is not connected to any slot so the data will be lost, a possible solution is to use a QTimer::singleShot(0, ...) to be emitted a moment after the creation:



          MyResource::MyResource(QObject *parent=nullptr) : QObject(parent)
          if(!openResource())
          QTimer::singleShot(0, this, [this]()
          emit openResourceFailed("Check Permission of FileSystem For Example.");
          );




          Another alternative solution is to use QQmlParserStatus as an interface and emit the signal in the componentComplete() method:



          *.h



          #ifndef MYRESOURCE_H
          #define MYRESOURCE_H

          #include <QObject>
          #include <QQmlParserStatus>

          class MyResource: public QObject, public QQmlParserStatus

          Q_OBJECT
          Q_INTERFACES(QQmlParserStatus)
          public:
          MyResource(QObject *parent=nullptr);
          void classBegin();
          void componentComplete();
          signals:
          void openResourceFailed(const QString & error);
          private:
          bool openResource();
          ;


          #endif // MYRESOURCE_H


          *.cpp



          #include "myresource.h"

          MyResource::MyResource(QObject *parent) : QObject(parent)

          void MyResource::classBegin()

          void MyResource::componentComplete()
          if(!openResource())
          emit openResourceFailed("Check Permission of FileSystem For Example.");



          bool MyResource::openResource()
          // on situation opening resource failed
          return false;






          share|improve this answer
























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            1 Answer
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            active

            oldest

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            active

            oldest

            votes









            1















            The signals will invoke the methods that are connected at the time of the signal emission, in your case in the constructor is not connected to any slot so the data will be lost, a possible solution is to use a QTimer::singleShot(0, ...) to be emitted a moment after the creation:



            MyResource::MyResource(QObject *parent=nullptr) : QObject(parent)
            if(!openResource())
            QTimer::singleShot(0, this, [this]()
            emit openResourceFailed("Check Permission of FileSystem For Example.");
            );




            Another alternative solution is to use QQmlParserStatus as an interface and emit the signal in the componentComplete() method:



            *.h



            #ifndef MYRESOURCE_H
            #define MYRESOURCE_H

            #include <QObject>
            #include <QQmlParserStatus>

            class MyResource: public QObject, public QQmlParserStatus

            Q_OBJECT
            Q_INTERFACES(QQmlParserStatus)
            public:
            MyResource(QObject *parent=nullptr);
            void classBegin();
            void componentComplete();
            signals:
            void openResourceFailed(const QString & error);
            private:
            bool openResource();
            ;


            #endif // MYRESOURCE_H


            *.cpp



            #include "myresource.h"

            MyResource::MyResource(QObject *parent) : QObject(parent)

            void MyResource::classBegin()

            void MyResource::componentComplete()
            if(!openResource())
            emit openResourceFailed("Check Permission of FileSystem For Example.");



            bool MyResource::openResource()
            // on situation opening resource failed
            return false;






            share|improve this answer





























              1















              The signals will invoke the methods that are connected at the time of the signal emission, in your case in the constructor is not connected to any slot so the data will be lost, a possible solution is to use a QTimer::singleShot(0, ...) to be emitted a moment after the creation:



              MyResource::MyResource(QObject *parent=nullptr) : QObject(parent)
              if(!openResource())
              QTimer::singleShot(0, this, [this]()
              emit openResourceFailed("Check Permission of FileSystem For Example.");
              );




              Another alternative solution is to use QQmlParserStatus as an interface and emit the signal in the componentComplete() method:



              *.h



              #ifndef MYRESOURCE_H
              #define MYRESOURCE_H

              #include <QObject>
              #include <QQmlParserStatus>

              class MyResource: public QObject, public QQmlParserStatus

              Q_OBJECT
              Q_INTERFACES(QQmlParserStatus)
              public:
              MyResource(QObject *parent=nullptr);
              void classBegin();
              void componentComplete();
              signals:
              void openResourceFailed(const QString & error);
              private:
              bool openResource();
              ;


              #endif // MYRESOURCE_H


              *.cpp



              #include "myresource.h"

              MyResource::MyResource(QObject *parent) : QObject(parent)

              void MyResource::classBegin()

              void MyResource::componentComplete()
              if(!openResource())
              emit openResourceFailed("Check Permission of FileSystem For Example.");



              bool MyResource::openResource()
              // on situation opening resource failed
              return false;






              share|improve this answer



























                1














                1










                1









                The signals will invoke the methods that are connected at the time of the signal emission, in your case in the constructor is not connected to any slot so the data will be lost, a possible solution is to use a QTimer::singleShot(0, ...) to be emitted a moment after the creation:



                MyResource::MyResource(QObject *parent=nullptr) : QObject(parent)
                if(!openResource())
                QTimer::singleShot(0, this, [this]()
                emit openResourceFailed("Check Permission of FileSystem For Example.");
                );




                Another alternative solution is to use QQmlParserStatus as an interface and emit the signal in the componentComplete() method:



                *.h



                #ifndef MYRESOURCE_H
                #define MYRESOURCE_H

                #include <QObject>
                #include <QQmlParserStatus>

                class MyResource: public QObject, public QQmlParserStatus

                Q_OBJECT
                Q_INTERFACES(QQmlParserStatus)
                public:
                MyResource(QObject *parent=nullptr);
                void classBegin();
                void componentComplete();
                signals:
                void openResourceFailed(const QString & error);
                private:
                bool openResource();
                ;


                #endif // MYRESOURCE_H


                *.cpp



                #include "myresource.h"

                MyResource::MyResource(QObject *parent) : QObject(parent)

                void MyResource::classBegin()

                void MyResource::componentComplete()
                if(!openResource())
                emit openResourceFailed("Check Permission of FileSystem For Example.");



                bool MyResource::openResource()
                // on situation opening resource failed
                return false;






                share|improve this answer













                The signals will invoke the methods that are connected at the time of the signal emission, in your case in the constructor is not connected to any slot so the data will be lost, a possible solution is to use a QTimer::singleShot(0, ...) to be emitted a moment after the creation:



                MyResource::MyResource(QObject *parent=nullptr) : QObject(parent)
                if(!openResource())
                QTimer::singleShot(0, this, [this]()
                emit openResourceFailed("Check Permission of FileSystem For Example.");
                );




                Another alternative solution is to use QQmlParserStatus as an interface and emit the signal in the componentComplete() method:



                *.h



                #ifndef MYRESOURCE_H
                #define MYRESOURCE_H

                #include <QObject>
                #include <QQmlParserStatus>

                class MyResource: public QObject, public QQmlParserStatus

                Q_OBJECT
                Q_INTERFACES(QQmlParserStatus)
                public:
                MyResource(QObject *parent=nullptr);
                void classBegin();
                void componentComplete();
                signals:
                void openResourceFailed(const QString & error);
                private:
                bool openResource();
                ;


                #endif // MYRESOURCE_H


                *.cpp



                #include "myresource.h"

                MyResource::MyResource(QObject *parent) : QObject(parent)

                void MyResource::classBegin()

                void MyResource::componentComplete()
                if(!openResource())
                emit openResourceFailed("Check Permission of FileSystem For Example.");



                bool MyResource::openResource()
                // on situation opening resource failed
                return false;







                share|improve this answer












                share|improve this answer



                share|improve this answer










                answered Mar 27 at 17:13









                eyllanesceyllanesc

                106k12 gold badges38 silver badges70 bronze badges




                106k12 gold badges38 silver badges70 bronze badges





















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