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Open a new winform below from a textbox

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0

I need to open a form exactly below from a textbox. My problem is that i include some invisible panels. When a panel become visible and the textbox is changing it's position, then i am getting wrong new winfrom start position.

Here is what i am trying to do.

 foreach (Control ctrl in myPanel.Controls)
 
 if (ctrl is TextBox)
 
 tb = (TextBox)ctrl;

 tb.DoubleClick += Tb_DoubleClick;
 

 

 private void Tb_DoubleClick(object sender, EventArgs e)
 
 TextBox ts = sender as TextBox;
 if (ts.BackColor == Color.White)
 
 int x = ts.Location.X;
 int y = ts.Location.Y;
 VirtualNumPad2 frm = new VirtualNumPad2();
 frm.Location = new Point(x, y+200 ); 
 frm.ShowDialog();


 


 

c#

share|improve this question

edited Mar 28 at 20:49

user10775950

asked Mar 28 at 20:40

user10775950user10775950

1788 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  foreach (var tb in myPanel.Controls.OfType<TextBox>()) tb.DoubleClick += Tb_DoubleClick; (slightly simpler way to write that loop)
  
  – Rufus L
  Mar 28 at 20:45
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  What start position do you want if the panel is not visible?
  
  – Rufus L
  Mar 28 at 20:47
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  I have upload a picture for understading better what i am trying to do.
  
  – user10775950
  Mar 28 at 20:50
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  When the panel becomes in/visible, handle that event and recalculate the location.
  
  – CodingYoshi
  Mar 28 at 20:57
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  I agree with @CodingYoshi. You need to recalculate location based on visibility. I did something similar in past. if (GlobalParameters.IsSupportPanel1) lciPanel1.Visibility = LayoutVisibility.Always; esiLeft.Width = (lycgMain.Width - lycgMain.Padding.Left - lycgMain.Padding.Right - 96 * 8) / 2; else lciPanel1.Visibility =LayoutVisibility.Never; esiLeft.Width = (lycgMain.Width - lycgMain.Padding.Left - lycgMain.Padding.Right - 96 * 7) / 2;
  
  – Mdyahiya
  Mar 28 at 21:16
  
  

  
  
  
  

 | 
show 2 more comments

0

I need to open a form exactly below from a textbox. My problem is that i include some invisible panels. When a panel become visible and the textbox is changing it's position, then i am getting wrong new winfrom start position.

Here is what i am trying to do.

 foreach (Control ctrl in myPanel.Controls)
 
 if (ctrl is TextBox)
 
 tb = (TextBox)ctrl;

 tb.DoubleClick += Tb_DoubleClick;
 

 

 private void Tb_DoubleClick(object sender, EventArgs e)
 
 TextBox ts = sender as TextBox;
 if (ts.BackColor == Color.White)
 
 int x = ts.Location.X;
 int y = ts.Location.Y;
 VirtualNumPad2 frm = new VirtualNumPad2();
 frm.Location = new Point(x, y+200 ); 
 frm.ShowDialog();


 


 

c#

share|improve this question

edited Mar 28 at 20:49

user10775950

asked Mar 28 at 20:40

user10775950user10775950

1788 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  foreach (var tb in myPanel.Controls.OfType<TextBox>()) tb.DoubleClick += Tb_DoubleClick; (slightly simpler way to write that loop)
  
  – Rufus L
  Mar 28 at 20:45
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  What start position do you want if the panel is not visible?
  
  – Rufus L
  Mar 28 at 20:47
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  I have upload a picture for understading better what i am trying to do.
  
  – user10775950
  Mar 28 at 20:50
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  When the panel becomes in/visible, handle that event and recalculate the location.
  
  – CodingYoshi
  Mar 28 at 20:57
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  I agree with @CodingYoshi. You need to recalculate location based on visibility. I did something similar in past. if (GlobalParameters.IsSupportPanel1) lciPanel1.Visibility = LayoutVisibility.Always; esiLeft.Width = (lycgMain.Width - lycgMain.Padding.Left - lycgMain.Padding.Right - 96 * 8) / 2; else lciPanel1.Visibility =LayoutVisibility.Never; esiLeft.Width = (lycgMain.Width - lycgMain.Padding.Left - lycgMain.Padding.Right - 96 * 7) / 2;
  
  – Mdyahiya
  Mar 28 at 21:16
  
  

  
  
  
  

 | 
show 2 more comments

I need to open a form exactly below from a textbox. My problem is that i include some invisible panels. When a panel become visible and the textbox is changing it's position, then i am getting wrong new winfrom start position.

Here is what i am trying to do.

 foreach (Control ctrl in myPanel.Controls)
 
 if (ctrl is TextBox)
 
 tb = (TextBox)ctrl;

 tb.DoubleClick += Tb_DoubleClick;
 

 

 private void Tb_DoubleClick(object sender, EventArgs e)
 
 TextBox ts = sender as TextBox;
 if (ts.BackColor == Color.White)
 
 int x = ts.Location.X;
 int y = ts.Location.Y;
 VirtualNumPad2 frm = new VirtualNumPad2();
 frm.Location = new Point(x, y+200 ); 
 frm.ShowDialog();


 


 

c#

share|improve this question

edited Mar 28 at 20:49

user10775950

asked Mar 28 at 20:40

user10775950user10775950

1788 bronze badges

 foreach (Control ctrl in myPanel.Controls)
 
 if (ctrl is TextBox)
 
 tb = (TextBox)ctrl;

 tb.DoubleClick += Tb_DoubleClick;
 

 

 private void Tb_DoubleClick(object sender, EventArgs e)
 
 TextBox ts = sender as TextBox;
 if (ts.BackColor == Color.White)
 
 int x = ts.Location.X;
 int y = ts.Location.Y;
 VirtualNumPad2 frm = new VirtualNumPad2();
 frm.Location = new Point(x, y+200 ); 
 frm.ShowDialog();


 


 

share|improve this question

edited Mar 28 at 20:49

user10775950

asked Mar 28 at 20:40

user10775950user10775950

1788 bronze badges

share|improve this question

edited Mar 28 at 20:49

user10775950

asked Mar 28 at 20:40

user10775950user10775950

1788 bronze badges

asked Mar 28 at 20:40

user10775950user10775950

1788 bronze badges

asked Mar 28 at 20:40

user10775950user10775950

1788 bronze badges