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Ionic pass *ng-for information into query params


webpack html-loaders lowercase angular 2 built-in directivesBinding URL Params via RouterLink in Angular AppWhere to put nested for each loops in an Angular component table?Angular QueryParams not fetched on page loadAngular route - how to use forward slashes in routing pathHow do i concatenate the ngFor index variable with a hash symbol?ionic 4 - how to retrieve data passed to a modalHow do I implement Nativescript + Angular list view swipe actions to achieve an item delete?Pass ion-select-option to function - Ionic 4How to generate different routerLinks from ngFor created items?













1















I have an *ng-for loop, churning out ion-items, but I want those items to route to another page, but pass the index of that item, as a query parameter.



Here is my code:



<ion-item *ngFor="let item of items; index as i;" 
[routerLink]="['/itempage']" [queryParams]="id: 'i'"
routerDirection="forward">
<ion-label>item.name</ion-label>
</ion-item>


I have no idea how to get the q: 'i' part to actually make i equal to the index, I keep getting errors and such.










share|improve this question
























  • can you post the errors?

    – Praveenkumar Beedanal
    17 hours ago






  • 2





    I think this [queryParams]="id: 'i'" should look like this [queryParams]="id: i" because you are setting the id to 'i' (string)

    – Josef Katič
    17 hours ago












  • @JosefKatič That worked! How silly of me.

    – Curtis Hennessy
    17 hours ago











  • I will post it as answer

    – Josef Katič
    17 hours ago















1















I have an *ng-for loop, churning out ion-items, but I want those items to route to another page, but pass the index of that item, as a query parameter.



Here is my code:



<ion-item *ngFor="let item of items; index as i;" 
[routerLink]="['/itempage']" [queryParams]="id: 'i'"
routerDirection="forward">
<ion-label>item.name</ion-label>
</ion-item>


I have no idea how to get the q: 'i' part to actually make i equal to the index, I keep getting errors and such.










share|improve this question
























  • can you post the errors?

    – Praveenkumar Beedanal
    17 hours ago






  • 2





    I think this [queryParams]="id: 'i'" should look like this [queryParams]="id: i" because you are setting the id to 'i' (string)

    – Josef Katič
    17 hours ago












  • @JosefKatič That worked! How silly of me.

    – Curtis Hennessy
    17 hours ago











  • I will post it as answer

    – Josef Katič
    17 hours ago













1












1








1


0






I have an *ng-for loop, churning out ion-items, but I want those items to route to another page, but pass the index of that item, as a query parameter.



Here is my code:



<ion-item *ngFor="let item of items; index as i;" 
[routerLink]="['/itempage']" [queryParams]="id: 'i'"
routerDirection="forward">
<ion-label>item.name</ion-label>
</ion-item>


I have no idea how to get the q: 'i' part to actually make i equal to the index, I keep getting errors and such.










share|improve this question
















I have an *ng-for loop, churning out ion-items, but I want those items to route to another page, but pass the index of that item, as a query parameter.



Here is my code:



<ion-item *ngFor="let item of items; index as i;" 
[routerLink]="['/itempage']" [queryParams]="id: 'i'"
routerDirection="forward">
<ion-label>item.name</ion-label>
</ion-item>


I have no idea how to get the q: 'i' part to actually make i equal to the index, I keep getting errors and such.







angular ionic-framework ionic4






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited 15 hours ago









Augustin R

1,009216




1,009216










asked 17 hours ago









Curtis HennessyCurtis Hennessy

155




155












  • can you post the errors?

    – Praveenkumar Beedanal
    17 hours ago






  • 2





    I think this [queryParams]="id: 'i'" should look like this [queryParams]="id: i" because you are setting the id to 'i' (string)

    – Josef Katič
    17 hours ago












  • @JosefKatič That worked! How silly of me.

    – Curtis Hennessy
    17 hours ago











  • I will post it as answer

    – Josef Katič
    17 hours ago

















  • can you post the errors?

    – Praveenkumar Beedanal
    17 hours ago






  • 2





    I think this [queryParams]="id: 'i'" should look like this [queryParams]="id: i" because you are setting the id to 'i' (string)

    – Josef Katič
    17 hours ago












  • @JosefKatič That worked! How silly of me.

    – Curtis Hennessy
    17 hours ago











  • I will post it as answer

    – Josef Katič
    17 hours ago
















can you post the errors?

– Praveenkumar Beedanal
17 hours ago





can you post the errors?

– Praveenkumar Beedanal
17 hours ago




2




2





I think this [queryParams]="id: 'i'" should look like this [queryParams]="id: i" because you are setting the id to 'i' (string)

– Josef Katič
17 hours ago






I think this [queryParams]="id: 'i'" should look like this [queryParams]="id: i" because you are setting the id to 'i' (string)

– Josef Katič
17 hours ago














@JosefKatič That worked! How silly of me.

– Curtis Hennessy
17 hours ago





@JosefKatič That worked! How silly of me.

– Curtis Hennessy
17 hours ago













I will post it as answer

– Josef Katič
17 hours ago





I will post it as answer

– Josef Katič
17 hours ago












1 Answer
1






active

oldest

votes


















3














You are not setting an index there but you are setting id to 'i' which is string.



Change it to this [queryParams]="id: i"






share|improve this answer






















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    3














    You are not setting an index there but you are setting id to 'i' which is string.



    Change it to this [queryParams]="id: i"






    share|improve this answer



























      3














      You are not setting an index there but you are setting id to 'i' which is string.



      Change it to this [queryParams]="id: i"






      share|improve this answer

























        3












        3








        3







        You are not setting an index there but you are setting id to 'i' which is string.



        Change it to this [queryParams]="id: i"






        share|improve this answer













        You are not setting an index there but you are setting id to 'i' which is string.



        Change it to this [queryParams]="id: i"







        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered 17 hours ago









        Josef KatičJosef Katič

        904414




        904414





























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