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Creating a serial port on a com port that is already occupied does not throw an exception

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0

I am using the following python code that I have found in various places to get a list of available com ports that I can connect to.

 def getPorts(self):
 if sys.platform == 'linux':
 ports = ['/dev/ttyUSB%s' % (i) for i in range(60)] # for Linux boxes

 else:
 ports = ['COM%s' % (i) for i in range(20)] #for Windows boxes

 results = list()
 for port in ports:
 try:
 s = serial.Serial(port) #try to create a serial port object

 results.append(port) #if it get this far the port is available
 except (OSError, serial.SerialException):
 print("no port" + port )

 return results

I have two usb ports connected one on USB1 and one on USB2. USB2 is being actively written to by a separate python process. When I use the code the ttyUSB2 port hangs and it gets added to the list of available ports. To me this means that the serial port gets created and an exception is not thrown.

My question is why is an exception not thrown? Could this be something do do with my os? I have used this code snippet successfully in the past.

My os is redhat 7.6

python-3.6 pyserial

share|improve this question

asked Mar 22 at 19:18

JasonJason

11

add a comment | 

0

I am using the following python code that I have found in various places to get a list of available com ports that I can connect to.

 def getPorts(self):
 if sys.platform == 'linux':
 ports = ['/dev/ttyUSB%s' % (i) for i in range(60)] # for Linux boxes

 else:
 ports = ['COM%s' % (i) for i in range(20)] #for Windows boxes

 results = list()
 for port in ports:
 try:
 s = serial.Serial(port) #try to create a serial port object

 results.append(port) #if it get this far the port is available
 except (OSError, serial.SerialException):
 print("no port" + port )

 return results

I have two usb ports connected one on USB1 and one on USB2. USB2 is being actively written to by a separate python process. When I use the code the ttyUSB2 port hangs and it gets added to the list of available ports. To me this means that the serial port gets created and an exception is not thrown.

My question is why is an exception not thrown? Could this be something do do with my os? I have used this code snippet successfully in the past.

My os is redhat 7.6

python-3.6 pyserial

share|improve this question

asked Mar 22 at 19:18

JasonJason

11

add a comment | 

I am using the following python code that I have found in various places to get a list of available com ports that I can connect to.

 def getPorts(self):
 if sys.platform == 'linux':
 ports = ['/dev/ttyUSB%s' % (i) for i in range(60)] # for Linux boxes

 else:
 ports = ['COM%s' % (i) for i in range(20)] #for Windows boxes

 results = list()
 for port in ports:
 try:
 s = serial.Serial(port) #try to create a serial port object

 results.append(port) #if it get this far the port is available
 except (OSError, serial.SerialException):
 print("no port" + port )

 return results

I have two usb ports connected one on USB1 and one on USB2. USB2 is being actively written to by a separate python process. When I use the code the ttyUSB2 port hangs and it gets added to the list of available ports. To me this means that the serial port gets created and an exception is not thrown.

My question is why is an exception not thrown? Could this be something do do with my os? I have used this code snippet successfully in the past.

My os is redhat 7.6

python-3.6 pyserial

share|improve this question

asked Mar 22 at 19:18

JasonJason

11

 def getPorts(self):
 if sys.platform == 'linux':
 ports = ['/dev/ttyUSB%s' % (i) for i in range(60)] # for Linux boxes

 else:
 ports = ['COM%s' % (i) for i in range(20)] #for Windows boxes

 results = list()
 for port in ports:
 try:
 s = serial.Serial(port) #try to create a serial port object

 results.append(port) #if it get this far the port is available
 except (OSError, serial.SerialException):
 print("no port" + port )

 return results

share|improve this question

asked Mar 22 at 19:18

JasonJason

11

share|improve this question

asked Mar 22 at 19:18

JasonJason

11

asked Mar 22 at 19:18

JasonJason

11

asked Mar 22 at 19:18

JasonJason

11