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How to set salary for object before adding it arraylist
How do I efficiently iterate over each entry in a Java Map?Create ArrayList from arrayHow do I read / convert an InputStream into a String in Java?When to use LinkedList over ArrayList in Java?How do I generate random integers within a specific range in Java?Initialization of an ArrayList in one lineSort ArrayList of custom Objects by propertyIs null check needed before calling instanceof?Convert ArrayList<String> to String[] arrayHow do I convert a String to an int in Java?
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Im reading data from a text file
which includes information about employees details
as the following:
H ,name ,socialNumber,hours,rate
S,name,social number,salary
and add them to tow lists.
If they are hourly employee:
H.add(new Hourly(name ,number,hour,rate);
Else if they were salaried:
S.add(new salaried(name,number);
The question is: how to add the salary for the employee before adding the object to the list?
hourly = rate*hours
Salaried = salary
I have attribute salary
and mutator method which sets double salary
I also set the salary after adding the object to the list,
but the took the last salary form the text
The first 1500 the second 2000
java
edited Mar 22 at 19:32
Pavel Smirnov
2,5591818
asked Mar 22 at 19:15
Faisal GaroushFaisal Garoush
1
add a comment |
Im reading data from a text file
which includes information about employees details
as the following:
H ,name ,socialNumber,hours,rate
S,name,social number,salary
and add them to tow lists.
If they are hourly employee:
H.add(new Hourly(name ,number,hour,rate);
Else if they were salaried:
S.add(new salaried(name,number);
The question is: how to add the salary for the employee before adding the object to the list?
hourly = rate*hours
Salaried = salary
I have attribute salary
and mutator method which sets double salary
I also set the salary after adding the object to the list,
but the took the last salary form the text
The first 1500 the second 2000
java
edited Mar 22 at 19:32
Pavel Smirnov
2,5591818
asked Mar 22 at 19:15
Faisal GaroushFaisal Garoush
1
4
Can't you just calculate that in the constructor of the objects, or create the objects above theaddline, and set the salary before adding it in? Show some code as a Minimal, Complete, and Verifiable example and clarify what exactly you need help with.
– Carcigenicate
Mar 22 at 19:17
It works , obj 1 , 2 then set salary cause I know there is only tow employee What if I don’t now how many salaried employee? How many objects should I create ?
– Faisal Garoush
Mar 22 at 19:58
I tried to upload a photo of the project but it couldn’t upload
– Faisal Garoush
Mar 22 at 20:02
All relevant code should be posted here directly as text.
– Carcigenicate
Mar 22 at 20:05
add a comment |
Im reading data from a text file
which includes information about employees details
as the following:
H ,name ,socialNumber,hours,rate
S,name,social number,salary
and add them to tow lists.
If they are hourly employee:
H.add(new Hourly(name ,number,hour,rate);
Else if they were salaried:
S.add(new salaried(name,number);
The question is: how to add the salary for the employee before adding the object to the list?
hourly = rate*hours
Salaried = salary
I have attribute salary
and mutator method which sets double salary
I also set the salary after adding the object to the list,
but the took the last salary form the text
The first 1500 the second 2000
java
edited Mar 22 at 19:32
Pavel Smirnov
2,5591818
asked Mar 22 at 19:15
Faisal GaroushFaisal Garoush
1
Im reading data from a text file
which includes information about employees details
as the following:
H ,name ,socialNumber,hours,rate
S,name,social number,salary
and add them to tow lists.
If they are hourly employee:
H.add(new Hourly(name ,number,hour,rate);
Else if they were salaried:
S.add(new salaried(name,number);
The question is: how to add the salary for the employee before adding the object to the list?
hourly = rate*hours
Salaried = salary
I have attribute salary
and mutator method which sets double salary
I also set the salary after adding the object to the list,
but the took the last salary form the text
The first 1500 the second 2000
java
java
edited Mar 22 at 19:32
Pavel Smirnov
2,5591818
asked Mar 22 at 19:15
Faisal GaroushFaisal Garoush
1
edited Mar 22 at 19:32
Pavel Smirnov
2,5591818
asked Mar 22 at 19:15
Faisal GaroushFaisal Garoush
1
edited Mar 22 at 19:32
Pavel Smirnov
2,5591818
edited Mar 22 at 19:32
Pavel Smirnov
2,5591818
edited Mar 22 at 19:32
Pavel Smirnov
2,5591818
2,5591818
asked Mar 22 at 19:15
Faisal GaroushFaisal Garoush
1
asked Mar 22 at 19:15
Faisal GaroushFaisal Garoush
1
asked Mar 22 at 19:15
Faisal GaroushFaisal Garoush
1
1
4
Can't you just calculate that in the constructor of the objects, or create the objects above theaddline, and set the salary before adding it in? Show some code as a Minimal, Complete, and Verifiable example and clarify what exactly you need help with.
– Carcigenicate
Mar 22 at 19:17
It works , obj 1 , 2 then set salary cause I know there is only tow employee What if I don’t now how many salaried employee? How many objects should I create ?
– Faisal Garoush
Mar 22 at 19:58
I tried to upload a photo of the project but it couldn’t upload
– Faisal Garoush
Mar 22 at 20:02
All relevant code should be posted here directly as text.
– Carcigenicate
Mar 22 at 20:05
add a comment |
4
Can't you just calculate that in the constructor of the objects, or create the objects above theaddline, and set the salary before adding it in? Show some code as a Minimal, Complete, and Verifiable example and clarify what exactly you need help with.
– Carcigenicate
Mar 22 at 19:17
It works , obj 1 , 2 then set salary cause I know there is only tow employee What if I don’t now how many salaried employee? How many objects should I create ?
– Faisal Garoush
Mar 22 at 19:58
I tried to upload a photo of the project but it couldn’t upload
– Faisal Garoush
Mar 22 at 20:02
All relevant code should be posted here directly as text.
– Carcigenicate
Mar 22 at 20:05
4
4
Can't you just calculate that in the constructor of the objects, or create the objects above the
add line, and set the salary before adding it in? Show some code as a Minimal, Complete, and Verifiable example and clarify what exactly you need help with.– Carcigenicate
Mar 22 at 19:17
Can't you just calculate that in the constructor of the objects, or create the objects above the
add line, and set the salary before adding it in? Show some code as a Minimal, Complete, and Verifiable example and clarify what exactly you need help with.– Carcigenicate
Mar 22 at 19:17
It works , obj 1 , 2 then set salary cause I know there is only tow employee What if I don’t now how many salaried employee? How many objects should I create ?
– Faisal Garoush
Mar 22 at 19:58
It works , obj 1 , 2 then set salary cause I know there is only tow employee What if I don’t now how many salaried employee? How many objects should I create ?
– Faisal Garoush
Mar 22 at 19:58
I tried to upload a photo of the project but it couldn’t upload
– Faisal Garoush
Mar 22 at 20:02
I tried to upload a photo of the project but it couldn’t upload
– Faisal Garoush
Mar 22 at 20:02
All relevant code should be posted here directly as text.
– Carcigenicate
Mar 22 at 20:05
All relevant code should be posted here directly as text.
– Carcigenicate
Mar 22 at 20:05
add a comment |
2 Answers
2
active
oldest
votes
If you want to set the Salary before adding it to the List, you can define the new Entry before, change the Salary and then adding it:
Salaried s = Salaried(name,number);
s.setSalary(computedSalary);
S.add(s);
I hope that help you,
Regards
answered Mar 22 at 19:37
Alejandro GranadosAlejandro Granados
1086
add a comment |
You may consider the builder pattern, which offers a flexible way of constructing objects:
public class Salaried
String name;
String socialNumber;
Double salary;
...
public static class Builder
String name;
String socialNumber;
Double salary;
public Builder(String name, String socialNumber)
this.name = name;
this.socialNumber = socialNumber;
public Builder salary(Double salary)
this.salary = salary;
return this;
public Salaried build()
Salaried salaried = new Salaried(name, socialNumber);
salaried.setSalary(salary);
return salaried;
S.add(new Salaried.Builder("bob","12345678").salary(40000).build());
answered Mar 22 at 19:56
Jin KimJin Kim
7,121134373
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
If you want to set the Salary before adding it to the List, you can define the new Entry before, change the Salary and then adding it:
Salaried s = Salaried(name,number);
s.setSalary(computedSalary);
S.add(s);
I hope that help you,
Regards
answered Mar 22 at 19:37
Alejandro GranadosAlejandro Granados
1086
add a comment |
If you want to set the Salary before adding it to the List, you can define the new Entry before, change the Salary and then adding it:
Salaried s = Salaried(name,number);
s.setSalary(computedSalary);
S.add(s);
I hope that help you,
Regards
answered Mar 22 at 19:37
Alejandro GranadosAlejandro Granados
1086
add a comment |
If you want to set the Salary before adding it to the List, you can define the new Entry before, change the Salary and then adding it:
Salaried s = Salaried(name,number);
s.setSalary(computedSalary);
S.add(s);
I hope that help you,
Regards
answered Mar 22 at 19:37
Alejandro GranadosAlejandro Granados
1086
If you want to set the Salary before adding it to the List, you can define the new Entry before, change the Salary and then adding it:
Salaried s = Salaried(name,number);
s.setSalary(computedSalary);
S.add(s);
I hope that help you,
Regards
answered Mar 22 at 19:37
Alejandro GranadosAlejandro Granados
1086
answered Mar 22 at 19:37
Alejandro GranadosAlejandro Granados
1086
answered Mar 22 at 19:37
Alejandro GranadosAlejandro Granados
1086
answered Mar 22 at 19:37
Alejandro GranadosAlejandro Granados
1086
1086
add a comment |
add a comment |
You may consider the builder pattern, which offers a flexible way of constructing objects:
public class Salaried
String name;
String socialNumber;
Double salary;
...
public static class Builder
String name;
String socialNumber;
Double salary;
public Builder(String name, String socialNumber)
this.name = name;
this.socialNumber = socialNumber;
public Builder salary(Double salary)
this.salary = salary;
return this;
public Salaried build()
Salaried salaried = new Salaried(name, socialNumber);
salaried.setSalary(salary);
return salaried;
S.add(new Salaried.Builder("bob","12345678").salary(40000).build());
answered Mar 22 at 19:56
Jin KimJin Kim
7,121134373
add a comment |
You may consider the builder pattern, which offers a flexible way of constructing objects:
public class Salaried
String name;
String socialNumber;
Double salary;
...
public static class Builder
String name;
String socialNumber;
Double salary;
public Builder(String name, String socialNumber)
this.name = name;
this.socialNumber = socialNumber;
public Builder salary(Double salary)
this.salary = salary;
return this;
public Salaried build()
Salaried salaried = new Salaried(name, socialNumber);
salaried.setSalary(salary);
return salaried;
S.add(new Salaried.Builder("bob","12345678").salary(40000).build());
answered Mar 22 at 19:56
Jin KimJin Kim
7,121134373
add a comment |
You may consider the builder pattern, which offers a flexible way of constructing objects:
public class Salaried
String name;
String socialNumber;
Double salary;
...
public static class Builder
String name;
String socialNumber;
Double salary;
public Builder(String name, String socialNumber)
this.name = name;
this.socialNumber = socialNumber;
public Builder salary(Double salary)
this.salary = salary;
return this;
public Salaried build()
Salaried salaried = new Salaried(name, socialNumber);
salaried.setSalary(salary);
return salaried;
S.add(new Salaried.Builder("bob","12345678").salary(40000).build());
answered Mar 22 at 19:56
Jin KimJin Kim
7,121134373
You may consider the builder pattern, which offers a flexible way of constructing objects:
public class Salaried
String name;
String socialNumber;
Double salary;
...
public static class Builder
String name;
String socialNumber;
Double salary;
public Builder(String name, String socialNumber)
this.name = name;
this.socialNumber = socialNumber;
public Builder salary(Double salary)
this.salary = salary;
return this;
public Salaried build()
Salaried salaried = new Salaried(name, socialNumber);
salaried.setSalary(salary);
return salaried;
S.add(new Salaried.Builder("bob","12345678").salary(40000).build());
answered Mar 22 at 19:56
Jin KimJin Kim
7,121134373
answered Mar 22 at 19:56
Jin KimJin Kim
7,121134373
answered Mar 22 at 19:56
Jin KimJin Kim
7,121134373
answered Mar 22 at 19:56
Jin KimJin Kim
7,121134373
7,121134373
add a comment |
add a comment |
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4
Can't you just calculate that in the constructor of the objects, or create the objects above the
addline, and set the salary before adding it in? Show some code as a Minimal, Complete, and Verifiable example and clarify what exactly you need help with.– Carcigenicate
Mar 22 at 19:17
It works , obj 1 , 2 then set salary cause I know there is only tow employee What if I don’t now how many salaried employee? How many objects should I create ?
– Faisal Garoush
Mar 22 at 19:58
I tried to upload a photo of the project but it couldn’t upload
– Faisal Garoush
Mar 22 at 20:02
All relevant code should be posted here directly as text.
– Carcigenicate
Mar 22 at 20:05