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0

I tried to solve the problem below:

My Index Of:
Define a function, myIndexOf, that accepts three arguments:

• source (string)


• searchValue (string)


• startIdx (number) - optional

If the source contains the searchValue, return the index at which the searchValue starts.

If the searchValue appears more than once in the source, return the index from the first occurance of the searchValue. If the searchValue doesn't exist in the source, return -1.

If a startIdx is passed into the function, ignore any instances of the searchValue that occur before that index. If no startIdx is provided, start searching from the beginning of the source.

Do not use the built-in .indexOf string method in your answer.

I tried the following code:

function myIndexOf(source, searchValue, startIdx=0)

 for (i=startIdx; i<=source.length - searchValue.length; i++)

 //console.log(source[i])

 let subString = source.slice(i, i+searchValue.length);

 if(subString === searchValue)
 return i
 
 else 
 return -1
 
 


myIndexOf('twice twice', 'ice', 5);

The function should return 8 but instead it returns -1. I know the else statement is probably what's causing the error but I don't understand why the else statement can't be where it is.

javascript string if-statement search indexing

share|improve this question

edited Mar 22 at 20:20

chazsolo

5,44511234

asked Mar 22 at 20:02

PineNuts0PineNuts0

90731432

add a comment | 

0

I tried to solve the problem below:

My Index Of:
Define a function, myIndexOf, that accepts three arguments:

• source (string)


• searchValue (string)


• startIdx (number) - optional

If the source contains the searchValue, return the index at which the searchValue starts.

If the searchValue appears more than once in the source, return the index from the first occurance of the searchValue. If the searchValue doesn't exist in the source, return -1.

If a startIdx is passed into the function, ignore any instances of the searchValue that occur before that index. If no startIdx is provided, start searching from the beginning of the source.

Do not use the built-in .indexOf string method in your answer.

I tried the following code:

function myIndexOf(source, searchValue, startIdx=0)

 for (i=startIdx; i<=source.length - searchValue.length; i++)

 //console.log(source[i])

 let subString = source.slice(i, i+searchValue.length);

 if(subString === searchValue)
 return i
 
 else 
 return -1
 
 


myIndexOf('twice twice', 'ice', 5);

The function should return 8 but instead it returns -1. I know the else statement is probably what's causing the error but I don't understand why the else statement can't be where it is.

javascript string if-statement search indexing

share|improve this question

edited Mar 22 at 20:20

chazsolo

5,44511234

asked Mar 22 at 20:02

PineNuts0PineNuts0

90731432

add a comment | 

I tried to solve the problem below:

My Index Of:
Define a function, myIndexOf, that accepts three arguments:

• source (string)


• searchValue (string)


• startIdx (number) - optional

If the source contains the searchValue, return the index at which the searchValue starts.

If the searchValue appears more than once in the source, return the index from the first occurance of the searchValue. If the searchValue doesn't exist in the source, return -1.

If a startIdx is passed into the function, ignore any instances of the searchValue that occur before that index. If no startIdx is provided, start searching from the beginning of the source.

Do not use the built-in .indexOf string method in your answer.

I tried the following code:

function myIndexOf(source, searchValue, startIdx=0)

 for (i=startIdx; i<=source.length - searchValue.length; i++)

 //console.log(source[i])

 let subString = source.slice(i, i+searchValue.length);

 if(subString === searchValue)
 return i
 
 else 
 return -1
 
 


myIndexOf('twice twice', 'ice', 5);

The function should return 8 but instead it returns -1. I know the else statement is probably what's causing the error but I don't understand why the else statement can't be where it is.

javascript string if-statement search indexing

share|improve this question

edited Mar 22 at 20:20

chazsolo

5,44511234

asked Mar 22 at 20:02

PineNuts0PineNuts0

90731432

function myIndexOf(source, searchValue, startIdx=0)

 for (i=startIdx; i<=source.length - searchValue.length; i++)

 //console.log(source[i])

 let subString = source.slice(i, i+searchValue.length);

 if(subString === searchValue)
 return i
 
 else 
 return -1
 
 


myIndexOf('twice twice', 'ice', 5);

share|improve this question

edited Mar 22 at 20:20

chazsolo

5,44511234

asked Mar 22 at 20:02

PineNuts0PineNuts0

90731432

share|improve this question

edited Mar 22 at 20:20

chazsolo

5,44511234

asked Mar 22 at 20:02

PineNuts0PineNuts0

90731432

edited Mar 22 at 20:20

chazsolo

5,44511234

edited Mar 22 at 20:20

chazsolo

5,44511234

asked Mar 22 at 20:02

PineNuts0PineNuts0

90731432

asked Mar 22 at 20:02

PineNuts0PineNuts0

90731432

1 Answer
1

active

oldest

votes

0

The problem is that the for loop ends after the first iteration. With an else block in there the whole function ends its execution (and therefore the for loop) prematurely because, regardless of the condition being fulfilled, it returns a value.

Try this:

function myIndexOf(source, searchValue, startIdx=0)

 for (i=startIdx; i<=source.length - searchValue.length; i++) 

 let subString = source.slice(i, i+searchValue.length);

 if(subString === searchValue)
 return i;
 

 

 return -1; 

In the function above the for loop will only stop if the searched value is found. If it's never found, the function will return -1 by default.

share|improve this answer

edited Mar 22 at 20:27

answered Mar 22 at 20:13

ChristophChristoph

20125

add a comment | 

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0

The problem is that the for loop ends after the first iteration. With an else block in there the whole function ends its execution (and therefore the for loop) prematurely because, regardless of the condition being fulfilled, it returns a value.

Try this:

function myIndexOf(source, searchValue, startIdx=0)

 for (i=startIdx; i<=source.length - searchValue.length; i++) 

 let subString = source.slice(i, i+searchValue.length);

 if(subString === searchValue)
 return i;
 

 

 return -1; 

In the function above the for loop will only stop if the searched value is found. If it's never found, the function will return -1 by default.

share|improve this answer

edited Mar 22 at 20:27

answered Mar 22 at 20:13

ChristophChristoph

20125

add a comment | 

0

The problem is that the for loop ends after the first iteration. With an else block in there the whole function ends its execution (and therefore the for loop) prematurely because, regardless of the condition being fulfilled, it returns a value.

Try this:

function myIndexOf(source, searchValue, startIdx=0)

 for (i=startIdx; i<=source.length - searchValue.length; i++) 

 let subString = source.slice(i, i+searchValue.length);

 if(subString === searchValue)
 return i;
 

 

 return -1; 

In the function above the for loop will only stop if the searched value is found. If it's never found, the function will return -1 by default.

share|improve this answer

edited Mar 22 at 20:27

answered Mar 22 at 20:13

ChristophChristoph

20125

add a comment | 

The problem is that the for loop ends after the first iteration. With an else block in there the whole function ends its execution (and therefore the for loop) prematurely because, regardless of the condition being fulfilled, it returns a value.

Try this:

function myIndexOf(source, searchValue, startIdx=0)

 for (i=startIdx; i<=source.length - searchValue.length; i++) 

 let subString = source.slice(i, i+searchValue.length);

 if(subString === searchValue)
 return i;
 

 

 return -1; 

In the function above the for loop will only stop if the searched value is found. If it's never found, the function will return -1 by default.

share|improve this answer

edited Mar 22 at 20:27

answered Mar 22 at 20:13

ChristophChristoph

20125

function myIndexOf(source, searchValue, startIdx=0)

 for (i=startIdx; i<=source.length - searchValue.length; i++) 

 let subString = source.slice(i, i+searchValue.length);

 if(subString === searchValue)
 return i;
 

 

 return -1; 

share|improve this answer

edited Mar 22 at 20:27

answered Mar 22 at 20:13

ChristophChristoph

20125

answered Mar 22 at 20:13

ChristophChristoph

20125

answered Mar 22 at 20:13

ChristophChristoph

20125